Changing background-image with jquery fadeTo() animation fails after a while - javascript

Update: I found a better way of doing this. There's a library called Backstretch.
I hope it will be helpful for someone else.
I'm trying to change the background of the tag every 10 seconds with animation but after a while of working, it does change every 2-3 seconds instead of 10.
What is wrong with the code? Why does it go crazy after a while of waiting as I explained above? For example, after about 10 minutes or so.
<section class='set-bg'>...</section>
$('.set-bg').each(function() {
var bgs = [];
$.get('/api/listbanners', (e) => {
bgs = e["background"];
x(0);
});
function x(i) {
$('.set-bg').css('background-image', 'url(' + bgs[i] + ')').fadeTo(0, 0.6).fadeTo(1000, 1);
i++;
if (i == bgs.length) {
i = 0;
}
setTimeout(x, 10000, i);
}
});

Related

Javascript: Countdown by animation.width()

I am currently trying to make a visual countdown for my user for when the animation is finished. My current attempt looks somewhat like this:
function setClassAndFire(){
timer = setInterval(function () {
t--;
$(this).attr('class', 'timerAnimation');
countdownTimer();
if (t === 0) {
clearInterval(timer);
timer = undefined;
funcForCall();
}
}, 1000);
}
function countdownTimer(){
var timerCurrentWidth = $('.timerAnimation').width(),
timerMaxWidth = $("#awardQueueText").width(),
pxPerSecond = timerMaxWidth / 60,
currentCountdown = timerCurrentWidth / pxPerSecond;
currentCountdown = Math.round(currentCountdown);
document.getElementById("timer").innerHTML = "<span style='white-space : nowrap;'>Animation ends in:</br></span>"+
"<span style='white-space : nowrap;'>" + currentCountdown + " sec.</span>";
}
Important to know is that the animation only displays the time until we may be able to send an API call. So the animation will be re-engaged if we have something in queue.
So as you can see my current attempt works, but is some-what cluncky:
The countdown sometimes fails to subtract a second and "fixes"
that with a 2 seconds subtract in the next attempt.
This is probably caused by the Math.round() for currentCountdown, but is there a work around for that? I mean I have the max possible width of the animation object and can seperate it from the current width.
Is there a way to bring it to work? We need to relate the timer to the animation to achive desired behavior. So when the animation count hits 25, I want that the displayed number is 25 as well!
You got this problem because you got the number from the width andh the width can't have decimals (or better, they can be but they are gonna be truncated sometimes).
So my suggestion is to use a differente variable for the number you will show and the width of the DOM element.
It seems to me that the variable t is what I am talking about, so just try to use it.
function setClassAndFire(){
timer = setInterval(function () {
t--; //What is t?
$(this).attr('class', 'timerAnimation');
countdownTimer(t);
if (t === 0) {
clearInterval(timer);
timer = undefined;
funcForCall();
}
}, 1000);
}
function countdownTimer(t){
document.getElementById("timer").innerHTML = "<span style='white-space : nowrap;'>Animation ends in:</br></span>"+
"<span style='white-space : nowrap;'>" + t+ " sec.</span>";
}

