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Access properties from array of objects inside looping in Typescript

I have an array with a combination of strings and objects. Then I tried to display the properties of the array based on the key in a loop. Is it possible to do this in typescript?
This is the sample code:
const arr = [
{ name: 'John' },
'Amber',
{ name: 'Cathrine' },
'Louis',
{ name: 'Mike' }
]
arr.forEach((item, key) => {
if (typeof item !== 'string') {
console.log(item.name) // Works
console.log(arr[key].name) // Doesn't work, losing type
}
}
Please check this link to run the code:
https://www.typescriptlang.org/play?#code/MYewdgzgLgBAhgJwTAvDA2gKBjA3jMOAWwFMAuGAcgCkQALMSmAXwBpsqBBIgIxIUrsc+QqQqUAwnCh0EASzAkmbDpQAyIAK5yIgjiOLkqAWTkBrJS0wBdTJkQIAdADMQCAKJxgdABQ+5UCRErDAWAJ4AlKgAfHgccs4wPlBhAA4kIIkBQTAAhCholNDyYADmlFG4HDigkCAANiSO9SCl-oFEjqIkUQD0vTAA6m5mENUwtRANTS1tDujh1l2GfQMAIiAkEIywAO4jIS0gEAqlMCnpHMyYzEA
I really appreciate your help, Thank you!

This is how type guards work in TypeScript. They only filter the type of variable that is checked. In your case you are checking for item (in typeof item !== 'string') and therefore only item is assumed to be not a string.
Fix
If you want to access arr[key].name then store that in a variable, type check that variable with a type guard, and then you are good to go.
Full fixed example:
const arr = [
{ name: 'John' },
'Amber',
{ name: 'Cathrine' },
'Louis',
{ name: 'Mike' }
]
arr.forEach((item, key) => {
const member = arr[key];
if (typeof member !== 'string') {
console.log(member.name) // Okay
}
});

Creating a JavaScript function that filters out duplicate in-memory objects?

Okay, so I am trying to create a function that allows you to input an array of Objects and it will return an array that removed any duplicate objects that reference the same object in memory. There can be objects with the same properties, but they must be different in-memory objects. I know that objects are stored by reference in JS and this is what I have so far:
const unique = array => {
let set = new Set();
return array.map((v, index) => {
if(set.has(v.id)) {
return false
} else {
set.add(v.id);
return index;
}
}).filter(e=>e).map(e=>array[e]);
}
Any advice is appreciated, I am trying to make this with a very efficient Big-O. Cheers!
EDIT: So many awesome responses. Right now when I run the script with arbitrary object properties (similar to the answers) and I get an empty array. I am still trying to wrap my head around filtering everything out but on for objects that are referenced in memory. I am not positive how JS handles objects with the same exact key/values. Thanks again!

Simple Set will do the trick
let a = {'a':1}
let b = {'a': 1,'b': 2, }
let c = {'a':1}
let arr = [a,b,c,a,a,b,b,c];
function filterSameMemoryObject(input){
return new Set([...input])
}
console.log(...filterSameMemoryObject(arr))
I don't think you need so much of code as you're just comparing memory references you can use === --> equality and sameness .
let a = {'a':1}
console.log(a === a ) // return true for same reference
console.log( {} === {}) // return false for not same reference

I don't see a good reason to do this map-filter-map combination. You can use only filter right away:
const unique = array => {
const set = new Set();
return array.filter(v => {
if (set.has(v.id)) {
return false
} else {
set.add(v.id);
return true;
}
});
};
Also if your array contains the objects that you want to compare by reference, not by their .id, you don't even need to the filtering yourself. You could just write:
const unique = array => Array.from(new Set(array));

The idea of using a Set is nice, but a Map will work even better as then you can do it all in the constructor callback:
const unique = array => [...new Map(array.map(v => [v.id, v])).values()]
// Demo:
var data = [
{ id: 1, name: "obj1" },
{ id: 3, name: "obj3" },
{ id: 1, name: "obj1" }, // dupe
{ id: 2, name: "obj2" },
{ id: 3, name: "obj3" }, // another dupe
];
console.log(unique(data));
Addendum
You speak of items that reference the same object in memory. Such a thing does not happen when your array is initialised as a plain literal, but if you assign the same object to several array entries, then you get duplicate references, like so:
const obj = { id: 1, name: "" };
const data = [obj, obj];
This is not the same thing as:
const data = [{ id: 1, name: "" }, { id: 1, name: "" }];
In the second version you have two different references in your array.
I have assumed that you want to "catch" such duplicates as well. If you only consider duplicate what is presented in the first version (shared references), then this was asked before.

