another javascript redirecting - javascript

My view :
<div class="container">
<form class="form-signin" method="post" action="">
<h2 class="form-signin-heading">Admin Login</h2>
<input type="text" id="inputUsername" name ="inputUsername"
class="form-control" placeholder="Admin" required autofocus />
<label for="inputPassword" class="sr-only"> Password</label>
<input type="password" id="inputPassword" name="inputPassword"
class="form-control" placeholder="Password" required />
<br/>
<button class="btn btn-lg btn-primary btn-block" name="login"
type="submit">Login</button>
</form>
</div>
My controller :
if (isset($_POST['login'])) {
$username = $_POST['inputUsername'];
$password = $_POST['inputPassword'];
echo "<script>window.location.href = 'collections.php';</script>";
}
When I clicked the button,
it doesnt redirect me to collections.php , what I missed here ?

use php header to redirect the page ,it's easy and better compaire to what you did here.
header('Location: http://www.example.com/');

you redirect from php
<?php
if (isset($_POST['login'])) {
$username = $_POST['inputUsername'];
$password = $_POST['inputPassword'];
header('Location: collections.php'); //<------- php redirect to other page
}
?>

this is what you were trying outputting JS in PHP for redirection be careful with url if you use relative
$redirectURL = "../controller/collection.php";
print("<script>");
print("var t = setTimeout(\"window.location='".$redirectURL."';\", 3000);");
print("</script>");

Related

Form submit with ajax passing form to php without page refresh

can somebody please tell me why this code is not working I want to sent form data to PHP by post method but my PHP is not receiving any request
here is my signup form
signupmodal.php
<form action="<?php htmlentities($_SERVER['PHP_SELF']) ?>" method="post" id="signupForm">
<div class="form-group">
<label for="forUserName">User Name:</label>
<input type="text" name="username" id="username" class="form-control" placeholder="Enter User Name" aria-describedby="helpId">
</div>
<div class="form-group">
<label for="forEmail">Email:</label>
<input type="email" name="email" id="email" class="form-control" placeholder="Enter Your Email" aria-describedby="helpId">
</div>
<div class="form-group">
<label for="">password:</label>
<input type="password" name="password" id="password" class="form-control" placeholder="Enter Password" aria-describedby="helpId">
</div>
<div class="form-group">
<label for="forConfirmPassword">Confirm Password</label>
<input type="password" name="cpassword" id="cpassword" class="form-control" placeholder="Enter Confirm Password" aria-describedby="helpId">
</div>
<input type="submit" class="btn btn-primary" value="SignUp" id="subbtn" onclick="myFunction()">
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
</div>
<?php echo json_encode($_POST);
// echo $_POST['email'];
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$username = $_POST['username'];
$email = $_POST['email'];
$password = $_POST['password'];
$cpassword = $_POST['cpassword'];
echo $username;
if ($password == $cpassword) {
//code
} else
echo '<div class="alert alert-danger" role="alert">
<strong>danger</strong>
</div>';
} ?>
</div>
script.js
function myFunction() {
console.log(window.location.href);
$('form').on('submit', function (event) {
$.ajax({
type: 'POST',
url: 'includes/signupmodal.php',
data: $('form#signupForm').serialize(),
success: function () {
data = $('form#signupForm').serialize();
console.log(data);
},
});
event.preventDefault();
});
}
I want to submit my data using ajax without loading the page so, please tell me where I am wrong
You are only running myFunction() when you click the submit button and by then it's too late to add a submit event listener.
I suggest you add your listener when the document is ready.
Remove the onclick="myFunction()" from your submit button and add this to your script
jQuery(function() {
myFunction() // executes when the document has completely loaded
})
// or even just
// jQuery(myFunction)
See https://api.jquery.com/jquery/#jQuery3

How to return second register form on submition?

