We Keep Coding

Javascript replace on multiple Japanese character

I want to replace this
"】|"
character from string with this"】".
mystring is ="【権利確定月】|1月"
and desired output is
"【権利確定月】1月".
I have tried with array operation and also with this code:
mystring.replace(/】|/g, '】')
but not working.
I only want to this with sequence for"】|".
Because after that string will grow like this
example:
"【権利確定月】1月|other|other|【other】other|other|other".
I have tried many other solution provided on stack overflow but all regex contain single character I want for above sequence character.

You need to escape the | because it has a special meaning within regex. 】| equates to 】 or (an empty string) so the result is that it replaces 】 with itself and inserts 】 between all the other characters in the string.
var mystring ="【権利確定月】|1月"
var myModifiedString = mystring.replace(/】\|/g, '】');
console.log(myModifiedString);

You need to escape the logical OR operator as it is a metacharacter in RegEx.
var x = "【権利確定月】|1月".replace(/】\|/g, '】');
console.log(x);

You can define the strings that need to be replaced in separate variables. Following worked for me.
var x = "】|";
var y = "】";
var word = "【権利確定月】|1月";
word.replace(x, y)

You can split your string by 】| and join by 】. Or (as was answered before me) escape | in regex.
const string = '【権利確】|】|定月】|1月';
let splitAndJoin = string.split('】|').join('】');
let replaceRegex = string.replace(/】\|/g, '】');
console.log(splitAndJoin);
console.log(replaceRegex);

Get replaced characters with javascript regex replace

I am currently replacing all non-letter characters using
var stringwithoutspecialCharacter = "testwordwithpunctiuation.".replace(/[^\w\s!?]/g, '');
The problem is that I do not know which special character will appear (that needs removing). However I do need to be able to access the removed special character after I've run some code with the word without the special character.
Example inputs:
"test".
(temporary)
foo,
Desired output:
['"','test','"',"."]
['(','temporary',')']
['foo',',']
How could this be achieved in javascript?

Edit: To get both valid and invalid characters, change the regular expression
Quick solution is to define an array to collect the matches.
Then pass in a function into your replace() call
var matches = [];
var matcher = function(match, offset, string) {
matches.push(match);
return '';
}
var stringwithoutspecialCharacter = "testwordwithpunctiuation.".replace(/[^\w\s!?]|[\w\s!?]+/g, matcher);
console.log("Matches: " + matches);

How to remove the special characters from a string using javascript

I have the below String value to be displayed in text area and i want to remove the first characters ##*n|n from the string .
The string is as follows :
Symbol-001
##*n|nClaimant Name
##*n|nTransaction
I have used the below code to deal with removing the special characters
var paramVal1 = parent.noteText; //paramVal1 will have the string now
var pattern = /[##*n|n]/g;
var paramVal1 = paramVal1.replace(pattern,'');
document.getElementById("txtNoteArea").value = paramval1;//appending the refined string to text area
For the above used code am getting the out put string as below
Symbol-001
|Claimat Name //here 'n' is missing and i have an extra '|' character
|Transactio //'n' is missing here too and an extra '|' character
Kindly help to remove the characters ##*n|n without affecting the other values

What your regex is saying is "remove any of the following characters: #|*n". Clearly this isn't what you want!
Try this instead: /##\*n\|n/g
This says "remove the literal string ##*n|n". The backslashes remove the special meaning from * and |.

You are using regular expression reserved chars in your pattern, you need to escape them
You can use this expression:
var pattern = /[\#\#\*n\|n]/g;

i think use this /[##*n\|n]/g regEx

If you want to replace the first occurrence as you say on your question, you don't need to use regex. A simple string will do, as long as you escape the asterisk:
var str = "Symbol-001 ##*n|nClaimant Name ##*n|nTransaction";
var str2 = str.replace("##\*n|n", ""); //output: "Symbol-001 Claimant Name ##*n|nTransaction"
If you want to replace all the occurrences, you can use regex, escaping all the characters that have a special meaning:
var str3 = str.replace(/\#\#\*n\|n/g, ""); //output: "Symbol-001 Claimant Name Transaction"
Have a look at this regex builder, might come in handy - http://gskinner.com/RegExr/

Replace single backslash "\" with double backslashes "\\"

I have string with file path. I want to replace all single backslashes ("\") with double backslashes ("\\").
var replaceableString = "c:\asd\flkj\klsd\ffjkl";
var part = /#"\\"/g;
var filePath = replaceableString .replace(part, /#"\\"/);
console.log(filePath);
Console showed me it.
c:asdlkjklsdfjkl
I found something like this, unfortunately it didn't work.
Replacing \ with \\

Try:
var parts = replaceableString.split('\\');
var output = parts.join('\\\\');
Personally, as I am not so expert in reg exps, I tend to avoid them when dealing with non-alphanumeric characters, both due to readability and to avoid weird mistake.

var replaceableString = "c:\asd\flkj\klsd\ffjkl";
alert(replaceableString);
This will alert you c:asdlkjklsdfjkl because '\' is an escape character which will not be considered.
To have a backslash in your string , you should do something like this..
var replaceableString = "c:\\asd\\flkj\\klsd\\ffjkl";
alert(replaceableString);
This will alert you c:\asd\flkj\klsd\ffjkl
JS Fiddle
Learn about Escape sequences here
If you want your string to have '\' by default , you should escape it .. Use escape() function
var replaceableString = escape("c:\asd\flkj\klsd\ffjkl");
alert(replaceableString);
JS Fiddle

