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Validating a data input javascript

I have been looking to validate the data input to check whether it is a integer or a string. I looked around and saw some suggestions and typeof suggestions but nothing seems to work.
var nam = prompt("Enter name:")
person.push(nam);
var mk1 = prompt("Enter mark 1:");
var mk1 = parseInt(mk1);
mark1.push(mk1);

If you want to check whether input string is not a number try this:
if (isNaN(parseInt(name, 10)) {
//name is String
} else {
//name is Number
}

use the === operator as below
if (mk1 === parseInt(mk1 , 10))
alert("mk1 is integer")
else
alert("mk1 is not an integer. May be String")
If you don't know that the argument is a number-
function isInt(n){
return Number(n)===n && n%1===0;
}

Try this way to find input type;
if(!isNaN(parseInt(mk1)))
// for integer
else if(!isNaN(parseFloat(mk1)))
//for float
else
// String

When you prompt() the user for data, you always get a string. If you want to check, whether it actually contains just a number, you can try this:
var value = prompt('...'),
num = parseInt(value, 10);
if (num == value) {
// ... it is an integer, use `num`
} else {
// ... it's not an integer (or not *just* an integer), use `value`
}
(or use parseFloat(value) for real numbers).

It's hard to say what are you trying to do really. You seem to declare var mk1 twice, which looks a bit strange. Also, even if parseInt fails (then returns NaN [Not a Number]) you add it to mark1, which is probably not what you want. Have a look at this:
var nam = prompt("Enter name:")
person.push(nam);
var mk1 = prompt("Enter mark 1:");
mk1 = parseInt(mk1);
if (Number.isNaN(mk1) === false) {
mark1.push(mk1);
} else {
alert("mark 1 is not a number");
}

Use this function:
isNaN(parseInt(mk1))
It will return "true" if not a number, and "false" if a number

jQuery Validation, Numeric Value Only

I'm trying to validate a form input value. The function below states is the value of the input is a number below 150, show error. Works as it should. However, I want to add to it. If the value contains ANYTHING other than a numeric value AND/OR is a value under 150, show error...
How can I modify?
if ($('.billboard-height').val() < 150) {
$('.sb-billboardalert').fadeIn(600);
}

Since your more thorough validation should be on the server-side anyway, you could just use parseInt or parseFloat depending on what sort of value you are expecting. Then check if the result is actually a number and that it also meets your constraints:
var number = parseFloat($('.billboard-height').val()); // or parseInt depending on expected input
if (isNaN(number) || number < 150) {
$('.sb-billboardalert').fadeIn(600);
}
EDIT:
Based on your comments, you are entering regex land. I gather you only ever want a natural number (and the way parseInt/parseFloat ignores trailing non-numeric characters like px, em, etc. is not ok). How about:
var val = $('.billboard-height').val();
var number = parseInt(val, 10);
if ( ! val.match(/^[0-9]{3,4}$/) || number < 150) {
$('.sb-billboardalert').fadeIn(600);
}
This should only allow natural numbers 150-9999.

I would suggest using regexes:
var intRegex = /^\d+$/;
var floatRegex = /^((\d+(\.\d *)?)|((\d*\.)?\d+))$/;
var str = $('#myTextBox').val();
if(intRegex.test(str) || floatRegex.test(str)) {
alert('I am a number');
...
}
Or with a single regex as per #Platinum Azure's suggestion:
var numberRegex = /^[+-]?\d+(\.\d+)?([eE][+-]?\d+)?$/;
var str = $('#myTextBox').val();
if(numberRegex.test(str)) {
alert('I am a number');
...
}
ref: checking if number entered is a digit in jquery

Don't forget the radix parameter in parseInt():
if (parseInt($('.billboard-height').val(), 10) < 150) {
It's probably faster than using a regex. Regular expressions are not known for being fast, but they are very powerful. It might be overkill for this scenario.

You can try out HTML5's built in form validation:
<input type="number" min="150">
browser support is still pretty shakey though

Any value from an input or select will be a string in javascript. You need to use parseInt() to use operators like > or <. == can be used if you use it to compare to a string like if ($('.billboard-height').val() == "150")

Try parseInt and isNaN functions for check if value is number and less than 150:
var intVal = parseInt($('.billboard-height').val());
if(!isNaN(intVal)){ //not Number
if (parseInt($('.billboard-height').val()) < 150) { //not less than 150
$('.sb-billboardalert').fadeIn(600);
}
}

If you need to support floating point numbers, you can check if a variable is valid using:
function isNumber (n) {
return !isNaN(parseFloat(n)) && isFinite(n);
}
var val = $('.billboard-height').val();
if (isNumber(val) && parseFloat(val) < 150) {
$('.sb-billboardalert').fadeIn(600);
}
If you only need to support integers, use parseInt(n, 10), where 10 is the base to convert the string to.
var val = parseInt($('.billboard-height').val(), 10);
if (val && val < 150) {
$('.sb-billboardalert').fadeIn(600);
}

