We Keep Coding

loop through this Object that contain Array as values and combine all values, sort them, reindex and update values

I have to loop through the object values and sort them in such a way that I remove number 1 & 2 (lets call it index) from Self and Spouse. Then reindex Child3 and Child4 to Child1 and Child2.
Though the Object got from API response looks like below it makes more sense to reindex them as I'll be displaying this information on the screen.
Object looks like below: This is just a sample data. This object is
dynamically created based on User household information
eligibilityMap: {
"CHIP": [
"CHILD3" // should be Child1
],
"APTC/CSR": [
"SELF1", //should be Self
"SPOUSE2", //should be Spouse
"CHILD4" //should be Child2
]
}
My question is how should I loop through this Object and just sort the child and reindex the same?
Expected Result:
newMapping: {
"CHIP": ["Child1"],
"APTC/CSR": ["Self, Spouse and Child2"]
}
CODE:
var sortedMember = Object.keys(eligibilityMap).reduce((acc, key) => {
//fetch the array for the given key
var array = eligibilityMap[key];
console.log('array', array);
var sortedArray = array.sort( function (firstValue, secondValue) {
if (firstValue.indexOf("SELF") >= 0) return -1;
if (secondValue.indexOf("SELF") >= 0) return 1;
if (firstValue.indexOf("SPOUSE") >= 0) return -1;
if (secondValue.indexOf("SPOUSE") >= 0) return 1;
return 0;
});
console.log("sortedArray", sortedArray)
acc[key] = sortedArray;
return acc;
}, {})
$scope.memberString = Object.keys(sortedMember).reduce(function (acc, key) {
var array = sortedMember[key]
var formattedString = array.reduce(function (memberAcc, member, index) {
if (member.indexOf("SELF") >= 0) {
return "Applicant"
}
if (member.indexOf("SPOUSE") >= 0) {
var delimiter = index > 0 ? ", " : "";
return memberAcc + delimiter + "Spouse"
}
if(index === 0) return member;
var delimiter = index === array.length - 1 ? " and " : ", ";
return memberAcc + delimiter + member //CHILD1
}, "");
console.log("STRING", key, formattedString)
acc[key] = formattedString;
return acc;
}, {});
RESULT: (But still not what I wanted)
MEMBERS STRING {CHIP: "CHILD4", APTC/CSR: "Applicant, Spouse, CHILD3 and CHILD5"}

You can check this approach. I've created a dataMapper to map the specific data with their new values.
var obj = {
"CHIP": [
"CHILD3", // should be Child1
],
"APTC/CSR": [
"SELF1", //should be Self
"SPOUSE2", //should be Spouse
"CHILD4" //should be Child2
],
"TEST": [
"SELF1",
"CHILD3"
]
};
// Code to support IE9
var i = 0;
var updatedObj = {};
var data = Object.keys(obj).map(function(key) {
var values = obj[key];
var memberArr = new Array();
var dataObj = values.reduce(function(store, value) {
var storeKey = value.replace(/[0-9]/g, '');
var number = Number(value.replace(/^\D+/g, ''));
if(storeKey !== 'SELF' && storeKey !== 'SPOUSE') {
var arr = new Array();
for(i = 0; i < number; i++) {
arr.push(storeKey);
memberArr.push(storeKey);
}
store[storeKey] = arr;
} else {
var anotherArr = new Array(storeKey);
memberArr.push(storeKey);
store[storeKey] = anotherArr;
}
return store;
}, {});
memberArr.sort(function(a, b) {
return b - a;
})
var sortedMemberArr = memberArr.map(function(member, index) {
return member+''+(index+1);
})
updatedObj[key] = sortedMemberArr;
})
console.log(updatedObj)
/*
// Code Using Modern Syntax
const data = Object.entries(obj).map(([key, value]) => {
const memberCount = value.reduce((store, val) => {
const key = val.replace(/[0-9]/g, '');
const number = +val.replace(/^\D+/g, '');
if(!['SELF', 'SPOUSE'].includes(key)) {
store[key] = Array(number).fill(key);
} else {
store[key] = [key];
}
return store;
}, {})
const sortedMembers = Object.values(memberCount).flat().sort((a, b) => b - a);
const sortedMembersWithNumber = sortedMembers.map((member, index) => `${member}${index+1}`)
return [key, sortedMembersWithNumber]
})
const updatedObj = Object.fromEntries(data);
console.log(updatedObj)
*/

Find the Words with an even number of occurrences in an Array - Javascript

Given an array of words, write a function that returns an array of the words that occur an even number of times.
function even(["hello", "hi", "hello", "elephant", "hi"]);
That output should be:
["hello", "hi"]
This has been a toy problem I have been struggling with recently. I have solved similar problems counting and returning the number of occurrences of elements in an array but am having trouble taking that logic and applying it to this problem.
This is what I have tried so far, but have hit a wall when trying to output just the even occurrences:
function even(collection) {
var results = [];
for(var i = 0; i < collection.length; i++){
var value = collection[i];
if(results[value]){
results[value] = results[value] + 1;
}else{
results[value] = 1;
}
}
return results;
}

