We Keep Coding

how to get varaiable if only have more than 3 letters javascript

var result="stackoverflow";
var string="22342st";
if(more than 3 letters)
{
var new=data;
}
1)how I can get variable if only have more than
using match() (function ) in javascript
2)what if I do getting variable in for time delay
some (because of TCP connection)
Does anyone have an idea?

you can use .length property to check string length is greater than 3 or not.
var result = "stackoverflow";
if(result.length > 3)
{
//Your business logic goes here
}
if you want to check only character counts in string is greater than three then you can try below code
var input = "45749ce";
var result = input.match(/[a-zA-Z]/gi);
if(result.length > 3)
{
//Your business logic goes here
console.log(`${result} length is greater than 3`);
}

That should work
var myRegEx = /[a-zA-Z(.+)]{3}/g;
var myString="22342st";
if(myString.match(myRegEx)!==null)
{
}
Also
myString.match(myRegEx)
will return an array of matched values, so you can work with them if needed.

To find the more than three letter in variable using match you have to need regex
([a-zA-Z0-9)]){3,}
code how looks like
var result="stackoverflow";
var string="22342st";
var res = string.match(/([a-zA-Z0-9)]){3,}/g);
if(res!=null){
//here what you want
}

Why method setValue doesn't output same as Browser.msgBox?

Since I could not make .toFixed(2) to work I designed my own piece of code to add desired decimal digits after the "." by simple joining two strings with + sign.
While Browser.msgBox outputs the 2 strings joined correctly as "1.00",
it seems like getRange.setValue outputs only the first of the 2 strings as "1" :(
function myFunction() {
var ss_calc = SpreadsheetApp.openById("1cFt0DbnpWGHquKk4ijxdKhwkaF8GhumWDWjTpHuSXbQ");
var sheet_calc = ss_calc.getSheetByName("Calcs");
var ss_source = SpreadsheetApp.openById("1gXeXmiw9EnzQXaiE7H8_zrilE2zyotlSuuIS8X9IxfQ");
var sheet_source = ss_source.getSheetByName("Farmah");
var decDig = ""; var strDec = ""; var impVal = "";
impVal = sheet_source.getRange(12,7).getValue().toString();
if (JSON.stringify(impVal).indexOf(".")>-1)
{ if (JSON.stringify(impVal).split(".")[1].length < 2 )
{
if (JSON.stringify(impVal).split(".")[1].length < 1)
{
decDig = "00";
}
else
{
decDig = "0";
}
}
}
else
{
decDig = ".00";
}
var strDec = impVal.toString() + decDig.toString();
Browser.msgBox(JSON.stringify(impVal).indexOf(".")+ "\\n" +
impVal.toString()+ "\\n" +
decDig+ "\\n" +
strDec);
sheet_calc.getRange(1,1).setValue(strDec);
}
From sheet_calc.getRange(1,1).setValue(strDec); I am expecting to get output "1.00" but I get only "1" :(
What am I missing?
Here are the links to google spreadsheets ( anyone with the link can edit :)
(above code has to be triggered manually by script editor in the first spreadsheet here under):
https://docs.google.com/spreadsheets/d/1cFt0DbnpWGHquKk4ijxdKhwkaF8GhumWDWjTpHuSXbQ/edit?usp=sharing
https://docs.google.com/spreadsheets/d/1gXeXmiw9EnzQXaiE7H8_zrilE2zyotlSuuIS8X9IxfQ/edit?usp=sharing

