Javascript/PHP redirect - javascript

Hello fellow programmers!
I'm working on a personal project (mainly to learn php/javascript) and have ran into an issue with redirection when clicking on a link. I have a bit of a strange situation on a tabbed page I've created and I think that may be what is causing my problem.
I'm trying to allow the user to click the (which due to css has made it look different than normal ) to redirect them to a new page with more details. I THINK that the second tag on my page is what is throwing me off because I have a form in it.
I have tried tons of different things like window.location.href="", location.href="", document.location="", etc... But the same thing always occurs. I am able to get both alert messages, so I know I am getting into my JavaScript (even when I put it into it's own .js file).
Anyway advice/help would be very helpful. Also, if anyone has a suggestion on cleaning this code up a bit, that would also be truly helpful.
Below is basically what I have.
Thanks in advance for your help!
<html>
<head>
<title>test site</title>
<link rel="stylesheet" href="test.css" type="text/css" media="screen" />
<script src="test.js" type="text/javascript"></script>
<script type="text/javascript">
function viewDetails(modelId){
alert(modelId);
window.location.href="new url?ModelID=" + modelId;
alert('redirecting would be way awesome...');
}
</script>
</head>
<body onload="load()">
<div id="tabbed_box_1" class="tabbed_box">
<h4>Navigation Tabs<small>Select a tab</small></h4>
<div class="tabbed_area">
<?php
mysql_connect('host','user','password');
mysql_select_db("database");
echo "<ul class='tabs'>";
echo "<li><a href='javascript:tabSwitch(1, 2);' id='tab_1' class='active'>Inventory</a></li>";
echo "<li><a href='javascript:tabSwitch(2, 2);' id='tab_2' >Add Project</a></li>";
echo "</ul>";
echo "<div id='content_1' class='content'>";
echo "<ul>";
$modelsSQL = "SELECT * FROM Model ORDER BY Name";
$modelsResult = mysql_query($modelsSQL);
while ($modelRow = mysql_fetch_array($modelsResult)){
$modelID = $modelRow[0];
$sqlAvailCount = "SELECT * FROM Project WHERE ModelID = " . $modelID . " AND Sold = 0";
$sqlSoldCount = "SELECT * FROM Project WHERE ModelID = " . $modelID . " AND Sold = 1";
$resultAvailCount = mysql_query($sqlAvailCount);
$resultSoldCount = mysql_query($sqlSoldCount);
$rowAvailCount = mysql_num_rows($resultAvailCount);
$rowSoldCount = mysql_num_rows($resultSoldCount);
echo "<li><a href='' onclick='javascript:viewDetails($modelID);'>" . $modelRow[1] . "<small>in stock: <value>"
. $rowAvailCount . "</value> sold: <value>" . $rowSoldCount . "</value></small></a></li>";
}
echo "</ul>";
echo "</div>";
echo "<div id='content_2' class='content'>";
echo "<form action='project_insert.php' method='post' name='projectAddForm'>";
echo "<table cellpadding='5'>";
// Project Model Selection
echo "<tr><td>";
echo "<label for='model'>Model</label>";
echo "</td><td>";
echo "<select name='model' style='width: 250px;'>";
echo "<option value='-1' selected>SELECT</option>";
$modelListSQL = "SELECT * FROM Model ORDER BY Name";
$modelListResult = mysql_query($modelListSQL);
while ($modelListRow = mysql_fetch_array($modelListResult)){
echo "<option value='" . $modelListRow['ID'] . "'>" . $modelListRow['Name'] . "</option>";
}
echo "</select>";
echo "</td></tr>";
// Project Material Selection
echo "<tr><td>";
echo "<label for='material'>material</label>";
echo "</td><td>";
echo "<select name='material' style='width: 250px;'>";
echo "<option value='-1' selected>SELECT</option>";
$materialListSQL = "SELECT * FROM Material ORDER BY Name";
$materialListResult = mysql_query($materialListSQL);
while ($materialListRow = mysql_fetch_array($materialListResult)){
echo "<option value='" . $materialListRow['ID'] . "'>" . $materialListRow['Name'] . "</option>";
}
echo "</select>";
echo "</td></tr>";
// Project Finish Selection
echo "<tr><td>";
echo "<label for='finish'>finish</label>";
echo "</td><td>";
echo "<select name='finish' style='width: 250px;'>";
echo "<option value='-1' selected>SELECT</option>";
$finishListSQL = "SELECT * FROM Finish ORDER BY Name";
$finishListResult = mysql_query($finishListSQL);
while ($finishListRow = mysql_fetch_array($finishListResult))
{
echo "<option value='" . $finishListRow['ID'] . "'>" . $finishListRow['Name'] . "</option>";
}
echo "</select>";
echo "</td></tr>";
// Project Craftsman Selection
echo "<tr><td>";
echo "<label for='craftsman'>craftsman</label>";
echo "</td><td>";
echo "<select name='craftsman' style='width: 250px;'>";
echo "<option value='-1' selected>SELECT</option>";
$craftsmanListSQL = "SELECT * FROM Craftsman ORDER BY FirstName";
$craftsmanListResult = mysql_query($craftsmanListSQL);
while ($craftsmanListRow = mysql_fetch_array($craftsmanListResult)){
echo "<option value='" . $craftsmanListRow['ID'] . "'>" . $craftsmanListRow['FirstName'] . " " . $craftsmanListRow['LastName'] . "</option>";
}
echo "</select>";
echo "</td></tr>";
//Project Description
echo "<tr><td>";
echo "<label for='description'>Description</label>";
echo "</td><td>";
echo "<input type='text' name='description' id='textArea' style='width:250px'>";
echo "</td></tr>";
// Project Selling Price
echo "<tr><td>";
echo "<label for='price'>Price</label>";
echo "</td><td>";
echo "<input id='price' name='price' type='number' style='width:150px'>";
echo "</td></tr>";
// Project Completion Date
echo "<tr><td>";
echo "<label for='date'>Finish Date</label>";
echo "</td><td>";
$dateArray = getdate();
$month = $dateArray[mon];
$day = $dateArray[mday];
if ($month < 10){
$month = '0' . $dateArray[mon];
}
if ($day < 10){
$day = '0' . $dateArray[mday];
}
$todaysDate = $dateArray[year] . '-' . $month . '-' . $day;
echo "<input type='date' name='date' value='" . $todaysDate . "' style='width:150px'>";
echo "</td></tr>";
// Buttons
echo "<tr><td align='center'>";
echo "<input type='button' name='Save' value='Save' onclick='javascript:validateAndSubmit(this.form);' style='width:100px'>";
echo "</td><td align='center'>";
echo "<input type='button' name='Cancel' value='Cancel' onclick='javascript:cancelEntry();' style='width:100px'>";
echo "</td></tr>";
echo "</table>";
echo "</form>";
echo "</div>";
?>
</div>
</div>
</body>