You can use reduce to get an actual count of the words, then simply return an array of the ones that have an even count:
function even(wordsArr) {
//Object of words and counts
var wordCounts = wordsArr.reduce(function(counts, word) {
if (!counts.hasOwnProperty(word)) {
counts[word] = 0;
}
counts[word]++;
return counts;
}, {});
//Now filter that out and return
return Object.keys(wordCounts).filter(function(word) {
return wordCounts[word] % 2 === 0
});
}
even(["hello", "hi", "hello", "elephant", "hi"]); //["hello", "hi"]

var arr = ["hello", "hi", "hello", "elephant", "hi"];
function onlyEvens( arr )
{
var countObj = {};
for( var i = 0; i < arr.length; i++ )
{
var item = arr[i];
if( countObj[ item ] !== undefined )
countObj[item]++;
else
countObj[item] = 1;
}//for()
var filteredArray = [];
for(var key in countObj )
{
if( countObj[key] % 2 == 0 )
filteredArray.push( key );
}
return filteredArray;
}//onlyEvens()
console.log( onlyEvens( arr ) );

Issues in your code:
you use collection instead of words
you cannot access array the associative way. You must declare it as object:
results[value]
you return result variable, but it is undeclared.
return result;
results only contains the occurrences of every word. There miss the code that calculates if the occurrences of a word are odd or even.
fixed code:
function even(words) { // <<< in your code was collection
var results = {};
for(var i = 0; i < words.length; i++){
var value = words[i];
if(results[value]){
results[value] = results[value] + 1;
}else{
results[value] = 1;
}
}
var ret = [];
for(var word in results)
if(results[word]%2 !== 0)
rest.push(word);
return ret;
}

function even(list) {
var d = list.reduce(function(d, w) { d[w] = !d[w]; return d; }, {});
return Object.keys(d).filter(function(w) { return !d[w]; });
}
console.log(even(["hello", "hi", "hello", "elephant", "hi"]));
console.log(even(["hello", "yo", "yo", "hi", "hello", "yo", "elephant", "hi"]));
Explanation: Use the array .reduce() method to create an object (d) with a property for each word (w) with a boolean value indicating whether the word has an odd number of occurrences. Then .filter() the keys to get all the ones that are not odd.

If you previously sort the array you can filter it as required in just a code line like this :
var even = (str) => str.sort().filter((element, index, arr) => index+1 === arr.lastIndexOf(element));
console.log(even(["hello", "hello", "hi", "elephant", "hi", "hi"])); //[ 'hello', 'hi' ]

Convert a JavaScript object's keys with dot notation into an object [duplicate]

I threw some code together to flatten and un-flatten complex/nested JavaScript objects. It works, but it's a bit slow (triggers the 'long script' warning).
For the flattened names I want "." as the delimiter and [INDEX] for arrays.
Examples:
un-flattened | flattened
---------------------------
{foo:{bar:false}} => {"foo.bar":false}
{a:[{b:["c","d"]}]} => {"a[0].b[0]":"c","a[0].b[1]":"d"}
[1,[2,[3,4],5],6] => {"[0]":1,"[1].[0]":2,"[1].[1].[0]":3,"[1].[1].[1]":4,"[1].[2]":5,"[2]":6}
I created a benchmark that ~simulates my use case http://jsfiddle.net/WSzec/
Get a nested object
Flatten it
Look through it and possibly modify it while flattened
Unflatten it back to it's original nested format to be shipped away
I would like faster code: For clarification, code that completes the JSFiddle benchmark (http://jsfiddle.net/WSzec/) significantly faster (~20%+ would be nice) in IE 9+, FF 24+, and Chrome 29+.
Here's the relevant JavaScript code: Current Fastest: http://jsfiddle.net/WSzec/6/
var unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array.isArray(data))
return data;
var result = {}, cur, prop, idx, last, temp;
for(var p in data) {
cur = result, prop = "", last = 0;
do {
idx = p.indexOf(".", last);
temp = p.substring(last, idx !== -1 ? idx : undefined);
cur = cur[prop] || (cur[prop] = (!isNaN(parseInt(temp)) ? [] : {}));
prop = temp;
last = idx + 1;
} while(idx >= 0);
cur[prop] = data[p];
}
return result[""];
}
var flatten = function(data) {
var result = {};
function recurse (cur, prop) {
if (Object(cur) !== cur) {
result[prop] = cur;
} else if (Array.isArray(cur)) {
for(var i=0, l=cur.length; i<l; i++)
recurse(cur[i], prop ? prop+"."+i : ""+i);
if (l == 0)
result[prop] = [];
} else {
var isEmpty = true;
for (var p in cur) {
isEmpty = false;
recurse(cur[p], prop ? prop+"."+p : p);
}
if (isEmpty)
result[prop] = {};
}
}
recurse(data, "");
return result;
}
EDIT 1 Modified the above to #Bergi 's implementation which is currently the fastest. As an aside, using ".indexOf" instead of "regex.exec" is around 20% faster in FF but 20% slower in Chrome; so I'll stick with the regex since it's simpler (here's my attempt at using indexOf to replace the regex http://jsfiddle.net/WSzec/2/).
EDIT 2 Building on #Bergi 's idea I managed to created a faster non-regex version (3x faster in FF and ~10% faster in Chrome). http://jsfiddle.net/WSzec/6/ In the this (the current) implementation the rules for key names are simply, keys cannot start with an integer or contain a period.
Example:
{"foo":{"bar":[0]}} => {"foo.bar.0":0}
EDIT 3 Adding #AaditMShah 's inline path parsing approach (rather than String.split) helped to improve the unflatten performance. I'm very happy with the overall performance improvement reached.
The latest jsfiddle and jsperf:
http://jsfiddle.net/WSzec/14/
http://jsperf.com/flatten-un-flatten/4

