Related
I have a very simple code snippet like this
async function neverResolve() {
return new Promise(() => {
console.log("This promise will never resolve");
});
}
(async () => {
try {
console.log("START");
// neverResolve().then().catch(); // uncommenting this line works as expected
await neverResolve();
await new Promise((resolve) => setTimeout(() => resolve(), 5000));
console.log("END");
} catch (error) {
console.log("ERR: ", error);
}
})();
Why the above function doesn't wait for 5 second and print's the END.
It automatically terminates after printing
START
This promise will never resolve
But if we execute the same function but with a .then() construct, I get the expected result.
async function neverResolve() {
return new Promise(() => {
console.log("This promise will never resolve");
});
}
(async () => {
try {
console.log("START");
neverResolve().then().catch();
await new Promise((resolve) => setTimeout(() => resolve(), 5000));
console.log("END");
} catch (error) {
console.log("ERR: ", error);
}
})();
This is what's happening in your case:
Your program starts it's execution from an anonymous IIFE async function, as this is an async function, it immediately returns a Promise to a global scope.So the execution of anonymous IIFE is deferred .
You can easily validate this by adding a console.log("OK"); at the end of your IIFE invocation, which is printed to the console
Node keeps a reference count of things like timers and network requests. When you make a network, or other async request, set a timer, etc. Node adds on to this ref count. When the times/request resolve Node subtracts from the count. Ref. video link
So what happens inside your IIFE is:
console.log("START"); <--- gets printed to console
await neverResolve(); Here things get's interesting, this await call will defer the execution and blocks until the callback are executed, either resolve or reject.
But in this case there are no callbacks registered and nodejs will think that it finished processing all the request and will terminate the process.
neverResolve neither resolves or rejects, so the program hangs indefinitely at the await. Consider abstracting the timeout functionality in its own generic function, timeout -
const sleep = ms =>
new Promise(r => setTimeout(r, ms));
const timeout = (p, ms) =>
Promise.race([
p,
sleep(ms).then(() => { throw Error("timeout") })
]);
const neverResolve = () => new Promise(() => {});
(async function() {
try {
console.log("connecting...");
await timeout(neverResolve(), 2000);
}
catch (err) {
console.error(err);
}
})();
In the first example await neverResolve(); waits forever and never resolves as stated. Javascript can go off and do other things in other tasks while waiting for this.
In the second example by adding .then() you've told javascript to continue processing code below. Typically, all the code below would either be inside the callback for then() or catch() which would then create the same pause you're seeing.
There are very deliberate reasons for these nuances that allow you to send a fetch request, do other work and then come back to see if the fetch is done later. See my comments in this marked up and slightly modified example.
async function slowFetch() {
return new Promise((resolve) => {
// a fetch statement that takes forever
fetch().then(data => resolve(data));
});
}
(async () => {
try {
console.log("START");
// start the slow fetch right away
const dataPromise = slowFetch();
// do some other tasks that don't take as long
await new Promise((resolve) => setTimeout(() => resolve(), 5000));
// wait for the data to arrive
const data = await dataPromise;
// do something with the data like fill in the page.
console.log("END");
} catch (error) {
console.log("ERR: ", error);
}
})();
By doing neverResolve().then().catch(); what you actually did is;
async function neverResolve() {
return new Promise(() => {
console.log("This promise will never resolve");
});
}
(async () => {
try {
console.log("START");
(async function(){
try {
await neverResolve()
}
catch{
}
})();
await new Promise((resolve) => setTimeout(() => resolve(), 5000));
console.log("END");
} catch (error) {
console.log("ERR: ", error);
}
})();
The inner async IIFE runs just like neverResolve().then().catch(); does. You should not mix promises with async await abstraction.
Why the above function doesn't wait for 5 second and print's the END. It automatically terminates after printing
Because your code never gets past this:
await neverResolve();
Since neverResolve() returns a promise that never resolves or rejects, this function is forever suspended at that line and the lines of code after this statement in the function never execute.
await means that the function execution should be suspended indefinitely until the promise you are awaiting either resolves or rejects.
But if we execute the same function but with a .then() construct, I get the expected result.
