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Modify a source based on strings in the current URL

I am a little bit stuck trying to get a tracking code to work for my website.
Every click to my website through a tracker inserts a randomly generated unique string within the URL. For example, http://www.examplepage.com/?sub_ref=333ktcm1ckpv2uvd
When someone does goes through a step by step process on my website, a PHP script will load containing various variables, one of which is an external javascript:
$script = <script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa970aa5f018dcce821dc6251"></script>
In order for me to facilitate the tracking, I want to be able to add the unique string in the URL into the javascript. The idea is that I can track when someone clicks my website and then completes an entry with an external script. For example:
$script = <script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa970aa5f018dcce821dc6251?sub_ref=333ktcm1ckpv2uvd"></script>
Could someone advise the best way to achieve this? I've been playing around with this for most of the day without success.
I should add, at the point I want the unique ID added onto the script, the URL on my website is http://www.examplepage.com/?sub_ref=333ktcm1ckpv2uvd#submit-entry

Thank you #CFP Support that's really useful.
So based on your advice, I've managed to work out that using the below displays the correct URL string that I'm looking to add within the javascript.
https://example.com/test/test.php?sub_ref=230948324095
<?php
echo __LINE__ . " here, we look at _GET "; print_r($_GET); echo "<br>";?>
8 here, we look at _GET Array ( [sub_ref] => 230948324095 )
So based on the above, I believe I should be using:
<?php echo ($_GET['sub_ref'])?>"
The problem I've got now, is that if I use the following, I end up with an error:
$script = <script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=<?php echo ($_GET['sub_ref']); ?>"></script>
PHP message: PHP Parse error: syntax error, unexpected '<' in
/home/admin/web/exampledomain.com/public_html/settings.php
on line 13" while reading response header from upstream
EDIT:
This is where I am at currently. I've made the change you recommended (first one) which doesn't product an error, however the sub_ref in the button that loads the script is still blank.
settings.php file
<?php
// Set the referral network
$network = 'A';
// Set your submit code below.
$onClick_code = 'call_referral()';
// Set your the referral script below.
$script = '
<script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=' . $_GET['sub_ref'] . '"></script>';
?>
final-step.php
<?php
require_once '../settings.php';
?>
<h1>Submitting Data</h1>
<p class="second-paragraph">Please wait while we process your data.</p>
<div class="data-processing-wrapper">
<div class="data-processing-inner-wrapper">
<div class="cssload-loader-walk">
<div></div>
<div></div>
<div></div>
<div></div>
<div></div>
</div>
<span class="console-msg"></span>
<div class="data-verification-wrapper">
<h3>Data Verification</h3>
<p>Thank you, you are almost done submitting your data.
<br>Click on the Submit Now button below to submit your data.
</p>
<div class="button-wrapper data-verification-button-wrapper">
<a class="button data-verification-button"
<?php if ($network == 'A' || $network == 'B') {?> onclick="
<?php if (!empty($onClick_code)) { echo $onClick_code; } ?>"
<?php } ?>>Submit Now
</a>
<?php if ($network == 'A' && !empty($script)) { echo $script; } ?>
</div>
</div>
<div id="progressBarConsole" class="console-loadbar">
<div></div>
</div>
</div>
</div>
From inspecting the Submit Now button in Chrome, this is what it shows (the ?sub_ref is blank):
<div class="button-wrapper data-verification-button-wrapper">
<a class="button data-verification-button" onclick="call_referral()">Submit Now</a>
<script type="text/javascript" id="js1" src="https://www.example.com.net/test.php?id=8bb1ff8&sub_ref="></script> </div>
Am I correct in assuming that the sub_ref does not appear because the script is not being when the page is opened (only when final-step.php runs)?

