Get first element in an array of object by index [duplicate] - javascript

This question already has answers here:
How to get value at a specific index of array In JavaScript?
(8 answers)
Closed 4 years ago.
I have an array of object :
this.things=[
{
id:XYZ,
event: Fri Jul 20 2018 15:00:04 GMT+0200 (CEST)
person: 3
}, {
person: 4
id:XYZ1,
event: Fri Jul 10 2018 15:00:04 GMT+0200 (CEST)
}, {
id:XYZ2,
person: 5
event: Fri Aug 20 2018 15:00:04 GMT+0200 (CEST)
}
]
I only want to get the first event value like this.
event: Fri Jul 20 2018 15:00:04 GMT+0200 (CEST)
tried this
this.things[Object.keys(this.things)[0]['event']]
unfortunately not working.


You don't need to use Object.keys here.
this.things[0]['event']
or
this.things[0].event


this.things = [
{
id: 'XYZ',
event: 'Fri Jul 20 2018 15:00:04 GMT+0200 (CEST)',
person: '3'
}, {
person: 4,
id: 'XYZ1',
event: 'Fri Jul 10 2018 15:00:04 GMT+0200 (CEST)',
}, {
id: 'XYZ2',
person: '5 ',
event: 'Fri Aug 20 2018 15:00:04 GMT+0200 (CEST)',
}
]
var i = 0;
document.getElementById("demo").innerHTML = this.things[i].event
Clear your Array object error ","
<h1 id="demo"></h1>

Related

Subtracting months from current date is returning unexpected results. Same Month (March) is being returned twice

I have created a method that returns the past months according to the current date and how many months from the past you need, seems like the javascript date object is
behaving wrongly.
I guess the problem has only popped up today as it's the 29th of the current month and subtracting 1 month from 29 March which is supposed to be 29 February (doesn't exist) lead javascript to fallback to +1 day...
Can someone please suggest a great fix for this.
Thanks 🙌
export type Config = {
n: number;
i18n: i18n;
};
export default function NMonthsAgo(config: Config): MonthsAgo[] {
const date = new Date();
const { i18n } = config;
let { n } = config;
n = Math.max(n, 0);
// add one month in future to include the current one.
date.setMonth(date.getMonth() + 1);
return Array.from({ length: n || 1 })
.map(() => {
date.setMonth(date.getMonth() - 1);
console.log(date.toDateString()); ===> console print.
return {
monthName: formatDate(i18n, date, { month: 'long' }),
monthNameShort: formatDate(i18n, date, { month: 'short' }),
year: formatDate(i18n, date, { year: 'numeric' }),
};
})
.reverse();
}
Output:
NMonthsAgo.js:36 Wed Dec 29 2021
NMonthsAgo.js:36 Mon Nov 29 2021
NMonthsAgo.js:36 Fri Oct 29 2021
NMonthsAgo.js:36 Wed Sep 29 2021
NMonthsAgo.js:36 Sun Aug 29 2021
NMonthsAgo.js:36 Thu Jul 29 2021
NMonthsAgo.js:36 Tue Jun 29 2021
NMonthsAgo.js:36 Sat May 29 2021
NMonthsAgo.js:36 Thu Apr 29 2021
NMonthsAgo.js:36 Mon Mar 29 2021 <=== Mars is returned twice...
NMonthsAgo.js:36 Mon Mar 01 2021 <=== Mars is returned twice...
NMonthsAgo.js:36 Mon Feb 01 2021
NMonthsAgo.js:36 Fri Jan 01 2021
NMonthsAgo.js:36 Wed Dec 29 2021

