Place animated footer under other divs - javascript

so I wanted an animated footer for my webpage using jquery. There's supposed to be a button which should trigger the animation. I found a nice example for all this, and everything is fine and dandy. Except that the button (including the footer) has this code that makes it stick to the bottom of your web browser, rather than to the bottom of the page. I do [i]not[/i] want it to, like, "scroll" along with the page, I realy want it to be underneath all my other divs. I tried putting it in the div container (which has all my other divs in it as well), but that doesn't seem to work.
Now, (after 2.5 hours of googling) I found out that it might/may/could have something to do with "absolute" positioning in the CSS, so I tried switching some things around such as giving the footer's container a relative position or giving it an "overflow: hidden;" along with the rest a left float but nothing seemed to solve my problem. (I could've done something wrong, not that great with CSS after all :-/)
I hope someone is able/willing to help.
P.S. Here's the example I used:
http://return-true.com/2010/04/jquery-pop-up-footer-version-2/
and here's the code:
Javascript:
jQuery(function($) {
var open = false;
$('#footerSlideButton').click(function () {
if(open === false) {
$('#footerSlideContent').animate({ height: '300px' });
$(this).css('backgroundPosition', 'bottom left');
open = true;
} else {
$('#footerSlideContent').animate({ height: '0px' });
$(this).css('backgroundPosition', 'top left');
open = false;
}
});
});
HTML:
<div id="footerPlacement">
<div id="footerSlideContainer">
<div id="footerSlideButton"></div>
<div id="footerSlideContent">
<div id="footerSlideText">
<h3>Hey! I'm a Sliding Footer</h3>
<p>What's a Sliding Footer? Well I'm a cool little element which can be hidden from view, and revealed when the user wants to see me.</p>
<p>What can you use me for? Well look at all this stuff:</p>
<ul>
<li>Sales information</li>
<li>Important updates</li>
<li>Unobtrusive about panel</li>
<li>Or just a good ol' footer</li>
</ul>
<p>There are obviously many other uses, but these are the few useful ones I can think of.</p>
</div>
</div>
</div>
</div>
CSS:
#footerPlacement {
margin-bottom: 0px;
width: 1000px;
margin-left: auto;
margin-right: auto;
}
#footerSlideContainer {
position: fixed;
margin-left: 0px;
bottom:0px;
width: 1000px;
}
#footerSlideButton {
background: url('../images/footer/footerbtn.png') top left no-repeat transparent;
position: absolute;
top: -55px;
right: 20px;
width:50px;
height:50px;
border: none;
cursor: pointer;
}
#footerSlideContent {
width: 100%;
height: 10px;
background: #251b15;
color: #CCCCCC;
font-size: 0.8em;
border: none;
font-family: DejaVuSansBook, Sans-Serif;
}
#footerSlideText {
padding: 15px 10px 25px 25px;
}
Thanks in advance!

if you change your #footerPlacement to include position:relative, you can change #footerSlideContainer to be position:absolute and then your footer will sit below any content above it.
However you will need to make the content have a min-height of around 350px for the footer to work properly and if your content isn't long enough, the footer won't be at the bottom of the browser.
I also added overflow:hidden to #footerSlideContent. I have made a fiddle to demonstrate:
http://jsfiddle.net/tc6b8/

Related

How to change logo and add a colored border to the bottom of my fixed header when user scrolls down?