// Displays an alert if s contains a non-numeric character.
function alertForNonNumeric(s) {
var rgx = /[^0-9]/;
if (s.search(rgx) !== -1) {
alert("Input contains non-numeric characters!");
}
}
JS Fiddle here
NOTE: If you want to check for negative ints as well, you can add a minus sign to the regex:
function alertForNonNumeric(s) {
var rgx = /[^0-9-]/;
if (s.search(rgx) !== -1) {
alert(s + " contains non-numeric characters!");
}
}

I use this solution, I find it quite ellegant - no alerts, user is effectively unable to enter non numeric characters.
This is jQuery example:
function digitsOnly(){
// extract only numbers from input
var num_val = $('#only_numbers').val().match(/\d+/);
$('#only_numbers').val(num_val);
}
Your html:
<input type="text" name="only_numbers" id="only_numbers" on oninput="digitsOnly();"/>

jQuery - Weird bug where 100.00 < 2.50

Having a weird issue with jQuery/JavaScript. I'm using this code:
var minimumPercent = $('.donationTextBox').val();
$('.donationTextBox').change(function() {
var donationAmount = parseFloat($('.donationTextBox').val());
donationAmount = donationAmount.toFixed(2);
if(donationAmount < minimumPercent || donationAmount == "NaN") {
$('.donationTextBox').val(minimumPercent);
}
else {
$('.donationTextBox').val(donationAmount);
}
});
This code I've written changes the value of an input box (text) so the value entered by the user is in money format (EG: 96.49) and also checks to make sure it isn't lower than the amount in minimumPercent. If it is, then it'll change the value to minimumPercent.
The problem I'm having is, say if minimumPercent holds 2.50 and the user inputs 100.00, for some strange reason it assumes that 100.00 is lower than 2.50. Although, 200.00 works fine.
Any ideas? Thanks for the help!

Try ParseFloat when you set minimumPercent.
var minimumPercent = ParseFloat($('.donationTextBox').val());
I think the is engine is comparing a string to a float, thus converting your float back to a string and when you do that 100.00 < 2.50 = true do to the left to right alphabetical comparison.
Mike

and also using toFixed will convert your float value to string, so for comparison always ues float values
var minimumPercent = parseFloat($('.donationTextBox').val());
$('.donationTextBox').change(function() {
var donationAmount = parseFloat($('.donationTextBox').val());
if(donationAmount < minimumPercent || donationAmount == "NaN") {
$('.donationTextBox').val(minimumPercent.toFixed(2));
}
else {
$('.donationTextBox').val(donationAmount.toFixed(2));
}
});

Round the value in Javascript

I have scenario where if user enters for example 000.03, I want to show the user it as .03 instead of 000.03. How can I do this with Javascript?

You can use a regular expression:
"000.03".replace(/^0+\./, ".");
Adjust it to your liking.

This actually is trickier than it first seems. Removing leading zero's is not something that is standard Javascript. I found this elegant solution online and edited it a bit.
function removeLeadingZeros(strNumber)
{
while (strNumber.substr(0,1) == '0' && strNumber.length>1)
{
strNumber = strNumber.substr(1);
}
return strNumber;
}
userInput = "000.03";
alert(removeLeadingZeros(userInput));

How about:
function showRounded(val) {
var zero = parseInt(val.split('.')[0],10) === 0;
return zero ? val.substring(val.indexOf('.')) : val.replace(/^0+/,'') );
}
console.log(showRounded('000.03')); //=> ".03"
console.log(showRounded('900.03')); //=> "900.03"
console.log(showRounded('009.03')); //=> "9.03"
Or adjust Álvaro G. Vicario's solution to get rid of leading zero's into:
String(parseFloat("090.03")).replace(/^0+\./, ".")

This function will take any string and try to parse it as a number, then format it the way you described:
function makePretty(userInput) {
var num,
str;
num = parseFloat(userInput); // e.g. 0.03
str = userInput.toString();
if (!isNaN(num) && str.substring(0, 1) === '0') {
str = str.substring(1); // e.g. .03
} else if (isNaN(num)) {
str = userInput; // it’s not a number, so just return the input
}
return str;
}
makePretty('000.03'); // '.03'
makePretty('020.03'); // '20.03'
It you feed it something it cannot parse as a number, it will just return it back.
Update: Oh, I see If the single leading zero needs to be removed as well. Updated the code.

Assuming your input's all the same format, and you want to display the .
user = "000.03";
user = user.substring(3);

You can convert a string into a number and back into a string to format it as "0.03":
var input = "000.03";
var output = (+input).toString(); // "0.03"
To get rid of any leading zeroes (e.g. ".03"), you can do:
var input = "000.03";
var output = input.substr(input.indexOf(".")); // ".03"
However, this improperly strips "20.30" to ".30". You can combine the first two methods to get around this:
var input = "000.03";
var output = Math.abs(+input) < 1 ?
input.substr(input.indexOf(".")) :
(+"000.03").toString();

How to parse float with two decimal places in javascript?

