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Animate one at a time with ng-repeat

I am trying to use ngRepeat to load an image and play it's associated tone, then move the image from the center of the circle to a specific position on a circle, and proceed with the doing the same thing with the next image. I got the images to display and move one by one using ng-enter-stagger, however the images have different positions so when I change it to to use a different class for each repetition, ng-enter-stagger does not work.
How can I go about loading one image, moving it to the proper position, hiding the image, then proceeding with the next image?
I have created a plunkr but the animation does not work in it https://plnkr.co/edit/DddST6JsemsCKKf3mQ6N?p=preview.
An example of what I want to do is the Learn the sounds part of this (http://www.absolutepitchstudy.com/animalgame/) click either Start Control or Start Animal Game
The data looks like this:
"ImageTones":[{"CPosition":"deg60","Image":{"ImageFileName":"Alligator.png","ImageId":1},"Tone":{"ToneFileName":"C3.mp4","ToneId":1}},
{"CPosition":"deg0","Image":{"ImageFileName":"Cow.png","ImageId":4},"Tone":{"ToneFileName":"B5.mp4","ToneId":2}},
{"CPosition":"deg270","Image":{"ImageFileName":"Bird.png","ImageId":3},"Tone":{"ToneFileName":"E3.mp4","ToneId":3}}]
Html page:
<div class="circle-container">
<div ng-repeat="it in model.imageTones" class="it.CPosition">
<img ng-src="../Content/Game/Animals/{{it.Image.ImageFileName}}"/>
<!--Audio tag goes here-->
</div>
</div>
My CSS (I may be able to fix this to not have as many classes, just am unsure how)
.circle-container {
position: relative;
width: 38em;
height: 38em;
padding: 2.8em;
/*2.8em = 2em*1.4 (2em = half the width of a link with img, 1.4 = sqrt(2))*/
border: dashed 1px;
border-radius: 80%;
margin: -5.25em auto 0;
}
.circle-container div {
display: block;
position: absolute;
top: 50%;
left: 50%;
width: 4em;
height: 4em;
margin: -2em;
}
.circle-container div.ng-enter {
transition: 5s linear all;
opacity: 0;
}
.circle-container div.ng-enter-stagger {
/* this will have a 100ms delay between each successive leave animation */
transition-delay: 5.0s;
/* As of 1.4.4, this must always be set: it signals ngAnimate
to not accidentally inherit a delay property from another CSS class */
transition-duration: 0s;
}
.circle-container div.ng-enter.ng-enter-active {
/* standard transition styles */
opacity:1;
}
.deg0.ng-enter-active {
transform: translate(19em);
}
.deg30.ng-enter-active {
transform: rotate(30deg) translate(19em) rotate(-30deg);
}
.deg60.ng-enter-active {
transform: rotate(60deg) translate(19em) rotate(-60deg);
}
.deg90.ng-enter-active {
transform: rotate(90deg) translate(19em) rotate(-90deg);
transition: transform 5s;
}
.deg120.ng-enter-active {
transform: rotate(120deg) translate(19em) rotate(-120deg);
}
.deg150.ng-enter-active {
transform: rotate(150deg) translate(19em) rotate(-150deg);
}
.deg180.ng-enter-active {
transform: rotate(180deg) translate(19em) rotate(-180deg);
}
.deg210.ng-enter-active {
transform: rotate(210deg) translate(19em) rotate(-210deg);
}
.deg240.ng-enter-active {
transform: rotate(240deg) translate(19em) rotate(-240deg);
}
.deg270.ng-enter-active {
transform: rotate(270deg) translate(19em) rotate(-270deg);
}
.deg300.ng-enter-active {
transform: rotate(300deg) translate(19em) rotate(-300deg);
}
.deg330.ng-enter-active {
transform: rotate(330deg) translate(19em) rotate(-330deg);
}

There's a couple of errors to look at 1st, To get a value of a class from an angular item, it's ng-class you should be looking for:
<div ng-repeat="it in model.imageTones" ng-class="it.CPosition" ng-if="!it.hidden" >
<img ng-src="http://www.absolutepitchstudy.com/animalgame/content/images/{{it.Image.ImageFileName}}" />
</div>
Then in you style sheet there seems to be something wrong with the CSS, so I removed a class that wasn't being used:
.deg60{
transform: rotate(60deg) translate(19em) rotate(-60deg);
}
Although to hide stuff you may want that back.
The updated plunk with the work so far is at:
plunky
Now it's being rendered in the right place, you can use $timeout, ng-click or someother method to alter the class definition in your model. The position of the graphic should automatically update.
What method were you going to use?

