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Convert object to array of prorperties

I need to convert object:
{
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}
to array:
[{
key: "name",
propertyValue: "Test Name",
},
{
key: "middleName",
propertyValue: null,
},
{
key: "university.isGraduated",
propertyValue: true,
},
{
key: "university.speciality",
propertyValue: "Computer Science",
},
{
key: "university.country.code",
propertyValue: "PL"
}];
I wrote algorithm, but it's pretty dummy, how can I improve it? Important, if object has nested object than I need to write nested object via dot (e.g university.contry: "value")
let arr = [];
Object.keys(parsedObj).map((key) => {
if (parsedObj[key] instanceof Object) {
Object.keys(parsedObj[key]).map((keyNested) => {
if (parsedObj[key][keyNested] instanceof Object) {
Object.keys(parsedObj[key][keyNested]).map((keyNestedNested) => {
arr.push({ 'key': key + '.' + keyNested + '.' + keyNestedNested, 'propertyValue': parsedObj[key][keyNested][keyNestedNested] })
})
} else {
arr.push({ 'key': key + '.' + keyNested, 'propertyValue': parsedObj[key][keyNested] })
}
})
} else {
arr.push({ 'key': key, 'propertyValue': parsedObj[key] })
}
});
Thanks

A recursive function implementation.
I have considered that your object consist of only string and object as the values. If you have more kind of data types as your values, you may have to develop on top of this function.
const myObj = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}
const myArr = [];
function convertObjectToArray(obj, keyPrepender) {
Object.entries(obj).forEach(([key, propertyValue]) => {
if (typeof propertyValue === "object" && propertyValue) {
const updatedKey = keyPrepender ? `${keyPrepender}.${key}` : key;
convertObjectToArray(propertyValue, updatedKey)
} else {
myArr.push({
key: keyPrepender ? `${keyPrepender}.${key}` : key,
propertyValue
})
}
})
}
convertObjectToArray(myObj);
console.log(myArr);

I'd probably take a recursive approach, and I'd probably avoid unnecessary intermediary arrays (though unless the original object is massive, it doesn't matter). For instance (see comments):
function convert(obj, target = [], prefix = "") {
// Loop through the object keys
for (const key in obj) {
// Only handle "own" properties
if (Object.hasOwn(obj, key)) {
const value = obj[key];
// Get the full key for this property, including prefix
const fullKey = prefix ? prefix + "." + key : key;
if (value && typeof value === "object") {
// It's an object...
if (Array.isArray(value)) {
throw new Error(`Arrays are not valid`);
} else {
// ...recurse, providing the key as the prefix
convert(value, target, fullKey);
}
} else {
// Not an object, push it to the array
target.push({key: fullKey, propertyValue: value});
}
}
}
// Return the result
return target;
}
Live Example:
const original = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
};
function convert(obj, target = [], prefix = "") {
// Loop through the object keys
for (const key in obj) {
// Only handle "own" properties
if (Object.hasOwn(obj, key)) {
const value = obj[key];
// Get the full key for this property, including prefix
const fullKey = prefix ? prefix + "." + key : key;
if (value && typeof value === "object") {
// It's an object...
if (Array.isArray(value)) {
throw new Error(`Arrays are not valid`);
} else {
// ...recurse, providing the key as the prefix
convert(value, target, fullKey);
}
} else {
// Not an object, push it to the array
target.push({key: fullKey, propertyValue: value});
}
}
}
// Return the result
return target;
}
const result = convert(original, []);
console.log(result);
.as-console-wrapper {
max-height: 100% !important;
}
Note that I've assumed the order of the array entries isn't significant. The output you said you wanted is at odds with the standard order of JavaScript object properties (yes, they have an order now; no, it's not something I suggest relying on 😀). I've gone ahead and not worried about the order within an object.

This is the most bulletproof I could do :D, without needing a global variable, you just take it, and us it wherever you want!
const test = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
};
function toPropertiesByPath(inputObj) {
let arr = [];
let initialObj = {};
const getKeys = (obj, parentK='') => {
initialObj = arr.length === 0 ? obj: initialObj;
const entries = Object.entries(obj);
for(let i=0; i<entries.length; i++) {
const key = entries[i][0];
const val = entries[i][1];
const isRootElement = initialObj.hasOwnProperty(key);
parentK = isRootElement ? key: parentK+'.'+key;
if(typeof val === 'object' && val!==null && !Array.isArray(val)){
getKeys(val, parentK);
} else {
arr.push({ key: parentK, property: val });
}
}
};
getKeys(inputObj);
return arr;
}
console.log(toPropertiesByPath(test));