javascript string date from array and group by day and return new array per day

I got a array of data the data is dates they are sorted per day.
Wat i want to get is the data grouped by date(day) and all the data of every day needs to be in new and separated array. my data can be short 1 date string in 1 day or very long month's or year
My data:
accountDateArray = [
Mon Jun 08 2020 19:47:16 GMT+0200 (Midden-Europese zomertijd),
Mon Jun 08 2020 19:47:26 GMT+0200 (Midden-Europese zomertijd),
Mon Jun 08 2020 19:47:34 GMT+0200 (Midden-Europese zomertijd),
Tue Jun 09 2020 15:40:31 GMT+0200 (Midden-Europese zomertijd),
Tue Jun 09 2020 15:42:28 GMT+0200 (Midden-Europese zomertijd),
Wed Jun 10 2020 00:06:50 GMT+0200 (Midden-Europese zomertijd),
Wed Jun 10 2020 00:06:50 GMT+0200 (Midden-Europese zomertijd),
Wed Jun 10 2020 08:10:51 GMT+0200 (Midden-Europese zomertijd),
Fri Jun 12 2020 10:59:21 GMT+0200 (Midden-Europese zomertijd),
...
]
What i want is:
[
[
Mon Jun 08 2020 19:47:16 GMT+0200 (Midden-Europese zomertijd),
Mon Jun 08 2020 19:47:26 GMT+0200 (Midden-Europese zomertijd),
Mon Jun 08 2020 19:47:34 GMT+0200 (Midden-Europese zomertijd),
],
[
Tue Jun 09 2020 15:40:31 GMT+0200 (Midden-Europese zomertijd),
Tue Jun 09 2020 15:42:28 GMT+0200 (Midden-Europese zomertijd),
],
...
]
My code
let NewDateArray = [];
for (let i in accountDateArray) {
NewDateArray.push(accountDateArray[i].toString().substring(0, 10));
}
let unique = [...new Set(NewDateArray)];
for (let i in accountDateArray) {
for (let n in unique) {
if (
unique[n] === accountDateArray[i].toString().substring(0, 10)
) {
console.log(accountDateArray[i]);
}
}
}

You can make use of reduce function, I hope this will lead you to the right direction.
var accountDateArray = ['Mon Jun 08 2020 19:47:16 GMT+0200 (Midden-Europese zomertijd)','Mon Jun 08 2020 19:47:26 GMT+0200 (Midden-Europese zomertijd)','Mon Jun 08 2020 19:47:34 GMT+0200 (Midden-Europese zomertijd)','Tue Jun 09 2020 15:40:31 GMT+0200 (Midden-Europese zomertijd)','Tue Jun 09 2020 15:42:28 GMT+0200 (Midden-Europese zomertijd)','Wed Jun 10 2020 00:06:50 GMT+0200 (Midden-Europese zomertijd)','Wed Jun 10 2020 00:06:50 GMT+0200 (Midden-Europese zomertijd)','Wed Jun 10 2020 08:10:51 GMT+0200 (Midden-Europese zomertijd)','Fri Jun 12 2020 10:59:21 GMT+0200 (Midden-Europese zomertijd)',];
var result = Object.values(accountDateArray.reduce((acc, date)=>{
const key = new Date(date).getDate();
acc[key] = [...(acc[key] || []), date];
return acc;
},{}));
console.log(result);

Convert an array of IsoDate to a Date Format [duplicate]

This question already has answers here:
How do I format a date in JavaScript?
(68 answers)
Closed 4 years ago.
I have an array of date
["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)"]
I want to get it in a different format as exemple
Monday 16 July 2018 instead of "Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)"
Is there a way to go through the table and transform the date ?
const test1 = test.map(a => a.toISOString().slice(0, 10))
console.log(test1)
Tried this got an error
var test = ["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)"
]
// Monday 16 July 2018 instead of "Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)"
const test1 = test.map(a => a.toISOString().slice(0, 10));
console.log(test1)