jQuery fade in box with unique content

I am making an info screen, and for that, it needs to show reviews from their customers pulled from Trustpilot.
I got the reviews and everything formatted in HTML showing the 20 latest, but I want to present it very sweet. I am not a JavaScript guru, but I thought i would do it using jQuery and its fadein function.
What is want, is have 20 unique divs fading in with X milliseconds difference popping randomly up. By unique I mean, that each div must have unique content. And by randomly popping up, I mean that if box 1 spawns first, then the next should be 5, then 14 etc, and then another cycle the next time around.
Just like what I made here;
$(function() {
var box = $('.box');
var delay = 100;
for (i = 0; i < 30; i++) {
setTimeout(function() {
var new_box = box.clone();
$('.container').append(new_box);
new_box.fadeIn();
}, delay);
delay += 500; // Delay the next box by an extra 500ms
}
});
http://jsfiddle.net/CCawh/5/
Is this even possible, and how would this be done?
I am very new to JavaScript, so please bear with me if I ask to much
Thanks in advance.
EDIT:
The HTML i want to spawn will all be wrapped in divs, so it would go like this;
<div id="one">content</div>
<div id="two">content</div>
<div id="three">content</div>
<div id="four">content</div>
etc.
Made up a nice function for you. I believe this may be what you are looking for
Here's a rundown of how it works :
Populate an array with numbers randomly generated 1-10 in this case.
Run through that array with a set interval, and when everything has
been added stop the interval
pretty straightforward from there. Set the visibility etc. You should be able to change up the function to dynamically add HTML elements and what-not, but just giving you something to start with.
var usedNum = [];
var i, j, y;
i = 0;
for(y = 0; y < 10; y++){
var x = Math.floor((Math.random() * 10) + 1);
if(!isUsed(x)) usedNum.push(x);
else y--;
}
var showInterval = setInterval ( function(){
if(i == 10){
clearInterval(showInterval);
}
$(".container div[data-line='" + usedNum[i] + "']").css({opacity: 0.0, visibility: "visible"}).animate({opacity: 1.0});
i++;
}, 500);
function isUsed(num) {
var used = false;
for(j = 0; j < usedNum.length; j++){
if(usedNum[j] == num){
used = true;
}
}
return used;
}
Demo fiddle : http://jsfiddle.net/xS39F/3/
Edit:
You can also mess around with the speed of the animation. In this demo (http://jsfiddle.net/adjit/XYU34/1/) I set the speed to 1000 so the next element starts fading in before the last element was done fading in. Makes it look a little smoother.
Instead of using a for loop and setTimeout, would setInterval work better for what you need? Some HTML might help better understand what you're trying to achieve.
$(function() {
var box = $('.box');
var delay = 100;
var interval = setInterval(function() {
var new_box = box.clone();
$('.container').append(new_box);
new_box.fadeIn();
}, delay);
delay += 500; // Delay the next box by an extra 500ms
}, delay);
});

