Post variable croped - javascript

I am using some ajax request to access to php file. It's working perfectly exept one part. When I am getting the $_POST value of one of my variable, it crops the end of the word.
$.ajax({
type: 'post',
url: 'https://myadress.com',
data: {
workout: JSON.stringify(workout),
username: localStorage.getItem('username'),
workout_name: $('#name').val().toString(),
},
success: function (data) {
alert(data);
},
});
If i alert workout_name before sending it, it displays "test" but when i echo it from my php file, it displays "te".
I am wondering why it's doing that, i can't fix it. I was thinking maybe the size of my other variable are too big...
Here is my php code:
` if(isset($_POST['username']) && isset($_POST['workout_name']) && isset($_POST['workout'])) {
$workout_name = $_POST['workout_name'];
echo $workout_name;
$username = $_POST['username'];
$workout = json_decode($_POST['workout']);
}`
Thank you for your answer.
Edit:
Thanks to the answer, it's working now. I just need to do :
workout_name: encodeURIComponent($('#name').val())
in my js file and when I retrieve the data in the php file I use :
urldecode($_POST['workout_name']);

Related

Unable to Pass JS variable to another PHP page

I am not a technical person, but a semi technical business man and learning/creating my own website.
I want to pass JS variables (from html page) to my another Php page.
NOTE** I am getting redirect with required parameters in URL (title). Now, I want to pass another variables, but not through the URL
Here is my html page code:
$.ajax({
type: 'GET',
url: "'search_result.php' + '?title=' + dtitle",
data: { selectedFT: "hello"}
});
And my php page code:
<php>
$fueltype = $_GET['selectedFT'];
echo $fueltype;
// I will be using this variable as $fueltype in my further code.
?>
Appreciate your help. I wasted many hours to solves this through google, but nothing fits.
Please provide me sample so that I can understand easily.
Post method may help you:
$.ajax({
type: 'post',
data: {
title: dtitle,
selectedFT: "hello"
},
url: 'search_result.php'
});
In Your PHP page add:
<php>
$fueltype = $_POST['selectedFT'];
echo $fueltype;
// I will be using this variable as $fueltype in my further code.
?>
Try this solution.
let dtitle = "Hello";
$.ajax({
type: 'GET',
url: `search_result.php?title=${dtitle}`,
});
PHP file
<?php
$fueltype = $_GET['title'];
echo $fueltype;
?>

How to fix success problem while getting data from php to javascript file?

I have used before these jquery-ajax and php codes. Everything was fine but know there is a problem that success function not working. However, php codes are working, I can add data to mysql database, but I couldn't post info back to javascript file again by use "echo" or any way. Is this problem could originate because of server? I need your support.
I have checked php file is working or not and there was no problem about php. In javascript file in ajax codes, I have tried beforeSend and complete functions, everything were fine. But success function not working.
JS codes:
var userCookie = 1;
var question_txt = document.getElementById("question_txt").value;
var category_slct = document.getElementById("category_slct").value;
$.ajax({
type: "POST",
url: websitePHP + "ask.php",
data: {
user : userCookie,
quest : question_txt,
cat : category_slct
},
beforeSend: function(){
},
success: function(data){
alert(data);
if(data == 'ok'){
alert('Question added');
}
}
})
PHP codes:
include("ayar.php");
$userID = $_POST['user'];
$categoryID = $_POST['cat'];
$question_txt = $_POST['quest'];
$askedTime = time();
$addQuestion = $vt->prepare("INSERT INTO ".$QUESTIONS." (userID, categoryID, question, image, link, sight, pinned, bestAnswerID, askedTime, publishedTime, published)
VALUES (?,?,?,?,?,?,?,?,?,?,?)");
$addQuestion->execute(array(''.$userID.'',''.$categoryID.'', ''.$question_txt.'', '', '', 0, 0, '', ''.$askedTime.'', '', 0));
echo 'ok';
exit();
I need to get back response from php to js by success function in ajax.
Thanks for your help,
Best regards.
Can you try
return 'ok'; instead of echo 'ok'; and removing exit(); function

Cannot pass JS variable to PHP using AJAX

I am trying to get current location of user.
I have JS script to get current Latitude and Longitude with AJAX to send js variables to index.php.
$(document).ready(function() {
if ("geolocation" in navigator){
navigator.geolocation.getCurrentPosition(function(position){
var userLat = position.coords.latitude;
var userLong = position.coords.longitude;
console.log(userLong);
console.log(userLat);
$.ajax({
type: 'POST',
url: 'index.php',
data: {
userLat : userLat,
userLong : userLong
},
success: function(data)
{
console.log(data);
}
});
});
}else{
console.log("Browser doesn't support geolocation!");
}});
Then I am trying to do this in my index.php:
echo $_POST['userLat'];
echo $_POST['userLong'];
Nothing shows up. Thanks in advance.
Nothing shows up.
And that's correct you will never get any thing by browsing index.php because there is no POST at this time , AJAX is internal and the only way to show a result from index.php is in the page that you send from it an ajax call.
At this :
success: function(data)
{
console.log(data);
}
you could control where to show your data that comes from index.php by , for example alert(data) or document.getElementById("someelement").innerHTML=data; and so on.
It might help to define and return a dataType for the ajax.
add this to your list of ajax options
dataType: 'json',
Then in index.php encode and echo a json string. Remove the lines
echo $_POST['userLat'];
echo $_POST['userLong'];
replace them with
echo json_encode($_POST);
The console.log(data); in the success function should show an object with two items: 'userlat' and 'userLong' and associated values for each. Or it should if $_POST had those two items.
If you want the browser screen to update you will have to take data and use it to modify the DOM.