Here's my much shorter implementation:
Object.unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array.isArray(data))
return data;
var regex = /\.?([^.\[\]]+)|\[(\d+)\]/g,
resultholder = {};
for (var p in data) {
var cur = resultholder,
prop = "",
m;
while (m = regex.exec(p)) {
cur = cur[prop] || (cur[prop] = (m[2] ? [] : {}));
prop = m[2] || m[1];
}
cur[prop] = data[p];
}
return resultholder[""] || resultholder;
};
flatten hasn't changed much (and I'm not sure whether you really need those isEmpty cases):
Object.flatten = function(data) {
var result = {};
function recurse (cur, prop) {
if (Object(cur) !== cur) {
result[prop] = cur;
} else if (Array.isArray(cur)) {
for(var i=0, l=cur.length; i<l; i++)
recurse(cur[i], prop + "[" + i + "]");
if (l == 0)
result[prop] = [];
} else {
var isEmpty = true;
for (var p in cur) {
isEmpty = false;
recurse(cur[p], prop ? prop+"."+p : p);
}
if (isEmpty && prop)
result[prop] = {};
}
}
recurse(data, "");
return result;
}
Together, they run your benchmark in about the half of the time (Opera 12.16: ~900ms instead of ~ 1900ms, Chrome 29: ~800ms instead of ~1600ms).
Note: This and most other solutions answered here focus on speed and are susceptible to prototype pollution and shold not be used on untrusted objects.

I wrote two functions to flatten and unflatten a JSON object.
Flatten a JSON object:
var flatten = (function (isArray, wrapped) {
return function (table) {
return reduce("", {}, table);
};
function reduce(path, accumulator, table) {
if (isArray(table)) {
var length = table.length;
if (length) {
var index = 0;
while (index < length) {
var property = path + "[" + index + "]", item = table[index++];
if (wrapped(item) !== item) accumulator[property] = item;
else reduce(property, accumulator, item);
}
} else accumulator[path] = table;
} else {
var empty = true;
if (path) {
for (var property in table) {
var item = table[property], property = path + "." + property, empty = false;
if (wrapped(item) !== item) accumulator[property] = item;
else reduce(property, accumulator, item);
}
} else {
for (var property in table) {
var item = table[property], empty = false;
if (wrapped(item) !== item) accumulator[property] = item;
else reduce(property, accumulator, item);
}
}
if (empty) accumulator[path] = table;
}
return accumulator;
}
}(Array.isArray, Object));
Performance:
It's faster than the current solution in Opera. The current solution is 26% slower in Opera.
It's faster than the current solution in Firefox. The current solution is 9% slower in Firefox.
It's faster than the current solution in Chrome. The current solution is 29% slower in Chrome.
Unflatten a JSON object:
function unflatten(table) {
var result = {};
for (var path in table) {
var cursor = result, length = path.length, property = "", index = 0;
while (index < length) {
var char = path.charAt(index);
if (char === "[") {
var start = index + 1,
end = path.indexOf("]", start),
cursor = cursor[property] = cursor[property] || [],
property = path.slice(start, end),
index = end + 1;
} else {
var cursor = cursor[property] = cursor[property] || {},
start = char === "." ? index + 1 : index,
bracket = path.indexOf("[", start),
dot = path.indexOf(".", start);
if (bracket < 0 && dot < 0) var end = index = length;
else if (bracket < 0) var end = index = dot;
else if (dot < 0) var end = index = bracket;
else var end = index = bracket < dot ? bracket : dot;
var property = path.slice(start, end);
}
}
cursor[property] = table[path];
}
return result[""];
}
Performance:
It's faster than the current solution in Opera. The current solution is 5% slower in Opera.
It's slower than the current solution in Firefox. My solution is 26% slower in Firefox.
It's slower than the current solution in Chrome. My solution is 6% slower in Chrome.
Flatten and unflatten a JSON object:
Overall my solution performs either equally well or even better than the current solution.
Performance:
It's faster than the current solution in Opera. The current solution is 21% slower in Opera.
It's as fast as the current solution in Firefox.
It's faster than the current solution in Firefox. The current solution is 20% slower in Chrome.
Output format:
A flattened object uses the dot notation for object properties and the bracket notation for array indices:
{foo:{bar:false}} => {"foo.bar":false}
{a:[{b:["c","d"]}]} => {"a[0].b[0]":"c","a[0].b[1]":"d"}
[1,[2,[3,4],5],6] => {"[0]":1,"[1][0]":2,"[1][1][0]":3,"[1][1][1]":4,"[1][2]":5,"[2]":6}
In my opinion this format is better than only using the dot notation:
{foo:{bar:false}} => {"foo.bar":false}
{a:[{b:["c","d"]}]} => {"a.0.b.0":"c","a.0.b.1":"d"}
[1,[2,[3,4],5],6] => {"0":1,"1.0":2,"1.1.0":3,"1.1.1":4,"1.2":5,"2":6}
Advantages:
Flattening an object is faster than the current solution.
Flattening and unflattening an object is as fast as or faster than the current solution.
Flattened objects use both the dot notation and the bracket notation for readability.
Disadvantages:
Unflattening an object is slower than the current solution in most (but not all) cases.
The current JSFiddle demo gave the following values as output:
Nested : 132175 : 63
Flattened : 132175 : 564
Nested : 132175 : 54
Flattened : 132175 : 508
My updated JSFiddle demo gave the following values as output:
Nested : 132175 : 59
Flattened : 132175 : 514
Nested : 132175 : 60
Flattened : 132175 : 451
I'm not really sure what that means, so I'll stick with the jsPerf results. After all jsPerf is a performance benchmarking utility. JSFiddle is not.