How to make my script loop

I created an image slider that ends on one image, but now I'd like to take it a step further and make it loop.
Here is my code in the head tag
<style>
#picOne, #picTwo, #picThree, #picFour, #picFive{
position:absolute;
display: none;
}
#pics {
width:500px;
height:332px;
}
</style>
<script src="http://code.jquery.com/jquery-1.4.4.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function() {
$('#picOne').fadeIn(1500).delay(3500).fadeOut(1500);
$('#picTwo').delay(5000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picThree').delay(10000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFour').delay(15000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFive').delay(20000).fadeIn(1500).delay(3500);
});
</script>
and here is where it is implemented in the body code
<div id="pics">
<center>
<img src="img/dolllay.jpg" width="500" height="332" id="picFive" />
<img src="img/dye.jpg" width="500" height="332" id="picTwo" />
<img src="img/dollsit.jpg" width="500" height="332" id="picThree" />
<img src="img/heirloom.jpg" width="500" height="332" id="picFour" />
<img src="img/heritage.jpg" width="500" height="332" id="picOne" />
</center>
</div>
Could I turn it into a function and then loop it? Can I get any guidance on that? Thank you very much
Everyone's answering the question, but not solving the problem.
Sure, you can just put a loop wrapper around it (preferably one that doesn't terminate), but why not just program it right? Why have all the hardcoded times, and why not make it more robust?
Try rewriting your code like this. It makes it much easier to modify the pictures you loop through:
var pictures = ["picOne", "picTwo", "picThree", "picFour", "picFive"];
var index = 0;
var displayImage = function() {
if (index == pictures.length) { return; }
$("#" + pictures[index++]).fadeIn(1500).delay(3500).fadeOut(1500, displayImage);
};
displayImage();
Then, if you want to loop back, you simply tweak the displayImage function:
var displayImage = function() {
if (index == pictures.length) { index = 0; }
$("#" + pictures[index++]).fadeIn(1500).delay(3500).fadeOut(1500, displayImage);
};
TRY IT at jsfiddle
EDIT
On more careful reading of your question, I see that my original answer didn't do exactly what you needed. You have it set so that every five seconds, one will have faded out and the other one will have faded in. Currently, mine takes 6.5 seconds, since mine is all operating sequentially instead of concurrently. To make it come close to matching yours, just change the 1500s to 750s:
$("#" + pictures[index++]).fadeIn(750).delay(3500).fadeOut(750, displayImage);
This will take the right amount of time. It's slightly different from yours, in that one fades out all the way before the other fades in. The alternative is to actually skip the fadeIn and keep the fadeout. This is a lot closer to the way yours looks.
$("#" + pictures[index++]).show().delay(3500).fadeOut(1500, displayImage);
Or, make a very small fadein, to help reduce the flash of the new image:
$("#" + pictures[index++]).fadeIn(100).delay(3500).fadeOut(1400, displayImage);
Final Edit (really!)
Ok, to get the fadeIn and fadeOut to work reliably at the same time, the solution was to use neither. I went back to using animate, instead. As a result, I had to completely rewrite the displayImage function, but this is exactly what you need:
var displayImage = function () {
if (index == pictures.length) {
index = 0;
}
$("#" + pictures[index]).show().delay(3500).animate({
opacity: 0.2
}, {
step: function (now) {
var idx = (index + 1) % pictures.length;
var val = 1.2 - now;
$("#" + pictures[idx]).show().css("opacity", val);
},
complete: function () {
$("#" + pictures[index++]).hide();
displayImage();
}
});
};
What this does is move the sequence to "show->fadeIn and Out" instead of "fade in -> show -> fade out". To make your transition smooth, I only fade it out to 0.2 instead of 0. The step function is what fades the other one in at the same time. Once the new pic is visible, I completely hide the old pic.
Here's the working fiddle for it.
$(document).ready(function() {
setInterval(example, 10000); // repeat every 10 seconds
});
function example() {
$('#picOne').fadeIn(1500).delay(3500).fadeOut(1500);
$('#picTwo').delay(5000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picThree').delay(10000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFour').delay(15000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFive').delay(20000).fadeIn(1500).delay(3500);
}
A better way would be to give each pic the same class such as 'fadeinout'. This will mean you don't have to re-write your code when you add/remove more pics.
eg
<img id="picFive" class="fadeinout" ....
/* not sure if they are even <img>s but whatever they are*/
Then do
$(document).ready(function() {
beginFades();
});
function beginFades() {
$('.fadeinout').each( function(i,el) { // find all elements with fadeinout
//for each one, trigger the start of the fading after i*5000 milliseconds
//i is the index of the element as it was found by jQuery - this will be in
//document order (which actually may not be what you have but I'm guessing
//it is)
setTimeout(function(){
makeImgFadeInOut($(el))
}, i*5000);
});
}
function makeImgFadeInOut(el) {
//trigger a single fadeIn, fadeOut.
//But add a callback function to the end of fadeOut which retriggers the whole
//thing
el.fadeIn(1500).delay(3500).fadeOut(1500, function(){makeImgFadeInOut(el);});
}
WORKING DEMO (WITH DIVS)
You can use setInterval to loop it forever, or setTimeout to loop it for a specific duration.
<script type="text/javascript">
$(document).ready(function() {
setInterval(ImageSlider, 1000);
});
function ImageSlider() {
$('#picOne').fadeIn(1500).delay(3500).fadeOut(1500);
$('#picTwo').delay(5000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picThree').delay(10000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFour').delay(15000).fadeIn(1500).delay(3500).fadeOut(1500);
$('#picFive').delay(20000).fadeIn(1500).delay(3500);
}
</script>
If you want to have total control upon your elements you can use this:
var elements = [{
el: '#pic1',
delay: 3500,
fadeIn: 1500,
fadeOut: 1500
},
{
el: '#pic2',
delay: 3500,
fadeIn: 1500,
fadeOut: 1500
}
//... other elements
]
var index = null;
(function loop(){
index = index || 0;
index = index % elements.length();
$(elements[index].el).fadeIn(elements[index].fadeIn, function(){
$(this).delay(elements[index].delay)
.fadeOut(elements[index].fadeOut, function(){
index++;
window.setTimeout(loop, 5000);
});
})();
Edit : forgot to execute the first iteration of the loop function and removing the useless call for index inside the loop
The good thing about how this loop works is that it doesn't use the SetInterval function.
and the code inside the loop need to finish what it does inside before iterating again.
(you won't have this hideous bug if you click an other tab and go back to your carousel)
#ElRoconno answer is pretty good too if you require less configuration
Use any of this-
setInterval() - executes a function, over and over again, at specified time intervals
setInterval(function(){alert("Hello")},3000);
setTimeout() - executes a function, once, after waiting a specified number of milliseconds.
setTimeout(function(){alert("Hello")},3000);
What is the difference between both setInterval and setTimeout
for you may be the setTimeout will not work as it will run only once after a delay and setInterval will go on to make continuous repetitive call until the window.clearInterval(intervalVariable) is been called
I have created an example on jsfiddler here. Basically you don't have to do this one at a time. Just get the whole collection of images as an array and loop over them. Hope this helps
$(document).ready(function () {
var arr = $('.pics')
arr.hide();
$(arr[0]).fadeIn(1500).delay(3500).fadeOut(1500);
var index = 1;
var maxIndex = arr.length - 1;
setInterval(function () {
/*arr.hide();
var pic = $(arr[index]);
pic.show();
*/
var pic = $(arr[index]);
pic.fadeIn(1500).delay(3500).fadeOut(1500);
index++;
if (index >= maxIndex) {
index = 0;
}
}, 6500);
});
There's really no need for setInterval here since you can use the callback built-into .fadeOut(), nor having to enumerate an array of images. You can do something as simple as:
var idx = 0;
fade();
function fade() {
if (idx >= $('img').length) idx = 0;
$('img').eq(idx).fadeIn(1500).delay(3500).fadeOut(1500, fade);
idx++;
}
jsFiddle example

