I'm trying to do a GreaseMonkey script and i'm stucked on a REGEX to get the ID of an article in URL.
I have URL like https://www.blabla.com/poney-2000-poneys-dance-bla,272317
And i want to use the ID at the end after the Comma : 272317
I tried this REGEX : (,([\d]+)) to avoid taking digit in the rest of the URL and it get me ,272317 but I want it without the comma at the begining.
Do you have an idea how i can improve my REGEX ?
Thanks a lot :)
Just need to remove that outer paran since you don't want to capture the ,
,(\d+)$
An alternative approach without regex:
var url = 'https://www.blabla.com/poney-2000-poneys-dance-bla,272317';
url.substring(url.lastIndexOf(',') + 1);
The regex would be (\d+)$ to lookup the digits in the end but it doesn't consider the comma.
Try this: (?!,)([0-9]+){5}, it should be fine as long as the id is greater than 5
Related
I tried a lot to replace the query parammeter using Javascript. But its not working. Can you please share any solutions to replace the parameter
Below is the example
console.log("www.test.com?x=a".replace(new RegExp(`${"x=a"}&?`),''));
the output i am getting is www.test.com? . Is there any way to replace ? and to get only www.test.com.
If you want to remove whatever comes from the question mark including it, try this instead:
console.log("www.test.com?x=a".split("?")[0]);
That way you get only what's before the question mark.
I hope that helps you out.
You can remove all query strings using the following regex:
\?(.*)
const url = "www.test.com?x=1&b=2"
console.log(url.replace(/\?(.*)/, ''));
You could brutally replace the '?x=a' string with the JavaScript replace function or, even better, you could split the string in two (based on the index of ?) with the JavaScript split function and take the first part, e.g.:
let str = 'www.test.com?x=a';
console.log(str.replace('?x=a', ''));
console.log(str.split('?')[0]);
I have the following code which replaces the current URL using JavaScript:
window.location.replace(window.location.href.replace(/\/?$/, '#/view-0'));
However if I have a URL like:
domain.com/#/test or domain.com/#/
It will append the #/view-0 to the current hash. What I want to is replace EVERYTHING after the last part of the URL including any query strings or hashes.
So presume my regex doesn't handle that... How can I amend it, to be more aggressive?
The following syntax may help:
location.href.replace(/[?#].*$/, '#/view')
It will replace everything after (and together with) ? or # in the string with #/view.
(^[^\/]*?\/)(?:.*)
Use this.Replace by \1 then your string
See demo.
http://regex101.com/r/sA7pZ0/28
I am trying to some some urls throught javascript where some replacement of urls needs to be done. I have a textarea with some URLs example given below:
http://mywebsite.com/preview.aspx?mode=desktop&url=http://mywebsite.com/post.aspx?id=44&content=1
http://mywebsite.com/preview.aspx?mode=desktop&url=http://mywebsite.com/post.aspx?id=44&content=2
http://mywebsite.com/preview.aspx?mode=desktop&url=http://mywebsite.com/post.aspx?id=44&content=3
http://mywebsite.com/preview.aspx?mode=desktop&url=http://mywebsite.com/post.aspx?id=44&content=3
Now what i am trying to do is replacing http://mywebsite.com/preview.aspx?mode=desktop&url= with spaces.
I have tried using str.replace() but it is replacing only first occurence of that url.
I have also tried with Global variable g the query i have used is
str_replace(\http://mywebsite.com/preview.aspx?mode=desktop&url=/g,'');
But its not working So can anyone tell me how i can do that ?
I want the output of the textarea like:
http://mywebsite.com/post.aspx?id=44&content=1
http://mywebsite.com/post.aspx?id=44&content=2
http://mywebsite.com/post.aspx?id=44&content=3
http://mywebsite.com/post.aspx?id=44&content=4
I believe that your biggest issue is that your regex syntax is incorrect. Try this:
Imagine that var s is equal the the value of your textarea.
s.replace(/http\:\/\/mywebsite\.com\/preview.aspx\?mode\=desktop\&url\=/g, '');
The issue you were having was improper delimiters and unescaped reserved symbols.
Though Javascript has some of its own regex idiosyncrasies, the issues here were related to basic regex, you might find these resources useful:
http://www.cheatography.com/davechild/cheat-sheets/regular-expressions/
http://regexpal.com
try this.
var string = document.getElementById('textareaidhere');
string.replace(/http:\/\/mywebsite\.com\/preview\.aspxmode=desktop&url=/g, '');
JSFiddle here
I have this urls:
C:\Projects\Ensure_Solution\GD_EServices_Web\App_WebReferences\GD_Eservices_Web_Service\GD_Eservices_Web_Service.wsdl
C:\Projects\Ensure_Solution\GD_EServices_Web\App_WebReferences\GD_Eservices_Web_Service\GD_Eservices_Web_Service.wsdl
I want to get the wsdl file name ( no leading slash)
I have succeeded with 2 solutions :
\\[^\\]+$
\\(.(?!\\))+$
But this returns the leading slash : http://regexr.com?32lvi
how can I enhance my regex return only the file ?
You just need to exclude the the leading slash in the regex.
var path = 'C:\\Projects\\Ensure_Solution\\GD_EServices_Web\\App_WebReferences\\GD_Eservices_Web_Service\\GD_Eservices_Web_Service.wsdl';
console.log(path.match(/[^\\]+$/));
And you could get it without regex, use split, and get the last element with pop:
console.log(path.split('\\').pop());
This should work [^\\]+$
But for your case I'd prefer smth like string.split('/').pop() (javascript) or array_pop(split('/', string)) (for php, I don't know language you are using) not regexp.
Try with the negative look-ahead (?!\\)(.(?!\\))+$
This should do it:
([\w\d_-]*)\.?[^\\\/]*$
This thread has some examples for javascript.
Alternatively, you can so a string split on "\" to create an array and get the last one in the array.
Try this
\\[^\\]+$
Note:that means try with only one leading backslash
If I am correct, the following code will only match a URL that is exactly as presented.
However, what would it look like if you wanted to identify subdomains as well as urls that contain various different query strings - in other words, any address that contains this domain:
var url = /test.com/
if (window.location.href.match(url)){
alert("match!");
}
If you want this regex to match "test.com" you need to escape the "." and both of the "/" that means any character in regex syntax.
Escaped : \/test\.com\/
Take a look for here for more info
No, your pattern will actually match on all strings containing test.com.
The regular expresssion /test.com/ says to match for test[ANY CHARACTER]com anywhere in the string
Better to use example.com for example links. So I replaces test with example.
Some example matches could be
http://example.com
http://examplexcom.xyz
http://example!com.xyz
http://example.com?q=123
http://sub.example.com
http://fooexample.com
http://example.com/asdf/123
http://stackoverflow.com/?site=example.com
I think you need to use /g. /g enables "global" matching. When using the replace() method, specify this modifier to replace all matches, rather than only the first one:
var /test.com/g;
If you want to test if an URL is valid this is the one I use. Fairly complex, because it takes care also of numeric domain & a few other peculiarities :
var urlMatcher = /(([\w]+:)?\/\/)?(([\d\w]|%[a-fA-f\d]{2,2})+(:([\d\w]|%[a-fA-f\d]{2,2})+)?#)?([\d\w][-\d\w]{0,253}[\d\w]\.)+[\w]{2,4}(:[\d]+)?(\/([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)*(\?(&?([-+_~.\d\w]|%[a-fA-f\d]{2,2})=?)*)?(#([-+_~.\d\w]|%[a-fA-f\d]{2,2})*)?/;
Takes care of parameters and anchors etc... dont ask me to explain the details pls.