I wrote a small version using recursive function and another for validation is an object.
let values = {
middleName: null,
name: "Test Name",
university: {
country: {
code: "PL"
},
isGraduated: true,
speciality: "Computer Science"
}
}
function isObject(obj) {
return obj != null && obj.constructor.name === "Object"
}
function getValues(values) {
let arrValues = Object.keys(values).map(
v => {
return { key: v, value: isObject(values[v]) ? getValues(values[v]) : values[v] };
});
console.log(arrValues);
}
getValues(values);

Spread operator with reduce function in js

I trying to generate all possible paths of the given json object. Some how I generated the paths but I want my final array in a flatten manner (no nested arrays inside the final array).
I tried speading the array, but the final array contains some nested arrays. I want to have all the elements in a flatter manner.
Current op:
[
"obj",
"level1.level2.level3.key",
[
"arrayObj.one[0].name",
"arrayObj.one[0].point"
]
]
Expected:
[
"obj",
"level1.level2.level3.key",
"arrayObj.one[0].name",
"arrayObj.one[0].point"
]
Below I have attached the snippet I tried.
const allPaths = (obj, path = "") =>
Object.keys(obj).reduce((res, el) => {
if (Array.isArray(obj[el]) && obj[el].length) {
return [...res, ...obj[el].map((item, index) => {
return [...res, ...allPaths(item, `${path}${el}[${index}].`)];
})];
} else if (typeof obj[el] === "object" && obj[el] !== null) {
return [...res, ...allPaths(obj[el], `${path}${el}.`)];
}
return [...res, path + el];
}, []);
const obj = {
obj: 'sample',
level1: {
level2: {
level3: {
key: 'value'
}
}
},
arrayObj: {
one: [{
name: 'name',
point: 'point'
},
{
name: 'name2',
point: 'point2'
},
{
name: 'name2',
point: 'point2'
}
]
}
}
console.log(allPaths(obj));

UPDATE: I didn't understood the question previously correctly. Now i do. So yes the below code will solve the problem for you.
You want your object to be flattened with dots
If thats the case the below should work
const obj = {
obj: 'sample',
level1: {
level2: {
level3: {
key: 'value'
}
}
},
arrayObj: {
one: [{
name: 'name',
point: 'point'
},
{
name: 'name2',
point: 'point2'
},
{
name: 'name2',
point: 'point2'
}
]
}
}
function flatten(data, prefix) {
let result = {}
for(let d in data) {
if(typeof data[d] == 'object') Object.assign(result, flatten(data[d], prefix + '.' + d))
else result[(prefix + '.' + d).replace(/^\./, '')] = data[d]
}
return result
}
console.log(flatten(obj, ''))

Get the difference object from two object in typescript/javascript angular

I am trying to get the change object from two objects using typescript in angular.
For example
this.productPreviousCommand = {
"id": "60f910d7d03dbd2ca3b3dfd5",
"active": true,
"title": "ss",
"description": "<p>ss</p>",
"category": {
"id": "60cec05df64bde4ab9cf7460"
},
"subCategory": {
"id": "60cec18c56d3d958c4791117"
},
"vendor": {
"id": "60ced45b56d3d958c479111c"
},
"type": "load_product_success"
}
model = {
"active": true,
"title": "ss",
"description": "<p>ss sss</p>",
"category": "60cec05df64bde4ab9cf7460",
"subCategory": "60cec18c56d3d958c4791117",
"vendor": "60ced45b56d3d958c479111c",
"tags": []
}
Now the difference between two objects are description: "<p>hello hello 1</p>". So I want to return {description: "<p>hello hello 1</p>"}
I used lodash https://github.com/lodash/lodash
import { transform, isEqual, isObject, isArray} from 'lodash';
function difference(origObj, newObj) {
function changes(newObj, origObj) {
let arrayIndexCounter = 0
return transform(newObj, function (result, value, key) {
if (!isEqual(value, origObj[key])) {
let resultKey = isArray(origObj) ? arrayIndexCounter++ : key
result[resultKey] = (isObject(value) && isObject(origObj[key])) ? changes(value, origObj[key]) : value
}
})
}
return changes(newObj, origObj)
}
This library is not working for me, it returns the whole object using this code const differenc = difference(this.productPreviousCommand, model);
The output of above code is
{
active: true
description: "<p>hello hello 1</p>"
id: "60f8f29dd03dbd2ca3b3dfd1"
title: "hello"
}

Try this function
differenceInObj(firstObj: any, secondObj: any): any {
let differenceObj: any = {};
for (const key in firstObj) {
if (Object.prototype.hasOwnProperty.call(firstObj, key)) {
if(firstObj[key] !== secondObj[key]) {
differenceObj[key] = firstObj[key];
}
}
}
return differenceObj;
}