How to make the div not dissapear when rotateY(90deg)

On my webpage I have a div. On that div I have "animation" that simulates the div being turned over (flipped).
<div id="wrapper">
<div id="content">
Some content
</div>
</div>
I rotate the "wrapper" div with the jQuery plugin transit. What the plugin does is just apply the CSS;
transform: rotateY(180deg);
When the div is on rotateY(90deg), I have to load some new content in the #content div. This takes a minuscule amount of time, but in the animation you can see that the div is gone/hidden fore that time.
SEE DEMO FIDDLE
(note that I don't have the actual content loading in here)
Is it possible to have the dive not totally disappearing when rotateY(90)?
Unfortunately I have no control over the HTML itself because it is being generated.

Try to add thickness to it. Refer to something like this: want to show the thickness of an element while it rotate
But make the animation of the css:
0%: transform: rotateY(0deg);
50%:transform: rotateY(90deg);
100%:transform: rotateY(180deg);
Hope this helps.
Make sure the jQuery plugin has css files or look into it.
And also you could do this using basic css and jQuery.

Don't change the contents of the div, just create two sides:
<div id="wrapper">
<div class="side-a">
Some content
</div>
<div class="side-b">
Some content
</div>
</div>
CSS:
#wrapper{
transition: all 2s;
position: relative;
}
#wrapper.flip{
transform: rotateY(180deg);
}
.side-a{
z-index: 1;
opacity: 1;
position: absolute;
height: 100%;
transition-delay: 1s; //half the transition time of the wrapper
}
.side-b{
z-index: 0;
opacity: 0;
transform: rotateY(180deg);
position: absolute;
height: 100%;
transition-delay: 1s;
}
.flip side-a{
z-index: 0;
opacity: 0;
}
.flip side-b{
z-index: 1;
opacity: 1;
}
Javascript:
$('.next-slide').click(function(){
$('#wrapper').addClass('flip');
});
$('.prev-slide').click(function(){
$('#wrapper').removeClass('flip');
});

z-index qith jquery not working on rotated image

JsFiddle: http://jsfiddle.net/E4s9k/
HTML:
<body>
<section id="pics" class="clearfix">
<figure
id="pic1"
class="pictures"
>
<img
alt="figure1"
src="http://b-i.forbesimg.com/kellyclay/files/2013/12/glass.jpg"
title="pic1"
>
<figcaption class="figuredetails">Fig1</figcaption>
</figure>
<figure
id="pic2"
class="pictures"
>
<img
alt="figure2"
src="http://glass-apps.org/wp-content/uploads/2013/06/google-glass1.jpg"
title="pic2"
>
<figcaption class="figuredetails">Fig2</figcaption>
</figure>
</section>
<section id="content">
<p>hello</p>
</section>
</body>
CSS:-
#CHARSET "UTF-8";
#pics{
width:100%;
padding: 50px 50px;
}
.pictures{
float: left;
width:200px;
height:200px;
box-shadow: 10px 10px 5px #888888;
}
.pictures img{
width:100%;
height:auto;
}
#pic1{
-ms-transform: rotate(30deg);
-webkit-transform: rotate(30deg);
transform: rotate(30deg);
z-index: -1
}
#pic2{
position: absolute;
-ms-transform: rotate(50deg);
-webkit-transform: rotate(50deg);
transform: rotate(50deg);
/* z-index: -2; */
}
#content{
clear: both;
}
.pictures > .figuredetails{
color: red;
padding-left: 20px;
}
.clearfix:after {
content: ".";
visibility: hidden;
display: block;
height: 0;
clear: both;
}
JQuery:
function pichoverfunc() {
$(this).css({"z-index":10});
}
function pichoverfuncO() {
$(this).css({"z-index":-10});
}
$(document).ready(
$("#pic2").hover(pichoverfunc, pichoverfuncO)
);
I'm trying to do something like this:-
Show 2 rotated images on the top of each other.
When hovered above any image (even near its egde), that image should come to the front and the one that is in front should go to back
This is a future things (in my to-do list) - Use more than 2 images to achieve the same functionality as in step 2.
The problem:
1. I cant hover on the second image
2. (This is linked to the requirement 3 above) If there are more than 2 images, then, how should I choose z-index for each image that is in the back?
What I've tried:-
I've used the Dev tools in chrome to inspect the #pic2 but, I still cant select it.
As I'm new to HTML, CSS, and Jquery, Any help would be great.

