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How to generate an array of unique objects from api?

I'm trying to disable booked times from calendar, depending on the date. My goal is to create an array, which holds objects with single date and array of booked times.
I have created an api, which outputs something like this:
"bookings": [
{
"_id": "5ce1b8792598adasf452",
"workType": "Nail polishing",
"client": "Mary Johnson",
"date": "2019-05-31T00:00:00.000Z",
"bookingTime": "09:00"
},
{
"_id": "5ce1b8753hs53gasf452",
"workType": "Makeup",
"client": "Kate Bush",
"date": "2019-05-31T00:00:00.000Z",
"bookingTime": "10:00"
}
]
I've tried using Sets, filters, but I just can't seem to wrap my head around how to implement it to my own code.
Snippet of my code:
bookedTimes: []
fetchBookedTimes() {
axios.get("http://localhost:8080/api/bookings").then(res => {
for (var i = 0; i < res.data.bookings.length; i++) {
this.bookedTimes.push({
date: moment(res.data.bookings[i].date).format("YYYY-MM-DD"),
times: [res.data.bookings[i].bookingTime.substring(0,2)]
});
}
});
}
I expect the output to be
bookedTimes: [
{
date: "2019-05-31",
times: ["09", "10"]
},
{
date: "2019-06-01",
times: ["10", "11"]
}
]
But the actual output is
bookedTimes: [
{
date: "2019-05-31",
times: ["09"]
},
{
date: "2019-05-31",
times: ["10"]
},
{
date: "2019-06-01",
times: ["10"]
},
{
date: "2019-06-01",
times: ["11"]
}
]

As per the code, the actual output is correct. You are looping the response and pushing the data to an array. If you want to group them by date, then you have to create an object and then convert it to the expected output.
var result = res.data.bookings.reduce(function (defaultValue, booking) {
var date = moment(booking.date).format("YYYY-MM-DD");
defaultValue[date] = defaultValue[date] || {date: date, times: []};
defaultValue[date].times.push(booking.bookingTime.substring(0,2));
return defaultValue;
}, {});
console.log(Object.values(result));

You can simply use reduce()
const arr = [
{
"_id": "5ce1b8792598adasf452",
"workType": "Nail polishing",
"client": "Mary Johnson",
"date": "2019-05-31T00:00:00.000Z",
"bookingTime": "09:00"
},
{
"_id": "5ce1b8753hs53gasf452",
"workType": "Makeup",
"client": "Kate Bush",
"date": "2019-05-31T00:00:00.000Z",
"bookingTime": "10:00"
},
{
"_id": "5ce1b8753hs53gasf452",
"workType": "Makeup",
"client": "Kate Bush",
"date": "2019-06-31T00:00:00.000Z",
"bookingTime": "11:00"
},
{
"_id": "5ce1b8753hs53gasf452",
"workType": "Makeup",
"client": "Kate Bush",
"date": "2019-06-31T00:00:00.000Z",
"bookingTime": "12:00"
}
]
const res = arr.reduce((ac,{date,bookingTime}) => {
ac[date] = ac[date] || {date,bookingTime:[]}
ac[date].bookingTime.push(bookingTime.slice(0,2));
return ac;
},{})
console.log(Object.values(res))

You're pushing values directly into array but you need to group them by date so you can use an object and then push values to array in the end
Here temp is used to group values by date
We check for date it exists we push the time value to times array if not we create a new property on temp
In the end we push values to this.bookedTimes array
fetchBookedTimes() {
axios.get("http://localhost:8080/api/bookings").then(res => {
let temp = {}
for (var i = 0; i < res.data.bookings.length; i++) {
let date = moment(res.data.bookings[i].date).format("YYYY-MM-DD"),
let time = [res.data.bookings[i].bookingTime.substring(0,2)]
temp[date] = temp[date] || {date: date, times:[]}
temp[date].times.push(time)
});
}
this.bookedTimes.push(Object.values(temp))
});
}

First, check if the date of already in the array. Check if 'times' already exist in 'object.times', if not, push it to the 'object.times' array.
Please see the code below.
const date = moment(res.data.bookings[i].date).format("YYYY-MM-DD");
const times = res.data.bookings[i].bookingTime.substring(0, 2);
const arrayIndex = bookedTimes.findIndex(item => item.date === date);
//Check if date already exist in array
if (arrayIndex !== -1) {
//Check if 'times' already exist in 'object.times'
if (!bookedTimes[arrayIndex].times.includes(times)) {
//Push 'times' in 'object.times'
bookedTimes[arrayIndex].times.push(times);
}
} else {
//Push a new object into the array
bookedTimes.push({
date: date,
times: [times]
});
}

How to create a new json out of three jsons?

