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php file's code not executing through ajax call

I have a button in my PHP file, and when I click on that button, I want another PHP file to run and save some data in a MySQL table. For that I am using AJAX call as suggested at this link (How to call a PHP function on the click of a button) which is an answer from StackOverflow itself.
Here is my show_schedule file from which I am trying to execute code of another PHP file:
$('.edit').click(function() {
var place_type = $(this).attr("id");
console.log(place_type);
$.ajax({
type: "POST",
url: "foursquare_api_call.php",
data: { place_type: place_type }
}).done(function( data ) {
alert("foursquare api called");
$('#userModal_2').modal('show');
});
});
here 'edit' is the class of the button and that button's id is being printed in the console correctly.
here is my foursquare_api_call.php file (which should be run when the button is clicked):
<?php
session_start();
include('connection.php');
if(isset($_POST['place_type'])){
$city = $_SESSION['city'];
$s_id = $_SESSION['sid'];
$query = $_POST['place_type'];
echo "<script>console.log('inside if, before url')</script>";
$url = "https://api.foursquare.com/v2/venues/search?client_id=MY_CLIENT_ID&client_secret=MY_CLIENT_SECRET&v=20180323&limit=10&near=$city&query=$query";
$json = file_get_contents($url);
echo "<script>console.log('inside if, after url')</script>";
$obj = json_decode($json,true);
for($i=0;$i<sizeof($obj['response']['venues']);$i++){
$name = $obj['response']['venues'][$i]['name'];
$latitude = $obj['response']['venues'][$i]['location']['lat'];
$longitude = $obj['response']['venues'][$i]['location']['lng'];
$address = $obj['response']['venues'][$i]['location']['address'];
if(isset($address)){
$statement = $connection->prepare("INSERT INTO temp (name, latitude, longitude, address) VALUES ($name, $latitude, $longitude, $address)");
$result = $statement->execute();
}
else{
$statement = $connection->prepare("INSERT INTO temp (name, latitude, longitude) VALUES ($name, $latitude, $longitude)");
$result = $statement->execute();
}
}
}
?>
none of the console.log is logged in the console and also the 'temp' table is not updated. Can anyone tell me where I am making mistake? Or is it even possible to execute the code of a PHP file like this?

Your JavaScript is making an HTTP request to the URL that executes you PHP program.
When it gets a response, you do this:
.done(function( data ) {
alert("foursquare api called");
$('#userModal_2').modal('show');
}
So you:
Alert something
Show a model
At no point do you do anything with data, which is where the response has been put.
Just sending some HTML containing a script element to the browser doesn't cause it to turn that HTML into a DOM and execute all the script elements.
You'd need to do that explicitly.
That said, sending chunks of HTML with embedded JS back through Ajax is messy at best.
This is why most web services return data formatted as JSON and leave it up to the client-side JS to process that data.

to return the contents of php code you can do something like this
you can use any call to this function
function check_foursquare_api_call(place_type) {
var place_type= encodeURIComponent(place_type);
var xhttp;
//last moment to check if the value exists and is of the correct type
if (place_type== "") {
document.getElementById("example_box").innerHTML = "missing or wrong place_type";
return;
}
xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (xhttp.readyState == 4 && xhttp.status == 200) {
document.getElementById("example_box").innerHTML = xhttp.responseText;
$('#userModal_2').modal('show');
}
};
xhttp.open("GET", "foursquare_api_call.php?place_type="+place_type, true);
xhttp.send();
}
this will allow you to send and execute the code of the foursquare_api_call file and return any elements to example_box, you can return the entire modal if you want,
you can use any POST / GET method, monitor the progress, see more here
XMLHttpRequest