There is a lot of information online regarding header effects on scroll and I've spent a lot of time trying to figure this out on my own. I was hoping to find a way to do this without using JS but there doesn't seem to be a way. I've tried just adding a simple effect (changing height of header on scroll) using JS ... hoping that once I got the header to actually respond to this I could work with it to make the effects that I'm wanting. But I can't even get the header to respond. Ultimately I'm wanting the header to slightly reduce in height, the logo will change to a different image and there will be a 15px colored border added to the bottom. I know that's a lot for a novice web designer to try to attempt but I'd really love to figure out how to do it. Any help or direction to good online resources for this would be so appreciated.
I'm adding only my html and css just to keep things less cluttered. I can add what I've tried in my js file if I need to. I've commenting out some css that went with the js that clearly doesn't work. Thanks in advance for your time.
<header>
<div id="nav">
<div id="nav_left">
HOME
SERVICES
PORTFOLIO
</div>
<a href="index.html" id="logo" class="noHover"><img src="images/logo_6_small.png" alt="Claire Crawford"
id="logo_Claire" /></a>
<div id="nav_right">
BLOG
ABOUT
GET IN TOUCH
</div>
</div>
</header>
header {
height: 160px;
position: fixed;
top: 0;
width: 100%;
background: white;
/* border-bottom: 15px solid rgb(197, 179, 55) */
}
/* header border on scroll
header.fixed.scrolled .header_bottom .container_inner {
border-bottom: 1px solid #0a0a0a;
} */
/* header.sticky {
height: 120px;
} */
/* header {
transition: padding 300ms ease;
} */
try to use this code in your actual code. It might work well
$(function() {
$(window).scroll(function() {
if ($(this).scrollTop() > 200) {
$('#logo img').attr('src', 'http://placehold.it/220?text=Original+Logo!');
$("#nav").css("border-bottom", "none");
}
if ($(this).scrollTop() < 200) {
$('#logo img').attr('src', 'https://cdn-images-1.medium.com/max/1600/1*4mdh6im57oFHSNY4syD_2Q.png');
$("#nav").css("border-bottom", "2px solid red");
}
})
});
header {
height: 160px;
position: fixed;
top: 0;
width: 100%;
background: white;
/* border-bottom: 15px solid rgb(197, 179, 55) */
}
.wrapper {
height: 1000px;
}
img {
width: 100px;
}
#nav {
width: 100%;
display: flex;
height: 110px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="wrapper">
<header>
<div id="nav">
<div id="nav_left">
HOME
SERVICES
PORTFOLIO
</div>
<img src="https://cdn-images-1.medium.com/max/1600/1*4mdh6im57oFHSNY4syD_2Q.png" alt="Claire Crawford" id="logo_Claire" />
<div id="nav_right">
BLOG
ABOUT
GET IN TOUCH
</div>
</div>
</header>
</div>
I am telling you step by step:
1. add this to your index.html page. you need to add jquery to work this code. <script src="code.jquery.com/jquery-3.4.1.min.js" integrity="sha256-CSXorXvZcTkaix6Yvo6HppcZGetbYMGWSFlBw8HfCJo=" crossorigin="anonymous"></script>
2. Then copy paste my code into your js file and edit it as you want.
3. i have write a funtion to scroll. you can see i have write 200 so that if you scroll 200px below the logo will change. so there are two condition I have written
if ($(this).scrollTop() > 200) {
$('#logo img').attr('src', 'http://placehold.it/220?text=Original+Logo!');
$("#nav").css("border-bottom", "none");
}
this one is for after you scroll 200px and the other one is your initial stage.
$('#logo img').attr('src', 'http://placehold.it/220?text=Original+Logo!');
here #logo is the id from html and img is for img inside logo div.
4.$("#nav").css("border-bottom", "none"); nav is for nav div and I added border css by adding .css here

How to create an interactive navigation, in a circular design, using HTML, CSS, and JQuery

// JavaScript Document
$('.page').hide();
$(".btns").click(function(e){
e.preventDefault(); //this method stops the default action of an element from happening.
var $me = $(this); //$(this) references .btns, the object in local scope.
var $myContent = $($me.attr('href')); //pulls href of page 01, 02, or 03.
$('.page').hide(); //hides all pages
$myContent.fadeIn();//fades in clicked href connected to btn
$(".btns").removeClass('selected');//
$me.addClass('selected');
});
*{
border-spacing: 0px;
}
body{
margin: 0px;
padding: 0px;
}
.circle-container {
position: relative;
width: 24em;
height: 24em;
padding: 2.8em;
/*2.8em = 2em*1.4 (2em = half the width of a link with img, 1.4 = sqrt(2))*/
border: dashed 1px;
border-radius: 50%;
margin: 1.75em auto 0;
}
.circle-container a {
display: block;
position: absolute;
top: 50%; left: 50%;
width: 4em; height: 4em;
margin: -2em;
}
.circle-container img { display: block; width: 100%; }
.deg0 { transform: translate(12em); }
<div class="body_content">
<div class="page" id="page_01">
<h2>1. Category 1</h2>
</div>
</div>
<div class="circle-container">
<nav class="navigation">
<a href="#page_01" class="btns deg0" >
<img id="one" src="imgs/button.png" alt="page01"/>
</a>
</nav>
</div>
I have a unique situation that I would like to discuss with you all. I am trying to create a web page that has a circular navigation, as shown here enter image description here
Each one of these buttons would display content when clicked, like an in-page link. The JQuery is as shown enter image description here
The concept seems simple enough, force all content to hide, when a user clicks a button, the page content linked to that button shows. It works when the links are inline or block display, but when in a circle, the links don't work, the button content doesn't show. Has anyone worked with a similar issue? Or would anyone have a potential solution? I apologize for the vagueness of the questions but the issue seems multi-faceted. Any advice or ideas would be greatly appreciated.
Are you sure your jQuery reference is working? I don't see any issue with the code, the click event should fire when you click on the links. Check the console for any errors, I strongly believe jQuery might not get loaded.

How to position two elements centered on top of each other?