window.location.href may not trigger reload in some browsers and cases..
You should add a reload after
like this:
window.location.href = '/foo/bar/';
window.locaton.reload(true)
But, some browsers delay milliseconds to perform location.href set. In this cases the window.location.reload(true) may complete before this.
Therefore, add a timeout in reload:
window.location.href = '/foo/bar/';
setTimeout('window.locaton.reload(true)', 500);
works in all browsers for me

Good morning! I found the cause of my problem this morning and have been able to resolve the issue. The problem I was causing is because I am using the tag (stylized by css) to display the information, with an onclick event to call my JS code to redirect. Within the tag I had the href='', thinking that the JS would override that functionality, it doesn't!
Removing the href='' from the tag resolved the issue and allowed me to redirect to the new page. A second solution is to use my php code to dynamically create the href link within the tag.
echo "<li><a onclick='viewDetails($modelID);'>" . $modelRow[1] . "<small>in stock: <value>" . $rowAvailCount . "</value> sold: <value>" . $rowSoldCount . "</value></small></a></li>";
OR
echo "<li><a href='inventorydetails.php?ModelID=" . $modelID . "'>" . $modelRow[1] . "<small>in stock: <value>" . $rowAvailCount . "</value> sold: <value>" . $rowSoldCount . "</value></small></a></li>";
I think I will go with the second example for two reasons. First, it provides the link icon when hovering (which I know I can add through css, but this is easier. Second, less JS code.
I thank you for all your help in resolving this!

