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How to disable View source and inspect element

How do you disable/ view source/ and /inspect element/, ctrl + u ctrl+shift+I f12 menu bar and right click, also ctrl + s ctrl p ctrl+v ctrl+a ctrl+c and drag select page, please answer all parts that's possible, I prefer to do this will JavaScript array keycodes or html no php or other languages.also I want to block ifram use on my site like somesites such as google.
As I understand it is not possible to completely disable view source and inspect element, so I want minification of code and rest of my question answered instead.
Edit:
I solved alot of it myself, I used onkeydown return false to disable all keys, still need the arrays, I disabled inspect element menu bar by forcing browser to window.open I still need right click, however would like to add that I need a custom right click menu, I disabled the possibility to disable Javascript in order to stop the key block by using noscript function redirects. I also still need the drag and select part. I would still like betterways to fix it...maybe even just minify the code or encrypt it. Of anyone needs some of the code I used just reply. I just need to fix it.

It is not possible to prevent the user from inspecting code running on their machine. At the end of the day the HTMl they are getting delivered will be readable in plain text. You can cause a nuisance for most people, but this will not be a valid security measure - chrome extensions will still run, for instance, so if someone is using the NoScript extension it will disable all javascript.
A much better option would be to handle your logic serverside, and only send the client the information they need to know/requested.
There are some free javascript obfuscators, such as https://javascriptobfuscator.com/. Please remember that it is not a secure method, though.

I mean no matter how much you block it a person can just type
view-source:https://example.com

document.onkeydown = function(e)
{
if(event.keyCode == 123)
{
return false;
}
if(e.ctrlKey && e.shiftKey && e.keyCode == 'I'.charCodeAt(0))
{
return false;
}
if(e.ctrlKey && e.shiftKey && e.keyCode == 'J'.charCodeAt(0))
{
return false;
}
if(e.ctrlKey && e.keyCode == 'U'.charCodeAt(0))
{
return false;
}
if(e.ctrlKey && e.shiftKey && e.keyCode == 'C'.charCodeAt(0))
{
return false;
}
}
e is a keyboard event. e.[key] returnes true if key pressed.
If document.onkeydown returns false, key doesn't count.
This programm seeing if code view combination pressed and returning false.
Example. if ctrl, shift and 'J' pressed - return false.

Bump
To the people saying it isn't possible, how would you recon this website managed to do so?
The following website disabled, view source, right click and the dev console.
I am genuinely interested.
https://www.techgyd.com/contact-facebook-directly/6579/
Edit:
all input from keyboard is disabled, but by adding "view-source:" before the httpps:// to the url to become:
view-source:https://www.techgyd.com/contact-facebook-directly/6579/
makes me able to see.
If you would like to know how they did that then take a look at their JS, raw copy/paste:
<script type="text/javascript">
//<![CDATA[
var show_msg = '';
if (show_msg !== '0') {
var options = {view_src: "View Source is disabled!", inspect_elem: "Inspect Element is disabled!", right_click: "Right click is disabled!", copy_cut_paste_content: "Cut/Copy/Paste is disabled!", image_drop: "Image Drag-n-Drop is disabled!" }
} else {
var options = '';
}
function nocontextmenu(e) { return false; }
document.oncontextmenu = nocontextmenu;
document.ondragstart = function() { return false;}
document.onmousedown = function (event) {
event = (event || window.event);
if (event.keyCode === 123) {
if (show_msg !== '0') {show_toast('inspect_elem');}
return false;
}
}
document.onkeydown = function (event) {
event = (event || window.event);
//alert(event.keyCode); return false;
if (event.keyCode === 123 ||
event.ctrlKey && event.shiftKey && event.keyCode === 73 ||
event.ctrlKey && event.shiftKey && event.keyCode === 75) {
if (show_msg !== '0') {show_toast('inspect_elem');}
return false;
}
if (event.ctrlKey && event.keyCode === 85) {
if (show_msg !== '0') {show_toast('view_src');}
return false;
}
}
function addMultiEventListener(element, eventNames, listener) {
var events = eventNames.split(' ');
for (var i = 0, iLen = events.length; i < iLen; i++) {
element.addEventListener(events[i], function (e) {
e.preventDefault();
if (show_msg !== '0') {
show_toast(listener);
}
});
}
}
addMultiEventListener(document, 'contextmenu', 'right_click');
addMultiEventListener(document, 'cut copy paste print', 'copy_cut_paste_content');
addMultiEventListener(document, 'drag drop', 'image_drop');
function show_toast(text) {
var x = document.getElementById("amm_drcfw_toast_msg");
x.innerHTML = eval('options.' + text);
x.className = "show";
setTimeout(function () {
x.className = x.className.replace("show", "")
}, 3000);
}
//]]>
</script>
or just look from line 86
I hope it helps

