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update echo "select option " on mysql

I have a form that updates the adds to the table. This table is retrieved live. which means once submitting the form you can view the content on the table. I added a select option drop down on the table content. I am not sure how to get this info in back to mysql once the user chooses his option. As seen in the code my file is a PHP file.
my select option is updates by javascript but it does not update mysql.
Kindly guide me. Thank you
while($row = mysqli_fetch_assoc($resultset))
{
echo "<tr id=\"row\">
<td class=\"fname\" data-id1=".$row["contact_id"]." contenteditable>" . $row['fname'] ." </td>
<td class=\"lname\" data-id2=".$row["contact_id"]." contenteditable>" . $row['lname']. "</td>
<td>" . $row['contact']."</td>
<td>
<select id4=".$row['contact_id']." name=\"rsvp\" onchange = \"fetch_select(this.value)\">
<option name=\"not-done\" value=\"not-done\">Not done</option>
<option name=\"attending\" value=\"attending\">Attending</option>
<option name=\"not-attending\" value=\"not-attending\">Not-attending</option>
<option name=\"maybe\" value=\"maybe\" selected>Maybe</option>
</select>
</td>
<td><button id3=".$row['contact_id']." name=\"button\"><i class=\"fa fa-trash-o\" aria-hidden=\"true\"></i></button>
<tr>";
}
echo "</table>";
mysqli_close($con);
?>
$('select').on('change', function()
{
// Show an alert
alert( "The new value of the select is " + $(this).val() );
var id=$(this).attr("id4");
var val=$(this).val();
function fetch_select(val ,id)
{
$.ajax({
url:"updateselect.php",
method:"POST",
data:{rsvp:val , id:id},
dataType:"text",
success:function(data){
alert(data);
}
});
}
});
<?php
$connect = mysqli_connect("localhost", "root", "", "registration");
$id = $_POST["id"];
$rsvp = $_POST["val"];
$sql = "UPDATE guestlist SET rsvp ='".$rsvp."' WHERE contact_id='".$id."'";
if(mysqli_query($connect, $sql))
{
echo 'Data Updated';
}
?>

You want to create a form surrounding your dropbox; now you can either submit it using ajax or just submit it to a different page, your call.
It would look something like this:
Note: Add a name param to your select so you can actually get it using $_POST and handle the data.
<form method="post" action="rsvp_handler.php">
<?php
while($row = mysqli_fetch_assoc($resultset))
{
echo "<tr id=\"row\">
<td class=\"fname\" data-id1=".$row["contact_id"]." contenteditable>" . $row['fname'] ." </td>
<td class=\"lname\" data-id2=".$row["contact_id"]." contenteditable>" . $row['lname']. "</td>
<td>" . $row['contact']."</td>
<td>
<select name='rsvp' id='rsvp'>
<option value=\"not-done\">Not done</option>
<option value=\"attending\">Attending</option>
<option value=\"not-attending\">Not-attending</option>
<option value=\"maybe\" selected>Maybe</option>
</select>
</td>
<td><button id3=".$row['contact_id']." name=\"button\"><i class=\"fa fa-trash-o\" aria-hidden=\"true\"></i></button>
<tr>";
}
echo "</table>";
mysqli_close($con);
?>
<button type="submit" name="submit">Submit</button>
</form>
Then for the rsvp_handler.php page just take the post result and then send the wanted data to your database:
if (isset($_POST['submit']))
{
$rsvp = $_POST['rsvp'];
//... any other elements
// create your query here
$sql = "INSERT INTO " . $table . " (rsvp, row2, row3) VALUES (?, ?, ?)";
// best way is to create prepared statements
if($stmt = $mysqli->prepare( $sql ))
{
// bind the params
$stmt->bind_param('sss', $rsvp, $val2, $val3);
// execute the query
$stmt->execute();
// close the connection
$stmt->close();
}
}

Hi I found the answer to the solutions.
My ajax need to have a separate function.