When you change the await to this:
neverResolve().then().catch();
The function execute is NOT suspended at all. It executes neverResolve(). That returns a promise which it then calls .then() on. That call to .then() just registers a callback with the promise (to be called later when the promise resolves). That returns another promise which it then calls .catch() on which just registers a callback with the promise (to be called later if/when the promise rejects).
Now, you aren't even passing a callback in either case, so those .then() and .catch() have nothing to actually do, but even if you did pass a callback to each of them, then they would just register that callback and immediately return. .then() and .catch() are not blocking. They just register a callback and immediately return. So, after they return, then next lines of code in the function will execute and you will get the output you were expecting.
Summary
await suspends execution of the function until the promise you are awaiting resolves or rejects.
.then() and .catch() just register callbacks for some future promise state change. They do not block. They do not suspend execution of the function. They register a callback and immediately return.
I wrote this code in lib/helper.js:
var myfunction = async function(x,y) {
....
return [variableA, variableB]
}
exports.myfunction = myfunction;
Then I tried to use it in another file :
var helper = require('./helper.js');
var start = function(a,b){
....
const result = await helper.myfunction('test','test');
}
exports.start = start;
I got an error:
await is only valid in async function
What is the issue?
The error is not refering to myfunction but to start.
async function start() {
....
const result = await helper.myfunction('test', 'test');
}
// My function
const myfunction = async function(x, y) {
return [
x,
y,
];
}
// Start function
const start = async function(a, b) {
const result = await myfunction('test', 'test');
console.log(result);
}
// Call start
start();
I use the opportunity of this question to advise you about an known anti pattern using await which is : return await.
WRONG
async function myfunction() {
console.log('Inside of myfunction');
}
// Here we wait for the myfunction to finish
// and then returns a promise that'll be waited for aswell
// It's useless to wait the myfunction to finish before to return
// we can simply returns a promise that will be resolved later
// useless async here
async function start() {
// useless await here
return await myfunction();
}
// Call start
(async() => {
console.log('before start');
await start();
console.log('after start');
})();
CORRECT
async function myfunction() {
console.log('Inside of myfunction');
}
// Here we wait for the myfunction to finish
// and then returns a promise that'll be waited for aswell
// It's useless to wait the myfunction to finish before to return
// we can simply returns a promise that will be resolved later
// Also point that we don't use async keyword on the function because
// we can simply returns the promise returned by myfunction
function start() {
return myfunction();
}
// Call start
(async() => {
console.log('before start');
await start();
console.log('after start');
})();
Also, know that there is a special case where return await is correct and important : (using try/catch)
Are there performance concerns with `return await`?
To use await, its executing context needs to be async in nature
As it said, you need to define the nature of your executing context where you are willing to await a task before anything.
Just put async before the fn declaration in which your async task will execute.
var start = async function(a, b) {
// Your async task will execute with await
await foo()
console.log('I will execute after foo get either resolved/rejected')
}
Explanation:
In your question, you are importing a method which is asynchronous in nature and will execute in parallel. But where you are trying to execute that async method is inside a different execution context which you need to define async to use await.
var helper = require('./helper.js');
var start = async function(a,b){
....
const result = await helper.myfunction('test','test');
}
exports.start = start;
Wondering what's going under the hood
await consumes promise/future / task-returning methods/functions and async marks a method/function as capable of using await.
Also if you are familiar with promises, await is actually doing the same process of promise/resolve. Creating a chain of promise and executes your next task in resolve callback.
For more info you can refer to MDN DOCS.
When I got this error, it turned out I had a call to the map function inside my "async" function, so this error message was actually referring to the map function not being marked as "async". I got around this issue by taking the "await" call out of the map function and coming up with some other way of getting the expected behavior.
var myfunction = async function(x,y) {
....
someArray.map(someVariable => { // <- This was the function giving the error
return await someFunction(someVariable);
});
}
I had the same problem and the following block of code was giving the same error message:
repositories.forEach( repo => {
const commits = await getCommits(repo);
displayCommit(commits);
});
The problem is that the method getCommits() was async but I was passing it the argument repo which was also produced by a Promise. So, I had to add the word async to it like this: async(repo) and it started working:
repositories.forEach( async(repo) => {
const commits = await getCommits(repo);
displayCommit(commits);
});
If you are writing a Chrome Extension and you get this error for your code at root, you can fix it using the following "workaround":
async function run() {
// Your async code here
const beers = await fetch("https://api.punkapi.com/v2/beers");
}
run();
Basically you have to wrap your async code in an async function and then call the function without awaiting it.