I have a page with two registration forms individual and business type and individual type form is set as default the other form is hidden, it works fine. but when I switch it to second form and click on submit button it submits second form but returns to first form after submition even on errors it return to first form.
I want it to stay on second form on errors and after submition.
Here is my php :
if (isset($_POST["btnRegister"])) {
echo "Done";
}elseif (isset($_POST["btnbusiness"])) {
echo "Done";
}
HTML and js codes in my page:
function swapConfig(x) {
var radioName = document.getElementsByName(x.name);
for(i = 0 ; i < radioName.length; i++){
document.getElementById(radioName[i].id.concat("Settings")).style.display="none";
}
document.getElementById(x.id.concat("Settings")).style.display="initial";
}
<div class="col-10 clmiddle">
<label for="production"><b>Individual</b></label>
<input type="radio" onchange="swapConfig(this)" name="urlOptions" id="production" checked="checked" />
<label for="development"><b> Business</b></label>
<input type="radio" onchange="swapConfig(this)" name="urlOptions" id="development" />
</div>
First Form :
<div id="productionSettings" class="col-12">
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="col-6">
<input type="text" class="form-control" name="fname" placeholder="Name..." required>
<button type="submit" name="btnRegister" class="btn btn-primary right">Send</button>
</div>
</form>
</div>
Second Form :
<div id="developmentSettings" style="display:none" class="col-12">
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]); ?>" method="post">
<div class="col-6">
<input type="text" class="form-control" name="fname" placeholder="Name..." required>
<button type="submit" name="btnbusiness" class="btn btn-primary right">Send</button>
</div>
</form>
</div>
EDIT: I changed JS to php, Here is the solution.
PHP codes (which get url):
$path = $_SERVER['REQUEST_URI'];
$Aurl = explode(",",$path);
for ($i=0; $i<count($Aurl);$i++){
$Burl = str_replace("?", "/", trim($Aurl[$i]));
}
$url = htmlspecialchars(basename($Burl));
$FormPostUrl = basename($path);
Html part :
Checkbox :
<div class="col-10 clmiddle" style="margin-top: 20px;">
<label for="production"><b>Individual</b></label>
<input type="checkbox" value="<?php echo htmlspecialchars("register.php"); ?>" name="checket"
onClick="if (this.checked) { window.location = this.value; }" <?php if($url === htmlspecialchars("register.php")){ echo 'checked="checked"';}?>>
<label for="development"><b>Business</b></label>
<input type="checkbox" value="<?php echo htmlspecialchars("register.php?business");?>"
name="checket"
onClick="if (this.checked) { window.location = this.value; }" <?php if($url === htmlspecialchars("business")){ echo 'checked="checked"';}?>>
</div>
First Form :
<?php if($url === htmlspecialchars("register.php")){?>
<div id="productionSettings" class="col-12">
<form action="<?php echo htmlspecialchars($FormPostUrl); ?>" method="post">
<div class="col-6">
<input type="text" class="form-control" name="fname" placeholder="Name..." required>
<button type="submit" name="btnRegister" class="btn btn-primary right">Send</button>
</div>
</form>
</div>
Second form:
<?php } elseif($url === htmlspecialchars("business")){ ?>
<div id="developmentSettings" class="col-12">
<form action="<?php echo htmlspecialchars($FormPostUrl); ?>" method="post">
<div class="col-6">
<input type="text" class="form-control" name="fname" placeholder="Name..." required>
<button type="submit" name="btnbusiness" class="btn btn-primary right">Send</button>
</div>
</form>
</div>
<?php } ?>
You can use PHP to control whether display:none is added to your divs or not. Use an if statement (or a ternary operator might be neater syntax in the context) to make the decision about what to echo. Since the default is to display the production settings form, we only need to check whether the other form has been submitted or not, in order to know whether to change that.
e.g. something like this (untested):
<input type="radio" onchange="swapConfig(this)" name="urlOptions" id="production" <?php echo (isset($_POST["btnRegister"]) ? "" : 'checked="checked"'); ?> />
and
<input type="radio" onchange="swapConfig(this)" name="urlOptions" id="development" <?php echo (isset($_POST["btnRegister"]) ? 'checked="checked"' : ""); ?> />
and
<div id="productionSettings" class="col-12" <?php echo (isset($_POST["btnbusiness"]) ? "style='display:none'" : ""); ?>>
and
<div id="developmentSettings" class="col-12" <?php echo (isset($_POST["btnbusiness"]) ? "" : "style='display:none'"); ?>>
P.S. Unless you've massively simplified these forms for the purpose of your example, they appear to be basically identical. It's questionable whether you actually need two separate forms at all. The only difference appears to be the choice between "individual" and "business" - that could be handled by a single form with a radio button to choose the type, which would then simplify how you handle the postback as well, and reduce the amount of duplicated code and HTML. Of course if you're actually capturing more distinct fields for these forms than you've shown, then these remarks don't really apply.