I have the following code. I would like to have it such that if price_result equals an integer, let's say 10, then I would like to add two decimal places. So 10 would be 10.00.
Or if it equals 10.6 would be 10.60. Not sure how to do this.
price_result = parseFloat(test_var.split('$')[1].slice(0,-1));

You can use toFixed() to do that
var twoPlacedFloat = parseFloat(yourString).toFixed(2)

If you need performance (like in games):
Math.round(number * 100) / 100
It's about 100 times as fast as parseFloat(number.toFixed(2))
http://jsperf.com/parsefloat-tofixed-vs-math-round

When you use toFixed, it always returns the value as a string. This sometimes complicates the code. To avoid that, you can make an alternative method for Number.
Number.prototype.round = function(p) {
p = p || 10;
return parseFloat( this.toFixed(p) );
};
and use:
var n = 22 / 7; // 3.142857142857143
n.round(3); // 3.143
or simply:
(22/7).round(3); // 3.143

To return a number, add another layer of parentheses. Keeps it clean.
var twoPlacedFloat = parseFloat((10.02745).toFixed(2));

If your objective is to parse, and your input might be a literal, then you'd expect a float and toFixed won't provide that, so here are two simple functions to provide this:
function parseFloat2Decimals(value) {
return parseFloat(parseFloat(value).toFixed(2));
}
function parseFloat2Decimals(value,decimalPlaces) {
return parseFloat(parseFloat(value).toFixed(decimalPlaces));
}

ceil from lodash is probably the best
_.ceil("315.9250488",2)
_.ceil(315.9250488,2)
_.ceil(undefined,2)
_.ceil(null,2)
_.ceil("",2)
will work also with a number and it's safe

You can use .toFixed() to for float value 2 digits
Exampale
let newValue = parseFloat(9.990000).toFixed(2)
//output
9.99

I have tried this for my case and it'll work fine.
var multiplied_value = parseFloat(given_quantity*given_price).toFixed(3);
Sample output:
9.007

parseFloat(parseFloat(amount).toFixed(2))
You have to parse it twice. The first time is to convert the string to a float, then fix it to two decimals (but the toFixed returns a string), and finally parse it again.

Please use below function if you don't want to round off.
function ConvertToDecimal(num) {
num = num.toString(); //If it's not already a String
num = num.slice(0, (num.indexOf(".")) + 3); //With 3 exposing the hundredths place
alert('M : ' + Number(num)); //If you need it back as a Number
}

For what its worth: A decimal number, is a decimal number, you either round it to some other value or not. Internally, it will approximate a decimal fraction according to the rule of floating point arthmetic and handling. It stays a decimal number (floating point, in JS a double) internally, no matter how you many digits you want to display it with.
To present it for display, you can choose the precision of the display to whatever you want by string conversion. Presentation is a display issue, not a storage thing.

#sd
Short Answer: There is no way in JS to have Number datatype value with trailing zeros after a decimal.
Long Answer: Its the property of toFixed or toPrecision function of JavaScript, to return the String. The reason for this is that the Number datatype cannot have value like a = 2.00, it will always remove the trailing zeros after the decimal, This is the inbuilt property of Number Datatype. So to achieve the above in JS we have 2 options
Either use data as a string or
Agree to have truncated value with case '0' at the end ex 2.50 -> 2.5.

You can store your price as a string
You can use
Number(string)
for your calculations.
example
Number("34.50") == 34.5
also
Number("35.65") == 35.65
If you're comfortable with the Number function , you can go with it.

Try this (see comments in code):
function fixInteger(el) {
// this is element's value selector, you should use your own
value = $(el).val();
if (value == '') {
value = 0;
}
newValue = parseInt(value);
// if new value is Nan (when input is a string with no integers in it)
if (isNaN(newValue)) {
value = 0;
newValue = parseInt(value);
}
// apply new value to element
$(el).val(newValue);
}
function fixPrice(el) {
// this is element's value selector, you should use your own
value = $(el).val();
if (value == '') {
value = 0;
}
newValue = parseFloat(value.replace(',', '.')).toFixed(2);
// if new value is Nan (when input is a string with no integers in it)
if (isNaN(newValue)) {
value = 0;
newValue = parseFloat(value).toFixed(2);
}
// apply new value to element
$(el).val(newValue);
}

Solution for FormArray controllers
Initialize FormArray form Builder
formInitilize() {
this.Form = this._formBuilder.group({
formArray: this._formBuilder.array([this.createForm()])
});
}
Create Form
createForm() {
return (this.Form = this._formBuilder.group({
convertodecimal: ['']
}));
}
Set Form Values into Form Controller
setFormvalues() {
this.Form.setControl('formArray', this._formBuilder.array([]));
const control = <FormArray>this.resourceBalanceForm.controls['formArray'];
this.ListArrayValues.forEach((x) => {
control.push(this.buildForm(x));
});
}
private buildForm(x): FormGroup {
const bindvalues= this._formBuilder.group({
convertodecimal: x.ArrayCollection1? parseFloat(x.ArrayCollection1[0].name).toFixed(2) : '' // Option for array collection
// convertodecimal: x.number.toFixed(2) --- option for two decimal value
});
return bindvalues;
}

I've got other solution.
You can use round() to do that instead toFixed()
var twoPlacedFloat = parseFloat(yourString).round(2)

The solution that work for me is the following
parseFloat(value)