toISOString does not give me the format you wanted.
You wanted
Monday 16 July 2018
instead of
"Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)"
toLocaleString gives us a long month:
new Date(a).toLocaleString("en-us",{
weekday: 'long',
year: 'numeric',
month: 'long',
day: 'numeric' })
then you can move the texts around like this:
var test = ["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)", "Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)", "Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)", "Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)", "Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)", "Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)", "Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)", "Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)", "Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)", "Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)" ]
const locale = "en-us";
var options = { weekday: 'long', year: 'numeric', month: 'long', day: 'numeric' }
let test1 = test.map(function(a) {
let dateStr = new Date(a).toLocaleString(locale,options);
return dateStr.replace(/(\w+), (\w+) (\d+), (\d+)/,"$1 $3 $2 $4");
})
console.log(test1)
// simpler if no replace of month:
// String
test1 = test.map(a => a.split(/ \d\d:/)[0]);
console.log(test1)
// date
test1 = test.map(a => new Date(a).toDateString());
console.log(test1)

Try this.
var days = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]
var months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
var test = ["Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:33:46 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:21:36 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:03:42 GMT+0200 (CEST)",
"Fri Jul 13 2018 09:01:05 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:53:23 GMT+0200 (CEST)",
"Fri Jul 13 2018 08:52:33 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:59 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:49 GMT+0200 (CEST)",
"Thu Jul 12 2018 13:41:42 GMT+0200 (CEST)"
]
// Monday 16 July 2018 instead of "Mon Jul 16 2018 11:40:28 GMT+0200 (CEST)"
const test1 = test.map(a => {
a= new Date(a);
var c= days[a.getDay()]+" "+a.getDate()+" "+months[a.getMonth()]+" "+a.getFullYear();
return c;
});
console.log(test1)

Javascript sorting with two properties

I'm struggling with sorting two levels. The logic is as follows. If any of the objects have a status, return the most recent object with a status. If none of the objects have a status, return the most recent object without a status.
var apps = [
{ status: 'PASS',
date_created: Thu Sep 03 2015 17:24:45 GMT-0700 (PDT)
},
{ status: 'FAIL',
date_created: Thu Sep 02 2015 17:24:45 GMT-0700 (PDT),
},
{ status: '',
date_created: Thu Sep 03 2015 17:24:45 GMT-0700 (PDT),
}
]
var desired_result = [{ status: 'PASS',
date_created: Thu Sep 03 2015 17:24:45 GMT-0700 (PDT)
}]
var apps_2 = [
{ status: '',
date_created: Thu Sep 03 2015 17:24:45 GMT-0700 (PDT)
},
{ status: '',
date_created: Thu Sep 02 2015 17:24:45 GMT-0700 (PDT),
},
{ status: '',
date_created: Thu Sep 01 2015 17:24:45 GMT-0700 (PDT),
}
]
var desired_resul2 = [{ status: '',
date_created: Thu Sep 03 2015 17:24:45 GMT-0700 (PDT)
}]
I've tried
var sorted = _.sort_by(apps, function (x) { x.date_updated });
I've also looked a few other SO questions but can't keep the objects in place after the first sort.

If I understand your question correctly, here is what you are looking for. http://jsfiddle.net/whxu5sea/3/
You need to filter the elements to ensure they have a status of ANY kind. Then sort them by date, earliest first. Then get that first value. In my example I assumed the dates where strings, but still should work.
var apps = [
{ status: 'PASS',
date_created: 'Thu Sep 03 2015 17:24:45 GMT-0700 (PDT)'
},
{ status: 'FAIL',
date_created: 'Thu Sep 02 2015 17:24:45 GMT-0700 (PDT)',
},
{ status: '',
date_created: 'Thu Sep 01 2015 17:24:45 GMT-0700 (PDT)',
}
];
var x;
var arr = _.filter(apps, function(data) {
return !!data.status.length;
});
x = _.chain( arr.length ? arr : apps )
.sortBy(function(data) {
return new Date(data.date_created).getTime();
}).last().value();
console.log( x );
To check if it works when no status is provided: http://jsfiddle.net/whxu5sea/4/
I hope this helps. LMK if any further clarification is needed.
EDIT: Updated to get NEWEST element (last).

