var price = "$23.03";
var newPrice = price.replace('$', '')
This works, but price can also be such as:
var price = "23.03 euros";
and many many other currencies.
Is there anyway that I could leave only numbers and decimal(.)?
var newPrice = price.replace(/[^0-9\.]/g, '');
No jQuery needed. You will also need to check if there is only one decimal point though, like this:
var decimalPoints = newPrice.match(/\./g);
// Annoyingly you have to check for null before trying to
// count the number of matches.
if (decimalPoints && decimalPoints.length > 1) {
// do whatever you do when input is invalid.
}
var newprice = price.replace( /\D+$/, '');
Related
I want to remove the decimals after a price if it ends on ',00'. If it ends on anything else it should remain. I'll have to be able to see on what the price ends to do so, but how do I achieve this in Javascript?
My idea was checking if the price ended on 00 and removing it in an if statement.
function gformFormatMoney(text, isNumeric){
if(!gf_global.gf_currency_config)
return text;
var currency = new Currency(gf_global.gf_currency_config);
var unformatted = currency.toMoney(text, isNumeric);
var formatted;
var formatting = unformatted%10;
if(formatting == 00) {
}
return unformatted;
}
^This gives a error 'Octal litterals with the prefix 0 are not allowed'
You need to parse your numbers as a float, fix it to 2 decimals (in all cases), and remove any matches for (.00). Something like this could work:
function fixFloat(num){
return parseFloat(num).toFixed(2).replace('.00', '');
}
console.log(fixFloat(20.00));
console.log(fixFloat(40.40));
console.log(fixFloat(30.01));
Please be aware that this will return a string. If you wish to convert this back to a number, you'll need to parse it again.
You should use toFixed.
as for :
let num = 50.00;
num.toFixed(2).includes('.00') ? num.toFixed() :num.toFixed(2);
If the data type is not string , the trailing zeros after decimal will be removed. If it is a string use parseInt to convert to number
let price = 20.00;
console.log(price)
let price1 = '40.00'
console.log(parseInt(price1, 10))
let price2 = '40.00'
console.log(parseFloat(price2, 10))
Turns out it wasn't an integer, but a string.
I fixed it by doing:
function gformFormatMoney(text, isNumeric){
if(!gf_global.gf_currency_config)
return text;
var currency = new Currency(gf_global.gf_currency_config);
var unformatted = currency.toMoney(text, isNumeric);
var formatted = unformatted.replace(',00', '');
return formatted;
}
i would like to format decimal values to specific format as like
1.23 should be shown as 0001.23 using javascript. is there any specific functions like toPrecision(), tofixed() in javascript to handle these kind of formatting or any pointers to go ahead with any solutions?
here preceeding decimal is dynamic one.
for example :
i have 2 values :
first value : 99.4545
second value : 100.32
in this second value has higher length (3)before decimal and first value has higher length after decimal(4). so subtracted result(0.8655) of this should be formatted as ###.#### (000.8685)
thank you
Just make a function that does what you want it to. Here is an example you can expand on if you want.
function pad(num, padSize){
var numString = "" + num.split('.')[0];
if(num.length < padSize){
var numZeroes = padSize-num.length;
var zeroes = "";
while(numZeroes){zeroes += "0"; numZeroes--;}
return zeroes + num;
}else return num;
}
if you want to lpad some 0 onto 1.23 you can do the following
var value = 1.23
value = ("0000000"+ value).slice(-7);
Change the -7 to be whatever you want the total string length including the decimal point to be.
Added after question edit
The above should handle your question pre-edit but for the rest of it you'll need something like this.
var formatNum = function (num, preLen, postLen) {
var value = num.split("."),
padstring = "0";
padLen = (preLen > postLen)?preLen:postLen;
for (i = 0; i < padLen; i++) {
padstring += padstring;
}
if (typeof(value[1]) === "undefined") {
value[1] = "0";
}
return ((padstring + value[0]).slice(-preLen)+ "." + (value[1] + padstring).substring(0,postLen));
}
This takes the number you want formatted and the lengths you want each string to be on either side of the '.'. It also handles the case of an integer.
If you want it to output any other cases such as returning an integer, you'll have to add that in.
Try to use a string, like "000" + some value
Trying to build a Javascript %age Discount calculator for my webshop. The problem is that the calculator calculates some products wrong by 2-10%. Please help, whats wrong in the code?
<script type="text/javascript">
$(document).ready(function() {
/*
Least allowed discount to show.
*/
var minDiscount = 15;
$('.gridArticlePrices').each(function() {
/* Get ordinary price */
var oldPrice = $(this).children('.gridArticlePriceRegular').html();
/* Get sale price */
var newPrice = $(this).children('.gridArticlePrice').children('.reducedPrice').html();
if ((oldPrice) && (newPrice)) {
/* Convert to numbers instead of strings */
var oldPrice = parseInt(oldPrice.replace("/[^0-9]/g", ""));
var newPrice = parseInt(newPrice.replace("/[^0-9]/g", ""));
/* Calcuate the precentage, rounded of to 0 decimals */
var discount = Math.round(100 - ((newPrice / oldPrice) * 100));
/* If the precentage is higher than "var min Discount" then write out the discount next to the products price.*/
if (discount >= minDiscount) {
$(this).parent().after("<div class='discount'>-" + discount + "%</div>");
}
}
});
});
</script>
UPDATE:
My original suggestion to use parseFloat was assuming your prices included decimal components. As I see now, they are in fact integers, so parseInt works fine.