Looks to me like you are close, just need to point to the right query....
src="https://www.example.com/load.php?id=8bb1ff8aa970aa5f018dcce821dc6251&sub_ref=<?php echo urlencode($_GET['sub_ref'])?>"
Looks fine (though from the example you gave you shouldn't need the urlencode).
It is really hard to tell what is going on though without some actual code.... (which is likely why nobody is answering you..... - nor can I give you much of an answer......)
However, as a 'troubleshooting' tip......
You have to know what you have as variables to work with at any given moment, so learn to stop the code at any given point and take a look what the code sees.
In this case, a good one would be to see what is in the $_SERVER array to see what links are really available before trying to build the reference link (this will tell you where you really are as well as how the user got to you, etc. - a wealth of info to be sure!)
echo __LINE__ . " here, we look at _SERVER "; print_r($_SERVER); echo "<br>";
Another good one at this point is the $_GET, which will tell you what is in the query string as an array....
echo __LINE__ . " here, we look at _GET "; print_r($_GET); echo "<br>";
Having the results of both those will tell you that you actually have the data you think you do (and that is quite often the reason things don't work like you expect!)
(you can also add a
die();
after any line to make the code stop..... Lots of ways to do this, and the most important part is just seeing what is going on!
Use the above, change your question to include more code and show what you are getting in $_SERVER and $_GET at that point and you will get some great, exact answers, I'm sure!
EDIT (after a bit more info.... - but still no full code..... :( again, seeing the script around all this would help get this done..... not sure why you aren't including it...)
Obviously you are in PHP at this moment (as it is a PHP error - the script would tell us that...) and your code won't work in PHP.
You have....
$script = <script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=<?php echo ($_GET['sub_ref']); ?>"></script>
and
PHP message: PHP Parse error: syntax error, unexpected '<' in
/home/admin/web/exampledomain.com/public_html/settings.php on line 13"
while reading response header from upstream
Which is telling you the issue - - - you can't write JS inside PHP! You can make it a variable, then use it later, or you could 'jump in/out' of PHP/HTML to do it, but you must remember what language you are in and respect that language's rules.
So, you could have:
$script = '<script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=' . $_GET['sub_ref'] . '"></script>';
Or, 'jump in/out' with:
// PHP code ......
// 'jump out'....
?>
<!-- now you are in HTML and can do some JS -->
<script type="text/javascript" id="js1" src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=<?php echo ($_GET['sub_ref']); ?>"></script>
<!-- where you had correctly 'jumped', but improperly mixed... -->
<!-- now, back to PHP... ->
<? // and you can do more PHP code here.....
You have to respect the language - and where you are at any point in the code!
If you still have issues, INCLUDE THE FULL CODE AROUND THIS (I'm sure it isn't rocket science gov't secret stuff, so save us all some time so you can get the help you are asking for, please!
EDIT:
in your settings.php the link shows as
src="https://www.example.com/load.php?id=8bb1ff8aa?&sub_ref=' . $_GET['sub_ref']
However, you say in the button it is
src="https://www.example.com.net/test.php?id=8bb1ff8&sub_ref="
Your code is not clear on how things are going...... (does this sound familiar? SHOW THE CODE AS IT IS PROCESSED..... - I can't {and now, won't be able to - I've put too much time on this and am getting 'looks'...} try to guess where that weird change came from. You need to show something that is logical.....
and, prove that you have the _GET - use the print_r just before the _GET to make sure you have the data as it is being processed (sometimes with PHP you have to do some 'tricks' to keep the data on one page and use it on another..... there are several ways to do it, but until I understand your flow and what you are trying to do overall {and mostly, why you are using so many pages.... - it could be an overall design/flow issue...}, it is really hard to get a picture of what you are trying to accomplish..)
SO is not really a training facility - and I have other projects (I'm allowed a bit of time each day to answer questions, etc. - part of the 'give back to the community' policy around here, but my primary work is on paid projects {I'm sure you understand...}, so I can't do more today, but if you give some clear 'steps' on what is going on and errors you see, etc. I can look at this again tomorrow.

How to load <iframe> after clicking on an image to improve performance?

Good evening, My first message here, where I read so much and did a lot of research to find a solution but without a good result. As a title, a good way to block uploads, when accessing the page, is contained within the <iframe> tags.
An example of code is: <iframe> width = "560" height = "315" src = "https://www.youtube.com/embed/example" frameborder = "0" allowfullscreen> </iframe>
I have read several codes on how to enter the youtube iframe and allow the upload of external resources later, more precisely after clicking on a preview image, adapting html, csss, and javascript in sync with the youtube video id .
But I did not try this solution because the affected iframes are not just part of youtube but they come from other sources, always with the same arrangement as in the above example, and found nothing that could guide me towards the right direction.
Always hoping I'm well explained, do you have any hints on how to hide iframes load and overlap a page loading image at the click, disappear, showing the contents of the frame? Thank you. Forgive my very poor English.

You can use an example for YouTube and just replace the iframe source along with the other variables with your own data. Just skip the thumbnail image part. Replace the on-click event with your own event if you need to.
The technique remains the same. YouTube or not!
see this vanilla js example
Make sure your video's have unique ID's. Render the HTML like this.
<?php $i = 0; ?>
<?php foreach ($sources as $source): ?>
<?php $i++; ?>
<div class="video" id="video-<?php echo $i; ?>">
<div class="divise" id="divise-<?php echo $i; ?>" data-embed="<?php echo $source; ?>">
<div class="play-button"></div>
</div>
</div>
<?php endforeach; ?>

Targeting dynamic id's within a javascript file

In a php file I have tags with dynamic id's.
Example:
<ul id="<?php echo 'ul_'.$xx; ?>">
<li id="test_li">...</li>
</ul>
In a separate JavaScript file I am wanting to use the load function and target that div.
$('<?php echo 'ul_'.$xx; ?>').load('../includes/myphpfile.inc.php #test_li');
My question is, how could I load that php within a JavaScript file?
Notes:- The reason I have it set up this way is due to looping multiple ul's. I just want my ajax file to refresh the li's within the specific ul I am inside of.
Edit: If I use classes instead of Id's it adds my newly inserted rows into all of the ul's with the same class. If I use a plain Id it only works on the first ul. Further explaining why I need to target the way I am.