Difficulty with setInterval loop using class of Divs

$(document).ready(function fadeIt() {
$("#cool_content > div").hide();
var sizeLoop = $("#cool_content > div").length;
var startLoop = 0;
$("#cool_content > div").first().eq(startLoop).fadeIn(500);
setInterval(function () {
$("#cool_content > div").eq(startLoop).fadeOut(1000);
if (startLoop == sizeLoop) {
startLoop = 0
} else {
startLoop++;
}
$("#cool_content > div").eq(startLoop).fadeIn(1500);
}, 2000);
});
Here I want a class of divs to animate, infinitely!
However, because the interval is set to two seconds there is period where no div is showing!
What would be an appropriate way to loop the animation of these divs?
I thought about using a for loop but couldn't figure out how to pass a class of divs as arguments. All your help is appreciated.
Thanks!
Ok, generally, you should know that Javascript is a single threaded environment. Along with this, the timer events are generally not on time accurately. I'm not sure how jQuery is doing fadeIn and fadeOut, but if it's not using CSS3 transitions, it's going to be using timeOut and Intervals. So basically, there's a lot of timer's going on.
If you go with the for loop on this one, you'd be blocking the single thread, so that's not the way to go forward. You'd have to do the fade in/out by yourself in the setInterval.
Setting the opacity on each interval call. Like div.css('opacity', (opacity -= 10) + '%')
If you're trying to fade in and out sequentially, I think maybe this code would help
var opacity = 100,
isFadingIn = false;
window.setInterval(function() {
if (isFadingIn) {
opacity += 10;
if (opacity === 100) isFadingIn = false;
} else {
opacity -= 10;
if (opacity === 0) isFadingIn = true;
}
$('#coolContent > div').css('opacity', opacity + '%');
}, 2000);
Consider the following JavaScript / jQuery:
$(function(){
var divs = $('#cool_content > div').hide();
var curDiv;
var counter = 0;
var doUpdate = function(){
// Hide any old div
if (curDiv)
curDiv.fadeOut(1000);
// Show the new div
curDiv = divs.eq(counter);
curDiv.fadeIn(1000);
// Increment the counter
counter = ++counter % divs.length;
};
doUpdate();
setInterval(doUpdate, 2000);
});
This loops infinitely through the divs. It's also more efficient than your code because it only queries the DOM for the list of divs once.
Update: Forked fiddle
instead of
if (startLoop == sizeLoop)
{
startLoop = 0
}
else
{
startLoop++;
}
use
startLoop =(startLoop+1)%sizeLoop;
Check the demo http://jsfiddle.net/JvdU9/ - 1st div is being animated just immediately after 4th disappears.
UPD:
Not sure I've undestood your question, but I'll try to answer :)
It doesn't matter how many divs you are being looped - 4, 5 or 10, since number of frames are being calculated automatically
x=(x+1)%n means that x will never be greater than n-1: x>=0 and x<n.
x=(x+1)%n is just shorten equivalent for
if(x<n-1)
x++;
else
x=0;
as for me first variant is much readable:)
And sorry, I gave you last time wrong demo. Correct one - http://jsfiddle.net/JvdU9/2/