External Link Notification - JavaScript or JQuery

I am looking for a way to set it up so that when an external link is clicked it will warn people that they are leaving the site. Preferably, it would darken the screen and display a message in the middle of the screen in a box with the option to click OK or Cancel.
I tried to use this code:
$("a.external").click(function () {
alert("You are about to proceed to an external website. The Great Western Market has no control over the content of this site. Click OK to proceed.");
});
and give each link a class of external but it doesn't seem to work. I don't want to use this because it means that the client will have to remember to add the class I would prefer something more automatic.
I also tried to use this code to do so but to no avail:
$('a').filter(function() {
return this.hostname && this.hostname !== location.hostname;
})
.click(function () {
var x=window.confirm('You are about to proceed to an external website. The Great Western Market has no control over the content of this site. Click OK to proceed.');
var val = false;
if (x)
val = true;
else
val = false;
return val;
});
I am using WordPress 3.8.1.
Thanks in advance for any help you can give.

Your filter logic should be correct, Try using the confirm function, and using jQuery instead of $.
jQuery('a').filter(function() {
return this.hostname && this.hostname !== location.hostname;
}).click(function(e) {
if(!confirm("You are about to proceed to an external website."))
{
// if user clicks 'no' then dont proceed to link.
e.preventDefault();
};
});
I tried this out in dev tools on your site and it seems to work correctly if you use jQuery. I think you may have some plugin that is causing conflicts with $.
JSFiddle Demo

Try using confirm instead of alert since that will pause and wait for user input. You'll then need function(e){ e.preventDefault(); } to prevent the default link actions.

To identify just external links you might do something like this:
var ignoreClick = false;
$(document).ready( function(){
$('input[type="submit"], input[type="image"], input[type="button"], button').click(function(e) {
ignoreClick = true;
});
$(document).click(function(e) {
if($(e.target).is('a'))
checkLink(e);
});
$('a').click(function(e) {
checkLink(e);
return true;
});
checkLink = function(e){
// bubble click up to anchor tag
tempTarget = e.target;
while (!$(tempTarget).is('a') && !!tempTarget.parentElement) {
tempTarget = tempTarget.parentElement;
}
if ($(tempTarget).is('a')){
if(!!tempTarget && $(tempTarget).is('a') &&
(tempTarget.hostname == "" || tempTarget.hostname == "#" || tempTarget.hostname == location.hostname)){
ignoreClick = true;
}
}
}
});
and to catch people with a message you might use beforeunload and the confirm option
$(window).bind("beforeunload", function (e) {
if (!ignoreClick){
if(!confirm("Leaving website message")) {
e.preventDefault();
}
}
});

It worked pretty well to me. I just removed unnecesary variables, but original script worked fine.
$('a').filter(function() {
return this.hostname && this.hostname !== location.hostname;
})
.click(function () {
return window.confirm('You are about to proceed to an external website. The Great Western Market has no control over the content of this site. Click OK to proceed.');
});
http://jsfiddle.net/3dkAN/1/
EDIT
Following #user1308743's line, seems that in cgmp.framework.min.js is summoning the jQuery.noConflict() mode, that unbinds the $() function for jQuery. So please use jQuery() for any jQuery implementation

How do I detect popup blocker in Chrome?

I have searched many issue in stack overflow and might be duplicate here Detect Popup
But not helped for me while testing in Chrome (tested v26.0.1410.64)
Following Approach Worked in IE and Firefox but not in Chrome
var popup = window.open(winPath,winName,winFeature,true);
if (!popup || popup.closed || typeof popup.closed=='undefined'){
//Worked For IE and Firefox
alert("Popup Blocker is enabled! Please add this site to your exception list.");
window.location.href = 'warning.html';
} else {
//Popup Allowed
window.open('','_self');
window.close();
}
Any better solution that works for Chrome also?