The problem:
I have a form with a button underneath it to submit (post) from data with jQuery ajax(). I want for the button to be replaced with a spinner (animated png) for the duration of server ajax call. But such a trivial task is impossible in css to do right.
What i have tried:
I have placed button and image inside a bootstrap row. Ox ajax call I have set button display to none and img display to block. But because this two are not of the same size makes the whole page flicker, breaks the positioning of other elements and so on.
Another idea was to try to place both elements on top of each other with absolute positioning. But, stupid as css is I cannot center it on the middle of the row.
Is there a way to position both elements on top of each other so I can control their visibility?
Please bear in mind that I cannot used absolute position in pixel, because this is a web page and I do not not how wide the browser will be, image can change in the future, text in the button can change in the future, all this things affect absolute size.
If there is another solution to my problem which would prevent the page from jumping up and down it would also be great.
EDIT
Link to one of fiddle experiments:
https://jsfiddle.net/ofb2qdt8/
.button {
position: relative;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: relative;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This renders second element underneath on screen. Not on different z layer.
Experiment 2:
https://jsfiddle.net/ofb2qdt8/
.button {
position: absolute;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: absolute;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This does not center both elements, and they are pushed to the top of the containing div. The element with less height should be centered.
Check this working demo: https://jsfiddle.net/ofb2qdt8/3/
Add in a few lines of jquery and update your css.
Position your loading div according to button div's position, width, height using jquery.
*Click the button to see loading div, and try to play the margin of the button to any pixel.
###JQUERY
$(document).ready(function () {
$('.c2').each(function () {
$(this).css({
'width': $(this).siblings('.c1').outerWidth(),
'height': $(this).siblings('.c1').outerHeight(),
'top': $(this).siblings('.c1').offset().top,
'left': $(this).siblings('.c1').offset().left
});
});
$('.c2').on('click', function () {
$(this).hide(0);
});
});
###CSS
.c1 {
margin: 100px auto;
width: 100px;
text-align: center;
padding: 5px 10px;
background: blue;
z-index: 1;
}
.c2 {
position: fixed;
text-align: center;
background: red;
z-index: 2;
cursor: pointer;
}
Rough, ready and untested:
HTML
<div>
<input type='submit' />
<img src="spinneyIMage.gif" />
</div>
CSS
div{ text-align: center; }
div img{ display: none; }
jQuery
$('submit').click(function(e){
e.preventDefault();
$(this).hide().next().show();
});
After the Ajax call completes reverse the above jQuery.
As I haven't been able to find a working solution I have reverted to my first idea which I discarded at first. Albeit with a little twist.
HTML
<div class="row>
<div id="container-button" class="col-xs-12>
<button id="button" onclick="button_OnClick(e)">submit form via ajax</button>
<img src="img/spinner.png" sytle="display: none" />
</div>
</div>
JS
function btnContact_OnClick() {
// show the soinner and hide the button
showSpinner();
$.ajax(
{
type: 'POST',
url: "someurl.com/target",
data: $("#form").serialize(),
dataType: "json",
complete: function() { hideSpinner();},
success: onAjaxSuccess,
error : onAjaxError
});
}
function hideSpinner() {
$("#spinner").hide();
$("#button").show();
// make container height non-fixed and content adjustable again
$("#container-button").height('auto');
}
function showSpinner() {
// THis is the trick !!!
// Make the container fixed height as it was before displaying spinner, so it does not change with content (spinner is not the same height as button
$("#container-button").height($("#container-button").height());
$("#button").hide();
$("#spinner").show();
}
This is not the perfect solution but the best I could make.
Drawbacks:
it is not clean, you have to use javasript to fix what is css layout
problem
it still causes a little flicker
the height of container while displaying spinner is dependant on button, this may cause clipping if spinner is too big

