Related
I have an User like so the id is NOT the _id)
{
id: string;
}
Which can create files like so
{
name: string;
author: User;
}
I would like to get all Files where the author is a given User, but I do not know how to use the "filter" function to do that.
So currently I do
const author = await this.userModel.find({ id });
return this.filesModel.find({ author });
Is there a more efficient way to do it ?
(I use NestJS with the Mongoose integration, the syntax used is the same as the Mongoose library)
EDIT
Given the User document
{
_id: 'OVZVIbovibiugb44'
id: 10
}
And the Files documents
[
{ name: "1.docx", author: ObjectId('OVZVIbovibiugb44') },
{ name: "2.docx", author: ObjectId('voisbvOVISBEIVBv') },
]
I would like to use the function
findOwned(authorId = 10) {
const author = await this.userModel.find({ id });
return this.filesModel.find({ author });
// But do it only with "filesModel"
}
And get, as a result,
[
{ name: '1.docx', author: 'ObjectId('OVZVIbovibiugb44') },
]
You can use $lookup into an aggregation query to merge collections.
Also, as your id is an String and your author is an ObjectId you will need one previous stage using $toObjectId
So the query is similar to this:
$match stage (optional) to query only with documents you want. Like a filter
$project to convert id String field to ObjectId. You can user $set also.
$lookup to merge collection and the ouput is in a field called files.
$project to output only files array from the merge.
db.User.aggregate([
{ "$match": { "id": "5a934e000102030405000001" } },
{ "$project": { "id": { "$toObjectId": "$id" } } },
{ "$lookup": {
"from": "Files",
"localField": "id",
"foreignField": "author",
"as": "files" }
},
{ "$project": { "files": 1 } }
])
Example here
I am trying to insert a time object into the times array for a specific activity name for a specific user. For example, if the user was "someuser" and I wanted to add a time to the times for guitar I am unsure as to what to do.
{
username: "someuser",
activities: [
{
name: "guitar",
times: []
},
{
name: "code",
times: []
}
]
}, {
username: "anotheruser",
activities: []
}
This is currently the function that I have, I cannot figure out what I am doing wrong, any help would be greatly appreciated:
function appendActivityTime(user, activityName, newRange) {
User.updateOne(
{username: user, 'activities.name': activityName},
{ $push: {'activities.$.times': {newRange}},
function (err) {
if (err) {
console.log(err);
} else {
console.log("Successfully added time range: " + newRange);
}
}}
);
}
appendActivityTime("someuser", "guitar", rangeObject);
i've tried your attempt and it worked for me:
db.getCollection("test").updateOne(
{ username: "someuser", "activities.name": "guitar" },
{ $push: { "activities.$.times": { from: ISODate(), to: ISODate() } } } //Don't worry about ISODate() in node.js use date objects
)
results:
{
"_id" : ObjectId("5f6c384af49dcd4019982b2c"),
"username" : "someuser",
"activities" : [
{
"name" : "guitar",
"times" : [
{
"from" : ISODate("2020-09-24T06:15:03.578+0000"),
"to" : ISODate("2020-09-24T06:15:03.578+0000")
}
]
},
{
"name" : "code",
"times" : [
]
}
]
}
what i would suggest you using instead is arrayFilter, they are much more precise and when you get used to them, they became very handy
If you are not confident with updating nested documents, let mongoose make the query.
let document = await Model.findOne ({ });
document.activities = new_object;
await document.save();
I want generate an ObjectID for each Object present inside my array. The thing is I'm getting the products with a .forEach statement from another server and push them inside my array without a Schema that generates an ObjectID....
