We Keep Coding

Unable to place unexpected identifier error [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 2 years ago.
Improve this question
Receiving the following error:
Uncaught SyntaxError: Unexpected identifier
The error states it is on this code line:
let whosUp = document.querySelector(#whosUp);
What is the unexpected identifier? Am I missing something? My complete function is below. I can include my entire file if necessary.
function whosUpFunc(){
let whosUp = document.querySelector(#whosUp);
if (gameOver === true){
whosUp.innerHTML = ""
}
else {whosUp.innerHTML = `Player ${currPlayer}'s turn`
};
}

The function document.querySelector expects a string as an argument. You're passing it #whosUp, which is triggering the SyntaxError.
let whosUp = document.querySelector(#whosUp);
Should be
let whosUp = document.getElementById('whosUp');

Javascript Functions - Calling Two Function In A File [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
Question: Two Functions Return Different Data But After Calling Both Functions Receive Output From Last Function. Why?
javascript
var printStudentInfo = function () {
return 'Name';
}
var printStudentTerritory = function () {
return 'Age';
}
printStudentInfo();
printStudentTerritory();

To put it simply, Here's what printStudentInfo(); printStudentTerritory(); suggest let someVariable = printStudentInfo(); printStudentTerritory(); Since the last function returns 'age'. Your variable is assigned to 'age'

Trying to define async function [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
Improve this question
I'm trying to define an async function with an arrow function. This code already throws an error, but I still want to know what the main error is.
async responseName = name => ('hello'+ name);
responseName('joshua').then(response => console.log(response));

You have a syntax error. You cannot define an identifier as async:
const responseName = async (name) => `hello ${name}`;

Basic Javascript i cannot understand [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
var MyCountry = "trolling";
console.log(MyCountry).length;
console.log(MyCountry).substring(0, 3)
This is the error message I'm getting:
TypeError: 'undefined' is not an object (evaluating 'console.log(MyCountry).length')

You're putting .length and .substring on the result of console.log(), which is always undefined. Put them inside on the MyCountry instead.

This is what you want. You're closing your console.log() too soon both times.
var MyCountry = "trolling";
console.log(MyCountry.length);
console.log(MyCountry.substring(0, 3));

console.log() returns undefined, so you're calling .length on undefined.
If you want to log the length of MyCountry do console.log(MyCountry.length)
Also, console.log(MyCountry.substring(0, 3))

Function causes error [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
Improve this question
I have created the mapWith function like this:
var mapWith=function(fn)
{
return funtion(list)
{
return Array.prototype.map.call(list,function(something){
return fn.call(this,something);
});
}
};
I use it on a function and an array:
var insertLatLong=function(obj)
{
//inserts to db...
}
var inception_cities=[{lat:35.0117,lng:135.7683},
{lat:48.8567,lng:2.3508},
{lat:-4.0500,lng:39.6667},
{lat:33.8600,lng:151.2111},
{lat:34.0500,lng:118.2500}];
var insertLocations=mapWith(insertLatLong);
insertLocations(inception_cities);
The error I get looks like this:
ReferenceError: list is not defined
at mapWith (/home/anr/Desktop/node js/mysql.js:11:17)
at Object.<anonymous> (/home/anr/Desktop/node js/mysql.js:40:21)

The error is caused because there's c missing in return funtion(list). Without it JavaScript thinks that you want to call something with name funtion. But you also want to pass list to it and since arguments are evaluated first then you get ReferenceError: it does not know what list is.