I am trying to find a way to switch an image on click.
I have two images.
I have one page, on this page I have one of the images displayed.
If I click on the image, I would like the other image to be loaded in its place.
I know a bit about html and css, and a bit less about php. I am assuming the correct way to go about this would be the use of javascript. Unfortunately, I know nothing about this.
Here is my code so far, what I want to do, is have .../page-2.jpg loaded when this image is clicked.
$pageContent = '
<h2>Promotions</h2>
<div class="promo-img">
<img src="'.$docPath.'/page-1.jpg" alt="Page 1" name="Page 1" width="100%" height="150%" id="page1" style="background: #FFF; display:block;" />
</div>
';
Any input here would be greatly appreciated, Thanks!
#Dennis
Where am I going wrong with this?
$pageContent = '
<h2>Promotions</h2>
<div class="promo-img"><img id="promoImage" src="'.$docPath.'/page-1.jpg" alt="Page 1" width="100%" height="150%" style="background: #FFF; display:block;"
onClick="document.getElementById(\'promoImage\').onclick = function() {
if(this.src == \''.$docPath.'/page-1.jpg\'){
this.src = \''.$docPath.'/page-2.jpg\';
} else {
this.src = \''.$docPath.'/page-1.jpg\';
}
};" /></div>
';
Okay, This does not seem to have an onclick effect?
$pageContent = '
<h2>Promotions</h2>
<div class="promo-img"><img id="promoImage" src="'.$docPath.'/page-1.jpg" alt="Page 1" width="100%" height="150%" style="background: #FFF;" /></div>
<script type="text/javascript">
document.getElementById(\'promoImage\').onclick = function() {
if(this.src == \''.$docPath.'/page-1.jpg\'){
this.src = \''.$docPath.'/page-2.jpg\';
} else {
this.src = \''.$docPath.'/page-1.jpg\';
}
};
</script>
';
HTML:
<img id="image" src="first.jpg">
Javascript: (click to switch)
document.getElementById("image").onclick = function() {
if(this.src == "first.jpg"){
this.src = "second.jpg";
} else {
this.src = "first.jpg";
}
};
Javascript: (hover to switch)
document.getElementById("image").onmouseover = function() {
this.src = "second.jpg";
};
document.getElementById("image").onmouseout = function() {
this.src = "first.jpg";
};
These are the simplest techniques. There are "better" solutions using jQuery or CSS that separate code from the HTML.
Related
Forgive me, it's been a while since figuring out anything with jQuery, I need some guidance/help: I'd love to swap an image 00x-a for 00x-b, but not just for a single image, but for many. Once the BTN below an IMG is clicked, I'd love to swap the IMG above for 00x-b while resetting other IMGs to 00x-a.
<div>
<img id="swap_this" src="img-001-a.jpg">
<a class="button">Change-IMG</a>
</div>
<div>
<img id="swap_this" src="img-002-a.jpg">
<a class="button">Change-IMG</a>
</div>
<div>
<img id="swap_this" src="img-003-a.jpg">
<a class="button">Change-IMG</a>
</div>
<script type="text/javascript">
jQuery(document).ready(function($) {
$(".button").click(function(){
$("#swap_this").attr()({
"src":"img-001-b.jpg";
})
})
});
</script>
This should do it. Only the first picture is set to img-001-a.jpg
var arr = ['img-001-a.jpg', 'img-002-a.jpg', 'img-003-a.jpg']
$.each($('.swap_this'), function(index, value) {
if(index == 0) {
$(this).attr('src', arr[0])
console.log($(this).attr('src'));
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
<img class="swap_this" src="img-001-b.jpg">
<a class="button">Change-IMG</a>
</div>
<div>
<img class="swap_this" src="img-002-b.jpg">
<a class="button">Change-IMG</a>
</div>
<div>
<img class="swap_this" src="img-003-b.jpg">
<a class="button">Change-IMG</a>
</div>
Tried to follow up on your answer, but ended up with something else. The below does what I need, but can it be written with "each" or using a for-loop to iterate through? Thx.
// clicking btn_100
$('.btn_100').click(function(e) {
// reset all IMG to version -a.gif..
$(".img_100").attr('src','img-100-a.gif');
$(".img_099").attr('src','img-099-a.gif');
$(".img_098").attr('src','img-098-a.gif');
// set IMG_100 ver -b.gif..
$(".img_100").attr('src','img-100-b.gif');
});
// clicking btn_099
$('.btn_099').click(function(e) {
// reset all IMG to version -a.gif..