You dont need to use Jquery to change an element on hover. CSS has this functionality built in, take a look at this link. As you can see you can set a css class or id to change on hover. So for instance:
#pic2{
position: absolute;
-ms-transform: rotate(50deg);
-webkit-transform: rotate(50deg);
transform: rotate(50deg);
/* z-index: -2; */
}
Then below that you could put somthing like this:
#pic2:hover{
z-index:10;
}
This should change the z-index of pic2 on hover with only CSS, also if you want to do this with many images try using a class instead of an id or maybe just do it using tag name. So for instance assign class="img-hover" to all the images youd like. Then in your css put:
.img-hover:hover{
z-index:10;
}
or if you want to just apply the hover to all img tags youd just put:
img:hover{
...
}

The root cause why your script does not work is probably the fact that:
z-index will only work on an element whose position property has been explicitly set to absolute, fixed, or relative.
Read more on the z-index: http://www.smashingmagazine.com/2009/09/15/the-z-index-css-property-a-comprehensive-look/
When it comes to your JSFiddle, I cleaned it up a bit and simplified it a bit - http://jsfiddle.net/E4s9k/
HTML:
<body>
<img
id="pic1"
alt="figure1"
src="http://b-i.forbesimg.com/kellyclay/files/2013/12/glass.jpg"
title="pic1"
>
<img
id="pic2"
alt="figure2"
src="http://glass-apps.org/wp-content/uploads/2013/06/google-glass1.jpg"
title="pic2"
>
</body>
JS:
function handlerIn() {
$('img').css({"z-index": -10}); //Push all images back
$(this).css({"z-index": 10}); //Bring our target to front
}
function handlerOut() {
$('img').css({"z-index": 10}); //Bring all our images to front
$(this).css({"z-index": -10}); //Push target back
}
$(document).ready(function(){
$("img").hover(handlerIn, handlerOut);
});
CSS:
img {
position: relative;
width:200px;
height:200px;
box-shadow: 10px 10px 5px #888888;
}
#pic1{
-ms-transform: rotate(30deg);
-webkit-transform: rotate(30deg);
transform: rotate(30deg);
}
#pic2{
-ms-transform: rotate(50deg);
-webkit-transform: rotate(50deg);
transform: rotate(50deg);
}

JS/CSS: Moving span in an animated way

First post here. Hope you can help me out with a problem I'm having:
I am writing a game, where a user needs to guess a word from shuffled letters by clicking on each letter to insert it in the first empty space of a "correct" field.
Now, when a letter is clicked, it needs to move to its new spot in an animated way. As I'm using span to create a separate field for each letter I couldn't figure out how to make this span move to its new location in an animated way using CCS3/JavaScript/JQuery.
The code is in JSFiddle here: http://jsfiddle.net/Pfsqu/
JS:
var randomNumber = Math.floor(Math.random() * words.length);
var word = words[randomNumber];
var chars = word.split('');
chars=_.shuffle(chars);
for (var i in chars) {
$('#shuffled').append('<span>'+chars[i]+'</span>');
$('#correct').append('<span>');
}
$('#shuffled > span').click(function() {
var letter = $(this);
letter.replaceWith('<span>');
$('#correct > span:empty').first().append( letter ); /* this part needs to be animated*/
CSS:
p > span{
background-color: white;
margin: 10px;
-webkit-border-radius: 15px;
border-radius: 15px;
width: 2.5em;
height: 2.5em;
display: inline-block;
text-align: center;
line-height: 2.5em;
vertical-align: middle;
animation: 1000ms move ease-in-out;
-webkit-animation: 1000ms move ease-in-out;
}