The current implementation of async / await only supports the await keyword inside of async functions Change your start function signature so you can use await inside start.
var start = async function(a, b) {
}
For those interested, the proposal for top-level await is currently in Stage 2: https://github.com/tc39/proposal-top-level-await
async/await is the mechanism of handling promise, two ways we can do it
functionWhichReturnsPromise()
.then(result => {
console.log(result);
})
.cathc(err => {
console.log(result);
});
or we can use await to wait for the promise to full-filed it first, which means either it is rejected or resolved.
Now if we want to use await (waiting for a promise to fulfil) inside a function, it's mandatory that the container function must be an async function because we are waiting for a promise to fulfiled asynchronously || make sense right?.
async function getRecipesAw(){
const IDs = await getIds; // returns promise
const recipe = await getRecipe(IDs[2]); // returns promise
return recipe; // returning a promise
}
getRecipesAw().then(result=>{
console.log(result);
}).catch(error=>{
console.log(error);
});
If you have called async function inside foreach update it to for loop
Found the code below in this nice article: HTTP requests in Node using Axios
const axios = require('axios')
const getBreeds = async () => {
try {
return await axios.get('https://dog.ceo/api/breeds/list/all')
} catch (error) {
console.error(error)
}
}
const countBreeds = async () => {
const breeds = await getBreeds()
if (breeds.data.message) {
console.log(`Got ${Object.entries(breeds.data.message).length} breeds`)
}
}
countBreeds()
Or using Promise:
const axios = require('axios')
const getBreeds = () => {
try {
return axios.get('https://dog.ceo/api/breeds/list/all')
} catch (error) {
console.error(error)
}
}
const countBreeds = async () => {
const breeds = getBreeds()
.then(response => {
if (response.data.message) {
console.log(
`Got ${Object.entries(response.data.message).length} breeds`
)
}
})
.catch(error => {
console.log(error)
})
}
countBreeds()
In later nodejs (>=14), top await is allowed with { "type": "module" } specified in package.json or with file extension .mjs.
https://www.stefanjudis.com/today-i-learned/top-level-await-is-available-in-node-js-modules/
This in one file works..
Looks like await only is applied to the local function which has to be async..
I also am struggling now with a more complex structure and in between different files. That's why I made this small test code.
edit: i forgot to say that I'm working with node.js.. sry. I don't have a clear question. Just thought it could be helpful with the discussion..
function helper(callback){
function doA(){
var array = ["a ","b ","c "];
var alphabet = "";
return new Promise(function (resolve, reject) {
array.forEach(function(key,index){
alphabet += key;
if (index == array.length - 1){
resolve(alphabet);
};
});
});
};
function doB(){
var a = "well done!";
return a;
};
async function make() {
var alphabet = await doA();
var appreciate = doB();
callback(alphabet+appreciate);
};
make();
};
helper(function(message){
console.log(message);
});
A common problem in Express:
The warning can refer to the function, or where you call it.
Express items tend to look like this:
app.post('/foo', ensureLoggedIn("/join"), (req, res) => {
const facts = await db.lookup(something)
res.redirect('/')
})
Notice the => arrow function syntax for the function.
The problem is NOT actually in the db.lookup call, but right here in the Express item.
Needs to be:
app.post('/foo', ensureLoggedIn("/join"), async function (req, res) {
const facts = await db.lookup(something)
res.redirect('/')
})
Basically, nix the => and add async function .
"await is only valid in async function"
But why? 'await' explicitly turns an async call into a synchronous call, and therefore the caller cannot be async (or asyncable) - at least, not because of the call being made at 'await'.
Yes, await / async was a great concept, but the implementation is completely broken.
For whatever reason, the await keyword has been implemented such that it can only be used within an async method. This is in fact a bug, though you will not see it referred to as such anywhere but right here. The fix for this bug would be to implement the await keyword such that it can only be used TO CALL an async function, regardless of whether the calling function is itself synchronous or asynchronous.