React: Calling filter on Object.keys

A React component is passed a state property, which is an object of objects:
{
things: {
1: {
name: 'fridge',
attributes: []
},
2: {
name: 'ashtray',
attributes: []
}
}
}
It is also passed (as a router parameter) a name. I want the component to find the matching object in the things object by comparing name values.
To do this I use the filter method:
Object.keys(this.props.things).filter((id) => {
if (this.props.things[id].name === this.props.match.params.name) console.log('found!');
return (this.props.things[id].name === this.props.match.params.name);
});
However this returns undefined. I know the condition works because of my test line (the console.log line), which logs found to the console. Why does the filter method return undefined?

Object.keys returns an array of keys (like maybe ["2"] in your case).
If you are interested in retrieving the matching object, then you really need Object.values. And if you are expecting one result, and not an array of them, then use find instead of filter:
Object.values(this.props.things).find((obj) => {
if (obj.name === this.props.match.params.name) console.log('found!');
return (obj.name === this.props.match.params.name);
});
Be sure to return that result if you use it within a function. Here is a snippet based on the fiddle you provided in comments:
var state = {
things: {
1: {
name: 'fridge',
attributes: []
},
2: {
name: 'ashtray',
attributes: []
}
}
};
var findThing = function(name) {
return Object.values(state.things).find((obj) => {
if (obj.name === name) console.log('found!');
return obj.name === name;
});
}
var result = findThing('fridge');
console.log(result);

You need to assign the result of filter to a object and you get the result as the [id]. You then need to get the object as this.props.things[id]
var data = {
things: {
1: {
name: 'fridge',
attributes: []
},
2: {
name: 'ashtray',
attributes: []
}
}
}
var name = 'fridge';
var newD = Object.keys(data.things).filter((id) => {
if (data.things[id].name === name) console.log('found!');
return (data.things[id].name === name);
});
console.log(data.things[newD]);

Deleting nested property in javascript object

I have a JS object like this:
var tenants = {
'first': {
'name': 'first',
'expired': 1
},
'second': {
'name': 'second'
}
}
And I'd like to delete the 'expired' property of tenant 'first', should I just do this?
delete tenants['first']['expired'];
Note: this question is more specific than the question: How do I remove a property from a JavaScript object?, in that my question focuses on the 'nested' part.

Yes. That would work.
delete tenants['first']['expired']; or delete tenants.first.expired;.
If you are deleting it only because you wanted to exclude it from JSON.stringify(), you can also just set it to undefined, like tenants['first']['expired'] = undefined;

If the property you want to delete is stored in a string, you can use this function
function deletePropertyPath (obj, path) {
if (!obj || !path) {
return;
}
if (typeof path === 'string') {
path = path.split('.');
}
for (var i = 0; i < path.length - 1; i++) {
obj = obj[path[i]];
if (typeof obj === 'undefined') {
return;
}
}
delete obj[path.pop()];
};
Example Usage
var tenants = {
'first': {
'name': 'first',
'expired': 1
},
'second': {
'name': 'second'
}
}
var property = 'first.expired';
deletePropertyPath(tenants, property);

If your app is using lodash, then _.unset is a safe way for deleting nested properties. You can specify nested keys without worrying about their existence.
let games = { 'hitman': [{ 'agent': { 'id': 47 } }] };
_.unset(games, 'hitman[0].agent.id');
_.unset(games, 'hitman[0].muffin.cupcake'); // won't break
further reading: https://lodash.com/docs/4.17.15#unset

I came up with this:
const deleteByPath = (object, path) => {
let currentObject = object
const parts = path.split(".")
const last = parts.pop()
for (const part of parts) {
currentObject = currentObject[part]
if (!currentObject) {
return
}
}
delete currentObject[last]
}
Usage:
deleteByPath({ "a" : { "b" : true }},"a.b")

If you want to delete a property with a particular name in an arbitrarily deep object, I would recommend that you use a battle-tested library. You can use DeepDash, an extension to Lodash.
// Recursively remove any "expired" properties
_.eachDeep(e, (child, prop, parent, ctx):boolean => {
if (prop === 'expired') {
delete parent[prop];
return false; // per docs, this means do not recurse into this child
}
return true;
});
And if you would rather have a new copy (rather than mutating the existing object), DeepDash also has an omitDeep function you can use that will return the new object.