Finally, it success by combining different answer from Stackoverflow's member
This code worked for me & tested in IE, Chrome & Firefox
var popup = window.open(winPath,winName,winFeature,true);
setTimeout( function() {
if(!popup || popup.outerHeight === 0) {
//First Checking Condition Works For IE & Firefox
//Second Checking Condition Works For Chrome
alert("Popup Blocker is enabled! Please add this site to your exception list.");
window.location.href = 'warning.html';
} else {
//Popup Blocker Is Disabled
window.open('','_self');
window.close();
}
}, 25);

Try Below..!!
var pop = window.open("about:blank", "new_window_123", "height=150,width=150");
// Detect pop blocker
setTimeout(function() {
if(!pop || pop.closed || pop.closed == "undefined" || pop == "undefined" || parseInt(pop.innerWidth) == 0 || pop.document.documentElement.clientWidth != 150 || pop.document.documentElement.clientHeight != 150){
pop && pop.close();
alert("Popups must be enabled.");
}else{
alert("Popups is enabled.");
pop && pop.close();
}}, 1000);
Look on below question
Detect blocked popup in Chrome
How do I detect whether popups are blocked in chrome
On Google It will more help you..
https://www.google.com/search?q=how+to+detect+a+blocked+popup+in+chrome

I found it much more effective to use try-catch as follows:
var popup = window.open(winPath,winName,winFeature,true);
try {
popup.focus();
} catch (e) {
alert('popup blocked!');
}

I know this is "resolved", but this simple code worked for me detecting "Better Popup Blocker" extension in Chrome:
if (!window.print) {
//display message to disable popup blocker
} else {
window.print();
}
}
Ockham's razor! Or am I missing something and it couldn't possibly be this simple?

I had used this method to open windows from js and not beeing blocked by Chrome.
http://en.nisi.ro/blog/development/javascript/open-new-window-window-open-seen-chrome-popup/

The below code works in chrome,safari and firefox. I have used jquery for this.
var popupWindow = window.open("http://www.google.com","directories=no,height=100,width=100");
$(document).ready(function(e) {
detectPopup();
function detectPopup() {
if(!popupWindow) {
alert("popup will be blocked");
} else {
alert("popup will be shown");
window.open('','_self');
window.close();
}
}
});

Check if Thickbox is open

I'm using WP and I use the Thickbox to upload images in the back end on a custom page.
Is there a way for JS to check to see if the Thickbox is open?
I need to check this as I have an onbeforeunload event (to show a warning when the user leaves the page, in certain situations), but obviously Idon't want the warning shown when the user is just navigating between Thickbox pages. Thanks.
Code I currently use -
var bol_submit_clicked = false;
$('input[name="Submit"]').click(function(){
bol_submit_clicked = true;
});
window.onbeforeunload = function closeEditorWarning(){
var bol_option_changed = false;
/** Check to see if the settings warning is displayed */
if($('#unsaved-settings').css('display') !== 'none'){
bol_option_changed = true;
}
/** Display a warning if the user is trying to leave the page with unsaved settings */
if(bol_option_changed === true && bol_submit_clicked === false){
return '';
}
};

There's no inherent function in Thickbox to check, but looking at the code, you should just be able to check for the presence and visibility of #TB_window:
var thickbox_shown = ($('#TB_window').is(':visible')) ? true : false;
Or, try counting the length of #TB_load:
var thickbox_shown = ($('#TB_load').length > 0) ? true : false;\

how to open outside links in a new tab

On my website i have many outside links, as well as internal links.
i'd like some kind of solution in javascript or w/e that detects outside links and opens them in a new tab, but leaves internal links to be opened in the same tab.
thanks! =)

function getXterlinks()
{
var Xterlinks = document.getElementsByTagName('A');
for (var i=0;i<Xterlinks.length;i++)
{
var eachLink = Xterlinks[i];
var regexp_isYourdomain="your-domain.com";
var regexp_ishttp=/(http(.)*:\/\/)/;
if( (eachLink.href != null) && (eachLink.href.match(regexp_isYourdomain) == null) && eachLink.href.match(regexp_ishttp)!=null )
{
eachLink.target ="_blank";
}
}
}
Source: http://www.mediawiki.org/wiki/Manual:Opening_external_links_in_a_new_window#How_to_make_external_links_open_in_a_new_window

Yeah, well, jQuery's still JavaScript. How about:
$('a[href^="http://your-domain.com"]').attr("target", "_self");
$('a').not('a[href^="http://your-domain.com"]').attr("target", "_blank");
Not sure about the second, though, but you get the idea.

I wrote this solution for my personal web site. As long as you like jQuery (which you should, imho), you can include this in a common js file and forget about it. It will work with dynamic content, and will not force internal links to open in the current tab if you set target="_blank".
$(function() {
$('body').on('click', 'a', function() {
var currentHost = document.location.protocol+'//'+document.location.hostname;
if (this.href.indexOf(currentHost) != 0 && (this.href.indexOf('http') == 0 || this.href.indexOf('ftp') == 0)) {
window.open(this.href, '_blank');
return false;
}
});
});
Note: If you are using jQuery < 7, use .bind() instead of .on()
See it in action on http://www.seanknutson.com.