My below code is working fine and gives the correct desired output. But I am trying to use map, filter etc. instead of for loop. Lodash map and filter also works.
var arr = [
{"comp_id":1, desc: 'from comp1', updated: true},
{
"comp_id":2, desc: 'from comp2', updated: false}
];
var complaint_sources = [
{"comp_id":2,"consumer_source":"Hotline In","description_option":"English"},
{"comp_id":1,"consumer_source":"Online","description_option":"Other"},
{"comp_id":1,"consumer_source":"Email","description_option":null},
{"comp_id":2,"consumer_source":"Email","description_option":null}]
for(let i =0 ;i<arr.length;i++) {
let x=[];
for(let j=0;j<complaint_sources.length;j++){
if(arr[i].comp_id === complaint_sources[j].comp_id){
x.push(complaint_sources[j]);
arr[i].comp_src = x;
}
}
}
console.log(arr);
Basically I am looping through arr array and inside that looping through the complaint_sources array and when the comp_id matches I am modifying the arr array and adding a comp_src property to the object of arr array. This comp_src property will be an array of complaint_sources matched by comp_id.
this will work:
var arr = [
{"comp_id":1, desc: 'from comp1', updated: true},
{"comp_id":2, desc: 'from comp2', updated: false}
];
var complaint_sources = [
{"comp_id":2,"consumer_source":"Hotline In","description_option":"English"},
{"comp_id":1,"consumer_source":"Online","description_option":"Other"},
{"comp_id":1,"consumer_source":"Email","description_option":null},
{"comp_id":2,"consumer_source":"Email","description_option":null}
];
const grouped_sources = complaint_sources.reduce((acc, value) => {
(acc[value.comp_id] = acc[value.comp_id] || []).push(value);
return acc;
}, {})
const data = arr.map((comp) => ({
...comp,
comp_src: grouped_sources[comp.comp_id]
}));
console.log(data);
Related
i'm new here, i have problem that i can not solve.
I have 2 different arrays:
The first array - contains ratings of users with their ID name
[
{"handle":"frontend1", "_redis":"3", "_nodejs":"5", "_mysql":"2", "_python":"3", "_mongo":"4"},
{"handle":"frontend3", "_php":"4", "_mysql":"4", "_oracle":"4", "_ruby":"3", "_mongo":"5", "_python":"5"},
{"handle":"frontend4", "_java":"5", "_ruby":"5", "_mysql":"5", "_mongo":"5"}
]
The second set - contains the ratings, which I want to return to each user.
If there is a rating that is not in the second set, I will not return it
In the second set, values do not matter, only keys
[
"_assembler",
"_css",
"_python",
"_php"
]
I want to return to the first set, the handle, and all the rankings that exist in the second set.
[
{"handle":"frontend1", "_python":"3" },
{"handle":"frontend3", "_php":"4", "_python":"5" },
{"handle":"frontend4"}
]
this is what i try to do.
keys = [
"_assembler",
"_css",
"_python",
"_php"
]
source = [
{"handle":"frontend1", "_redis":"3", "_nodejs":"5", "_mysql":"2", "_python":"3", "_mongo":"4"},
{"handle":"frontend3", "_php":"4", "_mysql":"4", "_oracle":"4", "_ruby":"3", "_mongo":"5", "_python":"5"},
{"handle":"frontend4", "_java":"5", "_ruby":"5", "_mysql":"5", "_mongo":"5"}
];
result = [];
tmp = {};
source.forEach((item) => {
Object.keys(item).map(({key,value}) =>
{
if(key == "handle")
{
tmp[key]=value;
}
if(keys.includes(key))
{
tmp[key]=value;
}
})
result.push(...tmp);
tmp = {};
});
You can do this with a map utilizing a couple of other array methods such as filter, and Object methods.