Here is a simple solution that iterates just once through apps, without a filtering step. See here for a jsfiddle.
The concept is that, if status is falsy, its date is converted into a negative number that retains the correct sort order among all falsy elements, but makes all falsy elements have a lower sort order than all non-falsy ones.
We convert the falsy element dates by subtracting 8640000000000001, which is (the maximimum millis in a Date, plus one).
var x = _.chain(apps).sortBy(function(x) {
var date = new Date(x.date_created).getTime();
return x.status ? date : date - 8640000000000001;
}).last().value();
console.log( x );

How to create array of object in angularjs or javascript

I have below array and I want to create another array of array. below is my array
$scope.data2 =
[
{"dt":"07 Jul 2015","avgdelay":"10","code_sent_time":"07 Jul 2015 12:30 PM","reply_received_time":"07 Jul 2015 12:40 PM","time_diff":10},
{"dt":"07 Jul 2015","avgdelay":"10","code_sent_time":"07 Jul 2015 02:10 AM","reply_received_time":"07 Jul 2015 02:30 AM","time_diff":20 },
{"dt":"07 Jul 2015","avgdelay":"10","code_sent_time":"07 Jul 2015 03:10 AM","reply_received_time":"07 Jul 2015 03:15 AM","time_diff":5 },
{"dt":"07 Jul 2015","avgdelay":"10","code_sent_time":"07 Jul 2015 04:45 AM","reply_received_time":"07 Jul 2015 05:00 AM","time_diff":15 },
{"dt":"08 Jul 2015","avgdelay":"20","code_sent_time":"08 Jul 2015 12:30 PM","reply_received_time":"08 Jul 2015 12:40 PM","time_diff":35},
{"dt":"08 Jul 2015","avgdelay":"20","code_sent_time":"08 Jul 2015 02:10 AM","reply_received_time":"08 Jul 2015 02:30 AM","time_diff":42 },
{"dt":"08 Jul 2015","avgdelay":"20","code_sent_time":"08 Jul 2015 03:10 AM","reply_received_time":"08 Jul 2015 03:15 AM","time_diff":5 },
{"dt":"08 Jul 2015","avgdelay":"20","code_sent_time":"08 Jul 2015 04:45 AM","reply_received_time":"08 Jul 2015 05:00 AM","time_diff":5 },
{"dt":"09 Jul 2015","avgdelay":"30","code_sent_time":"09 Jul 2015 12:30 PM","reply_received_time":"09 Jul 2015 12:40 PM","time_diff":1},
{"dt":"09 Jul 2015","avgdelay":"30","code_sent_time":"09 Jul 2015 02:10 AM","reply_received_time":"09 Jul 2015 02:30 AM","time_diff":28},
{"dt":"09 Jul 2015","avgdelay":"30","code_sent_time":"09 Jul 2015 03:10 AM","reply_received_time":"09 Jul 2015 03:15 AM","time_diff":12},
{"dt":"09 Jul 2015","avgdelay":"30","code_sent_time":"09 Jul 2015 04:45 AM","reply_received_time":"09 Jul 2015 05:00 AM","time_diff":17},
{"dt":"10 Jul 2015","avgdelay":"10","code_sent_time":"10 Jul 2015 12:30 PM","reply_received_time":"10 Jul 2015 12:40 PM","time_diff":19},
{"dt":"10 Jul 2015","avgdelay":"10","code_sent_time":"10 Jul 2015 02:10 AM","reply_received_time":"10 Jul 2015 02:30 AM","time_diff":21},
{"dt":"10 Jul 2015","avgdelay":"10","code_sent_time":"10 Jul 2015 03:10 AM","reply_received_time":"10 Jul 2015 03:15 AM","time_diff":15},
{"dt":"10 Jul 2015","avgdelay":"10","code_sent_time":"10 Jul 2015 04:45 AM","reply_received_time":"10 Jul 2015 05:00 AM","time_diff":15},
{"dt":"11 Jul 2015","avgdelay":"10", "code_sent_time":"11 Jul 2015 12:30 PM","reply_received_time":"11 Jul 2015 12:40 PM","time_diff":39},
{"dt":"11 Jul 2015","avgdelay":"10", "code_sent_time":"11 Jul 2015 02:10 AM","reply_received_time":"11 Jul 2015 02:30 AM","time_diff":7},
{"dt":"11 Jul 2015","avgdelay":"10", "code_sent_time":"11 Jul 2015 03:10 AM","reply_received_time":"11 Jul 2015 03:15 AM","time_diff":9},
{"dt":"11 Jul 2015","avgdelay":"10", "code_sent_time":"11 Jul 2015 04:45 AM","reply_received_time":"11 Jul 2015 05:00 AM","time_diff":22},