How do I email an html table containing mysql result data with a button in php?

Sorry if this is a poor description, I am relatively new to this.
I am developing a web tool which displays the results of mysql data filtered by a date range in an html table. I have an input and button which allows the user to input an email address to send the table data to. The problem is I am having trouble passing the html table data correctly to my php page to be emailed.
I've tried various methods with AJAX and Javascript, but nothing is working. At one point I was able to pass the table data, but not the inputted email (or vice versa); never both simultaneously. I need to be able to pass both the email that has been inputted as well as the data in the html table preferably reserving the table format as well for a cleaner look). Any help and/or insight is greatly appreciated. Apologies if this code is improper and/or wrong.
Relevant PHP:
<!-- download2csv button -->
<div>
<form action="getCSV.php" method="post">
<input type="hidden" name="csv_text" id="csv_text_computers">
<button class="btn btn-app btn-primary btn-xs no-radius" type="submit" onclick="getCSVDataComputers()">
<i class="icon-save"></i></button>
</form>
<!-- email button -->
<form action="mailto.php" method="post">
Email: <input type="text" name="einame" id="eiid" placeholder="example#example.com">
<button class="btn btn-app btn-info btn-xs no-radius" type="submit" name="ebname" id="ebid" onclick="mailer()">
<i class="icon-envelope"></i></button>
</form>
</div>
</div>
<!-- data table header -->
<div class="table-responsive">
<table id="table-computers1" name="table-computers" class="table table-striped table-bordered table-hover">
<thead>
<tr>
<th>Item Name</th>
<th>RFID Number</th>
<th>Link</th>
<th>Delivery Date</th>
</tr>
</thead>
<tbody>
<?php
foreach ($infocoms as $infocom)
{
//variables for glpi url
$itemtype = $infocom['itemtype'];
$items_id = $infocom['items_id'];
$url = "https://null.null.com/front/" . $itemtype. ".form.php?id=" . $items_id;
?>
<tr>
<?php
// database connection
$conn = mysqli_connect('null', 'null', 'null');
mysqli_select_db($conn, 'glpi');
if ($infocom['itemtype'] == "peripheral") {
$query = "SELECT glpi_peripherals.name AS devicename, TRIM(LEADING '0' FROM glpi_peripherals.otherserial) AS otherserial FROM glpi_peripherals INNER JOIN glpi_infocoms ON glpi_peripherals.id = glpi_infocoms.items_id WHERE glpi_infocoms.items_id = $infocom[items_id] AND glpi_infocoms.itemtype = 'peripheral'";
$result = mysqli_query($conn,$query) or die(mysqli_error($conn));
$devices = $result->fetch_assoc();
echo "<td>$devices[devicename]</td>";
echo "<td><center>$devices[otherserial]</center></td>";
} elseif ($infocom['itemtype'] == "computer") {
$query = "SELECT glpi_computers.name AS compname, TRIM(LEADING '0' FROM glpi_computers.otherserial) AS otherserial FROM glpi_computers INNER JOIN glpi_infocoms ON glpi_computers.id = glpi_infocoms.items_id WHERE glpi_infocoms.items_id = $infocom[items_id] AND glpi_infocoms.itemtype = 'computer'";
$result = mysqli_query($conn,$query) or die(mysqli_error($conn));
$computers = $result->fetch_assoc();
echo "<td>$computers[compname]</td>";
echo "<td><center>$computers[otherserial]</center></td>";
} elseif ($infocom['itemtype'] == "monitor") {