I have 3 different jsons, I need to extrapolate some data from each and create a new json with it. The three jsons have an id identifier in common, a unique identifier, so We could use that as a match since they are actually three different big jsons.
On json one we have "id":"265", on two and three "article_id":"265", so these can be the reference point when we loop.
I never worked with json this way so I wouldn't know how to approach it. I have put jQuery and JS as tags as they're what I know best.
1
{
"id":"265",
"title":"Battle of Gettysburg",
"page_id":"4849",
"language_id":"en",
"original_time":"July 1\u20133, 1863"
}
2
{
"id":"185",
"original_name":"United States",
"country_id":"24",
"article_id":"265"
}
3
{
"id":"73",
"month":"July",
"year":"1863",
"suffix":"",
"article_id":"265"
}
So the end result I am looking for is a single json exactly like this, we take id and title as objects from json 1, then we grab original_name from json two and year object from json three and we'll have:
{
"id":"265",
"title":"Battle of Gettysburg",
"original_name":"United States",
"year":"1863"
}
NOTE
The json above are just examples, in reality they are three huge lists, what I could do (manually), is to join them in order to have a single json.

There is some terminology confusion here; based on your comments you could be asking one of two very different questions. Fortunately one of them is very simple to answer so let's do both.
(I am handwaving past the details of loading json strings into the browser and converting them into javascript objects.)
If you have three objects
...then this is just a matter of plucking out the fields you need individually when constructing an output object:
var in1 = {
"id": "265",
"title": "Battle of Gettysburg",
"page_id": "4849",
"language_id": "en",
"original_time": "July 1\u20133, 1863"
};
var in2 = {
"id": "185",
"original_name": "United States",
"country_id": "24",
"article_id": "265"
}
var in3 = {
"id": "73",
"month": "July",
"year": "1863",
"suffix": "",
"article_id": "265"
}
// construct a new object using the selected fields
// from each object in1, in2, or in3:
var out = {
id: in1.id,
title: in1.title,
original_name: in2.original_name,
year: in3.year
}
console.log(out);
If you have three lists of objects:
...in this case it's a lot more complicated (and a lot more interesting). In this case you would need to match fields from the objects in each list which share the same IDs.
The following is definitely not the most efficient or memory-conserving way to do this; I've spread things out to (hopefully) make it easier to follow what it's doing.
I'm making two assumptions:
within each list, all IDs are unique (meaning you won't have two objects with the same ID in one JSON file)
Every ID will appear in all three lists (meaning you don't need to handle missing fields in output)
/* Again handwaving past loading JSON strings and parsing
them into javascript objects, we'll just start with
three arrays: */
var input1 = [{
"id": "265",
"title": "Battle of Gettysburg",
"page_id": "4849",
"language_id": "en",
"original_time": "July 1\u20133, 1863"
},
{
"id": "1",
"title": "Foo",
"page_id": "123",
"language_id": "en",
"original_time": "July 1\u20133, 1863"
}
];
var input2 = [{
"id": "1",
"original_name": "Bar",
"country_id": "24",
"article_id": "265"
},
{
"id": "265",
"original_name": "United States",
"country_id": "24",
"article_id": "265"
}
]
var input3 = [{
"id": "1",
"month": "July",
"year": "Baz",
"suffix": "",
"article_id": "265"
},
{
"id": "265",
"month": "July",
"year": "1863",
"suffix": "",
"article_id": "265"
}
]
/* It would be much easier to find corresponding IDs
across these arrays if they weren't arrays. We'll
start by converting them into objects keyed by the
item ids: */
var convertArray = function(arr) {
var output = {};
arr.forEach(function(o) {
output[o.id] = o;
});
return output;
}
var obj1 = convertArray(input1);
var obj2 = convertArray(input2);
var obj3 = convertArray(input3);
/* Now if we need to find (say) the object with id "foo", we don't
need to search the whole array, but can just use `obj1["foo"]` or
`obj1.foo`.
The last step is to iterate over the list of IDs and repeatedly
do basically the same thing as in the "if you have three objects"
part above. The only difference is that we need to access the
object with the same ID in each of the input lists: */
var constructOutput = function(in1, in2, in3) {
var output = []; // we'll be outputting a list of objects again.
// step through every ID (assuming in1 contains all of them):
Object.keys(in1).forEach(function(id) {
var obj = {
id: id,
title: in1[id].title,
original_name: in2[id].original_name,
year: in3[id].year
}
output.push(obj);
});
return output;
}
var final = constructOutput(obj1, obj2, obj3)
console.log(final)