The actual issue is your replace() call isn't removing anything. You should remove the quotes around the regex, and then it will remove the extra characters you don't want.
var oldPrice = parseInt(oldPrice.replace(/[^0-9]/g, ""));
var newPrice = parseInt(newPrice.replace(/[^0-9]/g, ""));
Note: If you do need to handle decimal prices, you would need to add "." to you regex (so it doesn't get removed), and use parseFloat instead of parseInt.
i have a Invoice form and a jquery function.
In Invoice if i enter the quantity greater then the available quantity then i have to alert the user.
My problem is: Let the max quantity is 5, if i input data as 7 (single digit>max avail quantity) then my code is working fine. But if i enter two digigist number eg. 17(two digists>max avail quantity) then my alert box is not coming.
I mean onkeyup my function is working only with single digit.
How can i make it happening? Please help.
$('input[name="quantity"]').keyup(function()
{
//problem is here
var $tr = $(this).closest("tr");
var unitprice = $tr.find('input[name^="unitprice"]').val();
var q = $tr.find('input[name^="quantity"]').val();
var cq = $tr.find('input[name^="checkquantity"]').val();
if(q>cq)
{
alert("Error: Quantity value exceeds then available quantity..Max Quantity is "+cq);
//this works fine only if single digit is entered in textbox quantity
}
//----below are some other stuffs -these are working fine
$tr.find('input[name^="sprice"]').val($(this).val() * unitprice);
var totalPrice = 0;
$('input[name="sprice"]').each(function()
{
totalPrice += parseFloat(this.value);
$('[name=subtotal]').val(totalPrice);
});
});
--------------
------------
// Form containing the above textboxes
<input type="submit" id="submitbtnId" value="Save"/>`
q > cq is comparing 2 strings, which is not what you want. You're trying to compare the numerical value of those strings.
Use this instead:
if ( +q > +cq)
{
// alert your error
}
Note that by prefixing the variables with the + sign, you're converting them to a number.
Better yet, convert them to a number as soon as you get the values:
var $tr = $(this).closest("tr");
var unitprice = +$tr.find('input[name^="unitprice"]').val();
var q = +$tr.find('input[name^="quantity"]').val();
var cq = +$tr.find('input[name^="checkquantity"]').val();
if ( q > cq )
{
alert("Error: Quantity value exceeds then available quantity..Max Quantity is " + cq);
}
You need to use parseInt() to ensure you are comparing integers, not strings:
if (parseInt(q, 10) > parseInt(cq, 10)) {
/* Rest of your code */
}
Your values are compared as string. If you want to compare Numbers, either use:
parseInt() or parseFloat()
or
[..].val() * 1, but this will return 'NaN' if its no digit, while parseInt() and parseFloat() will return 0
I have scenario where if user enters for example 000.03, I want to show the user it as .03 instead of 000.03. How can I do this with Javascript?
You can use a regular expression:
"000.03".replace(/^0+\./, ".");
Adjust it to your liking.
This actually is trickier than it first seems. Removing leading zero's is not something that is standard Javascript. I found this elegant solution online and edited it a bit.
function removeLeadingZeros(strNumber)
{
while (strNumber.substr(0,1) == '0' && strNumber.length>1)
{
strNumber = strNumber.substr(1);
}
return strNumber;
}
userInput = "000.03";
alert(removeLeadingZeros(userInput));
How about:
function showRounded(val) {
var zero = parseInt(val.split('.')[0],10) === 0;
return zero ? val.substring(val.indexOf('.')) : val.replace(/^0+/,'') );
}
console.log(showRounded('000.03')); //=> ".03"
console.log(showRounded('900.03')); //=> "900.03"
console.log(showRounded('009.03')); //=> "9.03"
Or adjust Álvaro G. Vicario's solution to get rid of leading zero's into:
String(parseFloat("090.03")).replace(/^0+\./, ".")
This function will take any string and try to parse it as a number, then format it the way you described:
function makePretty(userInput) {
var num,
str;
num = parseFloat(userInput); // e.g. 0.03
str = userInput.toString();
if (!isNaN(num) && str.substring(0, 1) === '0') {
str = str.substring(1); // e.g. .03
} else if (isNaN(num)) {
str = userInput; // it’s not a number, so just return the input
}
return str;
}
makePretty('000.03'); // '.03'
makePretty('020.03'); // '20.03'
It you feed it something it cannot parse as a number, it will just return it back.
Update: Oh, I see If the single leading zero needs to be removed as well. Updated the code.
Assuming your input's all the same format, and you want to display the .
user = "000.03";
user = user.substring(3);
You can convert a string into a number and back into a string to format it as "0.03":
var input = "000.03";
var output = (+input).toString(); // "0.03"
To get rid of any leading zeroes (e.g. ".03"), you can do:
var input = "000.03";
var output = input.substr(input.indexOf(".")); // ".03"
However, this improperly strips "20.30" to ".30". You can combine the first two methods to get around this:
var input = "000.03";
var output = Math.abs(+input) < 1 ?
input.substr(input.indexOf(".")) :
(+"000.03").toString();