$query = "SELECT glpi_monitors.name AS viewname, TRIM(LEADING '0' FROM glpi_monitors.otherserial) AS otherserial FROM glpi_monitors INNER JOIN glpi_infocoms ON glpi_monitors.id = glpi_infocoms.items_id WHERE glpi_infocoms.items_id = $infocom[items_id] AND glpi_infocoms.itemtype = 'monitor'";
$result = mysqli_query($conn,$query) or die(mysqli_error($conn));
$monitors = $result->fetch_assoc();
echo "<td>$monitors[viewname]</td>";
echo "<td><center>$monitors[otherserial]</center></td>";
} elseif ($infocom['itemtype'] == "networkequipment") {
$query = "SELECT glpi_networkequipments.name AS netname, TRIM(LEADING '0' FROM glpi_networkequipments.otherserial) AS otherserial FROM glpi_networkequipments INNER JOIN glpi_infocoms ON glpi_networkequipments.id = glpi_infocoms.items_id WHERE glpi_infocoms.items_id = $infocom[items_id] AND glpi_infocoms.itemtype = 'networkequipment'";
$result = mysqli_query($conn,$query) or die(mysqli_error($conn));
$networks = $result->fetch_assoc();
echo "<td>$networks[netname]</td>";
echo "<td><center>$networks[otherserial]</center></td>";
} elseif ($infocom['itemtype'] == "printer") {
$query = "SELECT glpi_printers.name AS printname, TRIM(LEADING '0' FROM glpi_printers.otherserial) AS otherserial FROM glpi_printers INNER JOIN glpi_infocoms ON glpi_printers.id = glpi_infocoms.items_id WHERE glpi_infocoms.items_id = $infocom[items_id] AND glpi_infocoms.itemtype = 'networkequipment'";
$result = mysqli_query($conn,$query) or die(mysqli_error($conn));
$printers = $result->fetch_assoc();
echo "<td>$printers[printname]</td>";
echo "<td><center>$printers[otherserial]</center></td>";
} else {
// error handling for null entries
echo "1 or more items were not found";
}
// end data loop and close mysql connection
mysqli_close($conn);
?>
<td><a target=_blank href=$url><?php echo $url; ?></a></td>
<td><center><?php echo $infocom['ddate']; ?></center></td>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
</form>
</div>
<?php
} else {
echo "<center><p style='font-size:125%;'>Please select a date range to submit.</p></center>";
}
error_log("\n");
?>
Relevant Javascript:
<script type="text/javascript">
jQuery(function($) {
var oTable1 = $('#table-computers').dataTable( {
"aLengthMenu": [[10, 25, 100, -1], [10, 25, 100, "All"]],
"iDisplayLength": -1,
"aoColumns": [
{ "bSortable": true },
null, null,null,
] } );
})
function getCSVDataComputers(){
var csv_value=$('#table-computers').table2CSV({delivery:'value'});
$("#csv_text_computers").val(csv_value);
}
</script>
<script type="text/javascript">
function mailer()
{
var tableContent=document.getElementById("table-computers").innerHTML;
alert(tableContent); // This works, but data does not echo in mailto.php
$.post('mailto.php',{content:tableContent},function(data) {
});
}
</script>
Mailto PHP page:
<?php
$mailto = $_POST['einame'];
$table = $_POST['tableContent'];
$headers .= 'MIME-Version: 1.0' . "\r\n";
$headers .= 'From: Test <test#example.com>' . "\r\n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
if (isset($mailto)) {
mail($mailto,"GLPI Notifications",$table,$headers);
echo "Mail sent successfully to $mailto." . "\r\n";
} else {
echo "Mail was not sent." . "\r\n";
}
?>
<br>
Home Page
<br>
<?php
echo $table; // Displays nothing
error_log("\n");
?>