Related

Undefined index after json_decode

I have a problem when I'm trying to get the contents of a JavaScript Array and pass its value to a PHP Array Variable.
What I'm doing is that, when a user clicks a button, the value of the item clicked will be added to the javascript array and every time the javascript array updates, the PHP variable will also update and so the contents of the div displaying the contents of the PHP array. I'm not using forms for this matter but buttons
However, when I try to use the json_decode function to get the values of a JavaScript array, it's giving me a Message: undefined index: data error
I'm a beginner in JavaScript, jQuery and AJAX so please bear with me
This is my code:
<script>
// ARRAY VARIABLE WHERE ITEM VALUES WILL BE STORED
var food_item = new Array();
// FUNCTION TO BE TRIGGERED WHEN USER CLICKED THE BUTTON, GET THE ITEM'S VALUE AND ADD IT TO ARRAY
function addToTray(data){
food_item.push(document.getElementById(data).value);
dataString = food_item; // array?
var jsonString = JSON.stringify(dataString);
$.ajax({
type: "POST",
url: "main",
data: {data: jsonString},
cache: false,
success: function(){
alert("OK");
}
});
}
</script>
<body>
...
// LINE OF CODE RESPONSIBLE FOR FETCHING JAVASCRIPT ARRAY VALUES
$this->session->userdata['food_tray'] = json_decode($_POST['data']);
// DIV TO BE UPDATED
<div class="col-md-3 food-tray" id="food-items" style="margin-top: 7%">
<!--FOOD TRAY-->
<div class="panel-heading">
<h3 class="ft-header">Food Tray</h3>
</div>
<div class="panel-body">
<?php
$count_fi = count($this->session->userdata('food_tray'));
echo "<p>Your Items (" . $count_fi . ")</p>";
if($count_fi == 0){
echo "<p class='no-avail-list'>NO ITEMS ADDED IN FOOD TRAY</p>";
}else{
echo "<table class='table borderless'>";
for($i = 0; $i < $count_fi; $i++){
echo "<tr>";
echo "<td>" . $this->session->userdata['food_tray'][$i] . "</td>";
echo "<td>P 200.00</td>";
echo "<td><form method='post'><input type='number' name='qty' min='1' max='100' value='1'/></form></td>";
echo "</tr>";
}
echo "</table>";
echo "<a href='' class='btn btn-success' data-toggle='modal' data-target='#myModal'>
Add Friend</a>";
echo "<a href='".base_url()."index.php/CheckOut' class='btn btn-warning'>Proceed to Checkout</a>";
}
?>
</div>
</div>
...
<?php
foreach($query->result() as $row){
echo "<div class='col-lg-7'>";
echo "<div class='thumbnail'>";
$file_name = strtolower(preg_replace('/[^A-Za-z0-9\-.]/', '', $row->name));
/*if(file_exists(FCPATH . '/assets/images/main/food/' . $file_name . '.jpg')){
echo "<img src='".base_url()."/assets/images/main/food/".$file_name.".jpg' alt='' width='320px' height='100px'>";
}else{
echo "<img src='http://placehold.it/320x150' alt=''>";
}*/
echo "<img src='http://placehold.it/320x150' alt=''>";
echo "<div class='caption'>";
echo "<h5 class='pull-right'>&#x20B1 " . $row->price . "</h5>";
echo "<h5><a href='#'>" . $row->name . "</a></h5>";
echo "<h5>Calorie Count : " . ($row->calorie_count == NULL ? "Not Available" : $row->calorie_count) . "</h5>";
// BUTTON FOR `addToTray()` FUNCTION
echo "<button class='btn btn-primary' id='".$row->id."' value='".$row->name."' style='width:100%' onclick='addToTray(".$row->id.")'>Add to Tray</button>";
// var_dump($row->name);
echo "</div>";
echo "</div>";
echo "</div>";
}
?>
</body>
Anyone who knows how to solve this problem? Any help would be appreciated.
create your session as
$array = array ('food_tray' => json_decode($javascriptarray));
$this->session->set_userdata($array);
check if your javascript libraries are loaded in sources tab.

passing variable from while loop when user press link (php)

i am searching for a way to pass variable ($result[1]) to a session variable from while loop within a link. will be glad for some help
while ($result = mysqli_fetch_array($dataset,MYSQLI_NUM)){
echo "<tr>";
echo " <td >", "<a href='Rate_Supplier.php'>" . $result[1] ."
</a>","</td>" ;
echo " <td >" . $result[0] . "</td>" ;
echo " <td >" . $result[2] . "</td>" ;
echo "</tr>\n";
}