Essentially what you have to do is mimic a SQL JOIN using JavaScript objects:
Use JSON.parse() on all three JSON collections to turn them into arrays of objects.
Iterate through JSON 1 objects; for each object...
Iterate through JSON 2 objects, testing if article ID matches the ID from JSON 1 that we are iterating over. Save this object.
Iterate through JSON 3 objects, testing if ID matches the ID of the object we found from JSON 2. Save this object.
After you have all three objects, make a new object literal that contains only the fields you want:
{
Id: obj1.id,
Title: obj1.title,
Original_name: obj2.original_name,
Year: obj3.year
}

Should you want to combine n number of JSON objects, e.g. a list of objects you can take a functional approach and utilise reduce + filter.
const data = [{
"id":"265",
"title":"Battle of Gettysburg",
"page_id":"4849",
"language_id":"en",
"original_time":"July 1\u20133, 1863"
},
{
"id":"185",
"original_name":"United States",
"country_id":"24",
"article_id":"265"
},
{
"id":"73",
"month":"July",
"year":"1863",
"suffix":"",
"article_id":"265"
}];
const final = data.reduce((accu, { id, title }, index, array) => {
// Find any related objects
const matches = array.filter(data => data.article_id === id);
if (matches.length) {
// Flatten them for ease of access. Duplicate keys will override.
const flat = matches.reduce((arr, item) => ({ ...arr, ...item }), [])
// Return new object
return accu.concat({
...flat,
id,
title,
});
}
return accu;
}, []);
console.log(final, '<<')
// Witness
document.getElementById('results').innerHTML = JSON.stringify(final);
<div id="results" style="font-family: Courier; font-size 14px; color: #fff; background: #000; padding: 20px; max-width: 80vw;"></div>

Edited*
Maybe this is what you need?
let arrPages = [{
"id":"265",
"title":"Battle of Gettysburg",
"page_id":"4849",
"language_id":"en",
"original_time":"July 1\u20133, 1863"
}];
let arrArticles = [{
"id":"185",
"original_name":"United States",
"country_id":"24",
"article_id":"265"
},
{
"id":"73",
"month":"July",
"year":"1863",
"suffix":"",
"article_id":"265"
}];
let getResult = (arrInput, arrCompare) => {
let joinedItems = [];
arrInput.forEach(item => {
let newItem = { id: item.id, title: item.title };
arrCompare.forEach(subItem => {
if(subItem.article_id !== undefined && subItem.article_id === item.id){
if(subItem.original_name !== undefined)
newItem.original_name = subItem.original_name;
if(subItem.year !== undefined)
newItem.year = subItem.year;
}
});
joinedItems.push(newItem);
});
return joinedItems;
};
let result = getResult(arrPages, arrArticles);
console.log(result);

In the first part of the code i create a var that has the json data.
To solve the problema i create 2 functions, the order of the creation dosen't metter, the first function getJSONData() take the json data as parameter and return a object filtered by the keys defined in the array keys. The secound function just check if the current key is present in the array of keys, this function could be replaced by the jQuery.inArray() method.
// JSON data
var json = [{
"id":"265",
"title":"Battle of Gettysburg",
"page_id":"4849",
"language_id":"en",
"original_time":"July 1\u20133, 1863"
},
{
"id":"185",
"original_name":"United States",
"country_id":"24",
"article_id":"265"
},
{
"id":"73",
"month":"July",
"year":"1863",
"suffix":"",
"article_id":"265"
}]
// keys that i want
var keys = ["title", "original_name", "year"];
// var that will have the filtered data
var newJSON = getJSONData(json);
console.log(JSON.stringify(newJSON))
// this is the main function of the code
// here we iterate in the json creating a new object that has all the tags definid in the keys array
function getJSONData(arrayJSON){
var JSONFiltered = {};
for(var i in arrayJSON){
for(var key in arrayJSON[i]){
if(hasElement(key)){
JSONFiltered[key] = arrayJSON[i][key];
}
}
}
return JSONFiltered;
}
// this function is used to check a key is present in the array of keys
function hasElement(key){
for(var elem in keys){
if(keys[elem] == key) return true;
}
return false;
}