Due to this bug, if you use await to call a real asynchronous function somewhere in your code, then ALL of your functions must be marked as async and ALL of your function calls must use await.
This essentially means that you must add the overhead of promises to all of the functions in your entire application, most of which are not and never will be asynchronous.
If you actually think about it, using await in a function should require the function containing the await keyword TO NOT BE ASYNC - this is because the await keyword is going to pause processing in the function where the await keyword is found. If processing in that function is paused, then it is definitely NOT asynchronous.
So, to the developers of javascript and ECMAScript - please fix the await/async implementation as follows...
await can only be used to CALL async functions.
await can appear in any kind of function, synchronous or asynchronous.
Change the error message from "await is only valid in async function" to "await can only be used to call async functions".
I am new to typescript / javascript, so I don't know much about promises. Here is my use-case: I am creating three different promises inside my cloud-function and then returning it with Promise.all([promise1, promise2, promise3]). Each of these promises are created inside a function with "return Promise...".
My question is, when I add ".catch" inside these functions, will Promise.all still work?. Does it make any difference returning someServiceThatCreatesPromise() with and without .catch()?
Code
export async function myCloudFirestoreFunction() {
try {
const myFirstPromise = createFirstPromise()
const mySecondPromise = createSecondPromise()
const thirdPromise = createThirdPromise()
return Promise.all([
myFirstPromise,
mySecondPromise,
myThirdPromise
]);
} catch (err) {
functions.logger.err(`Something bad happened, See: ${(err as Error).message}`
}
}
// Difference with and without `.catch`?
function createFirstPromise() {
return someServiceThatCreatesPromise().catch((err) => { // LOGGING });
}
// Difference with and without `.catch`?
function createSecondPromise() {
return someServiceThatCreatesPromise().catch((err) => { // LOGGING });
}
// Difference with and without `.catch`?
function createThirdPromise() {
return someServiceThatCreatesPromise().catch((err) => { // LOGGING });
}
Adding .catch inside createNPromise won't affect anything assuming all your Promises resolve and do not reject.
However, if one of the Promises rejects and you catch it within the .catch method, then it won't work as you're expecting unless you re-throw that error and catch it again inside the try/catch in your myCloudFirestoreFunction function.
async function myCloudFirestoreFunction() {
try {
const result = await Promise.all([
createFirstPromise(),
createSecondPromise()
]);
} catch (error) {
console.log({ error });
}
}
function createFirstPromise() {
return Promise.reject("Oof").catch((e) => {
// do work, e.g. log, then
// pass the error forward so that it can be caught
// inside the caller
throw e;
});
}
function createSecondPromise() {
return Promise.resolve("value");
}
myCloudFirestoreFunction();
Alternatively, you just catch errors inside the caller (myCloudFirestoreFunction) instead of catching them separately.
async function myCloudFirestoreFunction() {
const result = await Promise.all([
createFirstPromise(),
createSecondPromise()
]).catch((err) => console.log({ err }));
}
function createFirstPromise() {
return Promise.reject("Oof");
}
function createSecondPromise() {
return Promise.resolve("value");
}
myCloudFirestoreFunction();
when I add ".catch" inside these functions, will Promise.all still work?
Calling catch() on a promise does not in any way change the way the original promise works. It is just attaching a callback that gets invoked when the first promise becomes rejected, and also returning another promise that resolves after the original promise is fulfilled or rejected.
Does it make any difference returning someServiceThatCreatesPromise() with and without .catch()?
It would not make any difference to the code that depends on the returned promise. Both the original promise and the one returned by catch() will tell downstream code when the original work is done by becoming fulfilled.
I suggest reading comprehensive documentation on promises, for example:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise
There is a diagram in there that you can follow to understand what happens at each turn. Also in that document, you will read:
Processing continues to the next link of the chain even when a .then() lacks a callback function that returns a Promise object. Therefore, a chain can safely omit every rejection callback function until the final .catch().
Given the code samples below, is there any difference in behavior, and, if so, what are those differences?
return await promise
async function delay1Second() {
return (await delay(1000));
}
return promise
async function delay1Second() {
return delay(1000);
}
As I understand it, the first would have error-handling within the async function, and errors would bubble out of the async function's Promise. However, the second would require one less tick. Is this correct?