You can check loop through each key of the first object and compare it with the second object.
function getPropertyDifferences(obj1, obj2) {
return Object.entries(obj1).reduce((diff, [key, value]) => {
// Check if the property exists in obj2.
if (obj2.hasOwnProperty(key)) {
const val = obj2[key];
// Check if obj1's property's value is different from obj2's.
if (val !== value) {
return {
...diff,
[key]: val,
};
}
}
// Otherwise, just return the previous diff object.
return diff;
}, {});
}
const a = {
active: true,
description: '<p>hello</p>',
id: '60f8f29dd03dbd2ca3b3dfd1',
title: 'hello',
};
const b = {
active: true,
description: '<p>hello hello 1</p>',
id: '60f8f29dd03dbd2ca3b3dfd1',
title: 'hello',
};
const c = {
active: true,
description: '<p>hello hello 2</p>',
id: '60f8f29dd03dbd2ca3b3dfd1',
title: 'world',
};
console.log(getPropertyDifferences(a, b));
console.log(getPropertyDifferences(b, c));

function difference(origObj, newObj) {
const origObjKeyList = Object.keys(origObj),
newObjKeyList = Object.keys(newObj);
// if objects length is not same
if (origObjKeyList?.length !== newObjKeyList?.length) {
return;
}
// if object keys some difference in keys
if (Object.keys(origObj).filter((val) => !Object.keys(newObj).includes(val))?.length) {
return;
}
return Object.entries(origObj).reduce(
(acc, [key, value]) => (newObj[key] !== value ? { ...acc, ...{ [key]: newObj[key] } } : acc),
[]
);
}
const a = {
active: true,
description: '<p>hello</p>',
id: '60f8f29dd03dbd2ca3b3dfd1',
title: 'hello',
};
const b = {
active: true,
description: '<p>hello hello 1</p>',
id: '60f8f29dd03dbd2ca3b3dfd1',
title: 'hello',
};
console.log(difference(a, b));
You can try this code.
function difference(origObj, newObj) {
const origObjKeyList = Object.keys(origObj),
newObjKeyList = Object.keys(newObj);
// if objects length is not same
if (origObjKeyList?.length !== newObjKeyList?.length) {
return;
}
// if object keys is not same
if (Object.keys(origObj).filter((val) => !Object.keys(newObj).includes(val))?.length) {
return;
}
return Object.entries(origObj).reduce(
(acc, [key, value]) => (newObj[key] !== value ? { ...acc, ...{ [key]: newObj[key] } } : acc),
[]
);
}

Json Array compare with different length in javascript

Below code which I am using for creating the new array if the id is the same in arr1 and arr2. But doesn't work since arr1 and arr2 are different. array 1 has index and arr2 is without index. screenshot for your reference. Can someone help?
Note: ID in arr1 is the same as EmpId in arr2
for(let i=0; i<arr1.length; i++) {
merged.push({
...arr1[i],
...(arr2.find((itmInner) => itmInner.id === arr1[i].id))}
);
}
console.log(merged);
Array1 looks like this :
[{"Active":1,"Id":1},
{"Active":1,"Id":3},
{"Active":1,"Id":2}]
Array2 looks something like this:
Below is the sample code on how I am framing array 2:
renderElement(activity){
var arr2 = [] ;
for(var i = 0; i < activity.length; i++) {
obj = activity[i];
if(obj.Id == 28){
fetch(geturl)
.then(function (response) {
return response.json();
})
.then(function (data) {
res = data;
arr2.push(res)
})
}
else{
// Do nothing
}
}
return arr2
}
Calling Render method like below:
outputarray = currentComponent.renderElement(activity);
console.log('output', outputarray)
Expected Output:
[{"Active":1,"Id":1,"Param1": true},
{"Active":1,"Id":3}, / Keep it as such if nothing exists in other array
{"Active":1,"Id":2, "Param2": false}]