Make Div fixed bottom & scrollable

I want to have a long page, with a fixed top 100px div, and a fixed 50px bottom div. However, I want the bottom div to scroll as you scroll down the page.
Its hard to explain, but the best example of this is on the front page of PayPal.com
On the first page load, the bottom div looks like it is fixed, and as you adjust the height of the browser window, that div stays at the bottom. Yet as you scroll down the page it is not fixed.
Can anyone explain how they have done this? I am trying to re-create something similar, but cant see how they have managed it.
As far as I can see they have this html...
<div id="fixed-top">
<header class="table-row">
// header content
</header>
<div class="table-row table-row-two">
// Video content
</div>
<div class="table-row">
//bottom content
</div>
</div>
And this CSS...
#fixed-top {
height: 100%;
width: 100%;
display: table;
position: relative;
top: 0;
left: 0;
z-index: 1;
}
.table-row {
display: table-row;
}
But that alone doesn't do it. I also can't see any js thats getting window height and applying it to the main fixed div.
Help! :)
EDIT:
Have just found a way to do it with javascript, controlling the height of the middle row using the window height, minus the 150px for the header and third row.
jQuery(document).ready(function(){
$('div.table-row-two').css({'height':(($(window).height())-150)+'px'});
$(window).resize(function(){
$('div.table-row-two').css({'height':(($(window).height())-150)+'px'});
});
});
But saying that, Zwords CSS only method seems like a winner.
From what I understand, you are looking for something like a sticky footer. So basically if the content is not enough, the footer should go sit at the bottom like its fixed, but if content comes in, it should scroll down like other content.
Try this - http://css-tricks.com/snippets/css/sticky-footer/
First off, you'll need to set the height of the body and html tag, otherwise the table won't take the full screen. Then I altered your code, made it a bit easier.
HTML:
<div id="fixed-top">
<header>
// header content
</header>
<div>
// Video content
</div>
<div>
//bottom content
</div>
</div>
CSS:
html, body {
margin: 0;
padding: 0;
height: 100%;
min-height: 100%;
}
#fixed-top {
display: table;
width: 100%;
height: 100%;
}
#fixed-top > * { /* makes all the direct children of #fixed-top a table row*/
display: table-row;
background: lightblue;
}
#fixed-top > *:nth-child(1) {
background: lightgreen;
height: 40px;
}
#fixed-top > *:nth-child(3) {
background: lightgreen;
height: 25%;
}
You can either set the height to a fix height (in px) or percentages. If you only give two of the three rows a height, the third one will automaticly fill up the rest space.
Also, check this demo.
Check this fiddle / Fullscreen
Using display:table;,display:table-row;,min-height to adjust to screen
HTML
<div class="wrapper">
<div class="row">menu</div>
<div class="row">content</div>
<div class="row">footer</div>
</div>
<div class="wrapper">
<div class="row">content1</div>
<div class="row">content2</div>
<div class="row">content3</div>
</div>
CSS
html,body,.wrapper{
width:100%;
height:100%;
margin:0px auto;
padding:0px;
}
.wrapper{
display:table;
border:1px solid black;
}
.wrapper .row{
display:table-row;
background-color:rgb(220,220,220);
}
.wrapper .row:nth-of-type(1){
min-height:15px;
}
.wrapper .row:nth-of-type(2){
height:100%;
background-color:white;
}
.wrapper .row:nth-of-type(3){
min-height:15px
}
You can do this easily with jQuery using $(window).height() and subtracting your footer/header's heights. See Fiddle for an example.

How to stack divs beside each other to create a carousel

I am trying to create a carousel, where clicking on any element will slide it leftwards, simultaneously sliding the right element into viewport. For that, I need to have the divs stacked side by side. I am trying it out as a float based layout (see Fiddle ).
Problem is that here clicking the red colored div slides it leftward alright, but not the green element leftwards. This is probably due to the fact that they are actually lying below another, as visible when the overflow: hidden is removed from #cont's style. How elese to stack them side by side so that sliding one leftward automatically slides the next one leftwards as well? (Creating the to-be-next element on the fly while clicking and animating it into viewport is a no-no, the element should be present in the DOM!)
I'd suggest you use a plugin, as there is more to this than you may realize. There are many plugins out there for this, here's a list to get you started: http://www.tripwiremagazine.com/2012/12/jquery-carousel.html
I modified your Javascript, HTML, and CSS to get you pointed in the right direction:
http://jsfiddle.net/nf5Dh/2/
You need a container contContent, positioned absolutely, and that container gets moved within the container div. You just float the elements in contContent to get them next to each other.
HTML:
<div id='cont'>
<div id="contContent">
<div id='i1'></div>
<div id='i2'></div>
<div id='i3'></div>
</div>
</div>
CSS:
#cont {
width: 50px;
padding-top: 10px;
background: blue;
height: 50px;
overflow: hidden;
position: relative;
}
#contContent {
height: 50px;
width: 150px;
position: absolute;
top: 0;
left: 0;
}
#contContent > div {
float: left;
display: inline-block;
height: 50px;
width: 50px;
}
#i1 { background: red; }
#i2 { background: green; }
#i3 { background: yellow; }
And the JS:
$("#contContent > div").click(function(){
$("#contContent").animate({left: "-=50px"},1000);
});
You'd probably be better off using an ul instead of all divs, this is at least more semantically correct, though not technically necessary.
<div id="carousel">
<ul id="carouselContent">
<li id="slide1"></li>
<li id="slide2"></li>
<li id="slide3"></li>
</ul>
</div>
This:
#cont {
white-space:nowrap;
overflow: hidden;
}
.pane { // or whatever the slide divs are called. get rid of the float.
float: none;
display: inline-block;
*zoom:1;
*display:inline;
}
You can use that carousel where you can generate javascript for the carousel http://caroufredsel.dev7studios.com/configuration-robot.php
I've used http://sorgalla.com/jcarousel/ for things like this in the past, that's based on postion: relative and left/right offsets. Probably easier than messing with floats.
You can try using a list item instead, and display them inline.

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