{"dt":"12 Jul 2015","avgdelay":"10","code_sent_time":"12 Jul 2015 12:30 PM","reply_received_time":"12 Jul 2015 12:40 PM","time_diff":32},
{"dt":"12 Jul 2015","avgdelay":"10","code_sent_time":"12 Jul 2015 02:10 AM","reply_received_time":"12 Jul 2015 02:30 AM","time_diff":11},
{"dt":"12 Jul 2015","avgdelay":"10","code_sent_time":"12 Jul 2015 03:10 AM","reply_received_time":"12 Jul 2015 03:15 AM","time_diff":52},
{"dt":"12 Jul 2015","avgdelay":"10","code_sent_time":"12 Jul 2015 04:45 AM","reply_received_time":"12 Jul 2015 05:00 AM","time_diff":37}
];
My resultant array would be like,
$scope.resarray = [
{"dt":"07 Jul 2015","avgdelay":"10","data" :
[
{"code_sent_time":"07 Jul 2015 12:30 PM","reply_received_time":"07 Jul 2015 12:40 PM","time_diff":10},
{"code_sent_time":"07 Jul 2015 02:10 AM","reply_received_time":"07 Jul 2015 02:30 AM","time_diff":20 },
{"code_sent_time":"07 Jul 2015 03:10 AM","reply_received_time":"07 Jul 2015 03:15 AM","time_diff":5 },
{"code_sent_time":"07 Jul 2015 04:45 AM","reply_received_time":"07 Jul 2015 05:00 AM","time_diff":15 }
]
},
{"dt":"08 Jul 2015","avgdelay":"20","data":
[
{"code_sent_time":"08 Jul 2015 12:30 PM","reply_received_time":"08 Jul 2015 12:40 PM","time_diff":35},
{"code_sent_time":"08 Jul 2015 02:10 AM","reply_received_time":"08 Jul 2015 02:30 AM","time_diff":42 },
{"code_sent_time":"08 Jul 2015 03:10 AM","reply_received_time":"08 Jul 2015 03:15 AM","time_diff":5 },
{"code_sent_time":"08 Jul 2015 04:45 AM","reply_received_time":"08 Jul 2015 05:00 AM","time_diff":5 }
]
},
{"dt":"09 Jul 2015","avgdelay":"30","data":
[
{"code_sent_time":"09 Jul 2015 12:30 PM","reply_received_time":"09 Jul 2015 12:40 PM","time_diff":1},
{"code_sent_time":"09 Jul 2015 02:10 AM","reply_received_time":"09 Jul 2015 02:30 AM","time_diff":28},
{"code_sent_time":"09 Jul 2015 03:10 AM","reply_received_time":"09 Jul 2015 03:15 AM","time_diff":12},
{"code_sent_time":"09 Jul 2015 04:45 AM","reply_received_time":"09 Jul 2015 05:00 AM","time_diff":17},
]
}
];
Every date have 4 rows and I want to generate the array where every date have another array having all 4 details for that date.
I tried with various options but not successded. Kindly help me to solve this.
Below Is what I have tried,
$scope.genarr = function()
{
var data2length = $scope.data2.length;
var firstdate = $scope.data2[0].dt;
var sourcecheckdate = firstdate.split(' ');
$scope.resarray = {};
var dtcheckflag = false;
var insertrow = null;
var j = 0;
var k = 0;
var z = 1;
var data=[];
for (var i=0;i< data2length;i++)
{
var targetcheckdate = $scope.data2[i].code_sent_time.split(' ');
if (targetcheckdate[0] === sourcecheckdate[0] && targetcheckdate[1] === sourcecheckdate[1] && targetcheckdate[2] === sourcecheckdate[2])
{
firstdate = $scope.data2[i].dt;
sourcecheckdate = firstdate.split(' ');
}
else
{
firstdate = $scope.data2[i].dt;
sourcecheckdate = firstdate.split(' ');
}
if (insertrow != firstdate)
{
k = 0;
$scope.resarray[j] = {"dt":$scope.data2[i].dt,"avgdelay":$scope.data2[i].avgdelay,"data":[]};
//$scope.resarray[j].data[k] = null;
$scope.resarray[j].data[k]= {"code_sent_time":$scope.data2[i].code_sent_time , "reply_received_time" :$scope.data2[i].reply_received_time , "time_diff" : $scope.data2[i].time_diff};
insertrow = firstdate;
j+=1;
}
else
{
$scope.resarray[j].data[k]= {"code_sent_time":$scope.data2[i].code_sent_time , "reply_received_time" :$scope.data2[i].reply_received_time , "time_diff" : $scope.data2[i].time_diff};
}
k +=1;
}
};