Properly return value and print in html after a form submit

How do I return the result from a post in the original html?
For example in my form, I submit an email address. After the email address is submited I would like to show that email back in a div and hide the form.
How can I do that using angularjs and php?
simple HTML form
<form name="EmailForm" class="form-horizontal" method="post" action="mail_handler.php">
<div class="form-group form-group-lg">
<input id="email" type="email" name="email" class="form-control size" ng-model="email.text" placeholder="me#example.com" required>
</div>
<div class="form-group">
<label ng-show="EmailForm.email.$valid"><input ng-model="IAgree" name="tos" required="required" type="checkbox" /> I have read and agree to the Terms of Service</label>
</div>
<div class="form-group">
<button type="submit" name="submit" ng-show="IAgree" class="btn btn-lg btn-primary">
<span class="glyphicon glyphicon-play-circle" aria-hidden="true"></span>
Spam me now!
</button>
</div>
</form>
and a simple php
<?php
if(isset($_POST['submit'])){
$email = $_POST['email'];
header('Location: index.html');
}
?>
If you have
$email = $_POST['email'];
header('Location: index.html?email='.urlencode($email));
you can in index.html do
window.onload=function() {
var email = location.search?location.search.split("email=")[1]:"";
document.getElementById("emailId").innerHTML=decodeURIComponent(email);
}
You have two variants:
You should change the action of the form to "index.php" and put all the code for the form in index.php
2.In the other variant you will use everything you have done just change header('Location: index.html'); with header('Location: index.php/?email=' . urlencode($email));
And then in index.php:
$email = $_GET['email'];
echo '<div class="email">' . $email . '</div>';
You can write both html and php in single php file. i.e form_submit.php
After create php file you can write following code in form_submit file.
<form name="EmailForm" class="form-horizontal" method="post" action="mail_handler.php">
<div class="form-group form-group-lg">
<input id="email" type="email" name="email" class="form-control size" ng-model="email.text" placeholder="me#example.com" required>
</div>
<div class="form-group">
<label ng-show="EmailForm.email.$valid"><input ng-model="IAgree" name="tos" required="required" type="checkbox" /> I have read and agree to the Terms of Service</label>
</div>
<div class="form-group">
<button type="submit" name="submit" ng-show="IAgree" class="btn btn-lg btn-primary">
<span class="glyphicon glyphicon-play-circle" aria-hidden="true"></span>
Spam me now!
</button>
</div>
</form>
<?php
if(isset($_POST['submit']))
{
?>
<div>
<?php
$email = $_POST['email'];
?>
</div>
<style>
.form-horizontal{display:none}
<!-- above statement will hide form after submission of form -->
</style>
}
?>
After submit your form you will see email on same page in particular div.

problems resetting a form using php

I have a contact form which sends an email once submitted and displays an alert successfully when sent. My problem was 1) after its sent the email form still has content. 2) If I refresh the page the email is sent again with the previous details. In order to solve this I used the below code in php which is doing the job of refreshing with out sending an email.
header("Location: contact.php");
exit;
Now my problem is The alert is not displayed anymore which is true because the alert is in my HTML and header refreshes the page and it never reaches the alert in HTML(displayed using php echo). Here is the HTML Code :
<div class="container">
<div class="row">
<div class="col-md-6 col-md-offset-3" id="emailForm">
<h1 class="center">Email Form</h1>
<?php echo $result; //header( "Location: contact.php"); //exit; ?>
<p>Please get in touch ! I will get back to you as soon as I can !!</p>
<form method="post" id="contactForm">
<div class="form-group">
<label for="name">Your Name</label>
<input type="text" name="name" class="form-control" placeholder="Your Name" value="<?php echo $_POST['name'] ?>" />
</div>
<div class="form-group">
<label for="email">Your Email</label>
<input type="email" name="email" class="form-control" placeholder="Your Email" value="<?php echo $_POST['email'] ?>" />
</div>
<div class="form-group">
<label for="message">Message</label>
<textarea class="form-control" name="message">
<?php echo $_POST[ 'message'] ?>
</textarea>
</div>
<input type="submit" name="submit" id="send" class="btn btn-success btn-lg center" value="Submit" />
</form>
</div>
</div>
</div>
Here is the PHP code:
<?php
if($_POST['submit']) {
if(!$_POST['name']){
$error.="<br>Please enter your name";
}
if(!$_POST['email']){
$error.="<br>Please enter your email address";
}
if(!$_POST['message']){
$error.="<br>Please enter a message";
}
if ($_POST['email']!= "" AND !filter_var($_POST['email'], FILTER_VALIDATE_EMAIL)) {
$error.="<br>Please enter a valid email address";
}
if( $error )
{
$result='<div class="alert alert-danger"><strong>There were error(s):'.$error.'</strong></div>';
}
else {
if(mail("madistackcloud#gmail.com","Message from Deepak", "Name: ".$_POST['name']."Email: ".$_POST['email']."Message: ".$_POST['message'])) {
$result='<div class="alert alert-success alert-dismissible"><strong>Thank you! I\'ll be in touch.</strong></div>';
}
else
{
$result='<div class="alert alert-danger alert-dismissible"><strong>Oops! Something went wrong. Please try again !</strong></div>';
}
}
}
?>
Is there any workaround for this or any other method which can do the job. Kindly help.
Change your form to
<form method="post" id="contactForm">
<div class="form-group">
<label for="name">Your Name</label>
<input type="text" name="name" class="form-control" placeholder="Your Name" value="" />
</div>
<div class="form-group">
<label for="email">Your Email</label>
<input type="email" name="email" class="form-control" placeholder="Your Email" value="" />
</div>
<div class="form-group">
<label for="message">Message</label>
<textarea class="form-control" name="message"></textarea>
</div>
<input type="submit" name="submit" id="send" class="btn btn-success btn-lg center" value="Submit" />
</form>
If you don't want to show the content sent, dont use echo $POST on the value of the inputs.
You're always echoing the post data in the html section. You only want to echo data if there is an error.
value="<?php echo $_POST['name'] ?>"
in the control code above do something like
$name = cleanInput($_POST['name']);
$email = cleanInput($_POST['name']);
// etc...
Then in your
if( $error )
...
else
{
$name = "";
$email = "";
sendMail();
// etc...
and then back in your html:
value="<?php echo $name; ?>"
Why do you do this: value="<?php echo $_POST['email']? This sets the value of the input field to what the user inputted. This means next time you load your page this value is visible and thus will be emailed when transmitted.