$(".img_100").attr('src','img-100-a.gif');
$(".img_099").attr('src','img-099-a.gif');
$(".img_098").attr('src','img-098-a.gif');
// set IMG_100 ver -b.gif..
$(".img_099").attr('src','img-099-b.gif');
});
// and so on..
Maybe this could work…
for(a=1; a<=100; a++) {
// create fns for all btns
$(".btn_" + a).click(function(e) {
// reset all IMG to version -a.gif..
for(i=1; i<=100; i++) {
$(".img_" + i).attr("src","image-" + i + "-a.gif");
}
// set specific IMG to version -b.gif..
$(".img_" + a).attr("src","image-" + a + "-b.gif");
});
}
i have a div that contains 5 of the same image. i'm trying to make a button that can make one of the images disappear one after another when onclick. i've tried the style.visibility but it makes them all disappear together. This is my code
document.getElementById("btn1").onclick = function() {
document.getElementById("output").style.visibility = "hidden";
}
<input id="btn1" type="button" value="Click me" onclick="onClick1()" style="height: 100px; width: 100px;">
<div style="margin-top: 40px;"></div>
<div id="output">
<img src="/images/person1.jpg">
<img src="/images/person1.jpg">
<img src="/images/person1.jpg">
<img src="/images/person1.jpg">
<img src="/images/person1.jpg">
</div>
You are targeting the image container and then hiding it so all the images disappear at once.
It's not really clear from your question whether you want to click the button once and have the images disappear, or to click the button repeatedly and have one image disappear on each click. This solution answers the first problem.
If you want to hide the images one-by-one you're going to need to use setInterval or setTimeout to manage that. In this example I've used setTimeout.
document.getElementById('btn1').onclick = function() {
// Get all the images
const images = Array.from(document.querySelectorAll('#output img'));
// Loop over the images
function loop(images) {
// If there are images left remove the first one,
// hide it, and then call the function again with the
// reduced image array until all images are gone.
if (images.length) {
const image = images.shift();
image.style.visibility = 'hidden';
setTimeout(loop, 1000, images);
}
}
loop(images);
}
<input id="btn1" type="button" value="Click me" onclick="onClick1()" style="height: 100px; width: 100px;">
<div style="margin-top: 40px;"></div>
<div id="output">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
</div>
Additional documentation
shift
setTimeout
Array.from
If you want to make the images disappear on each click, cache the images, and return a function that the listener calls when you click the button.
const button = document.getElementById('btn1')
button.addEventListener('click', handleClick(), false);
// Cache the image elements, and then return a new
// function to your listener that removes an image on each click
function handleClick() {
const images = Array.from(document.querySelectorAll('#output img'));
return function() {
if (images.length) {
const image = images.shift();
image.style.visibility = 'hidden';
}
}
}
<input id="btn1" type="button" value="Click me" style="height: 100px; width: 100px;">
<div style="margin-top: 40px;"></div>
<div id="output">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
<img src="https://dummyimage.com/30x30/000/fff">
</div>
You should give id's to image tag instead of parent div.
Created variable which which will work as a counter.
On each click increase counter and hide the specific image tag.
Your code will look like:
let imageToDelete = 1;
document.getElementById("btn1").onclick = function() {
document.getElementById("image_" + imageToDelete).style.visibility = "hidden";
imageToDelete++;
}
<input id="btn1" type="button" value="Click me" onclick="onClick1()" style="height: 100px; width: 100px;">
<div style="margin-top: 40px;"></div>
<div>
<img id="image_1" src="/images/person1.jpg">
<img id="image_2" src="/images/person1.jpg">
<img id="image_3" src="/images/person1.jpg">
<img id="image_4" src="/images/person1.jpg">
<img id="image_5" src="/images/person1.jpg">
</div>
With that script, all you are doing is hiding the parent of all the images, which results in all the images "seemingly disappearing" at once. You have to remove each separately to achieve your desired result.