Product Schema:
const productsSchema = new mongoose.Schema({
apiKey: String,
domain: String,
totalcount: Number,
totaldone: Number,
allSKUS: Array,
allProducts: Array,
created_at: { type: Date },
updated_at: { type: Date },
}, { collection: 'products', timestamps: true });
productsSchema.plugin(uniqueValidator);
const Products = mongoose.model('Products', productsSchema);
module.exports = Products;
My Code:
const newProduct = {
apiKey: userApiProducts.apiKey,
domain: userApiProducts.domain,
totalcount: userApiProducts.totalcount,
totaldone: userApiProducts.totaldone,
allSKUS: userApiProducts.allSKUS,
allProducts: userApiProducts.allProducts // generate ObjectID for each object that gets pushed inside the Array
};
Products.findOneAndUpdate( userApiProducts.domain, newProduct, {upsert:true} , (err, existingProducts) => {
if (err) { return next(err); }
});
Output:
// Please Check ADD OBJECT ID HERE comment. This is where i want to generate an unique ObjectID before I push the data. I tried with var id = mongoose.Types.ObjectId(); but i'm afraid it will not be Unique...
{
"_id" : ObjectId("58780a2c8d94cf6a32cd7530"),
"domain" : "http://example.com",
"updatedAt" : ISODate("2017-01-12T23:27:15.465Z"),
"apiKey" : "nf4fh3attn5ygkq1t",
"totalcount" : 11,
"totaldone" : 11,
"allSKUS" : [
"Primul",
"Al doilea",
"Al treilea"
],
"allProducts" : [
{
// ADD OBJECT ID HERE
"id": 1,
"sku": "Primul",
"name": "Primul",
"status": 1,
"total_images": 2,
"media_gallery_entries": [
{
"id": 1,
"media_type": "image",
"label": null,
"position": 1,
"disabled": false,
"types": [
"image",
"small_image",
"thumbnail",
"swatch_image"
],
"file": "/g/r/grafolio_angel_and_devil.png"
},
{
"id": 2,
"media_type": "image",
"label": null,
"position": 2,
"disabled": false,
"types": [],
"file": "/g/r/grafolio_angel_and_devil_thumbnail.jpg"
}
]
},
{
// ADD OBJECT ID HERE
"id": 3,
"sku": "Al doilea",
"name": "Al doilea",
"status": 1,
"total_images": 2,
"media_gallery_entries": [
{
"id": 4,
"media_type": "image",
"label": null,
"position": 2,
"disabled": false,
"types": [],
"file": "/g/r/grafolio_angel_and_devil_thumbnail_1.jpg"
},
{
"id": 5,
"media_type": "image",
"label": null,
"position": 3,
"disabled": false,
"types": [],
"file": "/b/e/before.png"
}
]
}, etc ......
],
"__v" : 0,
"createdAt" : ISODate("2017-01-12T22:58:52.524Z")
}
Is there any way of doing this without having to make a ton of DB Calls? I can't imagine saving like this
array.forEach((x)=> {
Products.save({})
})
Hope someone has already worked on something similar and found the perfect solution for this !
If you want to add ObjectId automatically, you need to define a separate schema for it and set the _id options for the schema as true.
Do the following:
Change your productsSchema as CatalogueSchema (for ease of
understanding).
Define a new ProductSchema for Product (element of allProducts)
In CatalogueSchema define allProducts type as [Product.schema]. This will automatically add _id (ObjectId).
Also, you don't need to add created_at and updated_at as part of schema when you set timestamps option as true.
Catalogue Schema
const Product = require('Product_Schema_Module_Path'); // Edit
const CatalogueSchema = new mongoose.Schema({
apiKey: String,
domain: String,
totalcount: Number,
totaldone: Number,
allSKUS: Array,
allProducts: [Product.schema]
// Note the change here (Array -> [Product.schema]
// Creating a separate schema ensures automatic id (ObjectId)
}, { collection: 'catalogue', timestamps: true });
CatalogueSchema.plugin(uniqueValidator);
const Catalogue = mongoose.model('Catalogue', CatalogueSchema);
module.exports = Catalogue;
Product Schema
(New schema to ensure adding of ObjectId)
const ProductSchema = new mongoose.Schema({
id: Number,
sku: String,
name: String,
status: Number,
total_images: Number,
media_gallery_entries: Array
}, { _id: true, timestamps: true });
// _id option is true by default. You can ommit it.