You can try this approach instead:
Example #1
const arr1 = [
{ "Active":1, "Id":1 },
{ "Active":1, "Id":3 },
{ "Active":1, "Id":2 }
];
const arr2 = [
{
0: [
{
EmpId1: 1, Param1: true
}
]
},
{
1: [
{
EmpId2: 2,Param2: false
}
]
},
{
2: [
{
EmpId3: 2
}
]
},
];
const response = arr1
.reduce((acc, value) => {
const secondaryData = arr2.map((val, index) => {
const { [`EmpId${index + 1}`]: Id, ...others } = val[Object.keys(val)][0];
return { Id, ...others };
});
const match = secondaryData.findIndex(({ Id }) => Id === value.Id);
if (match >= 0) acc.push({...value, ...secondaryData[match]})
else acc.push(value);
return acc;
}, []);
console.log(response);
Example #2
const arr1 = [
{ "Active":1, "Id":1 },
{ "Active":1, "Id":3 },
{ "Active":1, "Id":2 }
];
const arr2 = [
[
{
EmpId1: 1,
Param1: true
}
],
[
{
EmpId2: 2,
Param2: false
}
],
[
{
EmpId3: 2
}
],
]
const response = arr1
.reduce((acc, value) => {
const secondaryData = arr2.map(([val], index) => {
const { [`EmpId${index + 1}`]: Id, ...others } = val;
return { Id, ...others };
});
const match = secondaryData.findIndex(({ Id }) => Id === value.Id);
if (match >= 0) acc.push({...value, ...secondaryData[match]})
else acc.push(value);
return acc;
}, []);
console.log(response);

Basically you can create a hash map by a object property and join on that property all the arrays, i.e. reduce an array of arrays into a result object, then convert the object's values back to an array. Since each array is reduced this means each array is only traversed once O(n) and the map object provides constant time O(1) lookup to match objects. This keeps the solution closer to O(n) rather than other solutions with a nested O(n) findIndex search, which yields a solution closer to O(n^2).
const mergeByField = (...arrays) => {
return Object.values(
arrays.reduce(
(result, { data, field }) => ({
...data.flat().reduce(
(obj, el) => ({
...obj,
[el[field]]: {
...obj[el[field]],
...el
}
}),
result
)
}),
{}
)
);
};
Load each array into a payload object that specifies the field key to match on. This will return all fields used to match by, but these can safely be ignored later, or removed, whatever you need. Example:
mergeByField(
{ data: arr1, field: "Id" },
{ data: arr2, field: "EmpId" },
);
const arr1 = [
{
Active: 1,
Id: 1
},
{
Active: 1,
Id: 2
},
{
Active: 1,
Id: 3
}
];
const arr2 = [[{ EmpId: 1, Param1: true }], [{ EmpId: 3, Param2: false }]];
const mergeByField = (...arrays) => {
return Object.values(
arrays.reduce(
(result, { data, field }) => ({
...data.flat().reduce(
(obj, el) => ({
...obj,
[el[field]]: {
...obj[el[field]],
...el
}
}),
result
)
}),
{}
)
);
};
console.log(
mergeByField({ data: arr1, field: "Id" }, { data: arr2, field: "EmpId" })
);

Nested object: Update all attributes with same names

I have a quit complex object with multiple nested objects.
This object i want to copy and update all id attributes.
So this:
{
id: 1,
name: "A",
car: {
id: 2,
vendor: "xy"
}
..
}
should become this:
{
id: 6,
name: "A",
car: {
id: 7,
vendor: "xy"
}
..
}
Is there a way to this in a short and generic way with JavaScript (TypeScript)?
Update:
What I did so far:
const a = new MyClass();
a.id = uuid();
a.name = "A"
a.car = new Car();
a.car.id = uuid();
a.car.vendor = "xy"
//copy a
const b = JSON.parse(JSON.stringify(a));
All I want to do is increase all ids in b by 5.

You can loop through all the items in b and do two things. If it's an id property, change it (add 5). If it's an object, loop through and check both the same conditions (recursive function). Here's how you could do it:
function checkObject(obj) {
Object.keys(obj).forEach(function(prop) {
if (typeof obj[prop] == "object" && prop !== null) {
checkObject(obj[prop]);
}
else if (prop == "id") {
obj[prop] += 5;
}
})
}
Then you'd call it like so:
function checkObject(obj) {
Object.keys(obj).forEach(function(prop) {
if (typeof obj[prop] == "object" && prop !== null) {
checkObject(obj[prop]);
}
else if (prop == "id") {
obj[prop] += 5;
}
})
}
var b = {
id: 1,
name: "A",
car: {
id: 2,
vendor: "xy"
}
}
checkObject(b);
console.log(b);

Here is a function that clones the original object into a new one where each id property receives a new value generated by a given uuid function:
function assignId(data, uuid) {
return Object(data) !== data ? data
: Object.assign({}, ...Object.entries(data).map( ([k, v]) =>
({ [k]: k === "id" ? uuid() : assignId(v, uuid) })
));
}
// Example use:
function uuid() {
return uuid.next = (uuid.next || 1000) + 1;
}
const a = { id: 1, name: "A", car: { id: 2, vendor: "xy" } };
const b = assignId(a, uuid);
console.log(b);