We Keep Coding

Functional Programming exercise I can't figure out

I've been looking at a problem for hours and failing to find a solution. I'm given an array of customer objects.
In each customer object is an array of friends.
In the array of friends is an object for each friend, containing some data, including a name key/value pair.
What I'm trying to solve for: I'm given this customers array and a customer's name. I need to create a function to find if this customer name is in any other customer's friend lists, and if so, return an array of those customer's names.
Below is a customer list. And as an example, one of the customers is Olga Newton. What the code should be doing is seeing that Olga Newton is a customer and is also in the friends lists of Regina and Jay, and should be returning an array of Regina and Jay.
I thought I could do this simply with a filter function, but because the friends list is an array with more objects, this is adding level of complexity for me I can't figure out.
Below is a customer array. The out put should be
['Regina', 'Jay']
and what I've gotten has either been
[{fullCustomerObj1}, {fullCustomerObj2}]
or
[ ]
What am I missing?
Here is the customer array:
var customers = [{
name: "Olga Newton",
age: 43,
balance: "$3,400",
friends: [{
id: 0,
name: "Justice Lara"
}, {
id: 1,
name: "Duke Patrick"
}, {
id: 2,
name: "Herring Hull"
}, {
id: 3,
name: "Johnnie Berg"
}]
}, {
name: "Regina",
age: 53,
balance: "$4,000",
friends: [{
id: 0,
name: "Cheryl Kent"
}, {
id: 1,
name: "Cynthia Wells"
}, {
id: 2,
name: "Gutierrez Waters"
}, {
id: 3,
name: "Olga Newton"
}]
}, {
name: "Jay",
age: 28,
balance: "$3,000",
friends: [{
id: 0,
name: "Cross Barnett"
}, {
id: 1,
name: "Raquel Haney"
}, {
id: 2,
name: "Olga Newton"
}, {
id: 3,
name: "Shelly Walton"
}]
}];

Use filter and map, please.
function friends(c, name){
return c.filter((a) => {
return a.friends.map(b => b.name).includes(name)
}).map(a => a.name);
}
console.log(friends(customers, "Olga Newton"));
// ['Regina', 'Jay']
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

We look to an array (friends[]) inside anther (customers[]), So used two for loops, the first determine witch customer will look for his friends, and the second the array will search inside, then set if statement if the cust name is inside friends[]: adding the customer name to customerFriends[] array, At the end return the customerFriends[].
let cust = "Olga Newton"; // Get the customer name who you look for his friends.
const findFriend = (cust, arrs) => { // Create findFriend function.
let customerFriends = []; // Create an array to set the result to it.
for (let i = 0; i < arrs.length; i++) { // For each Customer.
for (const arr of arrs[i].friends) { // For each Friend.
if (arr.name === cust) { // Use Strict equality to find Customer name in friends[].
customerFriends.push(arrs[i].name); // Add the customer name to the customerFriends[].
}
}
}
return customerFriends;// Return the final results.
}
console.log(findFriend(cust, customers)); // Call the function.

Javascript: How to iterate through an array looking for an object value?

I have a js file that is just a an array with the name and type of person. I am trying to write a function in my other file to iterate through that array of objects and return just the object that matches a certain criteria. Here is my code.
person.js
export const persons_options = [
{
name: 'Andrew',
type: 'Athlete',
},
{
name: 'Paul',
type: 'Worker',
},
{
name: 'Phil',
type: 'Developer',
},
]
utils.js
// params initialized already
person_type = params.subType
const name = persons_options.map((option) => {
if(person_type === option.type){
return option.name
}
})
const person = name
The issue is I know map creates a new array so the output is ,,Phil. How would I just return one of the object names instead of all of them.

find() will do the work
let persons_options = [
{
name: 'Andrew',
type: 'Athlete',
},
{
name: 'Paul',
type: 'Worker',
},
{
name: 'Phil',
type: 'Developer',
},
]
let obj = persons_options.find(o => o.type === 'Developer');
//to return name
console.log("name",obj.name);
console.log(obj);

You need to use the find function.
See here the list of functions that you can call on an array:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array#instance_methods
filter might best suit your case if multiple results may be returned.

How can i display more than one array elements that satisfy a condition?