You want to put the value of 1.00 to a cell "A1".
If my understanding is correct, how about this modification? I think that the reason of your issue is that the value by putting by setValue() is converted to the number. By this, 1 is shown. In order to put the value as 1.00, I think that there are 3 patterns. Please select one of them for your situation.
Pattern 1:
In this pattern, from your question, the value is put as a string using setNumberFormat("#").
From:
sheet_calc.getRange(1,1).setValue(strDec);
To:
sheet_calc.getRange(1,1).setNumberFormat("#").setValue(strDec);
Pattern 2:
In this pattern, from your question, the format of cell is set using setNumberFormat("0.00").
From:
sheet_calc.getRange(1,1).setValue(strDec);
To:
sheet_calc.getRange(1,1).setNumberFormat("0.00").setValue(strDec);
Pattern 3:
In this pattern, from the script of your shared Spreadsheet, When decDig is ".00", the format is set.
From:
sheet_calc.getRange(x+6,c).setValue(strDec);
To:
var range = sheet_calc.getRange(x+6,c);
if (decDig) {
range.setNumberFormat("0.00").setValue(strDec); // or setNumberFormat("#")
} else {
range.setValue(strDec);
}
Reference:
setNumberFormat(numberFormat)
If I misunderstood your question and this was not the result you want, I apologize.

From sheet_calc.getRange(1,1).setValue(strDec); I am expecting to get output "1.00" but I get only "1" :(
Google Sheets, as well as other spreadsheet apps, have an automatic data type assignation, so things that look as numbers are converted to Google Sheets number data type, etc.
You could prepend an ' to force that a value be treated as text or you could set the number format in such way that numbers are displayed with two decimals. The cell formatting could be applied in advance, i.e., by using the Google Sheets UI commands or you could use Apps Script to set the format for you.

Javascript Math.log() help wanted

World!
I'm trying to create a program in Javascript that takes the log of a number typed into an HTML input. Unfortunately i've encountered a problem where it wont accept the string with the .replace().
Its Function:
I.E: When log(10) is calculated, the function should first remove the first 4 char's "log(" next remove the last parenthesis ")" and then take the log of the no. between.
HTML includes style elements, button and input form and an output < DIV >.
//Function
function calculate()
{
var inputString = document.getElementById("inpstr");
var output = document.getElementById("output");
//TESTING CODE
/*
if (inputString.value.startsWith("log(").endsWith(")"))
{
console.log(output.innerHTML = inputString.value.substring(4, 20).replace(")", ""));
}
else
{
output.innerHTML = "false";
}
*/
//Math.log() calc *****DOESNT WORK*****
if (inputString.value.startsWith("log(").endsWith(")"))
{
output.innerHTML = Math.log(inputString.value.replace(")", "").substring(4, 20));
}
else
{
output.innerHTML = inputString.value;
}
event.preventDefault();
}
If someone can give me an effective solution that would be much appreciated.
Thanks,
Syntax

Since Math.log() accepts only number values and you're trying to pass a string to it, you should first parse this value into a float number and then pass it to the log function:
let val = parseFloat(inputString.value.replace(")", "").substring(4, 20));
output.innerHTML = Math.log(val);

I'm guessing I got downvoted for being lazy, so here is the quick info. Gonras got it right relating to what you want to extract, but he forgot to check that what's being input is actually a log.
That's where the regex below comes in handy! I'm matching the field to:
^ start of word, since we want to match the entire field.
log(
([-.\d])) any consecutive sequence () of numbers (\d), -, and '.', represented by the []. The \(...\) makes sure to save this inner part for later.
$ is end of word, see 1.
res will be null if there is no match. Otherwise, res[0] is the entire match (so the entire input field) and res[1] is the first 'capture group', at point 3 - which is presumably the number.
This of course fails for multiple "-" inside, or "." etc... so think it over.
//Function
function calculate()
{
var inputString = document.getElementById("inpstr");
var output = document.getElementById("output");
var res = /^log\(([-.\d]*)\)$/.exec(inputString.value);
if (res)
output.innerHTML = Math.log(res[1]);
else
output.innerHTML = res;
}
document.getElementById("output").innerHTML='start';
calculate()
<div id='output'></div>
<input id='inpstr' value='log(2.71828)'></input>
If I wanted to fix your if to supplement Gonras's solution:
if (inputString.value.startsWith("log(") && inputString.value.endsWith(")"))
Yours fails since startsWith() returns a boolean, which obviously doesn't have a endsWith function.