ES6 version:
const flatten = (obj, path = '') => {
if (!(obj instanceof Object)) return {[path.replace(/\.$/g, '')]:obj};
return Object.keys(obj).reduce((output, key) => {
return obj instanceof Array ?
{...output, ...flatten(obj[key], path + '[' + key + '].')}:
{...output, ...flatten(obj[key], path + key + '.')};
}, {});
}
Example:
console.log(flatten({a:[{b:["c","d"]}]}));
console.log(flatten([1,[2,[3,4],5],6]));

3 ½ Years later...
For my own project I wanted to flatten JSON objects in mongoDB dot notation and came up with a simple solution:
/**
* Recursively flattens a JSON object using dot notation.
*
* NOTE: input must be an object as described by JSON spec. Arbitrary
* JS objects (e.g. {a: () => 42}) may result in unexpected output.
* MOREOVER, it removes keys with empty objects/arrays as value (see
* examples bellow).
*
* #example
* // returns {a:1, 'b.0.c': 2, 'b.0.d.e': 3, 'b.1': 4}
* flatten({a: 1, b: [{c: 2, d: {e: 3}}, 4]})
* // returns {a:1, 'b.0.c': 2, 'b.0.d.e.0': true, 'b.0.d.e.1': false, 'b.0.d.e.2.f': 1}
* flatten({a: 1, b: [{c: 2, d: {e: [true, false, {f: 1}]}}]})
* // return {a: 1}
* flatten({a: 1, b: [], c: {}})
*
* #param obj item to be flattened
* #param {Array.string} [prefix=[]] chain of prefix joined with a dot and prepended to key
* #param {Object} [current={}] result of flatten during the recursion
*
* #see https://docs.mongodb.com/manual/core/document/#dot-notation
*/
function flatten (obj, prefix, current) {
prefix = prefix || []
current = current || {}
// Remember kids, null is also an object!
if (typeof (obj) === 'object' && obj !== null) {
Object.keys(obj).forEach(key => {
this.flatten(obj[key], prefix.concat(key), current)
})
} else {
current[prefix.join('.')] = obj
}
return current
}
Features and/or caveats
It only accepts JSON objects. So if you pass something like {a: () => {}} you might not get what you wanted!
It removes empty arrays and objects. So this {a: {}, b: []} is flattened to {}.

Use this library:
npm install flat
Usage (from https://www.npmjs.com/package/flat):
Flatten:
var flatten = require('flat')
flatten({
key1: {
keyA: 'valueI'
},
key2: {
keyB: 'valueII'
},
key3: { a: { b: { c: 2 } } }
})
// {
// 'key1.keyA': 'valueI',
// 'key2.keyB': 'valueII',
// 'key3.a.b.c': 2
// }
Un-flatten:
var unflatten = require('flat').unflatten
unflatten({
'three.levels.deep': 42,
'three.levels': {
nested: true
}
})
// {
// three: {
// levels: {
// deep: 42,
// nested: true
// }
// }
// }

Here's another approach that runs slower (about 1000ms) than the above answer, but has an interesting idea :-)
Instead of iterating through each property chain, it just picks the last property and uses a look-up-table for the rest to store the intermediate results. This look-up-table will be iterated until there are no property chains left and all values reside on uncocatenated properties.
JSON.unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array.isArray(data))
return data;
var regex = /\.?([^.\[\]]+)$|\[(\d+)\]$/,
props = Object.keys(data),
result, p;
while(p = props.shift()) {
var m = regex.exec(p),
target;
if (m.index) {
var rest = p.slice(0, m.index);
if (!(rest in data)) {
data[rest] = m[2] ? [] : {};
props.push(rest);
}
target = data[rest];
} else {
target = result || (result = (m[2] ? [] : {}));
}
target[m[2] || m[1]] = data[p];
}
return result;
};
It currently uses the data input parameter for the table, and puts lots of properties on it - a non-destructive version should be possible as well. Maybe a clever lastIndexOf usage performs better than the regex (depends on the regex engine).
See it in action here.