const RemoveImage = Event => {
const Target = Event.target;
const ImgPos = Target.getAttribute("data-remove");
const Selector = `#image-parent > img:${ImgPos}-of-type`;
const ImgToRemove = document.querySelector(Selector);
if(!ImgToRemove) return false;
ImgToRemove.parentElement.removeChild(ImgToRemove);
return true;
};
const Buttons = document.querySelectorAll("button[data-remove]");
Buttons.forEach(btn => btn.addEventListener("click", RemoveImage));
#image-parent > img:hover {
filter: brightness(92%);
}
#first {outline: 2px solid #a00;}
#last {outline: 2px solid #0a0;}
<div id="image-parent">
<img src="https://via.placeholder.com/70" id="first">
<img src="https://via.placeholder.com/70">
<img src="https://via.placeholder.com/70">
<img src="https://via.placeholder.com/70" id="last">
</div>
<button data-remove="first">Remove first img</button>
<button data-remove="last">Remove last img</button>
If you don't want the images to be removed fully, but rather just hidden:
Rreplce the line ImgToRemove.parentElement.removeChild(ImgToRemove); with something like ImgToRemove.classList.add("hidden-by-css");
Then declare this CSS class with opacity: 0; pointer-events: none;.
We know manipulating HTML DOM is not popular option. But this will work with your problem.
document.getElementById("btn1").onclick = function() {
let imageNode = document.getElementById("output").getElementsByTagName('img')[0];
imageNode.parentNode.removeChild(imageNode)
}
I have found that using the queue() and dequeue() methods from jQuery library is a very good option for resolving this step by step scenarios. This is the stated description of this in the official page:
"Queues allow a sequence of actions to be called on an element asynchronously, without halting program execution. "
I will leave an brief example of how I have implemented it in the past:
$('#anchoredToElement')
.queue("steps", function (next) {
console.log("Step 1");
//In case you want to hold the execution for a bit depending on the scenario you're running
setTimeout(function () { console.log("Action within timeout") }, 500);
next();
})
.queue("steps", function (next) {
console.log("Step 2");
setTimeout(function () {
//Execution example
UploadFile(fileUpload))
}, 500);
next();
})
.dequeue("steps");
Here an example of how I think the logic could be for your needs:
var removeImage = function (index) {
//Logic here to remove image within div according to passed index
};
var index = 0;
$('#output')
.queue("steps", function (next) {
console.log("Remove Image 1");
setTimeout(function () { removeImage(index); }, 250);
index++;
next();
})
.queue("steps", function (next) {
console.log("Remove Image 2");
setTimeout(function () { removeImage(index); }, 250);
index++;
next();
})
.queue("steps", function (next) {
console.log("Remove Image 3");
setTimeout(function () { removeImage(index); }, 250);
index++;
next();
})
.queue("steps", function (next) {
console.log("Remove Image 4");
setTimeout(function () { removeImage(index); }, 250);
index++;
next();
})
.queue("steps", function (next) {
console.log("Remove Image 5");
setTimeout(function () { removeImage(index); }, 250);
index++;
next();
})
.dequeue("steps");
Of course you can improve the JS code as I was just focusing on the step by step process.
This is just a first glance of how $.queue can help you to achieve the step by step process. I recommend to go check the documentation to learn the details and so apply it to your logic as needed.
When i click on an image, the popup does not seem to work, and there are no error messages as well. I searched google for examples but it doesnt work.
Here is my javascript code:
function eventHandlers(){
$(".img-thumbnail").click(togglePopup);}
function togglePopup(e){
var popup = document.getElementById("id_popup");
if (popup === null)
{
popup = document.createElement("span");
popup.id = id_popup;
popup.setAttribute("class","image-popup");
var thumbnail = e.target;
var small_image = thumbnail.src;
var large_image = small_image.replace("_small","_large");
popup.innerHTML = '<img src=' + large_image + '>';
thumbnail.insertAdjacentElement("afterend",popup);
} else
{
$('#' + id_popup).remove();
}}
Code in the main file:
<figure>
<img src="images/test.jpg" class="img-thumbnail" alt="Test" title="View larger image..."/>
<span id="id_popup"
<span id="id_popup" class="image-popup"></span>
<figcaption>Standard Test</figcaption>
</figure>
And my css code:
.image-popup {
border: 5px solid lightgrey;
margin-left: 25%;
margin-top: -60%;
height: 40vh;}
Additionally is there a way that i can modify my javascript file to allow the popup to close when clicked anywhere on the screen?
Help will be really appreciated. Thanks.
I've been trying for the past hours to create a Comic Book online reader to allow my images to load up.
Everything works fine but I use a counter using a increment method basically and it just doesn't work because bringing down the increments breaks the function.