This snippet is just a common function to return a Promise for reference.
function delay(ms) {
return new Promise((resolve) => {
setTimeout(resolve, ms);
});
}
Most of the time, there is no observable difference between return and return await. Both versions of delay1Second have the exact same observable behavior (but depending on the implementation, the return await version might use slightly more memory because an intermediate Promise object might be created).
However, as #PitaJ pointed out, there is one case where there is a difference: if the return or return await is nested in a try-catch block. Consider this example
async function rejectionWithReturnAwait () {
try {
return await Promise.reject(new Error())
} catch (e) {
return 'Saved!'
}
}
async function rejectionWithReturn () {
try {
return Promise.reject(new Error())
} catch (e) {
return 'Saved!'
}
}
In the first version, the async function awaits the rejected promise before returning its result, which causes the rejection to be turned into an exception and the catch clause to be reached; the function will thus return a promise resolving to the string "Saved!".
The second version of the function, however, does return the rejected promise directly without awaiting it within the async function, which means that the catch case is not called and the caller gets the rejection instead.
As other answers mentioned, there is likely a slight performance benefit when letting the promise bubble up by returning it directly — simply because you don’t have to await the result first and then wrap it with another promise again. However, no one has talked about tail call optimization yet.
Tail call optimization, or “proper tail calls”, is a technique that the interpreter uses to optimize the call stack. Currently, not many runtimes support it yet — even though it’s technically part of the ES6 Standard — but it’s possible support might be added in the future, so you can prepare for that by writing good code in the present.
In a nutshell, TCO (or PTC) optimizes the call stack by not opening a new frame for a function that is directly returned by another function. Instead, it reuses the same frame.
async function delay1Second() {
return delay(1000);
}
Since delay() is directly returned by delay1Second(), runtimes supporting PTC will first open a frame for delay1Second() (the outer function), but then instead of opening another frame for delay() (the inner function), it will just reuse the same frame that was opened for the outer function. This optimizes the stack because it can prevent a stack overflow (hehe) with very large recursive functions, e.g., fibonacci(5e+25). Essentially it becomes a loop, which is much faster.
PTC is only enabled when the inner function is directly returned. It’s not used when the result of the function is altered before it is returned, for example, if you had return (delay(1000) || null), or return await delay(1000).
But like I said, most runtimes and browsers don’t support PTC yet, so it probably doesn’t make a huge difference now, but it couldn’t hurt to future-proof your code.
Read more in this question: Node.js: Are there optimizations for tail calls in async functions?
Noticeable difference: Promise rejection gets handled at different places
return somePromise will pass somePromise to the call site, and await somePromise to settle at call site (if there is any). Therefore, if somePromise is rejected, it will not be handled by the local catch block, but the call site's catch block.
async function foo () {
try {
return Promise.reject();
} catch (e) {
console.log('IN');
}
}
(async function main () {
try {
let a = await foo();
} catch (e) {
console.log('OUT');
}
})();
// 'OUT'
return await somePromise will first await somePromise to settle locally. Therefore, the value or Exception will first be handled locally. => Local catch block will be executed if somePromise is rejected.
async function foo () {
try {
return await Promise.reject();
} catch (e) {
console.log('IN');
}
}
(async function main () {
try {
let a = await foo();
} catch (e) {
console.log('OUT');
}
})();
// 'IN'
Reason: return await Promise awaits both locally and outside, return Promise awaits only outside
Detailed Steps:
return Promise
async function delay1Second() {
return delay(1000);
}
call delay1Second();
const result = await delay1Second();
Inside delay1Second(), function delay(1000) returns a promise immediately with [[PromiseStatus]]: 'pending. Let's call it delayPromise.
async function delay1Second() {
return delayPromise;
// delayPromise.[[PromiseStatus]]: 'pending'
// delayPromise.[[PromiseValue]]: undefined
}
Async functions will wrap their return value inside Promise.resolve()(Source). Because delay1Second is an async function, we have:
const result = await Promise.resolve(delayPromise);
// delayPromise.[[PromiseStatus]]: 'pending'
// delayPromise.[[PromiseValue]]: undefined
Promise.resolve(delayPromise) returns delayPromise without doing anything because the input is already a promise (see MDN Promise.resolve):
const result = await delayPromise;
// delayPromise.[[PromiseStatus]]: 'pending'
// delayPromise.[[PromiseValue]]: undefined
await waits until the delayPromise is settled.
