Related
I have a data structure as the following
[
{
"models":[
{
"name":"xyz",
"options":[
{
"label":"blue"
},
{
"label":"brown"
},
]
},
{
"name":"abc",
"options":[
{
"label":"yellow"
}
]
},
{
"name":"def",
"options":[
{
"label":"green"
}
]
}
]
}
]
The end result should be an array with all of the labels and name like xyz: blue, xyz: brown, abc: yellow, def: green
so something like this
['xyz: blue', 'xyz: brown', 'abc: yellow','def: green']
I'm trying different approaches, one with RxJS operators and another with reduce
let flat = (acc, current) => {
}
models.reduce(flat, [])
You can use a reduce and a map like this.
const arr = [
{
"models":[
{
"name":"xyz",
"options":[
{
"label":"blue"
},
{
"label":"brown"
},
]
},
{
"name":"abc",
"options":[
{
"label":"yellow"
}
]
},
{
"name":"def",
"options":[
{
"label":"green"
}
]
}
]
}
];
const result = arr[0].models.reduce(
(acc, model) => [...acc, ...model.options.map(i => ({ [model.name]: i.label }))]
, []
);
console.log(result);
If the top level array can have multiple items rather than arr[0] you would need to add another reduce feeding it's accumulator in to the second reduce as it's starting accumulator rather than the empty starting array.
const arr = [
{
"models":[
{
"name":"xyz",
"options":[
{
"label":"blue"
},
{
"label":"brown"
},
]
},
{
"name":"abc",
"options":[
{
"label":"yellow"
}
]
},
{
"name":"def",
"options":[
{
"label":"green"
}
]
}
]
},
{
"models":[
{
"name":"ghi",
"options":[
{
"label":"gold"
},
{
"label":"pink"
},
]
}
]
}
];
const result = arr.reduce(
(acc, item) =>
item.models.reduce(
(acc2, model) => [...acc2, ...model.options.map((i) => ({ [model.name]: i.label }))]
, acc
),
[]
);
console.log(result);
Not sure where RxJs comes into this question but if you are looking to transform an object like this that comes back from a http request you would pipe it into the map operator and then use this function inside the map. If you are looking to do a reduce on a stream there is a reduce operator that emits the accumulator when the source stream completes or the scan operator that emits the accumulator each time the source emits.
Use nested calls to flatMap(), and in the innermost call you concatenate the model name with the option label.
const data = [{
"models": [{
"name": "xyz",
"options": [{
"label": "blue"
},
{
"label": "brown"
},
]
},
{
"name": "abc",
"options": [{
"label": "yellow"
}]
},
{
"name": "def",
"options": [{
"label": "green"
}]
}
]
}];
let result = data.flatMap(d => d.models.flatMap(model => model.options.map(option => `${model.name}: ${option.label}`)));
console.log(result);
Here is using multiple forEach and destructuring
const flat = (arr, res = []) => {
arr.forEach(({ models }) =>
models.forEach(({ name, options }) =>
options.forEach(({ label }) => res.push({ [name]: label }))
)
);
return res;
};
const data = [
{
models: [
{
name: "xyz",
options: [
{
label: "blue",
},
{
label: "brown",
},
],
},
{
name: "abc",
options: [
{
label: "yellow",
},
],
},
{
name: "def",
options: [
{
label: "green",
},
],
},
],
},
];
console.log(flat(data));
const response = array[0].models.reduce((initial, model) => {
if (model.options.length === 1)
initial.push(`${model.name}: ${model.options[0].label}`);
else {
model.options.forEach((option) =>
initial.push(`${model.name}: ${option.label}`),
);
}
return initial;
}, []);
console.log(response)
;
// there is no need if the inner option has just one object you can just access it by model.options[0].label, that why there is a check to see if it one
Given the following Array of Objects:
[
{
"teamFK": 8650,
"code": "yellow_cards",
"typeId": 554,
"value": "5",
"side": "home"
},
{
"teamFK": 8650,
"code": "goals",
"typeId": 554,
"value": "1",
"side": "home"
},
{
"teamFK": 8990,
"code": "yellow_cards",
"typeId": 555,
"value": "2",
"side": "away"
},
{
"teamFK": 8990,
"code": "goals",
"typeId": 555,
"value": "0",
"side": "away"
}
]
I would like to group this data by code and get this result:
{
"stats": [
{
"name": "yellow_cards",
"stats": ["5","2"]
},
{
"name": "goals",
"stats": ["2","0"]
}
]
}
What I've done is the following which works but I want to make sure that the alway the stat with "side":"home" always pushed first into the array "stats": []:
const groupedStats = Object.entries(
query.reduce((acc, { typeId, value, code, side }) => {
if (!acc[code]) {
acc[code] = [];
}
acc[code].push(value);
return acc;
}, {}),
).map(([name, stats]) => ({ name, stats }));
My approach is sort it first by side using Array.sort() and then looping through the objects and adding it to stats
i created a const match to find if there is a match already so i dont have to add the name and value again basically if its not a match i'll add it to the stats array and if its a match then i'll just update the current index
const objs = [
{
teamFK: 8650,
code: "yellow_cards",
typeId: 554,
value: "5",
side: "home",
},
{
teamFK: 8650,
code: "goals",
typeId: 554,
value: "1",
side: "away",
},
{
teamFK: 8990,
code: "yellow_cards",
typeId: 555,
value: "2",
side: "away",
},
{
teamFK: 8990,
code: "goals",
typeId: 555,
value: "0",
side: "home",
},
];
let stats = [];
const transformedObj = objs
.sort((a, b) => {
if (a.side > b.side) {
return -1;
}
if (a.side < b.side) {
return 1;
}
return 0;
})
.forEach((obj) => {
const match = stats.find((stat) => stat.name === obj.code);
const statsIndex = stats.findIndex((stat) => stat.name === obj.code);
if (!match) {
stats = [...stats, { name: obj.code, value: [obj.value] }];
} else {
stats[statsIndex] = {
name: stats[statsIndex].name,
value: [...stats[statsIndex].value, obj.value],
};
}
});
console.log(stats);
You can sort array and use key grouping approach:
const data = [{"teamFK": 8650,"code": "yellow_cards","typeId": 554,"value": "5","side": "home"},{"teamFK": 8650,"code": "goals","typeId": 554,"value": "1","side": "home"},{"teamFK": 8990,"code": "yellow_cards","typeId": 555,"value": "2","side": "away"},{"teamFK": 8990,"code": "goals","typeId": 555,"value": "0","side": "away"}];
const groups = data
.sort(({ side: a }, { side: b }) => b.localeCompare(a))
.reduce((acc, { code, value }) => {
acc[code] ??= { name: code, stats: [] };
acc[code]['stats'].push(value);
return acc;
}, {});
const result = { stats: Object.values(groups) };
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0 }
I am trying to find the best way to filter my array of objects with specific key's string. Basically what I am trying to achieve is to get the objects which contain "Type":"Blue". Here is my data:
[
{
"data": [
{}
],
"Name": "1",
"Type": "Blue"
},
{
"data": [
{}
],
"Name": "2",
"Type": "Red"
},
{
"data": [
{}
],
"Name": "3",
"Type": "Blue"
}
]
You could use the filter() method. See the snippet below, as well as a definition of the method from MDN:
The filter() method creates a new array with all elements that pass the test implemented by the provided function.
const data = [
{
data: [{}],
Name: "1",
Type: "Blue"
},
{
data: [{}],
Name: "2",
Type: "Red"
},
{
data: [{}],
Name: "3",
Type: "Blue"
}
];
const filteredData = data.filter((item) => item.Type === "Blue");
console.log(filteredData);
You can use the Array.prototype.filter() method.
arr.filter(obj => obj.Type == 'Blue');
will give you the array containing only the objects with type Blue.
If I understood your requirement correctly, You have a string "Type: Blue" and based on this string you have to filtered out the data array dynamically based on the key as Type and value as Blue. If Yes, Here you go :
const str = "Type: Blue";
const splittedStr = str.split(':');
const data = [
{
Name: "1",
Type: "Blue"
},
{
Name: "2",
Type: "Red"
},
{
Name: "3",
Type: "Blue"
}
];
const filteredData = data.filter((item) => item[splittedStr[0]] === splittedStr[1].trim());
console.log(filteredData);
I get an input like this:
input 1:
{
"name": "Ben",
"description": "Ben",
"attributes": [
{
"type": "Background",
"value": "Default"
},
{
"type": "Hair-color",
"value": "Brown"
}
]
}
input 2
{
"name": "Ice",
"description": "Ice",
"attributes": [
{
"type": "Background",
"value": "Green"
},
{
"type": "Hair-color",
"value": "White"
}
]
}
input 3
{
"name": "Itay",
"description": "Itay",
"attributes": [
{
"type": "Background",
"value": "Default"
},
{
"type": "Hair-color",
"value": "Brown"
}
]
}
What I want to do is count the amount of each type of background and each type of hair-color appearing.