You have several problems in your code.
To get a \ in your string variable you need to escape it.
When you create a string like this: replaceableString = "c:\asd\flkj\klsd\ffjkl"; characters with a \ before are treated as escape sequences. So during the string creation, it tries to interpret the escape sequence \a, since this is not valid it stores the a to the string. E.g. \n would have been interpreted as newline.
I assume the # is coming from a .net example. Javascript does not know "raw" strings.
remove the quotes from your regex.
This would do what you want:
var string = "c:\\asd\\flkj\\klsd\\ffjkl";
var regex = /\\/g;
var FilePath = string.replace(regex, "\\\\");

Here is the answer:
For replacing single backslash with single forward slash:
var stringReplaced = String.raw`c:\asd\flkj\klsd\ffjkl`.split('\\').join('/')
console.log(stringReplaced);
For replacing double backslash with single forward slash:
var stringReplaced = String.raw`c:\\asd\\flkj\\klsd\\ffjkl`.split('\\\\').join('/')
console.log(stringReplaced);

\ is a escape character. Therefore replaceableString does not contain any backslashes.
To fix this you should declare the string like this:
var replaceableString = "c:\\asd\\flkj\\klsd\\ffjkl";

First encode the string
then replace all occurrences of %5C with %5C%5C
At the end decode the string
var result = encodeURI(input);
result=decodeURI(result.replace(/%5C/g,"%5C%5C"));

If you have no control over the contents of the string you are trying to find backslashes in, and it contains SINGLE \ values (eg. variable myPath contains C:\Some\Folder\file.jpg), then you can actually reference the single backslashes in JavaScript as String.fromCharCode(92).
So to get the file name in my filepath example above.
var justTheName = myPath.split(String.fromCharCode(92)).pop();

In case of string matching, it is better to use encodeURIComponent, decodeURIComponent.
match(encodeURIComponent(inputString));
function match(input)
{
for(i=0; i<arr.length; i++)
{
if(arr[i] == decodeURIComponent(input))
return true;
else return false;
}
}

In the case of a single back slash in the string, the javascript replace method did not allow me to replace the single back slash.
Instead I had to use the split method which returns an array of the split strings and then concatenate the strings without the back slash (or whatever you want to replace it with)
Solution (replaced backslash with underscore):
var splitText = stringWithBackslash.split('\\');
var updatedText = splitText[0] + '_' + splitText[1];

You need to pass to pass value of a string through String.raw before you assign value to a variable.
var replaceableString = String.raw`c:\asd\flkj\klsd\ffjkl`.replace(/\\/g,"\\\\");
console.log(replaceableString)

I have a string and want to remove special chars in its specific part using javascript

I have a string looks like:
var myString= '{"key1":"value1", "key2":"value2", "key3":"value3"}';
What I want is to remove double qoutes and other special chars only from value3 ... for example some times we have string looks like:
var myString= '{"key1":"value1", "key2":"value2", "key3":"This is "value" with some special chars etc"}';
Please note I do not want to remove double quotes after colon and before This and similarly I do not want to remove last double quotes. I just want to modify string so it will become:
var myString = '{"key1":"value1", "key2":"value2", "key3":"This is value with some special chars etc"}';

Simple...
var myNewString = eval( '('+ myString +')');
var toBeEscaped = myNewString.key3;
var escapedString = doYourCleanUpStuff(toBeEscaped);
myNewString.key3 = escapedString;
myNewString = JSON.stringify(myNewString);
===============
What did I do?
1) Your string looks like valid JSON.
2) Cast it into JSON object. (using eval() )
3) Retrieve value of key3 and catch it in some temp variable.
4) Do cleanup things with this temporary variable.
5) assign cleaned up temporary variable back to key3.
6) Stringify the JSON.
Don't go around beating bush with array manipulation and split functions, especially when there are simpler ways :)

You will probably want to use the Array map function in conjunction with the string replace function.
To use the replace function, you'll probably want to use regular expressions. For example, the following regular expression will remove double quotes not immediately after a colon: [^:]".
To replace every quote not immediately followed by a colon in an array of strings, you could write this:
var myString= '{"key1":"value1", "key2":"value2", "key3":"value3"}';
var modified = myString.map(function(s) { return s.replace(/[^:]"/g, ''); });
Make your own modifications to the regular expression to match the characters you want to remove.
Refer to http://www.addedbytes.com/cheat-sheets/regular-expressions-cheat-sheet/.

First thing that comes to my mind is to isolate the Value you want.
You can .Split() for the value you want
var myString = '{"key1":"value1", "key2":"value2",
"key3":"value3"}';var n=str.split(" ");
var key3Value = str.split(//Based on your value);
//Run .replace() on your key3Value to replace your doublequotes, etc.
//Re-declare myString to include the updated key3Value
Sorry, no time at the moment to finish the code, and I am sure their are better/shorter answers than mine. Just wanted to include this as an option.