Unable to find a solution using the path I was on, I looked for alternate methods. Worked out I could add the event in the php file on the submit form button click.
The reason I wasn't using this method at first was because the code was running before it submitted to the DB and therefore was always behind in relation to the new data being submitted.
To my surprise I fixed this by just duplicating the line of code.
<script>
$("<?php echo '#enter_submit_button'.$linkid ?>").click(function(){
/*1*/
$('#<?php echo 'ul__'.$linkid; ?>').load('../includes/pursuit.inc.php <?php echo '#li__'.$linkid; ?>');
$("<?php echo '#insert_new'.$linkid; ?>").fadeOut();
/*2 with delay*/
$('#<?php echo 'ul__'.$linkid; ?>').delay( 800 ).load('../includes/pursuit.inc.php <?php echo '#li__'.$linkid; ?>');
});
</script>
I honestly couldn't say exactly why this works but the logic behind trying the method came from hoping that the double load would pick up the latest submission.

The simplest answer would be to put your JavaScript code into the PHP file inside
<script></script> tags, i.e, just before closing your <body> tag, do this:
<script type="text/javascript">
$('<?php echo 'ul_'.$xx; ?>').load('../includes/myphpfile.inc.php #test_li');
</script>
But if you must use an external js file, then you could do this:
Create a (.php) file and write:
<?php
header("Content-type: application/javascript");
?>
// your js code with php inside (as you would do in HTML)
var othervar='<?php echo $phpVar; ?>';
//<?php //some php ;?>
Then, in your main (html/php) file, put in:
<script src='myjs.php' type='application/javascript'></script>
Hope that solves it.

How can I put PHP code inside JavaScript document.write

Hello can anyone please help me in fixing this code?
1st code
<script type="text/javascript">
if (document.getElementById("tester") != undefined)
{
document.write('**2nd code should be here**');
}
else
{
document.write('<img scr="./img.png" />');
}
</script>
2nd code
<?php while (have_posts()) : the_post(); get_template_part('item-video');
endwhile; ?>
What I want to happen is to insert the 2nd code into the first code. But when I try to insert it, it gives me a blank page.

the biggest thing I've heard is that PHP is server side, while Javascript is client side. Therefore, changing the html page using document.write() isn't going to do anything unless you reload the page. I think you can circumvent this problem tho, using Ajax and the load() function.

How do I use php functions in javascript?

Situation:
I'm building a Wordpress Site. Menu becomes 'fixed' to the top of the page when scrolling down the page (http://deerfielddesigns.com.mlseo.net/). When i am logged into wordpress, the dashboard admin bar cover the menu. I wanted to create a different class for the menu when I am logged in as opposed to when I am logged out.
Code:
if ( direction === 'down' ) {
$('#main-header').addClass( 'et-fixed-header' );
} else {
$('#main-header').removeClass( 'et-fixed-header' );
}
I wanted to insert an "if ( is_user_logged_in() )" statement in there to change the class output but I don't really understand too much about javascript and if it plays nice with php. Does anyone have any insight as to what i need to do to make this work? Thanks all!

if this is not an AJAX driven login system, simply open your header.php file and perform the following
$the_class = is_user_logged_in() ? 'logged-in-class' : 'logged-out-class';
Then find your main-header and do what's required.
<header id="main-header" class="<?php echo $the_class;">
If it is an ajax driven login system, you'll need to understand how to work with wordpress' add_action, but that is an answer for an entirely different question.

Make an ajax request to the required php function whenever required. You may use ajax features of various JS libraries like jQuery, YUI etc. to do so.

PHP is a server side language (which quite likely is generating Javascript).
Javascript is in the browser.
The short answer is "You can't easily call PHP from JS".

The simple way to identify from you javascript if a user is logged in is to populate a javascript variable with their status. In your theme's header.php, add:
<script type="text/javascript">
var is_logged_in = <?php echo json_encode(is_user_logged_in()) ?>;
</script>
Then, in your javascript elsewhere, you can use:
if (is_logged_in) {
//....
}

If you write inline javascript in your php files you can do this:
<?php // some php code ?>
<script type="text/javascript">
<?php if ( is_user_logged_in() ) { ?>
// Place some javascript here
<?php } else { ?>
// Place some javascript here
<?php ?>
</script>
<?php // some php code ?>