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Issue with nested ajax call in jQuery

I have a situation where I make an ajax call, on returning from which (successfully), I make an another ajax call with the returned data and submit the page. The pseudo code looks something like this:
$.ajax({
url: 'first_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
}).done(function(response) {
$.ajax({
url: '2nd_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
});
thisPage.submit();
});
The inner ajax call is not executed if I do not comment out the 'submit' line. I do not understand the behaviour. Can someone please help me with this.
Thanks

You need to execute submit on second ajax sucess.
For example
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
//do your stuff
}

$("input[type='submit']").click(function(event){
event.preventDefault();
$.ajax({
url:'abcd.php',
method:'post',
type:'json',
async:false,
success:function(response){
$.ajax({
url:'abcde.php',
method:'post',
type:'json',
data:{res:response},
success:function(response){
console.log(response);
}
});
$("form").submit();
}
});
});
Try this one.Its working correctly.

Call function after ajax load()

I initiate a function after an ajax load(), but the function I intimate calls upon an additional function, which isn't working. How do I initiate ajaxstuff() after load()?
function ajaxstuff(data) {
$.ajax({
type: "POST",
url: "do-it.php",
data: {data},
success: function() {
console.log('I got this far'); // this doesn't work / isn't called
}
});
}
function doit() {
$('form').submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
console.log('I got this far'); // this works
ajaxstuff(formData);
}
}
$('.popup-loader').click(function() {
$(this).append('<div class="popup"></div>');
$('.popup').load('popup.php', function() {
doit(); // this works
}
});

Check for errors in your console, also, in your AJAX add an async option. set it to FALSE ("Setting async to false means that the statement you are calling has to complete before the next statement in your function can be called"):
function ajaxstuff(data) {
$.ajax({
async: false,
type: "POST",
url: "do-it.php",
data: data,
success: function(result) {
console.log(result); //check in your console for errors
}
});
}

Syntax error in ajaxstuff function. data: {data}, , probably should be data: data,
Also when you're passing a FormData object to $.ajax, you have to specify processData: false and contentType: false
$.ajax({
type: "POST",
url: "do-it.php",
data: data,
processData: false,
contentType: false,
success: function() {
console.log('I got this far');
}
});

Jquery set HTML via ajax

I have the following span:
<span class='username'> </span>
to populate this i have to get a value from PHP therefor i use Ajax:
$('.username').html(getUsername());
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
document.write(data);
}
})
}
Now when i debug i see that the returned data (data) is the correct value but the html between the span tags stay the same.
What am i doing wrong?
Little update
I have tried the following:
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
$('.username').html('RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRr');
}
})
}
getUsername();
Still there is no html between the tags (no text) but when i look at the console the method is completed and has been executed.
Answer to the little update
The error was in my Ajax function i forgot to print the actual response! Thank you for all of your answers, for those of you who are searching for this question here is my Ajax function:
public function ajax_getUsername(){
if ($this->RequestHandler->isAjax())
{
$this->autoLayout = false;
$this->autoRender = false;
$this->layout = 'ajax';
}
print json_encode($this->currentClient['username']);
}
Do note that i am using CakePHP which is why there are some buildin methods. All in all just remember print json_encode($this->currentClient['username']);

The logic flow of your code is not quite correct. An asynchronous function cannot return anything as execution will have moved to the next statement by the time the response is received. Instead, all processing required on the response must be done in the success handler. Try this:
function getUsername() {
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: { },
success: function(data){
$('.username').html(data); // update the HTML here
}
})
}
getUsername();

Replace with this
success: function(data){
$('.username').text(data);
}

In success method you should use something like this:
$(".username").text(data);

You should set the html in callback
function getUsername() {
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
$('.username').html(data);
}
})
}

Add a return statement for the function getUsername
var result = "";
$('.username').html(getUsername());
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
document.write(data);
result = data;
}
})
return result;
}

You can use .load()
Api docs: http://api.jquery.com/load/
In your case:
$('.username').load(myBaseUrl + 'Profiles/ajax_getUsername',
{param1: value1, param2: value2});

Do something after window load

I'm doing a (simple) ajax call on window load:
$(window).load(function () {
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
...........
How can I do something, for instance a function or event after this ajax proces is finished. The problem is I have to append something to the data recieved by the ajax call. But I can't append on window load because the data is still being processed.

Put it in the success handler of the ajax call:
$(window).load(function () {
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
// do whatever you want with data
}
});
});

You can call that in the success callback function of Ajax request
success: function(data) {
myFunction() ; // If function
$('#elementID').click() // If you want to trigger a click event
}

You may use the
`$(document).ready`
So it will be similar to this:
$(document).ready(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
//Your code should be here

After
success: function(data) {
for (var ii = 0; ii < data.length; ii++){
building html here
}
your code here
}
you want to enter in your functions within the success function for the ajax call but before the call is complete.

You could also do
$.ajax({
url: someUrl,
type: "get",
dataType: "",
context: document.body
}).done(function() {
// do whatever when is done
onCompleteFunction();
});

this should execute your request when page is just loaded.
$(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
// do whatever you want with data
}
});
});
or you can do:
$(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
complete: function(data) {
// do whatever you want with data
}
});
});

Why can't I do .ajax ( return data; )? jQuery

I'm trying to get my function to return the data it got into another function but it doesn't seem to work? How can I get it to return the data?
function playerid(playername) {
$.ajax({
type: "POST",
url: "fn.php?playerid",
data: "playername="+playername,
success: function(data) {
//$("#test").text(data);
return data;
}
});
}
I want to use it in another function like this
showBids(playerid(ui.item.value));
function showBids(playerid) {
$.ajax({
type: "POST",
url: "poll.php?",
async: true,
dataType: 'json',
timeout: 50000,
data: "playerid="+playerid,
success: function(data) {
//.each(data, function(k ,v) {
//})
//$("#current_high").append(data);
setTimeout("getData()", 1000);
}
});

First of all, your playerid() does not return anything, so what do you want to use? It has only $.ajax() call in it, no return statement (one of the callbacks in $.ajax() has return statement, but see below).
Secondly, JavaScript does some things asynchonously, otherwise every interface element would need to wait to react to user action until the AJAX call returns from the server.
Use event-based approach, by passing callbacks to some functions. Then, after they finish, just call the callbacks passing them the result:
function getplayerid(playername, callback) {
$.ajax({
type: "POST",
url: "fn.php?playerid",
data: "playername="+playername,
success: function(data) {
//$("#test").text(data);
callback(data);
}
});
}
and then use it like that:
getplayerid(ui.item.value, showBids);
(notice function name change since it does not actually return player ID, it gets it and passes it to callback)

You could try to use syncronous Ajax:
function playerid(playername) {
return $.ajax({
type: "POST",
url: "fn.php?playerid",
data: "playername="+playername,
async : false //making Ajax syncronous
}).responseText;
}
Otherwise you need to use showBids function as callback:
function playerid(playername, callback) {
$.ajax({
type: "POST",
url: "fn.php?playerid",
data: "playername="+playername,
success: function(data) {
callback(data);
}
});
}
//Usage
playerid(ui.item.value,showBids);