Chrome doesn't always repeat events with JavaScript setInterval()

I want to display several images of the same size at the same position, one at a time, with a 5s interval between each change. To do so I've used jQuery.Timer, that uses setInterval() to call some show_next_image() function every 5s.
It actually does work with IE, Opera, Safara, Firefox and.. partly with Google Chrome. It's not working with Google Chrome if I open a new window and directly type my website URL: it'll show the second image and stop. And with any other situation (reload, from another link, not right after opening a new window) it'll badly work: one can see the back image before the front image is shown.
Thus I'm wondering whether I've done something wrong with my JavaScript source. What I do is I use a front and a back image. When I want to show the next image, the back img source is set to the new image, and the front image is faded out while the back one is faded in through jQuery. You can check it out at http://www.laurent-carbon.com/ (in French). The two img are identified with bg1 and bg2.
var images = ["/img/IMG_0435bg.jpg", "/img/IMG_0400bg.jpg", "/img/maisonnette 2.jpg", "/img/IMG_0383bg.jpg", "/img/IMG_0409bg.jpg", "/img/IMG_0384bg.jpg"];
var idx = 1;
var waitTime = 5000; // ms
$(document).ready(function() {
$("#bg2").hide();
$.timer(waitTime, load_next);
$.preLoadImages(images);
});
function load_next(timer) {
var toshow = images[idx];
idx++;
idx %= images.length;
back_image().attr('src', toshow);
swap_images();
}
function front_image() {
return (idx % 2 == 0) ? $("#bg1") : $("#bg2");
}
function back_image() {
return (idx % 2 == 0) ? $("#bg2") : $("#bg1");
}
function swap_images() {
back_image().fadeOut('slow');
front_image().fadeIn('slow');
}
Thanks,
Ceylo
Ok I've worked out a solution .... without the use of plugins.
Demo
http://jsfiddle.net/morrison/PvPXM/9/show
source
http://jsfiddle.net/morrison/PvPXM/9/
This approach is a lot cleaner and removes the problem I had while viewing your page in chrome: the animation getting out of sync and flashing.
The only thing you have to do in the HTML is wrap the two images in a <div id="fadeBox" style="position:relative"></div>
$(function() {
var images = [
"http://www.laurent-carbon.com/img/IMG_0435bg.jpg",
"http://www.laurent-carbon.com/img/IMG_0400bg.jpg",
"http://www.laurent-carbon.com/img/maisonnette 2.jpg",
"http://www.laurent-carbon.com/img/IMG_0383bg.jpg",
"http://www.laurent-carbon.com/img/IMG_0409bg.jpg",
"http://www.laurent-carbon.com/img/IMG_0384bg.jpg"
];
var idx = 1;
var max = images.length;
var easing = "swing";
var waitTime = 5000; // ms
var fadeTime = 2000; // ms
var fadeShow = function(fadeTime, fadeDelay) {
var $topImage = $("#fadeBox img:last");
$topImage.fadeTo(fadeDelay, 1, function() {
$topImage.fadeTo(fadeTime, 0, easing, function() {
$topImage
.fadeTo(0, 1)
.insertBefore("#fadeBox img:first")
.attr("src", images[++idx == max ? idx = 0 : idx]);
fadeShow(fadeTime, fadeDelay);
});
});
};
fadeShow(fadeTime, waitTime);
});
Hope this helps
PS thanks to Levi for cleaning the code up a bit.
Answer: http://jsfiddle.net/morrison/RxyZY/
Notes:
You are trying to reinvent the wheel. You are creating a simple slideshow. There are numerous plugins to do exactly this and much more. I used jQuery cycle in my example, which is extremely customizable.
You should wrap your stuff up in a function, creating an expression. In my example, the (function($){}(jQuery)) is what does the trick. It scopes your variables to the function, rather than the global namespace.

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