(These are sample examples and in reality there are more types and different values)
Let's say in these examples we have 2 objects that have a background as default then I want to have a count of that like so:
export interface TraitCount {
value: string,
count: number
}
export interface CountOfEachAttribute {
trait_type: string,
trait_count: traitCount[] | null,
total_variations: number
}
I want the most effective code because there are other aspects to the code, in addition it will run on 5-10k queries not just three, so needs
to run in good times too :D
(It's similar to my other question done with python but now I need it in js also)
Atm it's something like this:
(Apart of a much bigger code so keep that in mind)
setInitalCountOfAllAttribute( state, { payload }: PayloadAction<CountOfEachAttribute[] | null> ) {
if (payload === null) {
state.countOfAllAttribute = null;
} else {
state.countOfAllAttribute = payload;
}
},
setCountOfAllAttribute(state, { payload }: PayloadAction<Attribute>) {
if (state.countOfAllAttribute !== null) {
state.countOfAllAttribute.map(
(countOfEachAttribute: CountOfEachAttribute) => {
// Find the trait type
if (countOfEachAttribute.trait_type === payload.trait_type) {
// initiate the trait count array to store all the trait values and add first trait value
if (countOfEachAttribute.trait_count === null) {
const new_trait_count = { value: payload.value, count: 1 };
countOfEachAttribute.trait_count = [new_trait_count];
countOfEachAttribute.total_variations++;
}
// Trait array already existed.
else {
// Check if value already present or not
const checkValue = (obj: any) => obj.value === String(payload.value);
const isPresent = countOfEachAttribute.trait_count.some(checkValue)
const isPresent2 = countOfEachAttribute.trait_count.find((elem: any) => elem.value === String(payload.value))
// Value matched, increase its count by one
if (isPresent2) {
countOfEachAttribute.trait_count &&
countOfEachAttribute.trait_count.map((trait) => {
if (trait.value === payload.value) {
trait.count++;
}
});
}
// Value doesn't match, add a new entry and increase the count of variations by one
else {
const new_trait_count = { value: payload.value, count: 1 };
countOfEachAttribute.trait_count = [
...countOfEachAttribute.trait_count,
new_trait_count,
];
countOfEachAttribute.total_variations++;
}
}
}
}
);
}
},
You can merge all arrays and use Array.reduce.
const input1 = {
"name": "Ben",
"description": "Ben",
"attributes": [{
"type": "Background",
"value": "Default"
},
{
"type": "Hair-color",
"value": "Brown"
}
]
}
const input2 = {
"name": "Ice",
"description": "Ice",
"attributes": [{
"type": "Background",
"value": "Green"
},
{
"type": "Hair-color",
"value": "White"
}
]
}
const input3 = {
"name": "Itay",
"description": "Itay",
"attributes": [{
"type": "Background",
"value": "Default"
},
{
"type": "Hair-color",
"value": "Brown"
}
]
}
const mergedInput = [input1, input2, input3];
const result = mergedInput.reduce((acc, item) => {
item.attributes.forEach(attrItem => {
const existType = acc.find(e => e.trait_type == attrItem.type);
if (existType) {
var existAttr = existType.trait_count.find(e => e.value == attrItem.value);
if (existAttr) {
existAttr.count++;
} else {
existType.trait_count.push({
value: attrItem.value,
count: 1
});
existType.total_variations++;
}
} else {
acc.push({
trait_type: attrItem.type,
trait_count: [{
value: attrItem.value,
count: 1
}],
total_variations: 1
})
}
});
return acc;
}, []);
console.log(result);
I suggest instead of creating an array for trait_count to make it an object so you don't have to iterate over it whenever you are adding a new attribute. In the snippet below I'm using the value of the attribute as a sort of hash that allows the access to the given property without having to call the Array.prototype.find function
const input1 = {"name":"Ben","description":"Ben","attributes":[{"type":"Background","value":"Default"},{"type":"Hair-color","value":"Brown"}]};
const input2 = {"name":"Ice","description":"Ice","attributes":[{"type":"Background","value":"Green"},{"type":"Hair-color","value":"White"}]};
const input3 = {"name":"Itay","description":"Itay","attributes":[{"type":"Background","value":"Default"},{"type":"Hair-color","value":"Brown"}]};
function countAtributes(input, totalCounts={}) {
input.attributes.forEach((attribute) => {
if (!totalCounts[attribute.type])