Maybe there is a simpler way? Also jQuery is the most obscure language to learn unlike HTML or PHP, jQuery has a documentation that pretty much has no organization. Its like here's all the stuff now read each one and maybe you'll find yours. My code is below
<script>
$(function manga () {
var count = 0;
var images = ["source_images/01.jpg", "source_images/02.jpg", "source_images/03.jpg", "source_images/04.jpg", "source_images/05.jpg", "source_images/06.jpg", "source_images/07.jpg"];
$("#left").click(function () {
var img = images[count % images.length];
++count;
$("#manga").attr("src", img);
//alert("clicked");
manga();
});
$("#right").click(function () {
var img = images[count % images.length];
--count;
$("#manga").attr("src", img);
//alert("clicked");
manga();
});
manga();
});
</script>
<title></title>
<center>
<img id="left" style="width:10%; float:left; padding:1.3%" src="files/left_arrow.png" />
<div >
<img id="manga" style="width:75%; float:left" src="source_images/00.jpg" />
</div>
<img id="right" style="width:10%; float:left; padding:1.2%" src="files/right_arrow.png" />
</center>
Basically your calling your function manga 3 times
first when it loads
second when your do left click
and third when you do right click
In this your initializing counter to keep track of the images and everytime
your calling function again your initializing it to 0
so your count again starting from 0.
So to avoid it make your count variable global declare it outside the manga() function.
checkout this code
<script>
var count = 0;
$(function manga () {
var images = ["source_images/01.jpg", "source_images/02.jpg", "source_images/03.jpg", "source_images/04.jpg", "source_images/05.jpg", "source_images/06.jpg", "source_images/07.jpg"];
$("#left").click(function () {
++count;
var img = images[count % images.length];
alert(img);
$("#manga").attr("src", img);
//alert("clicked");
manga();
});
$("#right").click(function () {
if(count == 0)
{
count = images.length-1;
}
else {
--count;
}
var img = images[count % images.length];
alert(img);
$("#manga").attr("src", img);
//alert("clicked");
manga();
});
manga();
});
</head>
<body>
<center>
<center>
<img id="left" style="width:10%; float:left; padding:1.3%" src="files/left_arrow.png" />
<div >
<img id="manga" style="width:75%; float:left" src="source_images/00.jpg" />
</div>
<img id="right" style="width:10%; float:left; padding:1.2%" src="files/right_arrow.png" />
</center>
</center>
I changed the position of count variable in both left and right click. And added one if condition in left click so that when the page loads first time and if user click left arrow first it will show last image.
so image src will move from first to last.It will work.
I want to change an image to some other image when i click on the object. the code is stacked in the following order:
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
What I wish to do is, when I click on the <li> i want to change the image to a coloured version of the image, i.e. some other image. Now, I know I can use JQuery/JS to accomplish it. But I don't want a huge amount of JS code to accomplish something so simple.
Can it be done using something simpler? Like pseudo selectors? .active class?
I cannot seem to think of it.
To change image onclik with javascript you need to have image with id:
<p>
<img alt="" src="http://www.userinterfaceicons.com/80x80/minimize.png"
style="height: 85px; width: 198px" id="imgClickAndChange" onclick="changeImage()"/>
</p>
Then you could call the javascript function when the image is clicked:
function changeImage() {
if (document.getElementById("imgClickAndChange").src == "http://www.userinterfaceicons.com/80x80/minimize.png"){
document.getElementById("imgClickAndChange").src = "http://www.userinterfaceicons.com/80x80/maximize.png";
} else {
document.getElementById("imgClickAndChange").src = "http://www.userinterfaceicons.com/80x80/minimize.png";
}
}
This code will set the image to maximize.png if the current img.src is set to minimize.png and vice versa.
For more details visit:
Change image onclick with javascript link
Or maybe
and that is prob it
<img src="path" onclick="this.src='path'">
How about this? It doesn't require so much coding.
$(".plus").click(function(){
$(this).toggleClass("minus") ;
})
.plus{
background-image: url("https://cdn0.iconfinder.com/data/icons/ie_Bright/128/plus_add_blue.png");
width:130px;
height:130px;
background-repeat:no-repeat;
}
.plus.minus{
background-image: url("https://cdn0.iconfinder.com/data/icons/ie_Bright/128/plus_add_minus.png");
width:130px;
height:130px;
background-repeat:no-repeat;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="plus">CHANGE</div>
If your images are named you can reference them through the DOM and change the source.
document["imgName"].src="../newImgSrc.jpg";
or
document.getElementById("imgName").src="../newImgSrc.jpg";
The most you could do is to trigger a background image change when hovering the LI. If you want something to happen upon clicking an LI and then staying that way, then you'll need to use some JS.
