I have a regular expression for allowing unicode chars in names(Spanish, Japanese etc), but I don't want to allow '.'(dot) anywhere in the string.
I have tried this regex but it fails when string length is less than 3. I am using xRegExp.
^[^.][\\pL ,.'-‘’][^.]+$
For Example:
NOËL // true
Sanket ketkar // true
.sank // false
san. ket // false
NOËL.some // false
Basically it should return false when name has '.' in it.
Your pattern ^[^.][\\pL ,.'-‘’][^.]+$ matches at least 3 characters because you use 3 characters classes, where the first 2 expect to match at least 1 character and the last one matches 1 or more times.
You could remove the dot from your character class and repeat that character class only to match 1+ times any of the listed to also match when there are less than 3 characters.
^[\p{L} ,'‘’-]+$
Regex demo
Or you could use a negated character class:
^[^.\r\n]+$
^ Start of string
[^.\r\n]+ Negated character class, match any char except a dot or newline
$ End of string
Regex demo
You could try:
^[\p{L},\-\s‘’]+(?!\.)$
As seen here: https://regex101.com/r/ireqbW/5
Explanation -
The first part of the regex [\p{L},\-\s‘’]+ matches any unicode letter, hyphen or space (given by \s)
(?!\.) is a Negative LookAhead in regex, which basically tells the regex that for each match, it should not be followed by a .
^[^.]+$
It will match any non-empty string that does not contain a dot between the start and the end of the string.
If there is a dot somewhere between start to end (i.e. anywhere) it will fail.
Related
I'm trying this regular expressión, but I can't validate correctly the end white space and the letter:
/^\d{0,2}(\-\d{0,2})?(\-\d{0,2})?(\ ?\d[W,E]?)?$/
Examples of correct values:
33-39-10 N //OK
85-50 W //OK
-85-50 E //Wrong
What's wrong?
\d{0,2} this quantifier also matches a digit zero times so that would match the leading - in the 3rd example.
In the character class [W,E] you could omit the comma and list the characters you allow to match [ENW]
If only the third group is optional you could try including the whitespace before the end of the line $
^\d{2}(-\d{2})(-\d{2})? [ENW] $
I have used this regular expression : ^(?!\-)\d{0,2}?(\-\d{0,2}).+\s(N|E|W|S)$
Using a negative lookahead, we have excluded anything that starts with a dash (-).
(?!\-) = Starting at the current position in the expression,
ensures that the given pattern will not match
\s(N|E|W|S) matches anything with a space (\s) and one of the letters using OR operator |.
You may also use \s+(N|E|W|S).
+ = Matches between one and unlimited times, as many times as
possible, giving back as needed
I need a regular expression that has the following constraints:
Contains only [A-Z0-9.*] characters
Is 1 to 15 characters in length
Must contain a * but only once.
Therefore, the following assertions:
ABC.123 invalid (no stars)
ABC.123* valid (star at end)
*ABC.123 valid (star at beginning)
ABC.*123 valid (star in the middle)
*ABC.123* invalid (more than one star)
My goal was to only have a single expression. I could obviously have an expression that asserts the first two constraints: [A-Z0-9.*]{1,15} and then a second expression to assert the third constraint \*{1}.
Is it possible to have an expression that essentially validates the overall structure of a string input, but then rewinds and re-evaluates the string with another expression?
Using a lookahead you can use this regex:
^(?=.{1,15}$)[A-Z0-9.]*\*[A-Z0-9.]*$
RegEx Demo
RegEx Breakup:
^: Start
(?=.{1,15}$): Positive lookahead to assert that we have 1 to 15 characters in input
[A-Z0-9.]*: Match zero or more [A-Z0-9.] characters
\*: Match an asterisk literally
[A-Z0-9.]*: Match zero or more [A-Z0-9.] characters
$: End
I have this ^[a-zA-Z0-9 #&$]*$, but not working for me in few cases.