totalCounts[attribute.type] = {trait_type: attribute.type, trait_count: {}, total_variations: 0};
if (!totalCounts[attribute.type].trait_count[attribute.value]) {
totalCounts[attribute.type].trait_count[attribute.value] = {value: attribute.value, count: 1};
totalCounts[attribute.type].total_variations+=1;
}
else totalCounts[attribute.type].trait_count[attribute.value].count +=1;
})
}
const totalCounts = {};
countAtributes(input1, totalCounts);
countAtributes(input2, totalCounts);
countAtributes(input3, totalCounts);
console.log(totalCounts);
It could be turned into the array afterwards with Object.values if necessary
I believe it is a much better approach to what you had before as you don't have to iterate over the tables of trait_counts. In theory it should significantly reduce the time taken. Iterating over the array and checking a condition each time is much slower than key lookup in Javascript object
I want to filter this array by attributevalue for example
if I do a search by color blue then all shirts give me a blue color then I do search fabric cotton in blue color then give all cottob with blue color you know search by like flipkart, amazon
var myObject= [
{
"Product-name": "Shirt",
"product-price": "500",
"attributevalue": [
{ "color": "red" },
{"fabric": "cottton"}
]
},
{
"Product-name": "Samsung mobile",
"product-price": "15000",
"attributevalue":[
{"Ram": "4 GB"},
{"Network": "4G"},
{"Primary Camera": "8 MP"},
{"Internal Memory": "8 GB"}
]
}
]
You can combinefilter, for and for...in to do that:
var myObject= [
{
"Product-name": "Shirt",
"product-price": "500",
"attributevalue": [
{ "color": "red" },
{"fabric": "cottton"}
]
},
{
"Product-name": "Samsung mobile",
"product-price": "15000",
"attributevalue":[
{"Ram": "4 GB"},
{"Network": "4G"},
{"Primary Camera": "8 MP"},
{"Internal Memory": "8 GB"}
]
}
]
const search = (arr, search) => {
return arr.filter(item => {
for (var i = 0; i < item.attributevalue.length; i++) {
for (var key in item.attributevalue[i]) {
if (item.attributevalue[i][key].toLowerCase() === search.toLowerCase()) {
return item;
}
}
}
})
}
console.log(search(myObject, 'red'))
Just the filter method of Array will do the trick.
var myObject = [{
"Product-name": "Shirt",
"product-price": "500",
"attributevalue": [{
"color": "red"
}, {
"fabric": "cottton"
}]
}, {
"Product-name": "Samsung mobile",
"product-price": "15000",
"attributevalue": [{
"Ram": "4 GB"
}, {
"Network": "4G"
}, {
"Primary Camera": "8 MP"
}, {
"Internal Memory": "8 GB"
}]
}]
function findProduct(property, searchField) {
return myObject.filter((x) => {
const result = x.attributevalue.filter((y) => y[property] === searchField);
if (result.length) {
return x;
}
})
}
console.log(findProduct('Network', '4G'))
Try doing this:
const filterBy = (obj, attr, query) =>
obj.filter((prod) => prod.attributevalue && prod.attributevalue[attr] === query);
Here is an approach supporting multiple filtering (multiple keys and values) and multiple support for the key-value check.
The routine is:
applying filter over the desired object.
mapping the array of attribute value to a single object holding the key (string) and the value.
evaluating the searchBy parameter, which holds an object containing the key, which is the searched key and the value that can either be a primitive, an object or a function. If that's a function, it will be evaluated through the argument passed, which is the currently looped value to search on.
return whether any of the searched criteria match.
var myObject = [
{
"Product-name": "Shirt",
"product-price": "500",
"attributevalue": [
{ "color": "red" },
{"fabric": "cottton"}
]
},
{
"Product-name": "Samsung mobile",
"product-price": "15000",
"attributevalue":[
{"Ram": "4 GB"},
{"Network": "4G"},
{"Primary Camera": "8 MP"},
{"Internal Memory": "8 GB"}
]
}
];
function filterBy(obj, searchBy) {
return obj.filter(item => {
const _assigned = Object.assign({}, ...item.attributevalue);
return Object.entries(searchBy).some(([k,v]) => {
return _assigned[k] && (typeof(v) === 'function' ? v.call(null, _assigned[k]) : _assigned[k] === v);
});
});
}
// Sample to filter by color and fabric.
console.log(filterBy(myObject, {
color: 'red',
fabric: (needle) => needle === 'cottton'
}));
// sample of callback filter that checks whether the "RAM" value exists and is, when lowercase, '4 gb'
console.log(
filterBy(myObject, {
Ram: (ram) => {
return ram && ram.toLowerCase() === '4 gb'
}
})
);