I would name the images starting with bw_ and clr_ and just use JS to swap between them.
example:
$("#images").find('img').bind("click", function() {
var src = $(this).attr("src"),
state = (src.indexOf("bw_") === 0) ? 'bw' : 'clr';
(state === 'bw') ? src = src.replace('bw_','clr_') : src = src.replace('clr_','bw_');
$(this).attr("src", src);
});
link to fiddle: http://jsfiddle.net/felcom/J2ucD/
Here, when clicking next or previous, the src attribute of an img tag is changed to the next or previous value in an array.
<div id="imageGallery">
<img id="image" src="http://adamyost.com/images/wasatch_thumb.gif" />
<div id="previous">Previous</div>
<div id="next">Next</div>
</div>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script>
$( document ).ready(function() {
var images = [
"http://placehold.it/350x150",
"http://placehold.it/150x150",
"http://placehold.it/50x150"
];
var imageIndex = 0;
$("#previous").on("click", function(){
imageIndex = (imageIndex + images.length -1) % (images.length);
$("#image").attr('src', images[imageIndex]);
});
$("#next").on("click", function(){
imageIndex = (imageIndex+1) % (images.length);
$("#image").attr('src', images[imageIndex]);
});
$("#image").attr(images[0]);
});
</script>
I was able to implement this by modifying this answer: jQuery array with next and previous buttons to scroll through entries
If you don't want use js, I think, you can use instead of img and then use css like
a {
background: url('oldImage.png');
}
a:visited {
background: url('newImage.png');
}
EDIT: Nope. Sorry it works only for :hover
You can try something like this:
CSS
div {
width:200px;
height:200px;
background: url(img1.png) center center no-repeat;
}
.visited {
background: url(img2.png) center center no-repeat;
}
HTML
<div href="#" onclick="this.className='visited'">
<p>Content</p>
</div>
Fiddle
This script helps to change the image on click the text:
<script>
$(document).ready(function(){
$('li').click(function(){
var imgpath = $(this).attr('dir');
$('#image').html('<img src='+imgpath+'>');
});
$('.btn').click(function(){
$('#thumbs').fadeIn(500);
$('#image').animate({marginTop:'10px'},200);
$(this).hide();
$('#hide').fadeIn('slow');
});
$('#hide').click(function(){
$('#thumbs').fadeOut(500,function (){
$('#image').animate({marginTop:'50px'},200);
});
$(this).hide();
$('#show').fadeIn('slow');
});
});
</script>
<div class="sandiv">
<h1 style="text-align:center;">The Human Body Parts :</h1>
<div id="thumbs">
<div class="sanl">
<ul>
<li dir="5.png">Human-body-organ-diag-1</li>
<li dir="4.png">Human-body-organ-diag-2</li>
<li dir="3.png">Human-body-organ-diag-3</li>
<li dir="2.png">Human-body-organ-diag-4</li>
<li dir="1.png">Human-body-organ-diag-5</li>
</ul>
</div>
</div>
<div class="man">
<div id="image">
<img src="2.png" width="348" height="375"></div>
</div>
<div id="thumbs">
<div class="sanr" >
<ul>
<li dir="5.png">Human-body-organ-diag-6</li>
<li dir="4.png">Human-body-organ-diag-7</li>
<li dir="3.png">Human-body-organ-diag-8</li>
<li dir="2.png">Human-body-organ-diag-9</li>
<li dir="1.png">Human-body-organ-diag-10</li>
</ul>
</div>
</div>
<h2><a style="color:#333;" href="http://www.sanwebcorner.com/">sanwebcorner.com</a></h2>
</div>
function chkicon(num,allsize) {
var flagicon = document.getElementById("flagicon"+num).value;
if(flagicon=="plus"){
//alert("P== "+flagicon);
for (var i = 0; i < allsize; i++) {
if(document.getElementById("flagicon"+i).value !=""){
document.getElementById("flagicon"+i).value = "plus";
document.images["pic"+i].src = "../images/plus.gif";
}
}
document.images["pic"+num].src = "../images/minus.gif";
document.getElementById("flagicon"+num).value = "minus";
}else if(flagicon=="minus"){
//alert("M== "+flagicon);
document.images["pic"+num].src = "../images/plus.gif";
document.getElementById("flagicon"+num).value = "plus";
}else{
for (var i = 0; i < allsize; i++) {
if(document.getElementById("flagicon"+i).value !=""){
document.getElementById("flagicon"+i).value = "plus";
document.images["pic"+i].src = "../images/plus.gif";
}
}
}
}