If you have the path of the key separated by ., say first.expired in your case, you can do deleteKey(tenants, 'first.expired'):
const deleteKey = (obj, path) => {
const _obj = JSON.parse(JSON.stringify(obj));
const keys = path.split('.');
keys.reduce((acc, key, index) => {
if (index === keys.length - 1) {
delete acc[key];
return true;
}
return acc[key];
}, _obj);
return _obj;
}
let tenants = {
'first': {
'name': 'first',
'expired': 1
},
'second': {
'name': 'second'
}
};
const PATH_TO_DELETE = 'first.expired';
tenants = deleteKey(tenants, PATH_TO_DELETE);
console.log('DELETE SUCCESSFUL:', tenants);

With modern JS you can simple do it this way:
const tenants = {
first: {
name: 'first',
expired: 1
},
second: {
name: 'second'
}
}
delete tenants?.first?.expired;
delete tenants?.second?.expired;
delete tenants?.third?.expired;
console.log(tenants);
By using optional chaining you're able to safely try to remove nested properties on objects that might not exist.
Check the mdn site to check browser compatibility
NOTE: Optional chaining does also works with braces

Remove value from object without mutation

What's a good and short way to remove a value from an object at a specific key without mutating the original object?
I'd like to do something like:
let o = {firstname: 'Jane', lastname: 'Doe'};
let o2 = doSomething(o, 'lastname');
console.log(o.lastname); // 'Doe'
console.log(o2.lastname); // undefined
I know there are a lot of immutability libraries for such tasks, but I'd like to get away without a library. But to do this, a requirement would be to have an easy and short way that can be used throughout the code, without abstracting the method away as a utility function.
E.g. for adding a value I do the following:
let o2 = {...o1, age: 31};
This is quite short, easy to remember and doesn't need a utility function.
Is there something like this for removing a value? ES6 is very welcome.
Thank you very much!

Update:
You could remove a property from an object with a tricky Destructuring assignment:
const doSomething = (obj, prop) => {
let {[prop]: omit, ...res} = obj
return res
}
Though, if property name you want to remove is static, then you could remove it with a simple one-liner:
let {lastname, ...o2} = o
The easiest way is simply to Or you could clone your object before mutating it:
const doSomething = (obj, prop) => {
let res = Object.assign({}, obj)
delete res[prop]
return res
}
Alternatively you could use omit function from lodash utility library:
let o2 = _.omit(o, 'lastname')
It's available as a part of lodash package, or as a standalone lodash.omit package.

With ES7 object destructuring:
const myObject = {
a: 1,
b: 2,
c: 3
};
const { a, ...noA } = myObject;
console.log(noA); // => { b: 2, c: 3 }

one line solution
const removeKey = (key, {[key]: _, ...rest}) => rest;
Explanations:
This is a generic arrow function to remove a specific key. The first argument is the name of the key to remove, the second is the object from where you want to remove the key. Note that by restructuring it, we generate the curated result, then return it.
Example:
let example = {
first:"frefrze",
second:"gergerge",
third: "gfgfg"
}
console.log(removeKey('third', example))
/*
Object {
first: "frefrze",
second: "gergerge"
}
*/

To add some spice bringing in Performance. Check this thread bellow
https://github.com/googleapis/google-api-nodejs-client/issues/375
The use of the delete operator has performance negative effects for
the V8 hidden classes pattern. In general it's recommended do not use
it.
Alternatively, to remove object own enumerable properties, we could
create a new object copy without those properties (example using
lodash):
_.omit(o, 'prop', 'prop2')
Or even define the property value to null or undefined (which is
implicitly ignored when serializing to JSON):
o.prop = undefined
You can use too the destructing way
const {remov1, remov2, ...new} = old;
old = new;
And a more practical exmple:
this._volumes[this._minCandle] = undefined;
{
const {[this._minCandle]: remove, ...rest} = this._volumes;
this._volumes = rest;
}
As you can see you can use [somePropsVarForDynamicName]: scopeVarName syntax for dynamic names. And you can put all in brackets (new block) so the rest will be garbage collected after it.
Here a test:
exec:
Or we can go with some function like
function deleteProps(obj, props) {
if (!Array.isArray(props)) props = [props];
return Object.keys(obj).reduce((newObj, prop) => {
if (!props.includes(prop)) {
newObj[prop] = obj[prop];
}
return newObj;
}, {});
}
for typescript
function deleteProps(obj: Object, props: string[]) {
if (!Array.isArray(props)) props = [props];
return Object.keys(obj).reduce((newObj, prop) => {
if (!props.includes(prop)) {
newObj[prop] = obj[prop];
}
return newObj;
}, {});
}
Usage:
let a = {propH: 'hi', propB: 'bye', propO: 'ok'};
a = deleteProps(a, 'propB');
// or
a = deleteProps(a, ['propB', 'propO']);
This way a new object is created. And the fast property of the object is kept. Which can be important or matter. If the mapping and the object will be accessed many many times.
Also associating undefined can be a good way to go with. When you can afford it. And for the keys you can too check the value. For instance to get all the active keys you do something like:
const allActiveKeys = Object.keys(myObj).filter(k => myObj[k] !== undefined);
//or
const allActiveKeys = Object.keys(myObj).filter(k => myObj[k]); // if any false evaluated value is to be stripped.
Undefined is not suited though for big list. Or development over time with many props to come in. As the memory usage will keep growing and will never get cleaned. So it depend on the usage. And just creating a new object seem to be the good way.
Then the Premature optimization is the root of all evil will kick in. So you need to be aware of the trade off. And what is needed and what's not.
Note about _.omit() from lodash
It's removed from version 5. You can't find it in the repo. And here an issue that talk about it.
https://github.com/lodash/lodash/issues/2930
v8
You can check this which is a good reading https://v8.dev/blog/fast-properties