You can use https://github.com/hughsk/flat
Take a nested Javascript object and flatten it, or unflatten an object with delimited keys.
Example from the doc
var flatten = require('flat')
flatten({
key1: {
keyA: 'valueI'
},
key2: {
keyB: 'valueII'
},
key3: { a: { b: { c: 2 } } }
})
// {
// 'key1.keyA': 'valueI',
// 'key2.keyB': 'valueII',
// 'key3.a.b.c': 2
// }
var unflatten = require('flat').unflatten
unflatten({
'three.levels.deep': 42,
'three.levels': {
nested: true
}
})
// {
// three: {
// levels: {
// deep: 42,
// nested: true
// }
// }
// }

This code recursively flattens out JSON objects.
I included my timing mechanism in the code and it gives me 1ms but I'm not sure if that's the most accurate one.
var new_json = [{
"name": "fatima",
"age": 25,
"neighbour": {
"name": "taqi",
"location": "end of the street",
"property": {
"built in": 1990,
"owned": false,
"years on market": [1990, 1998, 2002, 2013],
"year short listed": [], //means never
}
},
"town": "Mountain View",
"state": "CA"
},
{
"name": "qianru",
"age": 20,
"neighbour": {
"name": "joe",
"location": "opposite to the park",
"property": {
"built in": 2011,
"owned": true,
"years on market": [1996, 2011],
"year short listed": [], //means never
}
},
"town": "Pittsburgh",
"state": "PA"
}]
function flatten(json, flattened, str_key) {
for (var key in json) {
if (json.hasOwnProperty(key)) {
if (json[key] instanceof Object && json[key] != "") {
flatten(json[key], flattened, str_key + "." + key);
} else {
flattened[str_key + "." + key] = json[key];
}
}
}
}
var flattened = {};
console.time('flatten');
flatten(new_json, flattened, "");
console.timeEnd('flatten');
for (var key in flattened){
console.log(key + ": " + flattened[key]);
}
Output:
flatten: 1ms
.0.name: fatima
.0.age: 25
.0.neighbour.name: taqi
.0.neighbour.location: end of the street
.0.neighbour.property.built in: 1990
.0.neighbour.property.owned: false
.0.neighbour.property.years on market.0: 1990
.0.neighbour.property.years on market.1: 1998
.0.neighbour.property.years on market.2: 2002
.0.neighbour.property.years on market.3: 2013
.0.neighbour.property.year short listed:
.0.town: Mountain View
.0.state: CA
.1.name: qianru
.1.age: 20
.1.neighbour.name: joe
.1.neighbour.location: opposite to the park
.1.neighbour.property.built in: 2011
.1.neighbour.property.owned: true
.1.neighbour.property.years on market.0: 1996
.1.neighbour.property.years on market.1: 2011
.1.neighbour.property.year short listed:
.1.town: Pittsburgh
.1.state: PA

Here's mine. It runs in <2ms in Google Apps Script on a sizable object. It uses dashes instead of dots for separators, and it doesn't handle arrays specially like in the asker's question, but this is what I wanted for my use.
function flatten (obj) {
var newObj = {};
for (var key in obj) {
if (typeof obj[key] === 'object' && obj[key] !== null) {
var temp = flatten(obj[key])
for (var key2 in temp) {
newObj[key+"-"+key2] = temp[key2];
}
} else {
newObj[key] = obj[key];
}
}
return newObj;
}
Example:
var test = {
a: 1,
b: 2,
c: {
c1: 3.1,
c2: 3.2
},
d: 4,
e: {
e1: 5.1,
e2: 5.2,
e3: {
e3a: 5.31,
e3b: 5.32
},
e4: 5.4
},
f: 6
}
Logger.log("start");
Logger.log(JSON.stringify(flatten(test),null,2));
Logger.log("done");
Example output:
[17-02-08 13:21:05:245 CST] start
[17-02-08 13:21:05:246 CST] {
"a": 1,
"b": 2,
"c-c1": 3.1,
"c-c2": 3.2,
"d": 4,
"e-e1": 5.1,
"e-e2": 5.2,
"e-e3-e3a": 5.31,
"e-e3-e3b": 5.32,
"e-e4": 5.4,
"f": 6
}
[17-02-08 13:21:05:247 CST] done

Object.prototype.flatten = function (obj) {
let ans = {};
let anotherObj = { ...obj };
function performFlatten(anotherObj) {
Object.keys(anotherObj).forEach((key, idx) => {
if (typeof anotherObj[key] !== 'object') {
ans[key] = anotherObj[key];
console.log('ans so far : ', ans);
} else {
console.log(key, { ...anotherObj[key] });
performFlatten(anotherObj[key]);
}
})
}
performFlatten(anotherObj);
return ans;
}
let ans = flatten(obj);
console.log(ans);