Array Mapping in AngularJs

I have two arrays
$scope.tags = [{ "id": 1, "name": "python" }, { "id": 2, "name": "NodeJs" }, { "id": 3, "name": "git" }]
Other one is
$scope.skillsInterested = [1,2];
What is want to do ?
How can i map the above arrays and print only names of the id's in$scope.skillsInterested
I want to print names in first array only the id's present in second.
I have tried this after getting several answers
var tag_map = {};
for (var x = 0; x < $scope.tags.length; x++) {
tag_map[$scope.tags[x]['id']] = $scope.tags[x]['name'];
}
$scope.skillsInts = $scope.skillsInterested.map(function(x) {
return tag_map[x]
On running console.log
console.log("Result", tag_map);
It sometimes give result sometimes it gives 'map' of undefined.
TypeError: Cannot read property 'map' of undefined
at controllers.js:141
at angular.js:16383
at m.$eval (angular.js:17682)
at m.$digest (angular.js:17495)
at m.$apply (angular.js:17790)
at l (angular.js:11831)
at J (angular.js:12033)
at XMLHttpRequest.t.onload (angular.js:11966)
Thanks in advance.

Make a map of your data that looks like this:
var tagMap = { 1: "python", 2: "NodeJs" /* etc. */ };
You can do this by looping over your tags and adding a new property to an object. reduce lets you do this without creating any extra variables.
Then, you can select names from your newly created object using the [] notation: tagMap[1] returns "pyhton".
var tags = [{ "id": 1, "name": "python" }, { "id": 2, "name": "NodeJs" }, { "id": 3, "name": "git" }]
var selectedExpTags = [1,2];
// Make a map for `id: name`
var tagMap = tags.reduce(function(map, tag) {
map[tag.id] = tag.name;
return map;
}, {});
// Quickly select names from the map:
var selectedNames = selectedExpTags.map(function(id) {
return tagMap[id];
});
console.log(selectedNames);
Using this approach, you minimise the iterations over your data. The creation of the map loops over the tags once. Creating the array with names, loops over the selected tags once. So, roughly, the "loop count" is tags.length + selectedTags.length. If you would use an indexOf based approach, your loop count would be tags.length * selectedTags.length.

Use the filter function for first, and then check the id's existnent then map the names from the array.
var first = [{ "id": 1, "name": "python" }, { "id": 2, "name": "NodeJs" }, { "id": 3, "name": "git" }];
var selectedExpTags = [1,2];
var names = first.filter(item => selectedExpTags.some(id => item.id === id)).map(item => item.name);
console.log(names);

You can loop over $scope.selectedExpTags and get a list of all names. You can use array.find if you want first value only.
Sample
var first = [
{ "id": 1, "name": "python" },
{ "id": 2, "name": "NodeJs" },
{ "id": 3, "name": "git" }];
var selectedExpTags = [1,2];
var names = selectedExpTags.map(x=> first.find( y=> y.id === x ).name )
console.log(names);

$scope.newArray = []; // If you need a new array to work with
angular.forEach($scope.tags, function(tag){
$scope.selectedExpTags.forEach(function(selectedTag){
if(selectedTag == tag.id){
//tag.hide = false; // - If you want to update the current array
$scope.newArray.push(tag);
}
// else{ // - If you want to update the current array
// tag.hide = true;
// }
})
})
Lodash is more efficient than angular for manipulating data.

How can I merge JavaScript arrays containing objects, deduplicate and keep the newer object

I'm trying to merge two arrays of objects by checking if the titles are the same, and if they are, then checking for which entry is newer, and discarding the older one. I have found a lot of solutions for discarding true duplicates, but how can I do this in a way where I can decided which to keep based on dates?
const a = [{
"title": "title1",
"date": "2010-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
const b = [{
"title": "title1",
"date": "2015-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
Thanks for any tips you can provide!