IF delayPromise is fulfilled with PromiseValue=1:
const result = 1;
ELSE is delayPromise is rejected:
// jump to catch block if there is any
return await Promise
async function delay1Second() {
return await delay(1000);
}
call delay1Second();
const result = await delay1Second();
Inside delay1Second(), function delay(1000) returns a promise immediately with [[PromiseStatus]]: 'pending. Let's call it delayPromise.
async function delay1Second() {
return await delayPromise;
// delayPromise.[[PromiseStatus]]: 'pending'
// delayPromise.[[PromiseValue]]: undefined
}
Local await will wait until delayPromise gets settled.
Case 1: delayPromise is fulfilled with PromiseValue=1:
async function delay1Second() {
return 1;
}
const result = await Promise.resolve(1); // let's call it "newPromise"
const result = await newPromise;
// newPromise.[[PromiseStatus]]: 'resolved'
// newPromise.[[PromiseValue]]: 1
const result = 1;
Case 2: delayPromise is rejected:
// jump to catch block inside `delay1Second` if there is any
// let's say a value -1 is returned in the end
const result = await Promise.resolve(-1); // call it newPromise
const result = await newPromise;
// newPromise.[[PromiseStatus]]: 'resolved'
// newPromise.[[PromiseValue]]: -1
const result = -1;
Glossary:
Settle: Promise.[[PromiseStatus]] changes from pending to resolved or rejected
This is a hard question to answer, because it depends in practice on how your transpiler (probably babel) actually renders async/await. The things that are clear regardless:
Both implementations should behave the same, though the first implementation may have one less Promise in the chain.
Especially if you drop the unnecessary await, the second version would not require any extra code from the transpiler, while the first one does.
So from a code performance and debugging perspective, the second version is preferable, though only very slightly so, while the first version has a slight legibility benefit, in that it clearly indicates that it returns a promise.
In our project, we decided to always use 'return await'.
The argument is that "the risk of forgetting to add the 'await' when later on a try-catch block is put around the return expression justifies having the redundant 'await' now."
Here is a typescript example that you can run and convince yourself that you need that "return await"
async function test() {
try {
return await throwErr(); // this is correct
// return throwErr(); // this will prevent inner catch to ever to be reached
}
catch (err) {
console.log("inner catch is reached")
return
}
}
const throwErr = async () => {
throw("Fake error")
}
void test().then(() => {
console.log("done")
}).catch(e => {
console.log("outer catch is reached")
});
here i leave some code practical for you can undertand it the diferrence
let x = async function () {
return new Promise((res, rej) => {
setTimeout(async function () {
console.log("finished 1");
return await new Promise((resolve, reject) => { // delete the return and you will see the difference
setTimeout(function () {
resolve("woo2");
console.log("finished 2");
}, 5000);
});
res("woo1");
}, 3000);
});
};
(async function () {
var counter = 0;
const a = setInterval(function () { // counter for every second, this is just to see the precision and understand the code
if (counter == 7) {
clearInterval(a);
}
console.log(counter);
counter = counter + 1;
}, 1000);
console.time("time1");
console.log("hello i starting first of all");
await x();
console.log("more code...");
console.timeEnd("time1");
})();
the function "x" just is a function async than it have other fucn
if will delete the return it print "more code..."
the variable x is just an asynchronous function that in turn has another asynchronous function, in the main of the code we invoke a wait to call the function of the variable x, when it completes it follows the sequence of the code, that would be normal for "async / await ", but inside the x function there is another asynchronous function, and this returns a promise or returns a" promise "it will stay inside the x function, forgetting the main code, that is, it will not print the" console.log ("more code .. "), on the other hand if we put" await "it will wait for every function that completes and finally follows the normal sequence of the main code.
below the "console.log (" finished 1 "delete the" return ", you will see the behavior.