finally figured it out. updated code:
function mailer() {
var tableContent=document.getElementById("table-computers").innerHTML;
// alert(tableContent); confirmation
$.post("mailto.php",{ "content": $("#bmailto").val(tableContent) },function(data) {
});
}

How can I extract JSON data from PHP and display it in a datatable?

I want to get reports from my database by using PHP via turning it into JSON format and displaying it with AJAX JQuery. But I can't seem to pass the data correctly. Can somebody please tell me my fault?
Here is my code view:
$(document).ready(function() {
$("#searchOverall").click(function() {
var ay = $("#Overall_acadyear").val();
var year = $("#Overall_year").val();
if (ay === undefined || ay == '') {
alert("Select Academic year.");
} else if (year === undefined || year == '') {
alert("Select year level.");
} else {
$.ajax({
url: "js/overallreport.php",
dataType: "json",
data: "ay=" + ay + "&year=" + year,
success: function(data) {
//left this blank because I am not sure of what I am doing.
//I used $.getJSON and $.each
},
error: function() {
alert('Cannot retrieve data from server.');
}
}); //ajax
} //else
}); //btnOverall
});
//This is the JS FILE
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="form-group col-sm-4">
<select class="form-control" id="Overall_acadyear">
<option value='' active>Select AY</option>
<?php $r->selectAcademicYear(); ?>
</select>
<select class="form-control col-sm-4" id="Overall_year" align="right">
<option value='' active>Select year level</option>
<?php $r->selectYear(); ?>
</select>
<div class="form-group">
<button type="button" class="control-label btn-success" id="searchOverall" name='createAccount'>Search</button>
<button type="reset" class="control-label btn-danger" id="reset">Clear Fields</button>
</div>
</th>
</tr>
<tr>
<th>Student Number</th>
<th>Student Name</th>
<th>Section</th>
<th>Status</th>
</tr>
</thead>
<tbody id="tableBody">
</tbody> <!--This is the view file -->
<?php
require($_SERVER['DOCUMENT_ROOT']."/finalsis/include/config.php");
include_once($_SERVER['DOCUMENT_ROOT']."/finalsis/include/class.utility.php");
header("Content-Type: application/json");
$ay = $_GET['ay'];
$year = $_GET['year'];
$ay = $obj->cleanString($ay);
$year = $obj->cleanString($year);
$conn = mysqli_connect(db_server,db_user,db_password,db_database);
$ay = mysqli_escape_string($conn,$ay);
$year = mysqli_escape_string($conn,$year);
$selectSQL = "SELECT studentlevel_student, student_fname, student_mname, student_lname,
section_name, student_status FROM tblstudentlevel inner join
tblstudent on studentlevel_student = student_number inner join
tblyearsection on studentlevel_ys = ys_id WHERE studentlevel_acadyear = '" .$ay."' AND year_name = '" .$year. "'";
$result = mysqli_query($conn,$selectSQL);
$output = '{"student": [';
while($rs = mysqli_fetch_array($result)){
$name = $obj->getFullName($rs['student_fname'],$rs['student_mname'],$rs['student_lname']);
$output .= '{"sno":"' .$rs['studentlevel_student']. '", ';
$output .= '"name":"' .$name. '", ';
$output .= '"section":"' .$rs['section_name']. '",';
$output .= '"status":"' .$rs['student_status']. '"},';
}
$output .= "]}";
mysqli_close($conn);
echo json_encode($output);
//This is where my data gathering happens. ?>

Problem is in the following line:
echo json_encode($output);
json_encode needs an array. You are passing string.
$jsonData = array();
while($rs = mysqli_fetch_array($result)){
$name = $obj->getFullName($rs['student_fname'],$rs['student_mname'],$rs['student_lname']);
$jsonData[] = array(
'sno' => $rs['studentlevel_student'],
'name' => $name,
);
}
echo json_encode($jsonData);