I added +/- 10-15% efficiency to the selected answer by minor code refactoring and moving the recursive function outside of the function namespace.
See my question: Are namespaced functions reevaluated on every call? for why this slows nested functions down.
function _flatten (target, obj, path) {
var i, empty;
if (obj.constructor === Object) {
empty = true;
for (i in obj) {
empty = false;
_flatten(target, obj[i], path ? path + '.' + i : i);
}
if (empty && path) {
target[path] = {};
}
}
else if (obj.constructor === Array) {
i = obj.length;
if (i > 0) {
while (i--) {
_flatten(target, obj[i], path + '[' + i + ']');
}
} else {
target[path] = [];
}
}
else {
target[path] = obj;
}
}
function flatten (data) {
var result = {};
_flatten(result, data, null);
return result;
}
See benchmark.

Here's a recursive solution for flatten I put together in PowerShell:
#---helper function for ConvertTo-JhcUtilJsonTable
#
function getNodes {
param (
[Parameter(Mandatory)]
[System.Object]
$job,
[Parameter(Mandatory)]
[System.String]
$path
)
$t = $job.GetType()
$ct = 0
$h = #{}
if ($t.Name -eq 'PSCustomObject') {
foreach ($m in Get-Member -InputObject $job -MemberType NoteProperty) {
getNodes -job $job.($m.Name) -path ($path + '.' + $m.Name)
}
}
elseif ($t.Name -eq 'Object[]') {
foreach ($o in $job) {
getNodes -job $o -path ($path + "[$ct]")
$ct++
}
}
else {
$h[$path] = $job
$h
}
}
#---flattens a JSON document object into a key value table where keys are proper JSON paths corresponding to their value
#
function ConvertTo-JhcUtilJsonTable {
param (
[Parameter(Mandatory = $true, ValueFromPipeline = $true)]
[System.Object[]]
$jsonObj
)
begin {
$rootNode = 'root'
}
process {
foreach ($o in $jsonObj) {
$table = getNodes -job $o -path $rootNode
# $h = #{}
$a = #()
$pat = '^' + $rootNode
foreach ($i in $table) {
foreach ($k in $i.keys) {
# $h[$k -replace $pat, ''] = $i[$k]
$a += New-Object -TypeName psobject -Property #{'Key' = $($k -replace $pat, ''); 'Value' = $i[$k]}
# $h[$k -replace $pat, ''] = $i[$k]
}
}
# $h
$a
}
}
end{}
}
Example:
'{"name": "John","Address": {"house": "1234", "Street": "Boogie Ave"}, "pets": [{"Type": "Dog", "Age": 4, "Toys": ["rubberBall", "rope"]},{"Type": "Cat", "Age": 7, "Toys": ["catNip"]}]}' | ConvertFrom-Json | ConvertTo-JhcUtilJsonTable
Key Value
--- -----
.Address.house 1234
.Address.Street Boogie Ave
.name John
.pets[0].Age 4
.pets[0].Toys[0] rubberBall
.pets[0].Toys[1] rope
.pets[0].Type Dog
.pets[1].Age 7
.pets[1].Toys[0] catNip
.pets[1].Type Cat

I wanted an approach so that I could be able to easily convert my json data into a csv file.
The scenario is: I query data from somewhere and I receive an array of some model, like a bank extract.
This approach below is used to parse each one of these entries.
function jsonFlatter(data, previousKey, obj) {
obj = obj || {}
previousKey = previousKey || ""
Object.keys(data).map(key => {
let newKey = `${previousKey}${previousKey ? "_" : ""}${key}`
let _value = data[key]
let isArray = Array.isArray(_value)
if (typeof _value !== "object" || isArray || _value == null) {
if (isArray) {
_value = JSON.stringify(_value)
} else if (_value == null) {
_value = "null"
}
obj[newKey] = _value
} else if (typeof _value === "object") {
if (!Object.keys(_value).length) {
obj[newKey] = "null"
} else {
return jsonFlatter(_value, newKey, obj)
}
}
})
return obj
}
This way, I can count on the uniformity of the keys and inner keys of my object model, but arrays are simply stringified since I can't rely on their uniformity. Also, empty objects become the string "null", since I still want it's key to appear in the final result.
Usage example:
const test_data = {
a: {
aa: {
aaa: 4354,
aab: 654
},
ab: 123
},
b: 234,
c: {},
d: []
}
console.log('result', jsonFlatter(test_data))
#### output
{
"a_aa_aaa": 4354,
"a_aa_aab": 654,
"a_ab": 123,
"b": 234,
"c": "null",
"d": "[]"
}

try this one:
function getFlattenObject(data, response = {}) {
for (const key in data) {
if (typeof data[key] === 'object' && !Array.isArray(data[key])) {
getFlattenObject(data[key], response);
} else {
response[key] = data[key];
}
}
return response;
}