How can I display multiple values of an array to the console that match the condition (e.g: === "McDonalds")?
I only managed to display one item. But I don't know how i can display all the value of my array.
public products: product[] = [
{ id: 1, name: "McFlurry", price: 2, enseigne:"McDonalds" },
{ id: 2, name: "Potatoes", price: 3, enseigne:"McDonalds" },
{ id: 3, name: "BigMac", price: 4, enseigne:"KFC" },
{ id: 4, name: "Nuggets", price: 3, enseigne:"KFC" }
];
searchEnseigne(){
let server = this.products.find(x => x.enseigne === "McDonalds");
console.log(server);
}

let server = this.products.filter(x => x.enseigne === "McDonalds");
console.log(server);

Use filter instead of find:
The filter() method creates a new array with all elements that pass the test. While The find() method returns the value of the first element
searchEnseigne(){
let server = this.products.filter(x => x.enseigne === "McDonalds");
console.log(server);
}

Compare value and add if matches to an array

Im trying to merge 2 data sources in 1, I wanna loop through them and if a specefic value matches than add it to the first object with the same value and add the in the emty array what is already there. No matter how much objects I have.
So lets say I have this information
Source 1
one = {
"teams": [
{
name: 'ABC',
members: [],
rooms: '0'
},
{
name: 'DEF',
members: [],
rooms: '1'
}
]
}
Source 2
two = {
"persons": [
{
name: 'Foo',
gender: 'male',
room: '1'
},
{
name: 'Bar',
gender: 'female',
room: '2'
}
]
}
And what I want is that the 'persons' array merge to the members array if the 'room and rooms' value matches.
What I would assume is something similar like this:
for(var i = 0 ; i < two.persons.length; i++) {
if (one.teams[i].rooms == two.persons[i].room) {
data.teams[i].members.push(two.persons[i]);
}
}

using higher order methods you can do:
one = {
"teams": [
{
name: 'ABC',
members: [],
rooms: '0'
},
{
name: 'DEF',
members: [],
rooms: '1'
}
]
};
two = {
"persons": [
{
name: 'Foo',
gender: 'male',
room: '1'
},
{
name: 'Bar',
gender: 'female',
room: '2'
}
]
};
var ttt = one.teams.map(function(x){
var roomVal= x.rooms;
x.members = two.persons.filter(function(t){
return t.room == roomVal});
return x;
})
one.teams = ttt;
console.log(one)

The problem with your code is that once you iterate the two array, then you do not go back and see if the previous element matched with the current one.
For example, if [0] on each arrays does not match and you iterate to index [1] in the for-loop, you do not have a way to check if two[1] matched one[0].
To do a complete search, you could directly iterate the arrays for each value of two:
two.persons.forEach(function(person) {
one.teams.forEach(function(team) {
if (team.rooms == person.room) {
team.members.push(person);
}
});
});

There are many strategies to do this. But most important you should iterate each array separately. I would use an Array.forEach();
one.teams.forEach(function (team, teamsIndex, teamsArray) {
two.persons.forEach(function (person, personsIndex, personsArray) {
if (team.room == person.room) {
// Do what you need to do.
}
});
});
Didn't check syntax so be aware to read Array.forEach(); documentation.

Counting and storing distinct elements and their counts from an array of object

I have an array of object and I want to count the number of distinct elements and counts of those objects.
[ { name: 'Suman',
game: '5A'
},
{ name: 'Suman',
game: '5A'
},
{ name: 'Namus',
game: '5A'
},
{ name: 'Namus',
game: '5A'
}
]
I want to count the number of distinct names and store them in an object. I have tried it by 1# pushing all the names in an array,
2# then sorting them,
3# then calculating the number of distinct names and
4# finally pushing them to the object.
This process is too long. Is there a shorter way to do this. I am using Nodejs
Thanks in advance

You will create a new object, where the key is the name and the value the count:
var youArr = [
{ name: 'Suman',
game: '5A'
},
{ name: 'Suman',
game: '5A'
},
{ name: 'Namus',
game: '5A'
},
{ name: 'Namus',
game: '5A'
}
];
var count = {}
for(var i=0; i < youArr.length; i++){
count[youArr[i].name] = count[youArr[i].name] || 0;
count[youArr[i].name]++;
}
alert(count['Namus']); // 2

This is a great place to use the reduce function:
The reduce() method applies a function against an accumulator and each
value of the array (from left-to-right) has to reduce it to a single
value.
...
reduce executes the callback function once for each element present in
the array, excluding holes in the array, receiving four arguments: the
initial value (or value from the previous callback call), the value of
the current element, the current index, and the array over which
iteration is occurring.
It would look something like this:
var arr = [ { name: 'Suman',
game: '5A'
},
{ name: 'Suman',
game: '5A'
},
{ name: 'Namus',
game: '5A'
},
{ name: 'Namus',
game: '5A'
}
]
var counts = arr.reduce(function(counts, item) {
counts[item.name] = (counts[item.name] || 0) + 1;
return counts;
}, {});
counts is then:
{ Suman: 2, Namus: 2 }
Asked in the comments:
what if i want the count as well as name in an array of object like
[{name: 'Suman', count:'2'}, {name:'Namus', count:'2'}]
If you already have counts from the reduce call above, then you can map its keys to the format you want:
var countsArray = Object.keys(counts).map(function(name) {
return {name: name, count: counts[name]};
});
countsArray is then:
[ { name: 'Suman', count: 2 },
{ name: 'Namus', count: 2 } ]