// If _id is set to false, it will not add ObjectId
ProductSchema.plugin(uniqueValidator);
const Product = mongoose.model('Product', ProductSchema);
module.exports = Product;
EDIT (Save Products in Catalogue)
(Also, note that you have to require the ProductSchema module in your CatalogueSchema module)
// Map userApiProducts.allProducts to array of Product documents
const products = userApiProducts.allProducts.map(product => {
return new Product(product);
})
const newProduct = {
apiKey: userApiProducts.apiKey,
domain: userApiProducts.domain,
totalcount: userApiProducts.totalcount,
totaldone: userApiProducts.totaldone,
allSKUS: userApiProducts.allSKUS,
allProducts: products
};
Catalogue
.findOneAndUpdate({ domain: userApiProducts.domain }, newProduct, { upsert:true } , (err, products) => {
// Handle error
});
To add multiple documents into Mongo you can use db.collection.insert():
https://docs.mongodb.com/manual/reference/method/db.collection.insert/
In Mongoose you can use Model.insertMany():
http://mongoosejs.com/docs/api.html#model_Model.insertMany
But keep in mind that when you have one document inside of other document in Mongoose they are not actually stored like that in Mongo. Mongo only stores the IDs of the child documents and not their contents in the parent document - and not even any info on which collection those IDs belong to.
When you use population then Mongoose actually retrieves the relevant documents from the DB in separate requests to Mongo. So, population is a concept of Mongoose. Mongo just stores the IDs, so you need to create the documents first before you can insert the IDs.
The thing that you are trying to do would be easy without using Mongoose. You can store multiple documents in one request in Mongo using your own IDs if you want and you can store another document with an array of those IDs in another request.
Of course however you do it you will get inconsistent state during the operation because Mongo doesn't support transactions.
I'm pretty new to Mongoose and MongoDB in general so I'm having a difficult time figuring out if something like this is possible:
Item = new Schema({
id: Schema.ObjectId,
dateCreated: { type: Date, default: Date.now },
title: { type: String, default: 'No Title' },
description: { type: String, default: 'No Description' },
tags: [ { type: Schema.ObjectId, ref: 'ItemTag' }]
});
ItemTag = new Schema({
id: Schema.ObjectId,
tagId: { type: Schema.ObjectId, ref: 'Tag' },
tagName: { type: String }
});
var query = Models.Item.find({});
query
.desc('dateCreated')
.populate('tags')
.where('tags.tagName').in(['funny', 'politics'])
.run(function(err, docs){
// docs is always empty
});
Is there a better way do this?
Edit
Apologies for any confusion. What I'm trying to do is get all Items that contain either the funny tag or politics tag.
Edit
Document without where clause:
[{
_id: 4fe90264e5caa33f04000012,
dislikes: 0,
likes: 0,
source: '/uploads/loldog.jpg',
comments: [],
tags: [{
itemId: 4fe90264e5caa33f04000012,
tagName: 'movies',
tagId: 4fe64219007e20e644000007,
_id: 4fe90270e5caa33f04000015,
dateCreated: Tue, 26 Jun 2012 00:29:36 GMT,
rating: 0,
dislikes: 0,
likes: 0
},
{
itemId: 4fe90264e5caa33f04000012,
tagName: 'funny',
tagId: 4fe64219007e20e644000002,
_id: 4fe90270e5caa33f04000017,
dateCreated: Tue, 26 Jun 2012 00:29:36 GMT,
rating: 0,
dislikes: 0,
likes: 0
}],
viewCount: 0,
rating: 0,
type: 'image',
description: null,
title: 'dogggg',
dateCreated: Tue, 26 Jun 2012 00:29:24 GMT
}, ... ]
With the where clause, I get an empty array.