I wrote this code in lib/helper.js:
var myfunction = async function(x,y) {
....
return [variableA, variableB]
}
exports.myfunction = myfunction;
Then I tried to use it in another file :
var helper = require('./helper.js');
var start = function(a,b){
....
const result = await helper.myfunction('test','test');
}
exports.start = start;
I got an error:
await is only valid in async function
What is the issue?
The error is not refering to myfunction but to start.
async function start() {
....
const result = await helper.myfunction('test', 'test');
}
// My function
const myfunction = async function(x, y) {
return [
x,
y,
];
}
// Start function
const start = async function(a, b) {
const result = await myfunction('test', 'test');
console.log(result);
}
// Call start
start();
I use the opportunity of this question to advise you about an known anti pattern using await which is : return await.
WRONG
async function myfunction() {
console.log('Inside of myfunction');
}
// Here we wait for the myfunction to finish
// and then returns a promise that'll be waited for aswell
// It's useless to wait the myfunction to finish before to return
// we can simply returns a promise that will be resolved later
// useless async here
async function start() {
// useless await here
return await myfunction();
}
// Call start
(async() => {
console.log('before start');
await start();
console.log('after start');
})();
CORRECT
async function myfunction() {
console.log('Inside of myfunction');
}
// Here we wait for the myfunction to finish
// and then returns a promise that'll be waited for aswell
// It's useless to wait the myfunction to finish before to return
// we can simply returns a promise that will be resolved later
// Also point that we don't use async keyword on the function because
// we can simply returns the promise returned by myfunction
function start() {
return myfunction();
}
// Call start
(async() => {
console.log('before start');
await start();
console.log('after start');
})();
Also, know that there is a special case where return await is correct and important : (using try/catch)
Are there performance concerns with `return await`?
To use await, its executing context needs to be async in nature
As it said, you need to define the nature of your executing context where you are willing to await a task before anything.
Just put async before the fn declaration in which your async task will execute.
var start = async function(a, b) {
// Your async task will execute with await
await foo()
console.log('I will execute after foo get either resolved/rejected')
}
Explanation:
In your question, you are importing a method which is asynchronous in nature and will execute in parallel. But where you are trying to execute that async method is inside a different execution context which you need to define async to use await.
var helper = require('./helper.js');
var start = async function(a,b){
....
const result = await helper.myfunction('test','test');
}
exports.start = start;
Wondering what's going under the hood
await consumes promise/future / task-returning methods/functions and async marks a method/function as capable of using await.
Also if you are familiar with promises, await is actually doing the same process of promise/resolve. Creating a chain of promise and executes your next task in resolve callback.
For more info you can refer to MDN DOCS.
When I got this error, it turned out I had a call to the map function inside my "async" function, so this error message was actually referring to the map function not being marked as "async". I got around this issue by taking the "await" call out of the map function and coming up with some other way of getting the expected behavior.
var myfunction = async function(x,y) {
....
someArray.map(someVariable => { // <- This was the function giving the error
return await someFunction(someVariable);
});
}
I had the same problem and the following block of code was giving the same error message:
repositories.forEach( repo => {
const commits = await getCommits(repo);
displayCommit(commits);
});
The problem is that the method getCommits() was async but I was passing it the argument repo which was also produced by a Promise. So, I had to add the word async to it like this: async(repo) and it started working:
repositories.forEach( async(repo) => {
const commits = await getCommits(repo);
displayCommit(commits);
});
If you are writing a Chrome Extension and you get this error for your code at root, you can fix it using the following "workaround":
async function run() {
// Your async code here
const beers = await fetch("https://api.punkapi.com/v2/beers");
}
run();
Basically you have to wrap your async code in an async function and then call the function without awaiting it.
The current implementation of async / await only supports the await keyword inside of async functions Change your start function signature so you can use await inside start.
var start = async function(a, b) {
}
For those interested, the proposal for top-level await is currently in Stage 2: https://github.com/tc39/proposal-top-level-await
async/await is the mechanism of handling promise, two ways we can do it
functionWhichReturnsPromise()
.then(result => {
console.log(result);
})
.cathc(err => {
console.log(result);
});
or we can use await to wait for the promise to full-filed it first, which means either it is rejected or resolved.