As suggested in the comments above if you want to extend this to remove more than one item from your object I like to use filter. and reduce
eg
const o = {
"firstname": "Jane",
"lastname": "Doe",
"middlename": "Kate",
"age": 23,
"_id": "599ad9f8ebe5183011f70835",
"index": 0,
"guid": "1dbb6a4e-f82d-4e32-bb4c-15ed783c70ca",
"isActive": true,
"balance": "$1,510.89",
"picture": "http://placehold.it/32x32",
"eyeColor": "green",
"registered": "2014-08-17T09:21:18 -10:00",
"tags": [
"consequat",
"ut",
"qui",
"nulla",
"do",
"sunt",
"anim"
]
};
const removeItems = ['balance', 'picture', 'tags']
console.log(formatObj(o, removeItems))
function formatObj(obj, removeItems) {
return {
...Object.keys(obj)
.filter(item => !isInArray(item, removeItems))
.reduce((newObj, item) => {
return {
...newObj, [item]: obj[item]
}
}, {})
}
}
function isInArray(value, array) {
return array.indexOf(value) > -1;
}

My issue with the accepted answer, from an ESLint rule standard, if you try to destructure:
const { notNeeded, alsoNotNeeded, ...rest } = { ...ogObject };
the 2 new variables, notNeeded and alsoNotNeeded may throw a warning or error depending on your setup since they are now unused. So why create new vars if unused?
I think you need to use the delete function truly.

export function deleteKeyFromObject(obj, key) {
return Object.fromEntries(Object.entries(obj).filter(el => el[0] !== key))
}

with lodash cloneDeep and delete
(note: lodash clone can be used instead for shallow objects)
const obj = {a: 1, b: 2, c: 3}
const unwantedKey = 'a'
const _ = require('lodash')
const objCopy = _.cloneDeep(obj)
delete objCopy[unwantedKey]
// objCopy = {b: 2, c: 3}

For my code I wanted a short version for the return value of map() but the multiline/mutli operations solutions were "ugly". The key feature is the old void(0) which resolve to undefined.
let o2 = {...o, age: 31, lastname: void(0)};
The property stays in the object:
console.log(o2) // {firstname: "Jane", lastname: undefined, age: 31}
but the transmit framework kills it for me (b.c. stringify):
console.log(JSON.stringify(o2)) // {"firstname":"Jane","age":31}

I wrote big function about issue for me. The function clear all values of props (not itself, only value), arrays etc. as multidimensional.
NOTE: The function clear elements in arrays and arrays become an empty array. Maybe this case can be added to function as optional.
https://gist.github.com/semihkeskindev/d979b169e4ee157503a76b06573ae868
function clearAllValues(data, byTypeOf = false) {
let clearValuesTypeOf = {
boolean: false,
number: 0,
string: '',
}
// clears array if data is array
if (Array.isArray(data)) {
data = [];
} else if (typeof data === 'object' && data !== null) {
// loops object if data is object
Object.keys(data).forEach((key, index) => {
// clears array if property value is array
if (Array.isArray(data[key])) {
data[key] = [];
} else if (typeof data[key] === 'object' && data !== null) {
data[key] = this.clearAllValues(data[key], byTypeOf);
} else {
// clears value by typeof value if second parameter is true
if (byTypeOf) {
data[key] = clearValuesTypeOf[typeof data[key]];
} else {
// value changes as null if second parameter is false
data[key] = null;
}
}
});
} else {
if (byTypeOf) {
data = clearValuesTypeOf[typeof data];
} else {
data = null;
}
}
return data;
}
Here is an example that clear all values without delete props
let object = {
name: 'Semih',
lastname: 'Keskin',
brothers: [
{
name: 'Melih Kayra',
age: 9,
}
],
sisters: [],
hobbies: {
cycling: true,
listeningMusic: true,
running: false,
}
}
console.log(object);
// output before changed: {"name":"Semih","lastname":"Keskin","brothers":[{"name":"Melih Kayra","age":9}],"sisters":[],"hobbies":{"cycling":true,"listeningMusic":true,"running":false}}
let clearObject = clearAllValues(object);
console.log(clearObject);
// output after changed: {"name":null,"lastname":null,"brothers":[],"sisters":[],"hobbies":{"cycling":null,"listeningMusic":null,"running":null}}
let clearObject2 = clearAllValues(object);
console.log(clearObject2);
// output after changed by typeof: {"name":"","lastname":"","brothers":[],"sisters":[],"hobbies":{"cycling":false,"listeningMusic":false,"running":false}}