I'd like to add a new version of flatten case (this is what i needed :)) which, according to my probes with the above jsFiddler, is slightly faster then the currently selected one.
Moreover, me personally see this snippet a bit more readable, which is of course important for multi-developer projects.
function flattenObject(graph) {
let result = {},
item,
key;
function recurr(graph, path) {
if (Array.isArray(graph)) {
graph.forEach(function (itm, idx) {
key = path + '[' + idx + ']';
if (itm && typeof itm === 'object') {
recurr(itm, key);
} else {
result[key] = itm;
}
});
} else {
Reflect.ownKeys(graph).forEach(function (p) {
key = path + '.' + p;
item = graph[p];
if (item && typeof item === 'object') {
recurr(item, key);
} else {
result[key] = item;
}
});
}
}
recurr(graph, '');
return result;
}

Here is some code I wrote to flatten an object I was working with. It creates a new class that takes every nested field and brings it into the first layer. You could modify it to unflatten by remembering the original placement of the keys. It also assumes the keys are unique even across nested objects. Hope it helps.
class JSONFlattener {
ojson = {}
flattenedjson = {}
constructor(original_json) {
this.ojson = original_json
this.flattenedjson = {}
this.flatten()
}
flatten() {
Object.keys(this.ojson).forEach(function(key){
if (this.ojson[key] == null) {
} else if (this.ojson[key].constructor == ({}).constructor) {
this.combine(new JSONFlattener(this.ojson[key]).returnJSON())
} else {
this.flattenedjson[key] = this.ojson[key]
}
}, this)
}
combine(new_json) {
//assumes new_json is a flat array
Object.keys(new_json).forEach(function(key){
if (!this.flattenedjson.hasOwnProperty(key)) {
this.flattenedjson[key] = new_json[key]
} else {
console.log(key+" is a duplicate key")
}
}, this)
}
returnJSON() {
return this.flattenedjson
}
}
console.log(new JSONFlattener(dad_dictionary).returnJSON())
As an example, it converts
nested_json = {
"a": {
"b": {
"c": {
"d": {
"a": 0
}
}
}
},
"z": {
"b":1
},
"d": {
"c": {
"c": 2
}
}
}
into
{ a: 0, b: 1, c: 2 }

You can try out the package jpflat.
It flattens, inflates, resolves promises, flattens arrays, has customizable path creation and customizable value serialization.
The reducers and serializers receive the whole path as an array of it's parts, so more complex operations can be done to the path instead of modifying a single key or changing the delimiter.
Json path is the default, hence "jp"flat.
https://www.npmjs.com/package/jpflat
let flatFoo = await require('jpflat').flatten(foo)

Remove duplicate objects from array by a certain merge algorithm

Here's what I have in mind:
Given an array of objects:
[
{
"name": "Kirk",
"count": 1
},
{
"name": "Spock",
"count": 1
},
{
"name": "Kirk",
"count": 1
}
]
I am trying to get:
[
{
"name": "Kirk",
"count": 2
},
{
"name": "Spock",
"count": 1
}
]
I am wondering if there's already an algorithm, perhaps combining some higher order functions to achieve this. I could do this easily with loops, but I am looking for a way to solve it using higher order functions. If someone could point me to what I should use to achieve this, it would be great. Again, I'm looking for something as elegant as possible (two maps and a filter would not be a big improvement from loops).
This is my current solution and I'm looking for something better (and by better I mean more expressive):
function mergeDuplicates(input) {
var output = [];
var existingItem = null;
input.forEach(function (inputItem) {
existingItem = _.find(output, function (outputItem) {
return inputItem.name === outputItem.name;
});
existingItem ? existingItem.count += 1 : output.push({
name: inputItem.name,
count: 1
});
existingItem = null;
});
return output;
}
To make line #10 more clear: in the original array, count might be either non-existing or 1, hence I set it to 1.

I think the best way would be to hash each object if it does not already exist, and delete the ones that you found already hashed in your structure. This way, you'd be checking the existence of each object only 1 (depends on your hash scheme).

Just a function if you would like to use.
function merge(arr) {
for(var o = {}, i; i=arr.shift(); o[i.name] = i.count + (o[i.name] || 0));
for(i in o) arr.push({name:i, count:o[i]});
}
Calling :
var myArray = [{"name":"Kirk","count":1},
{"name":"Spock","count":1},
{"name":"Kirk","count":1}];
merge(myArray);
// myArray is now : [{"name":"Kirk","count":2}, {"name":"Spock","count":1}]

You can use reduce which is actually a fold.
a.reduce(function(p, c) {
var n = c.name;
if (p[n])
p[n].count++;
else
p[n] = c;
return p;
}, {})
will give you a object with "Kirk" and "Spock" as the key, what you want as values.