Here is ES6 code to do that:
var res = Array.from([...a,...b].reduce ( (hash, v) =>
!hash.has(v.title) || hash.get(v.title).date < v.date ? hash.set(v.title, v) : hash
, new Map()), v => v[1]);
var a = [{
"title": "title1",
"date": "2010-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
var b = [{
"title": "title1",
"date": "2015-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
var res = Array.from([...a,...b].reduce ( (hash, v) =>
!hash.has(v.title) || hash.get(v.title).date < v.date ? hash.set(v.title, v) : hash
, new Map()), v => v[1]);
console.log(res);
Explanation
First the input arrays are concatenated together into one new array with the spread operator:
[...a,...b]
Then an empty Map is created and passed as last argument to reduce:
new Map()
The reduce method calls the arrow function for each element in the concatenated array. The arrow function also receives the above mentioned map as argument (as hash).
The arrow function must return a value. That value is then passed again to subsequent call of this function (for the next element), and so we always return the map, which grows in each function call. It is, as it were, passed from one call to the next. In the last call the returned map becomes the return value of .reduce().
The arrow function itself checks if the current element's title is not yet in the map:
!hash.has(v.title)
If it is in the map already, then the next expression is also evaluated; it checks whether the date in the map entry is before the current element's date.
hash.get(v.title).date < date
If either of the above conditions is true (not in map, or with smaller date), then the map entry is (re)created with the current element as value.
? hash.set(v.title, v)
This set also returns the whole map after setting. Otherwise the map is returned unchanged:
: hash
The result of reduce() is thus a map, keyed by titles. This is really the result you need, but it is in Map format. To get it back to a normal array, the Array.from method is called on it. This changes the Map values into an array of key-value pairs (sub-arrays with 2 elements). Since we are only interested in the values, we apply a function to it:
v => v[1]
This replaces every pair with only the second value. This function is passed as second argument to Array.from which applies it to every pair.
Some remarks
This assumes that your dates are in ISO format, like in your sample: in that case the string comparison gives the correct result for determining whether one date precedes another.
The result will include also the objects that only occur in one of the two input arrays
This is easily extendible to three input arrays: just add a third one like this: [...a,...b,...c]
This runs in O(n) time, where n is the total number of objects present in the input arrays. This is because most JavaScript engines implement Map access operations like .has, .get and .put with O(1) time.

a.forEach(function(elem1,count1){
b.forEach(function(elem2,count2){
//loop trough each a frouvh each b
if(elem1.title==elem2.title){
var date1=new Date(elem1.date);
var date2=new Date(elem2.date);
if(date1.getTime()>date2.getTime()){
//elem from a is older
//delete elem from a
}else{
//elem from b is older
}
}
});
});

var a = [{
"title": "title1",
"date": "2010-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
var b = [{
"title": "title1",
"date": "2015-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}]
function assign(a, b) {
return a.reduce((acc, itemA) => {
const {title: titleA, date: dateA} = itemA
const itemB = b.find(({title: titleB}) => titleA == titleB)
if (itemB) {
if (new Date(dateA) - new Date(itemB.date) >= 0) {
acc.push(itemA)
} else {
acc.push(itemB)
}
}
return acc
}, [])
}

You can use for loop, new Date().getTime()
var a = [{
"title": "title1",
"date": "2010-08-20T15:51:59"
}, {
"title": "title2",
"date": "2015-09-20T16:45:22"
}];
var b = [{
"title": "title1",
"date": "2015-08-20T15:51:58"
}, {
"title": "title2",
"date": "2015-09-20T16:45:21"
}];
var res = [];
for (var i = 0; i < a.length; i++) {
var curr = a[i];
for (var n = 0; n < b.length; n++) {
if (curr.title === b[n].title) {
if (new Date(curr.date).getTime() > new Date(b[n].date).getTime()) {
res.push(curr)
} else {
res.push(b[n])
}
}
}
}
console.log(res);

Javascript sort function on dates not working

So I have this code -
console.log(data);
data = data.sort(function(d1,d2){
var a1= d1["date"].split('/'), b1=d2["date"].split('/');
if(a1[2]==b1[2]){
return (a1[0]==b1[0])? a1[1]-b1[1]: a1[0]-b1[0];
}
return a1[2]-b1[2];
});
console.log("DATA");
console.log(data);
with this data -
[
{ "date": "2/7/2012", "quantity: " 4"},
{ "date": "2/4/2012", "quantity: "5"},
{ "date": "2/3/2012", "quantity: "10"},
{ "date": "2/5/2012", "quantity" : "12"},
{ "date": "2/6/2012", "quantity" : "10"}
]
The two console logs show the data in the same way, or the sorting has no effect. The data coming out of the sort function is in the same order as the data going in.
Why?

Try:
data = data.sort(function(d1,d2){
return new Date(d1.date) - new Date(d2.date);
});
DD/MM/YYYY should be acceptable by Date parser, here is the spilt version.
data = data.sort(function(d1, d2){
var d1 = d1.split('/'), d2 = d2.split('/');
return new Date(d1[2], d1[0] - 1, d1[1]) - new Date(d2[2], d2[0] - 1, d2[1]);
});