I think that it is quite difficult to animate the items the way that you are intending.
The way I would solve it would be keeping the same DOM element, and changing its properties.
For instance, see this
demo
The HTML is
<div class="solution">
<span class="q q4">W</span>
<span class="q q2">O</span>
<span class="q q3">R</span>
<span class="q q1">D</span>
</div>
I have set the letters of WORD in order, and then I have set to them one of the classes q1 to q4. This class will set the span to a specific position on screen.
This is achieved in this CSS (and also the position for the "solved" status
.solution {
margin-top: 100px;
-webkit-transition: all 5s;
position: relative;
}
.solution span {
border: solid 1px green;
padding: 10px;
margin-top: 80px;
-webkit-transition: all 2s;
position: absolute;
background-color: lightgreen;
font-size: 30px;
}
.solution span:nth-child(1) {
-webkit-transform: translate(0px, 0px) rotate(0deg);
}
.solution span:nth-child(2) {
-webkit-transform: translate(80px, 0px) rotate(0deg);
}
.solution span:nth-child(3) {
-webkit-transform: translate(160px, 0px) rotate(0deg);
}
.solution span:nth-child(4) {
-webkit-transform: translate(240px, 0px) rotate(0deg);
}
div.solution span.q {
background-color: yellow !important;
border: solid 1px red;
border-radius: 50%;
}
.solution .q.q1 {
-webkit-transform: translate(0px, -100px) rotate(360deg);
}
.solution .q.q2 {
-webkit-transform: translate(80px, -100px) rotate(360deg);
}
.solution .q.q3 {
-webkit-transform: translate(160px, -100px) rotate(360deg);
}
.solution .q.q4 {
-webkit-transform: translate(240px, -100px) rotate(360deg);
}
Now the jQuery is very easy
$('.q').click(function(){
$(this).removeClass('q');
});
I have used the webkit prefixes, but you can easily set it to work for others browsers
Edited answer:
Changing the nth-child styles to:
.answer1 {
-webkit-transform: translate(0px, 0px) rotate(0deg);
}
.answer2 {
-webkit-transform: translate(80px, 0px) rotate(0deg);
}
.answer3 {
-webkit-transform: translate(160px, 0px) rotate(0deg);
}
.answer4 {
-webkit-transform: translate(240px, 0px) rotate(0deg);
}
and the script to:
var element = 1;
$('.q').click(function(){
$(this).removeClass('q').addClass("answer" + element);
element = element + 1;
});
You got, as per your request, that the letters go to the first available place.
The only remining task is to construct the spans from the array of letters.
I think that you have already some code that does quite a similar job; it's only a matter of adapting it.
updated demo

JavaScript/HTML/CSS: Zooming

Let's say I've got a page with a div, and a button. When you click the button, the div should be zoomed in on. In other words, if that div was 100px, when you zoom, it should then become, say, 200px. And all the children of this div should also be doubled in size.
What's the best way to do this?
My understanding is that there's a CSS zoom, but only in IE--it's not part of any CSS standard.

You should use CSS3's transform: scale().
See: http://jsfiddle.net/Favaw/ - (I used jQuery for convenience, but it's not a requirement)
.zoomedIn2x {
-moz-transform: scale(2);
-webkit-transform: scale(2);
-o-transform: scale(2);
-ms-transform: scale(2);
transform: scale(2);
-moz-transform-origin: 0 0;
-webkit-transform-origin: 0 0;
-o-transform-origin: 0 0;
-ms-transform-origin: 0 0;
transform-origin: 0 0;
}
If you need to support older versions of IE than 9, then generate .zoomedIn2x using this tool:
http://www.useragentman.com/IETransformsTranslator/index.html
If you want to do this more dynamically (such as other levels of zoom), then instead use cssSandpaper.

You might want to look into the jQuery plugin Zoomooz: http://janne.aukia.com/zoomooz/

best solution is using
zoom: 50%
i made this example with javascript, you can test it and change it as you like
var zoomediv = document.getElementById('zoomediv')
var zoomin_button = document.querySelector('#zoomin')
zoomin_button.addEventListener('click', function(){
zoomediv.style.zoom = '125%'
})
var zoomout_button = document.querySelector('#zoomout')
zoomout_button.addEventListener('click', () => {
zoomediv.style.zoom = '75%'
})
div {
background: #f0f0f0;
border: 1px solid #e0e0e0;
width: fit-content;
padding: 1rem;
margin-bottom: 1rem;
}
button {
padding: 0 3rem;
}
<div id="zoomediv">
<h1>
Title
</h1>
<p>
this is a paragraph
</p>
</div>
<button id="zoomin">
<h1>
+
</h1>
</button>
<button id="zoomout">
<h1>
-
</h1>
</button>