I know this is an old question, but I couldn't resist trying to solve it. Instead of two maps and a filter, we use a sort and then a reduce. This was a fun one to sort out :-)
function mergeDuplicates(list, prop, cb){
return list.sort(function(a,b){
if(a[prop] < b[prop]){ return -1;}
if(a[prop] > b[prop]){return 1;}
return 0;
}).reduce(function(acc, item, index, array){
if(index > 0 && array[index-1][prop] === item[prop]){
cb(acc[acc.length-1], item);
return acc;
}else{
var newItem = Object.assign({}, item);
cb(newItem);
acc.push(newItem);
return acc;
}
}, []);
}
Then use it like this:
var newList = mergeDuplicates(list, "name", function(item, dup){
if(dup){
item.count++;
}else{
item.count = 1;
}
});
EDIT: Here's another take at it using reduce and using an object as a hashmap to store duplicates (similar to some of the other answers). This one uses ramdajs
const mergeDups = (cb, prop, list) => R.pipe(
R.reduce((acc, item) => (
R.has(item[prop], acc) ?
R.assoc(item[prop], cb(acc[item[prop]], item), acc) :
R.assoc(item[prop], cb(item), acc)
), {}),
R.values
)(list);
const cb = (i, d) => ( !R.isNil(d) ?
R.assoc('count', i.count + 1, i) :
R.assoc('count', 1, i) )
mergeDups(cb, 'name', items);
Here it is in the repl on Ramda's site

Try this better i'll useful resolve your issues
cleanup(arrayOfObj, 'name');
function cleanup(arr, prop) {
var new_arr = [];
var lookup = {};
for (var i in arr) {
lookup[arr[i][prop]] = arr[i];
}
for (i in lookup) {
new_arr.push(lookup[i]);
}
return new_arr;
}

Yet another version using reduce function:
var items =
[
{
"name": "Kirk",
"count": 1
},
{
"name": "Spock",
"count": 1
},
{
"name": "Kirk",
"count": 1
}
];
var filtered = items.reduce(function(prev, current,index){
if(!(current.name in prev.keys)) {
prev.keys[current.name] = index;
prev.result.push(current);
}
else{
prev.result[prev.keys[current.name]].count += current.count;
}
return prev;
},{result: [], keys: []}).result;
document.getElementById("output").innerHTML = JSON.stringify(filtered,null,2);
<pre id='output' />

Count duplicates within an Array of Objects

I have an array of objects as follows within my server side JS:
[
{
"Company": "IBM"
},
{
"Person": "ACORD LOMA"
},
{
"Company": "IBM"
},
{
"Company": "MSFT"
},
{
"Place": "New York"
}
]
I need to iterate through this structure, detect any duplicates and then create a count of a duplicate is found along side each value.
Both of the values must match to qualify as a duplicate e.g. "Company": "IBM" is not a match for "Company": "MSFT".
I have the options of changing the inbound array of objects if needed. I would like the output to be an object, but am really struggling to get this to work.
EDIT: Here is the code I have so far where processArray is the array as listed above.
var returnObj = {};
for(var x=0; x < processArray.length; x++){
//Check if we already have the array item as a key in the return obj
returnObj[processArray[x]] = returnObj[processArray[x]] || processArray[x].toString();
// Setup the count field
returnObj[processArray[x]].count = returnObj[processArray[x]].count || 1;
// Increment the count
returnObj[processArray[x]].count = returnObj[processArray[x]].count + 1;
}
console.log('====================' + JSON.stringify(returnObj));

For example:
counter = {}
yourArray.forEach(function(obj) {
var key = JSON.stringify(obj)
counter[key] = (counter[key] || 0) + 1
})
Docs: Array.forEach, JSON.stringify.

Object.prototype.equals = function(o){
for(var key in o)
if(o.hasOwnProperty(key) && this.hasOwnProperty(key))
if(this[key] != o[key])
return false;
return true;
}
var array = [/*initial array*/],
newArray = [],
ok = true;
for(var i=0,l=array.length-1;i<l;i++)
for(var j=i;j<l+1;j++)
{
if(!array[i].equals(array[j]))
newArray.push(array[i]);
}

We are required to write a JavaScript function that takes in one such array of objects. The function creates and return a new array in which no objects are repeated (by repeated we mean objects having same value for "Country" property.)
Moreover, the function should assign a count property to each object that represents the number of times they appeared in the original array.
const arr = [
{
"Country": "BR",
"New Lv1−Lv2": "#N/A"
},
{
"Country": "BR",
"New Lv1−Lv2": "#N/A"
},
{
"Country": "",
"New Lv1−Lv2": "test"
}];
const convert = (arr) => {
const res = {};
arr.forEach((obj) => {
const key = `${obj.Country}${obj["New Lv1−Lv2"]}`;
if (!res[key]) {
res[key] = { ...obj, count: 0 };
};
res[key].count += 1;
});
return Object.values(res);
};
console.log(convert(arr));
know more

With ES6, one can use Array#reduce with an object to store the counts.
let counts = arr.reduce((acc, curr)=>{
const str = JSON.stringify(curr);
acc[str] = (acc[str] || 0) + 1;
return acc;
}, {});
Demo
To create a new array without duplicates, a Set can be used with Array#filter.
let set = new Set;
let res = arr.filter(x => {
const str = JSON.stringify(x);
return !set.has(str) && set.add(str);
});
Demo