alert box in PHP and navigation to another page

I am using javascript to check whether username and password are not empty. If one of these is empty, javascript alert is displayed and PHP script should not work, that is username and password validation should not occur and login page should be displayed once again. Is there any simple code to do this?
Nobody need to build whole form. I have already build login form and PHP script for its validation, I just want to know is there any method or function in PHP to stop script on entering empty username/password and submitting
Try This
Php Code :
<p>
<label for="first">User Name:</label>
<input type="text" name="First Name" id="first" />
</p>
<p>
<label for="last">Password:</label>
<input type="text" name="Last Name" id="last" />
</p>
<input type="submit" name="Submit" id="button2" value="Submit" onClick="javascript:verify()"/>
JavaScript Code :
function verify() {
if (document.getElementById('first').value=="") {
alert("Please Enter Your Name");
return false;
}
else if (document.getElementById('last').value=="") {
alert("Please Enter Your Password");
return false;
}
else {
document.form.submit();
}
}
Working Model : http://jsfiddle.net/NWWL4/24/
It took me awhile to get this right. I have my form in my html index
page. On a closed question here, I read this couldn't be done.
This php works VERY well with my form.
It generates a Javascript alert for good and bad results and
links back to the index page in either instance.
If you look at the 2nd echo, you'll see where you can redirect to
another page. I just loaded same page to clear form.
If you want to see the ccs, just ask.
PHP:
<?php
if(isset($_POST['submit'])) {
$to = "admin#blahblah.com";
$name_field = $_POST['name'];
$email_field = $_POST['email'];
$subject_field = $_POST['subject'];
$message = $_POST['message'];
$body = "From: $name_field\n E-Mail: $email_field:\n Subject: $subject_field\n Message: $message\n";
}
if(empty($name_field) || empty($email_field) || empty($subject_field) || empty($message)) {
echo '<script type="text/javascript">alert("There is a problem, please check the fields");window.history.go(-1);</script>';
}
else {
if(mail($to, $subject_field, $body)) {
echo '<script type="text/javascript">alert("Message successfully sent");window.location = "https://www.blahblah.com/";</script>';
}}
exit;
?>
html:
<div class="clear"></div>
<div class="container">
<div class="row">
<div class="col-md-3">
<form role="form" action="php\mailer.php" method="post" id="form">
<div class="form-group">
<input name="name" type="text" class="form-control" id="name" placeholder="Your Name" maxlength="30">
</div>
<div class="form-group">
<input name="email" type="text" class="form-control" id="email" placeholder="Your Email" maxlength="30">
</div>
<div class="form-group">
<input name="subject" type="text" class="form-control" id="subject" placeholder="Your Subject" maxlength="40">
</div>
<div><input type="submit" name="submit" class="btn btn-primary" value="Send Message"></input></div>
</div>
<div class="col-md-9">
<div class="txtarea">
<textarea name="message" rows="10" class="form-control" id="message"></textarea>
</form>
<div class="clear"></div>
<div class="col-lg-12" style="text-align:center">
<a class="btn btn-large btn-contact-link" href="#blahblah_home">Home</a>

Categories