Now if we want to use await (waiting for a promise to fulfil) inside a function, it's mandatory that the container function must be an async function because we are waiting for a promise to fulfiled asynchronously || make sense right?.
async function getRecipesAw(){
const IDs = await getIds; // returns promise
const recipe = await getRecipe(IDs[2]); // returns promise
return recipe; // returning a promise
}
getRecipesAw().then(result=>{
console.log(result);
}).catch(error=>{
console.log(error);
});
If you have called async function inside foreach update it to for loop
Found the code below in this nice article: HTTP requests in Node using Axios
const axios = require('axios')
const getBreeds = async () => {
try {
return await axios.get('https://dog.ceo/api/breeds/list/all')
} catch (error) {
console.error(error)
}
}
const countBreeds = async () => {
const breeds = await getBreeds()
if (breeds.data.message) {
console.log(`Got ${Object.entries(breeds.data.message).length} breeds`)
}
}
countBreeds()
Or using Promise:
const axios = require('axios')
const getBreeds = () => {
try {
return axios.get('https://dog.ceo/api/breeds/list/all')
} catch (error) {
console.error(error)
}
}
const countBreeds = async () => {
const breeds = getBreeds()
.then(response => {
if (response.data.message) {
console.log(
`Got ${Object.entries(response.data.message).length} breeds`
)
}
})
.catch(error => {
console.log(error)
})
}
countBreeds()
In later nodejs (>=14), top await is allowed with { "type": "module" } specified in package.json or with file extension .mjs.
https://www.stefanjudis.com/today-i-learned/top-level-await-is-available-in-node-js-modules/
This in one file works..
Looks like await only is applied to the local function which has to be async..
I also am struggling now with a more complex structure and in between different files. That's why I made this small test code.
edit: i forgot to say that I'm working with node.js.. sry. I don't have a clear question. Just thought it could be helpful with the discussion..
function helper(callback){
function doA(){
var array = ["a ","b ","c "];
var alphabet = "";
return new Promise(function (resolve, reject) {
array.forEach(function(key,index){
alphabet += key;
if (index == array.length - 1){
resolve(alphabet);
};
});
});
};
function doB(){
var a = "well done!";
return a;
};
async function make() {
var alphabet = await doA();
var appreciate = doB();
callback(alphabet+appreciate);
};
make();
};
helper(function(message){
console.log(message);
});
A common problem in Express:
The warning can refer to the function, or where you call it.
Express items tend to look like this:
app.post('/foo', ensureLoggedIn("/join"), (req, res) => {
const facts = await db.lookup(something)
res.redirect('/')
})
Notice the => arrow function syntax for the function.
The problem is NOT actually in the db.lookup call, but right here in the Express item.
Needs to be:
app.post('/foo', ensureLoggedIn("/join"), async function (req, res) {
const facts = await db.lookup(something)
res.redirect('/')
})
Basically, nix the => and add async function .
"await is only valid in async function"
But why? 'await' explicitly turns an async call into a synchronous call, and therefore the caller cannot be async (or asyncable) - at least, not because of the call being made at 'await'.
Yes, await / async was a great concept, but the implementation is completely broken.
For whatever reason, the await keyword has been implemented such that it can only be used within an async method. This is in fact a bug, though you will not see it referred to as such anywhere but right here. The fix for this bug would be to implement the await keyword such that it can only be used TO CALL an async function, regardless of whether the calling function is itself synchronous or asynchronous.
Due to this bug, if you use await to call a real asynchronous function somewhere in your code, then ALL of your functions must be marked as async and ALL of your function calls must use await.
This essentially means that you must add the overhead of promises to all of the functions in your entire application, most of which are not and never will be asynchronous.
If you actually think about it, using await in a function should require the function containing the await keyword TO NOT BE ASYNC - this is because the await keyword is going to pause processing in the function where the await keyword is found. If processing in that function is paused, then it is definitely NOT asynchronous.
So, to the developers of javascript and ECMAScript - please fix the await/async implementation as follows...
await can only be used to CALL async functions.
await can appear in any kind of function, synchronous or asynchronous.
Change the error message from "await is only valid in async function" to "await can only be used to call async functions".