Need to get indexes from array and output them to user in JavaScript

We're displaying five input fields to user. He can type some information in them. After that, we need to find out if his input is correct. For that purpose we use an array of possible correct values.
Like:
var input = document.getElementById("input").value;
input = input.toLowerCase();
inputPos = possibleInputs.indexOf(input);
inputPosArray.push(inputPos);
The code for analysis looks like that for now:
function arrayLookup() {
var inputCorrect = true;
inputPosArray.forEach(function(item, i, inputPosArray) {
if (inputPosArray[i] == -1) {
wrongInput = cardRPos.indexOf(cardRPos[i]) + 1;
wrongInputsArray.push(wrongInput);
inputCorrect = false;
} else {
null;
}
});
if (inputCorrect == false) {
alert("Wrong input! Check field " + wrongInputsArray);
} else {
nextStep();
}}
For now it correctly finds out if input is wrong and alerts user.
The problem is in "wrongInputsArray" - it doesn't display output correctly. E.g. if user has typed wrong information in 2nd field, it will print out "2".
But if he has made mistakes in 2nd and 5th field, he gets "Wrong input! Check field 2,2" alert.
Please show me what am I doing wrong.
Kindly yours,
Richard

You are using this code to insert the wrong asnwers:
wrongInput = cardRPos.indexOf(cardRPos[i]) + 1;
If two questions has the same answer, indexOf will return always the first match. Try just using this:
wrongInput = i + 1;

ExtJS 4.1.1: Evaluating a field in a grid

I'm struggling with a ExtJS 4.1.1 grid that has editable cells (CellEditing plugin).
A person should be able to type a mathematic formula into the cell and it should generate the result into the field's value. For example: If a user types (320*10)/4 the return should be 800. Or similar if the user types (320m*10cm)/4 the function should strip the non-mathematical characters from the formula and then calculate it.
I was looking to replace (or match) with a RegExp, but I cannot seem to get it to work. It keeps returning NaN and when I do console.log(e.value); it returns only the originalValue and not the value that I need.
I don't have much code to attach:
onGridValidateEdit : function(editor,e,opts) {
var str = e.value.toString();
console.log(str);
var strCalc = str.match(/0-9+-*\/()/g);
console.log(strCalc);
var numCalc = Number(eval(strCalc));
console.log(numCalc);
return numCalc;
},
Which returns: str=321 strCalc=null numCalc=0 when I type 321*2.
Any help appreciated,
GR.
Update:
Based on input by Paul Schroeder, I created this:
onGridValidateEdit : function(editor,e,opts) {
var str = e.record.get(e.field).toString();
var strCalc = str.replace(/[^0-9+*-/()]/g, "");
var numCalc = Number(eval(strCalc));
console.log(typeof numCalc);
console.log(numCalc);
return numCalc;
},
Which calculates the number, but I am unable to print it back to the grid itself. It shows up as "NaN" even though in console it shows typeof=number and value=800.
Final code:
Here's the final code that worked:
onGridValidateEdit : function(editor,e,opts) {
var fldName = e.field;
var str = e.record.get(fldName).toString();
var strCalc = str.replace(/[^0-9+*-/()]/g, "");
var numCalc = Number(eval(strCalc));
e.record.set(fldName,numCalc);
},

Lets break this code down.
onGridValidateEdit : function(editor,e,opts) {
var str = e.value.toString();
What listener is this code being used in? This is very important for us to know, here's how I set up my listeners in the plugin:
listeners: {
edit: function(editor, e){
var record = e.record;
var str = record.get("your data_index of the value");
}
}
Setting it up this way works for me, So lets move on to:
var strCalc = str.match(/0-9+-*\/()/g);
console.log(strCalc);
at which point strCalc=null, this is also correct. str.match returns null because your regex does not match anything in the string. What I think you want to do instead is this:
var strCalc = str.replace(/[^0-9+*-]/g, "");
console.log(strCalc);
This changes it to replace all characters in the string that aren't your equation operators and numbers. After that I think it should work for whole numbers. I think that you may actually want decimal numbers too, but I can't think of the regex for that off the top of my head (the . needs to be escaped somehow), but it should be simple enough to find in a google search.