If someone types
A string that only consists of digits (e.g. 1234567)
A string starting with a special character (e.g. &123abc)
need to be rejected. Note that a special char can be in the middle and at the end.
You seem to need to avoid matching strings that only consist of digits and make sure the strings start with an alphanumeric. I assume you also need to be able to match empty strings (the original regex matches empty strings).
That is why I suggest
^(?!\d+$)(?:[a-zA-Z0-9][a-zA-Z0-9 #&$]*)?$
See the regex demo
Details
^ - start of string
(?!\d+$) - the negative lookahead that fails the match if a string is numeric only
(?:[a-zA-Z0-9][a-zA-Z0-9 #&$]*)? - an optional sequence of:
[a-zA-Z0-9] - a digit or a letter
[a-zA-Z0-9 #&$]* - 0+ digits, letters, spaces, #, & or $ chars
$ - end of string.
you can do it with the following regex
^(?!\d+$)\w+\S+
check the demo here
I am trying to make regexp for validating string not containing
^ ; , & . < > | and having 1-20 characters. Any other Unicode characters are valid (asian letters for example).
How to do it?
You can use the following:
^[^^;,&.<>|]{1,20}$
Explanation:
^ assert starting of the string
[^ start of negated character class ([^ ])
^;,&.<>| all the characters you dont want to match
] close the negates character class
{1,20} range of matches
$ assert ending of the string
It will match any character other than specified characters within range of 1-20.
Your regex \w[^;,&.<>|]{1,20} contains \w that might not match all Unicode letters (I guess your regex flavor does not match Unicode letters with \w). Anyway, the \w only matches 1 character in your pattern.
Also, you say you need to exclude ^ but it is missing in your pattern.
When you want to validate length, you also must use ^/$ anchors to mark the beginning and end of a string.
To create a pattern for some range that does not match specific characters, you need a negated character class with anchors around it, and the length is set with limiting quantifiers:
^[^^;,&.<>|]{1,20}$
Or (this version makes sure we only match at the beginning and end of the string, never a line):
\A[^^;,&.<>|]{1,20}\z
Note that inside a character class, almost all special characters do not require escaping (only some of them, none in your case). Even the ^ caret symbol.
See demo
I want to extract a string from another using JavaScript / RegExp.
Here is what I got:
var string = "wp-button wp-image-45 wp-label";
string.match(/(?:(?:.*)?\s+)?(wp-image-([0-9]+))(:?\s(?:.*)?)?/);
// returnes: ["wp-button ", "wp-image-45", "45", undefined]
I just want to have "wp-image-45", so:
(Optional) any character
(Optional) followed by whitespace
(Required) followed by "wp-image-"
(Required) followed by any number
(Optional) followed by whitespacy
(Optional) followed by any character
What is missing here? Is it just some kind of bracketing or more?
I also tried
string.match(/(?:(?:.*)?\s+)?(?=(wp-image-([0-9]+)))(?=(:?\s(?:.*)?)?)/)
Edit: In the end I just want to have the number. But I'd also make this step in between.
Regexps are not required to start matching at the beginning of the string, so your attempts to match whitespace and any character aren't necessary. Also, "any character" includes whitespace (except newlines in certain modes).
This should be all you need:
string.match(/\bwp-image-(\d+)\b/)
This will capture, for example, "wp-image-123" into matching group 0, and "123" into matching group 1.
\b means "word boundary", which ensures that you won't match "abcwp-image-123def". A word boundary is defined as any place where a non-word character is followed by a word character, or vice versa. A word character is consists of a letter, a number or an underscore.
Also, I used \d instead of [0-9] simply out of convenience. They have slightly different meaning (\d also matches characters considered numbers in other languages), but that won't make a difference in your case.
If all of that surrounding stuff is optional and all you want is the number then there's no point to matching for any of that stuff except for that "wp-image-" prefix, just do:
var string = "wp-button wp-image-45 wp-label";
string.match(/wp-image-([0-9]+)/);