PHP laravel query database every 1 mintue

I want to query a mysql table in my project in every 1 minute. I used javascript setInterval method for timing and ajax for sending request and receives output as html. but there is many problems with it:
1- whole website goes very slow only for performing this action.
2- with this I can't query something else from database.
my code is :
function ajaxGetAllOrders(){
$.ajax('<?php echo url()?>/admin/getAllOrders',{
dataType:'json',
async: true,
success:function(data){
$('#page-content').html(data.content);
}
});
}
and interval method:
$(function(){
setInterval('ajaxGetAllOrders();',60000);
ajaxGetAllOrders();
});
I tried to create another connection to database for this but it wont help anyway.
and the php getAllOrders method:
public function getAllOrders(){
if (!$this->isAdmin()){
return;
}
$fields = DB::connection('mysql2')->table('z_orders')->orderBy('id','desc')->get();
$nFields = DB::connection('mysql2')->table('z_food_orders')->orderBy('id','desc')->get();
$count=0;
$i=1;
if (count($fields)>0){
foreach($fields as $field){
$userid = DB::connection('mysql2')->table('z_users')->whereId($field->user_id)->first();
$data['username']=$userid->name;
$data['address'] = $userid->address;
$orderId = DB::connection('mysql2')->table('z_food_orders')->whereOrderId($field->id)->first();
$foodId = DB::connection('mysql2')->table('z_foods')->whereId($orderId->food_id)->first();
$data['foodname'] =$foodId->title;
$data['foodcount'] = $orderId->foodcount;
$foodPrice = $foodId->price;
$count += $foodPrice * $orderId->foodcount;
$i++;
}
$cid = DB::connection('mysql2')->table('z_users')->whereId($userid->id)->first();
$data['customer_id'] = $cid->cctt;
$data['price']=$count;
$data['fields']=$nFields;
}
return response()->json(['content'=>view('admin.orders',$data)->render()]);
}
the whole idea behind this is user orders something.then in admin panel in orders section admin can see all orders. so i want to able that admin won't reload page and in every minute the list of orders show new orders.

Get the code of a page generated with JavaScript

I'm trying to get the code of an URL page after it JavaScript executed.
For the exemple :
<?php
function getVideoURL($link){
$data = file_get_contents($link);
print($data);
}
$link = htmlentities($_POST["link"]);
getVideoURL($link);
?>
But this code give me the code of the url before javasript execution, is there a way to get it after javascript execution ?

file_get_contents get the original code of the page, it doesn't execute any client side code ( javascript )
To execute javascript you will need an entire browser emulation engine -- a headless browser.
http://jonnnnyw.github.io/php-phantomjs/
use JonnyW\PhantomJs\Client;
function getVideoURL($link){
$client = Client::getInstance();
$request = $client->getMessageFactory()->createRequest($link, 'GET');
$response = $client->getMessageFactory()->createResponse();
$client->send($request, $response);
if($response->getStatus() === 200) {
// Dump the requested page content
return $response->getContent();
} else {
return false;
}
}
$link = htmlentities($_POST["link"]);
getVideoURL($link);

Error when sending html source from javascript to PHP

I am using the following to encode the html source of a ckeditor in a web application.
var updateString = app.getValue('wysiwygHomePage');
var encodedString = encodeURIComponent(updateString);
alert(encodedString);
app.httpRequest("www.xxxx.com/techy/savealldata.php", "GET", function(data, error, httpResponse){
alert(data);
},
{
"updateType":"homePage","updateString":encodedString}, "String", {}, {});
}
Then at the PHP end I am using :
<?php
$updateType = $_GET["updateType"];
$updateString = $_GET["updateString"];
$updateString2 = urldecode($updateString);
echo 'success here '.$updateType .' '.$updateString2 ;
?>
I am adding some coloured tex and the html source for this is:
<p>
<span style="color: rgb(255, 140, 0);">123</span><br />
</p>
<p>
This works okay until I cut and paste more than 32 times.
I then just get error returned from the PHP call.
I presume there are to many chars arriving at the PHP end ???
Any ideas why this is happening ?
Mr WARBY.
UPDATED PHP Code.
<?php
include 'dbdata.php';
$updateType = $_POST["updateType"];
$updateString = $_POST["updateString"];
$updateString2 = urldecode($updateString);
//echo 'success here '.$updateType .' '.$updateString2 ;
if($updateType === 'homePage')
{
$query5 = "UPDATE pageText SET HTML= "."'".$updateString2."'"." WHERE ID = 12";
//echo $query5;
echo 'Home Page Updated 2';
mysql_query($query5);
}
if($updateType === 'instructionPage')
{
$query5 = "UPDATE pageText SET HTML= "."'".$updateString2."'"." WHERE ID = 13";
echo 'Instruction Page Updated 2';
mysql_query($query5);
}
if($updateType === 'FAQPage')
{
$query5 = "UPDATE pageText SET HTML= "."'".$updateString2."'"." WHERE ID = 14";
echo 'FAQ Page Updated';
mysql_query($query5);
}
?>

There are a lot of variables in play here. You need to change your debugging strategy. Instead of testing end to end each time try isolating each component.
In Javascript, call "app.getValue('wysiwygHomePage')", encode the string, decode the string, and put it right back in the editor. Do that in a loop until you can determine if the client-side is mangling anything.
If not, try encoding a complicated string in Javascript, sending it to a PHP script that decodes/re-encodes and echos it back. Do that in a loop several times.
If you still haven't found the problem try making a PHP script that takes a complicated string, INSERTS it, SELECTs it, UPDATEs it in a loop to see if you database encoding or escaping is affecting it.
If at any point you find the string changing when it shouldn't you've probably found your problem.