ajax - save javascript value to php

After hours of trying to get this to work, i want to ask you :)
So i have a php Page that can display files from a server. Now I can edit
the files with a editor plugin.
Textarea is the tag where the editor gets rendered.
To save the changed text from the editor, I have a button that gets the innerHTML from the surrounding pre tag of the text with javascript.
I now want to pass that variable via ajax to a php variable on the site get.php,
so I can save it locally and send it to the server.
The problem is, that there is no reaction at all, if i click the "Save" button. I tested a lot of answers from similar ajax functions here, but none of them gave me a single reaction :/
php main
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
...
echo "<textarea><pre id='textbox'> ";
echo $ssh->exec($display);
echo "</textarea></pre>";
echo '<input type="button" value="Save File" id="butt">';
echo "<script>
var show = document.getElementById('textbox').innerHTML;
$(document).ready(function() {
$('#butt').click(function() {
$.ajax({
type: 'POST',
url: 'get.php',
data: {'variable': show},
success: function(data){
alert(data);
}
});
});
});
</script>";
...
get.php
if (isset($_POST["variable"])){
$show =$_POST["variable"];
echo $show;
}
Edit:
This is the actual working state:
echo "<textarea id='textbox'><pre> ";
echo $ssh->exec($display);
echo "</pre></textarea>";
echo '<input type="button" value="Save File" id="butt">';
echo "<script>
$(document).ready(function() {
$('#butt').click(function() {
var show = document.getElementById('textbox').value;
$.ajax({
type: 'POST',
url: 'get.php',
data: {'variable': show},
success: function(data){
alert(data);
},
});
});
});
</script>";
You have an error in the data: {'variable': show)} part. It should be: data: {variable: show}. Also you should use Firebug or Firefox developer tools for these kind of problems. A lot easier to see whats wrong.
I would suggest small changes to see if everything is running as it should.
I can see that pre tag is behind textarea closing tag - try to change it
Try putting var show = document.getElementById('textbox').innerHTML; inside of the ,,butt" function
Then I can see your problem here data: {'variable': 'show')}, - you are sending 'show' as a string - remove quotes to send it as a variable which will appear as a POST value in PHP site.
with this should work:
$.ajax({
type: 'POST',
url: 'get.php',
data: {variable: show)},
success: function (data){
alert(data);

AJAX call returns undefined in Header / form-data

I am trying to get the contents from some autogenerated divs (with php) and put the contents in a php file for further processing. The reason for that is I have counters that count the number of clicks in each div. Now, I ran into a problem. When I echo back the data from the php file, the call is made, but I get undefined in the form-data section of the headers, and NULL if I do var_dump($_POST). I am almost certain I am doing something wrong with the AJAX call. I am inexperienced to say the least in AJAX or Javascript. Any ideas? The code is pasted below. Thanks for any help / ideas.
The AJAX:
$(document).ready(function(e) {
$("form[ajax=true]").submit(function(e) {
e.preventDefault();
var form_data = $(this).find(".test");
var form_url = $(this).attr("action");
var form_method = $(this).attr("method").toUpperCase();
$.ajax({
url: form_url,
type: form_method,
data: form_data,
cache: false,
success: function(returnhtml){
$("#resultcart").html(returnhtml);
}
});
});
});
The PHP is a simple echo. Please advise.
Suppose you have a div
<div id="send_me">
<div class="sub-item">Hello, please send me via ajax</div>
<span class="sub-item">Hello, please send me also via ajax</span>
</div>
Make AJAX request like
$.ajax({
url: 'get_sorted_content.php',
type: 'POST', // GET is default
data: {
yourData: $('#send_me').html()
// in PHP, use $_POST['yourData']
},
success: function(msg) {
alert('Data returned from PHP: ' + msg);
},
error: function(msg) {
alert('AJAX request failed!' + msg);
}
});
Now in PHP, you can access this data passed in the following manner
<?php
// get_sorted_content.php
if(!empty($_POST['yourdata']))
echo 'data received!';
else
echo 'no data received!';
?>
It's sorted. Thanks to everyone. The problem was I didn't respect the pattern parent -> child of the divs. All I needed to do was to wrap everything in another div. I really didn't know this was happening because I was echoing HTML code from PHP.

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