Show specific text from a php loop of database results using jquery

I have selected data from my database and I have looped through the results to display them on my page. I have 3 results which are shown. Each result has a button with an id called decrease. When I click this button, an alert with the name of the item containing the alert button should be displayed. I am using jQuery to achieve this.
My problem is that whenever I click the button, the name of only the first item in the results array is displayed. The buttons in the other two results don't seem to work. What am I doing wrong?
The code that loops through the result and displays the items in the database table:
if(mysqli_num_rows($run) >= 1){
while($row = mysqli_fetch_assoc($run)) {
$name = $row['name'];
$quantity = $row['quantity'];
$price = $row['price'];
$image = $row['image'];
$category = $row['category'];
$total = $price * $quantity;
echo "<div class=\"post-container\">\n";
echo "<div class=\"post-thumb\">\n";
echo "<img src='$image'>\n";
echo "</div>\n";
echo "<div class=\"post-title\">\n";
echo "<h4 style=\"font-weight:bold;\">\n";
echo "$name\n";
echo "<span id=\"deletion\">Delete</span>\n";
echo "</h4>\n";
echo "</div>\n";
echo "<div class=\"post-content\">\n";
echo "<ul style=\"list-style-type:none;\">\n";
echo "<li>Cost Per Item: <span id=\"cost\">$price</span>/=</li>\n";
echo "<li>\n";
echo "Quantity: \n";
echo "<button type=\"submit\" id=\"decrease\" class=\"glyphicon glyphicon-minus\" title=\"Decrease Quantity\"></button>\n";
echo "\n";
echo "<span id=\"cost\" class=\"quantity\">&nbsp$quantity&nbsp</span>\n";
echo "\n";
echo "<button type=\"submit\" id=\"increase\" class=\"glyphicon glyphicon-plus\" title=\"Increase Quantity\"></button>\n";
echo "</li>\n";
echo "<li>Total Cost: <span id=\"cost\">$total</span>/=</li>\n";
echo "</ul>\n";
echo "</div>\n";
echo "</div>";
}
}
And here's the jquery:
$("#decrease").click(function(){
var name = $(this).parent("li").parent("ul").parent("div.post-content").siblings("div.post-title").find("a").text();
alert(name);
});
Your HTML markup is invalid as there can be only one element with given id - id must be unique. You can use classes instead, for example class decrease will have selector .decrease, that will pertain to all your buttons.

Oop check if database table is empty

I have a selector wich gets information from the database. But when my database table is empty, the selector still shows up like this:
However, when my database is empty. I don't want to show the selector. but a message that says something like: Database is empty! Add something.
My code for the selector:
$results = $database->Selector();
echo "<form name='form' method='POST' id='selector'>";
echo "<select name='train_name' id='train_name' multiple='multiple'>";
// Loop trough the results and make an option of every train_name
foreach($results as $res){
echo "<option value=" . $res['train_name'] . ">" . $res['train_name'] . "</option>";
}
echo "</select>";
echo "<br />" . "<td>" . "<input type='submit' name='Add' value='Add to list'/>" . "</td>";
echo "</form>";
The function:
function selector() {
$sql = "SELECT train_name, train_id FROM train_information ORDER BY train_name";
$sth = $this->pdo->prepare($sql);
$sth->execute();
return $sth->fetchAll();
}
EDIT:
Got this now:
$results = $database->Selector();
if(count($results) > 0) {
//Form etc here//
}else echo "nope";
It is working now! :D

Using JavaScript inside PHP code [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
Ok so I have a booking system that I am working on and I have events created in a table which gets populated by PHP if the admin adds new events. I would like to run a script if the user tries to book an event and then submit the form to php. I would like to do this because I want to know if the user has a voucher and wants to pay either by card or via paypal.
Here is the table screenshot, sorry only a link I need 10 rep points.
The PHP code that creates the tables:
<?php
$con = mysql_connect("localhost","root","");
if(!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("flexiflash", $con);
echo "<thead>";
echo "<tr>";
echo "<th>ID</th>";
echo "<th>Venue</th>";
echo "<th>Event</th>";
echo "<th>Date</th>";
echo "<th>Time</th>";
echo "<th></th>";
echo "</tr>";
echo "</thead>";
$result = mysql_query("SELECT * FROM events");
while($row = mysql_fetch_array($result))
{
echo "<tbody>";
echo "<form class='table-form' action='book_event.php' method='post' onsubmit='return check()'>";
echo "<tr>";
echo "<td>" . $row['Event_ID'] . "</td>";
echo "<td>" . $row['Event_Venue'] . "</td>";
echo "<td>" . $row['Event_Name'] . "</td>";
echo "<td>" . $row['Event_Date'] . "</td>";
echo "<td>" . $row['Event_Time'] . "</td>";
echo "<td><input type='submit' class='sub_btn' name='submit' value='Book now'></td>";
echo "</tr>";
echo "</form>";
echo "</tbody>";
}
mysql_close($con);
?>
IF YOU NEED ANY MORE INFO LET ME KNOW
PHP is backend. JavaScript is frontend. What do you want to do in the frontend? Perform the check() function? If so, just put this
<?php
echo '<script>
function check() {
//do something
return true;
}
</script>';
?>
before the table. This should do it. But it's kinda ugly :)

Categories