const keys = [
"_assembler",
"_css",
"_python",
"_php"
]
const source = [
{"handle":"frontend1", "_redis":"3", "_nodejs":"5", "_mysql":"2", "_python":"3", "_mongo":"4"},
{"handle":"frontend3", "_php":"4", "_mysql":"4", "_oracle":"4", "_ruby":"3", "_mongo":"5", "_python":"5"},
{"handle":"frontend4", "_java":"5", "_ruby":"5", "_mysql":"5", "_mongo":"5"}
];
const result = source.map( s => ({
handle: s.handle,
...Object.fromEntries(Object.entries(s).filter(x => x[0] != "handle" && keys.includes(x[0])))
}));
console.log(result);
I have an URL with query params like this:
myLocalSite/?attributes%5B0%5D%5Bname%5D=customer_property_number&attributes%5B0%5D%5Bop%5D=equal&attributes%5B0%5D%5Bvalue%5D=12&attributes%5B1%5D%5Bname%5D=feedback_tags&attributes%5B1%5D%5Bop%5D=in&attributes%5B1%5D%5Bvalue%5D=test+1%2Cwww
after JSON parsing it convert into next structure
{
attributes[0][name]: "customer_property_number"
attributes[0][op]: "equal"
attributes[0][value]: "12"
attributes[1][name]: "feedback_tags"
attributes[1][op]: "in"
attributes[1][value]: "test 1,www"
}
In the end, I need an array that look like this:
attributes = [
{
name: 'customer_property_number',
op: 'equal',
value: '12',
},
{
name: 'feedback_tags',
op: 'in',
value: 'test 1, www',
},
]
Now does anyone know how I can then put these items into attributes array?
Thanks!
Here is the approach using URLSearchParams and going over each search param, parse and push to array of objects.
var sp = new URLSearchParams(
"myLocalSite/?attributes%5B0%5D%5Bname%5D=customer_property_number&attributes%5B0%5D%5Bop%5D=equal&attributes%5B0%5D%5Bvalue%5D=12&attributes%5B1%5D%5Bname%5D=feedback_tags&attributes%5B1%5D%5Bop%5D=in&attributes%5B1%5D%5Bvalue%5D=test+1%2Cwww"
);
var attributes = [];
for (entry of sp) {
const [attr, value] = entry;
const [index, key] = attr
.split("[")
.filter(x => x.includes("]"))
.map(x => x.slice(0, -1));
if (!attributes[Number(index)]) {
attributes[Number(index)] = {};
}
attributes[Number(index)][key] = value;
}
console.log(attributes);
Say I have an array of objects that looks like this
let myArray = [
{item1: true},
{item2: false},
{item3: true},
{item4: false}
]
How would I iterate though this to return a new array of true values that looks like this:
let newArray = ['item1', 'item3']
I found this function but it only returns single items:
function findKey(map, term) {
var found = [];
for(var property in map) {
if(map.hasOwnProperty(property)) {
for(var key in map[property]) {
if(map[property].hasOwnProperty(key) && key === term) {
found.push(property);
}
}
}
}
return found;
}
Assuming myArray always contains objects with only 1 property.
let newArray = myArray
.map(item => Object.entries(item)[0])
.filter(([key, value]) => value)
.map(([key, value]) => key)
You could access the first key of each array item via Object.keys(), and use this to filter items with a true value for that first key, and then complete the process with a call to map() to transform the item to a value based on the same "first key" technique:
let myArray = [
{item1: true},
{item2: false},
{item3: true},
{item4: false}
]
let result = myArray
.filter(item => item[ Object.keys(item)[0] ] === true)
.map(item => Object.keys(item)[0])
console.log(result)
Use the function reduce to build the desired output. The handler of the function reduce will get the keys and check for each value === true.
This approach checks for the whole set of keys within an object. Further, this way you only use one loop.
let myArray = [{item1: true},{item2: false},{item3: true},{item4: false}],
result = myArray.reduce((a, c) => a.concat(Object.keys(c).filter(k => c[k] === true)), []);
console.log(result);
Something much optimized than the accepted answer would look like this:
const arr = [
{ item1: true },
{ item2: false },
{ item3: true },
{ item4: false }
]
const result = [];
const len = arr.length;
for (let i = 0; i < len; ++i) {
const obj = arr[i];
const key = Object.keys(obj)[0];
if(obj[key]) {
result.push(key);
}
}
console.log(result);
There is only one loop over the array, instead of map and filter which ends up looping twice.