Please check this : http://plnkr.co/edit/BOYqNcdpi8uGKRraDAw1?p=preview
Controller:
$scope.data = []; //New formated array of data
for(var k = 0; k < $scope.data2.length; k++) {
var arrayData = {}; //Temporary object
arrayData.dt = $scope.data2[k].dt;
arrayData.avgdelay = $scope.data2[k].avgdelay;
arrayData.data = [];
for(var j = 0; j<4; j++,k++) {
if (arrayData.dt == $scope.data2[k].dt) {
var tempObj = {'code_sent_time': $scope.data2[k].code_sent_time,
'reply_received_time':$scope.data2[k].reply_received_time,
'time_diff':$scope.data2[k].time_diff
};
arrayData.data.push(tempObj);
}
}
$scope.data.push(arrayData);
}

the data field is currently an object, but it needs to be an array.
{"dt":"07 Jul 2015","avgdelay":"10","data" :
{
{"code_sent_time":"07 Jul 2015 12:30 PM"},
{"code_sent_time":"07 Jul 2015 02:10 AM"},
{"code_sent_time":"07 Jul 2015 03:10 AM"},
{"code_sent_time":"07 Jul 2015 04:45 AM"}
}
},
should be
{"dt":"07 Jul 2015","avgdelay":"10","data" :
[
{"code_sent_time":"07 Jul 2015 12:30 PM"},
{"code_sent_time":"07 Jul 2015 02:10 AM"},
{"code_sent_time":"07 Jul 2015 03:10 AM"},
{"code_sent_time":"07 Jul 2015 04:45 AM"}
]
},
{} creates and object, [] creates and array

var newData = [];
var dateDict = {};
angular.forEach(data2,function(d){
var temp = {};
if(dateDict[d.dt]){
dateDict[d.dt].push(d);
}
else{
dateDict[d.dt] = [];
dateDict[d.dt].push(d);
}
});
angular.forEach(dateDict,function(val,key){
var obj = {
"dt":key,
"avgdelay":val[0].avgdelay,
"data": val
};
newData.push(obj);
});
I think this will solve your problem. data2 is old data, newData is the one that you want.

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