Will this huge javascript array loaded from a database crash my website?

So on this website I'm making (who knows if i'll actually finish it lol) when someone opens up the new user page, php echos into a javascript script all the usernames from the database to create an array.
<script type="text/javascript">
var allUsers = ['!' <?php
$result = mysql_query("SELECT username FROM users ") or die("error " .mysql_error());
$usersArray = array();
while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$usersArray[] = $row['username'] or die("error ". mysql_error());
}
foreach ($usersArray as $name) {
echo ',' . json_encode($name );
}
?> , ];
the point of this is to have a live checker so if you type in a username that already exists, red text shows up next to the username input. But let's say I get 1,000,000 users (completely theoretical). Fortunately, the array only gets created at the beginning of the web page load. But will the function that checks if the username already exists in the huge array and gets called everytime someone changes the text in the username input put too much stress on the script and crash the website? If so, is there a better way to do what I'm describing?
Here's the rest of the code
function contains(a, obj) {
var i = a.length;
while (i--) {
if (a[i] === obj) {
return true;
}
}
return false;
}
function onUserChange() { //gets called onkeypress, onpaste, and oninput
if(contains(allUsers, str)) {
div.innerHTML = "Username already exists";
div.style.color = "red";
userValid = false;
}
}
</script>

Something along these lines. ( with jQuery and PDO ) - note - code is not tested.
var keyTimer, request;
$('namefield').blur(function(){
onUserChange();
});
$('namefield').keyup(function(){
onUserChange();
});
function onUserChange() { //gets called onkeypress, onblur
keyTimer = setTimeout(function(){
if(request && request.readystate != 4){
//cancel a previous request if a new request is made.
request.abort();
}
request = $.post(
'http://yoursite.com/location/of/username/script.php', //post data to server
{username : $('namefield').val()},
function(data){
if(data == 0 ) { //might be a string here
alert( 'the name is ok to use.' );
}else{
alert( 'someone has this name already.' );
}
}
);
}, 500); //overwrite previous timeout if user hits key within 500 milliseconds
}
Then in the backend
$sql = 'SELECT id FROM users WHERE username = :username';
//insert from post username but we are good programers and are using PDO to prevent sql injection.
//search for the username in the db, count the number of users or rows should be 1 someone has it 0 no one has it assuming its unique.
$stmt = $Pdo->prepare($sql);
$stmt->execute(array(':username', $_POST['username']));
echo $stmt->rowCount();
exit();
etc.....

Do not do it. My counsel is to use ajax to load the php file that will make a query asking only for the user that was typed in the input and retunr only a boolean value(exists=true / notexists=false)
Code example:
HTML(yourFile.html):
<script>
jQuery(document).ready(function(){
//When the value inside the input changes fire this ajax querying the php file:
jQuery("#inputUser").change(function(){
var input = jQuery(this);
jQuery.ajax({
type:"post",
url:"path/to/file.php",
data:input.val(),
success: function(data){
//if php returns true, adds a red error message
if(data == "1"){
input.after('<small style="color:#ff0000;">This username already exists</small>');
//if php returns false, adds a green success message
} else if(data == "0"){
input.after('<small style="color:#00ff00;">You can use this username</small>');
}
}
});
});
});
</script>
<input id="inputUser" type="text" name="username" value="">
PHP(path/to/file.php):
<?php
$username = $_REQUEST['username']; // The value from the input
$res = mysqli_query("SELECT id FROM users WHERE username='".$username."'"); // asking only for the username inserted
$resArr = mysqli_fetch_array($res);
//verify if the result array from mysql query is empty.(if yes, returns false, else, returns true)
if(empty($resArr)){
echo false;
} else{
echo true;
}
?>

As I can see you need to load the PHP code when your website is loading.
First, I recommend you to separate the code. The fact that you can mix Javascript with PHP doesn't mean it is the best practice.
Second, yes, it's not efficient your code since you make Javascript load the result so you can search into it next. What I suggest you is making the search in the server side, not in client side, because as you say, if you have 100 elements maybe the best is to load all the content and execute the function, but if you have 1,000,000 elements maybe the best is to leave the server to compute so it can make the query with SQL.
Third, you can do all this using Ajax, using Javascript or using a framework like jQuery so you don't have to worry about the implementation of Ajax, but you only worry about your main tasks.