Shortest
let newArray = myArray.map( x=>Object.keys(x)[0] ).filter( (k,i)=>myArray[i][k] );
In above solution first we use: map which works as for-loop to get array of keys (using Object.keys) ["item1", "item2", "item3", "item4"]. Then we filter that array by choose only those keys for which original array object has true. e.g myArray[0]["item1"] -> true (we use fact that filter funtion takes array element (k) and its index (i) which is the same for elements in myArray). In map and filter we use arrow functions.
I would like to know how would I merge this bidimensional array
let arr[
['Reference', 'Price'],
['232323DD, 15.00]
];
I want to convert this into
[
{name: 'Reference', value: '232323DD'},
{name: 'Price', value: 15.00}
]
I've tried this:
Convert a two dimensional array into an array of objects
but It didn't work for me.
You can use .map():
let [keys, values] = [
['Reference', 'Price'],
['232323DD', 15.00]
];
let result = keys.map((k, i) => ({name: k, value: values[i]}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
You can map through the first array in that array and use their values as the keys to an object:
let arr = [
['Reference', 'Price'],
['232323DD', '15.00']
];
console.log(
arr[0].map((name, i) => ({name, value:arr[1][i]}))
)
If you are unsure about the size of the two arrays, you should first check whether their lengths are equal, to avoid undefined.
Other solution if you are not familiar with map (I think using map for this example make it a bit hard to read)...
const arr = [
['Reference', 'Price'],
['232323DD', 15.00]
]
const obj = []
arr.forEach(x => obj.push({name: x[0], value: x[1]}))
console.log(obj)
You can use the map function. It will run the callback on each array item, return it in a new array.
// where 'arr' is your original array
const new_arr = arr.map((item) => {
// this is called a 'destructuring assignment'
const [name, value] = item;
// return the values as fields in an object
return {name, value};
});
const arrArr = [['Reference', 'Price'], ['232323DD, 15.00]];
const objArr = [];
for (const item of arrArr) {
objArr.push({name: item[0], value: item[1]});
}
let arr = [
['Reference', 'Price'],
['232323DD', '15.00']
];
let result = arr[0].map((key, i) => ({name: key, value: arr[1] ? arr[1][i] : null}));
console.log(result);
I'll try to break this down:
// 1. create a new arr object:
let convertedArr = [];
// 2. loop over the original array:
for(let i = 0; i < arr.length; i++){
let currentItem = arr[i];
//create a temp object
let obj = {name:currentItem[0], value: name:currentItem[1] };
//push a new object to the array
convertedArr.push(obj);
}
I have an array like that
I want to pick the array item by property name, I am using lodash for that:
const result = _.map(this.thing, _.property('groups')).filter(x => x !== undefined);
But I am getting array of arrays as result
What I need is just single selected property array.
Any idea how to achieve that?
Try this>>>
var a = [{"p1":[3,4]},{"p2":[6,7]}];
function getArr(arr,key){
var res = [];
for(var v of arr){
if(v[key]!=undefined){
res = v[key];break;
}
};
return res;
}
console.log(getArr(a,"p1"));
If you can use ES6/ES7, you can rely on Object.keys and Object.values to access to the key (that is the property name) and the value (the array you want to get):
var arr = [
{ groups: [1, 2 ] },
{ category: [1, 2, 3 ] },
{ subCategory: [1, 2, 3, 4 ] }
];
function pickArray(propertyName) {
var element = arr.find(el => Object.keys(el)[0] === propertyName)
return element ? Object.values(element)[0] : null;
}
var res = pickArray('category');
console.log(res);
const output
= (Array.from(arr, (obj) => obj['product'], 'product')
.filter(x => typeof x !== 'undefined'))[0];
Try this:
const arr = [ {'groups': ['item1','item2']},
{'categories':['x','y']}
]
var ouptut= arr.find(item=> {
return item[Object.keys(item).find(key=>key === 'groups')]
})
console.log(ouptut)