unable to compare data from database to array of strings

i have a program where i need to insert words as much as i wish and then those words will be checked through database, if it is present in database , it should return how many words where present in database.
please tell me what is wrong with this code, it is not returning the number of similar entries to database
<html>
<head>
<script language="javascript" type="text/javascript">
// Pre-defined text:
var newtext = "This is the new text";
// Drop-Menu:
var newtext = myform.mymenu.options[myform.mymenu.selectedIndex].value;
// Prompt:
var newtext = prompt('Enter New Text Here:', '');
function addtext() {
var newtext = document.myform.inputtext.value;
document.myform.outputtext.value += newtext+' ';
}
</script>
</head>
<body>
<form name="myform" action="" method="post">
<table border="0" cellspacing="0" cellpadding="5"><tr>
<td><textarea name="inputtext"></textarea></td>
<input type="radio" name="placement" value="append" checked> Add to Existing Text<br>
<td><p><input type="radio" name="placement" value="replace"> Replace Existing Text<br>
<input type="button" value="Add New Text" onClick="addtext();"></p>
</td>
<td><textarea name="outputtext"></textarea></td>
</tr></table>
<input type="submit"/>
</form>
<?php
$string=$_POST['outputtext'];
$array=array();
$array=explode(';',$string);
# $db=new mysqli('localhost','root','','words');
if(mysqli_connect_errno())
{
echo 'Error:Could not connect to the database';
}
else
echo 'connected';
$db->select_db('words');
$count = 0;
foreach($array as $s)
{
$query="select * from collection where word LIKE '%".$s."%'";
$result=$db->query($query);
if($result)
$count += $db->num_rows;
}
echo $count;
$db->close();
?>
</body>
</html>

$count = 0;
foreach($array as $s)
{
$query="select count(*) as num_matched from collection where word LIKE '%".$s."%'";
$result=$db->query($query) or die($db->error);
$row = $result->fetch_assoc();
$count += $row['num_matched'];
}
echo $count;
You should also switch to parametrized queries instead of using the input directly.
$stmt = $db->prepare("select count(*)
FROM collection
WHERE word LIKE CONCAT('%', ?, '%')");
$stmt->bind_param("s", $s);
$count = 0;
foreach ($array as $s) {
$result = $stmt->execute();
$stmt->bind_result($num_matched);
$stmt->fetch();
$count += $num_matched;
}
echo $count;

$db->num_rows is already the number of rows... You don't need to manually count them.

its not feasible to run query in for loop so, you can try below solution,
$array=array('abc','xyz','lmn','pqr');
$query="select word from collection where word LIKE '%".$s."%'";
$result=$db->query($query);
while ( $row = mysql_fetch_array($result) )
{
$tblarray[] = $row['word'];
}
foreach($tblarray as $k => $v)
{
foreach($array AS $key => $value)
{
if (strpos($v, $value) !== false)
{
$finalarray[] = $v;
}
}
}
echo sum($finalarray);

Return dynamic select to null onChange

I have two select boxes, the second of which is dependent upon the selection in the first. I want to get the second select box (course) to have a value of null when the first box (subject) is changed. Any help on accomplishing this would be greatly appreciated.
This is what I have tried:
Javascript:
function autoSubmit() {
var formObject = document.forms['theForm'];
formObject.submit();
}
PHP:
<form name="theForm" method="get">
<select name="subject" onChange="autoSubmit();">
<option value="null">Select a Subject...</option>
<php
$sql = "SELECT DISTINCT subj_name, subj_id FROM table1 ORDER BY subj_name
$result = mysql_query($sql) or die ("couldn't execute query");
while($row = mysql_fetch_array($result))
{
echo ("<option value=\"$row[subj_id]\" " . ($subject == $row["subj_id"] ? "
selected" : "") . ">$row[subj_name]</option>");
}
?>
</select>
<select name="course" onChange="autoSubmit();">
<option value="null">All Courses</option>
<php
if($subject != null && is_numeric($subject))
{
$sql = "SELECT DISTINCT subj_id, course_id, course_name FROM table1
WHERE subj_id = $subject ORDER BY course_name
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo ("<option value=\"$row[course_id]\" " . ($course == $row["course_id"] ?
" selected" : "") . ">$row[course_number] - $row[course_name]</option>");
}
}
?>
</select>
</form>

You can put in the onChange of the first select, before the autoSubmit() :
this.form.course.value='null';
or
this.form.course.selectedIndex=0;
This way the value on the get will be ?subject=[the_subject]&course=null ( and then $course == $row["course_id"] will be false ).
( http://jsfiddle.net/HMT34/ )