With a modern MongoDB greater than 3.2 you can use $lookup as an alternate to .populate() in most cases. This also has the advantage of actually doing the join "on the server" as opposed to what .populate() does which is actually "multiple queries" to "emulate" a join.
So .populate() is not really a "join" in the sense of how a relational database does it. The $lookup operator on the other hand, actually does the work on the server, and is more or less analogous to a "LEFT JOIN":
Item.aggregate(
[
{ "$lookup": {
"from": ItemTags.collection.name,
"localField": "tags",
"foreignField": "_id",
"as": "tags"
}},
{ "$unwind": "$tags" },
{ "$match": { "tags.tagName": { "$in": [ "funny", "politics" ] } } },
{ "$group": {
"_id": "$_id",
"dateCreated": { "$first": "$dateCreated" },
"title": { "$first": "$title" },
"description": { "$first": "$description" },
"tags": { "$push": "$tags" }
}}
],
function(err, result) {
// "tags" is now filtered by condition and "joined"
}
)
N.B. The .collection.name here actually evaluates to the "string" that is the actual name of the MongoDB collection as assigned to the model. Since mongoose "pluralizes" collection names by default and $lookup needs the actual MongoDB collection name as an argument ( since it's a server operation ), then this is a handy trick to use in mongoose code, as opposed to "hard coding" the collection name directly.
Whilst we could also use $filter on arrays to remove the unwanted items, this is actually the most efficient form due to Aggregation Pipeline Optimization for the special condition of as $lookup followed by both an $unwind and a $match condition.
This actually results in the three pipeline stages being rolled into one:
{ "$lookup" : {
"from" : "itemtags",
"as" : "tags",
"localField" : "tags",
"foreignField" : "_id",
"unwinding" : {
"preserveNullAndEmptyArrays" : false
},
"matching" : {
"tagName" : {
"$in" : [
"funny",
"politics"
]
}
}
}}
This is highly optimal as the actual operation "filters the collection to join first", then it returns the results and "unwinds" the array. Both methods are employed so the results do not break the BSON limit of 16MB, which is a constraint that the client does not have.
The only problem is that it seems "counter-intuitive" in some ways, particularly when you want the results in an array, but that is what the $group is for here, as it reconstructs to the original document form.
It's also unfortunate that we simply cannot at this time actually write $lookup in the same eventual syntax the server uses. IMHO, this is an oversight to be corrected. But for now, simply using the sequence will work and is the most viable option with the best performance and scalability.
Addendum - MongoDB 3.6 and upwards
Though the pattern shown here is fairly optimized due to how the other stages get rolled into the $lookup, it does have one failing in that the "LEFT JOIN" which is normally inherent to both $lookup and the actions of populate() is negated by the "optimal" usage of $unwind here which does not preserve empty arrays. You can add the preserveNullAndEmptyArrays option, but this negates the "optimized" sequence described above and essentially leaves all three stages intact which would normally be combined in the optimization.
MongoDB 3.6 expands with a "more expressive" form of $lookup allowing a "sub-pipeline" expression. Which not only meets the goal of retaining the "LEFT JOIN" but still allows an optimal query to reduce results returned and with a much simplified syntax:
Item.aggregate([
{ "$lookup": {
"from": ItemTags.collection.name,
"let": { "tags": "$tags" },
"pipeline": [
{ "$match": {
"tags": { "$in": [ "politics", "funny" ] },
"$expr": { "$in": [ "$_id", "$$tags" ] }
}}
]
}}
])
The $expr used in order to match the declared "local" value with the "foreign" value is actually what MongoDB does "internally" now with the original $lookup syntax. By expressing in this form we can tailor the initial $match expression within the "sub-pipeline" ourselves.
In fact, as a true "aggregation pipeline" you can do just about anything you can do with an aggregation pipeline within this "sub-pipeline" expression, including "nesting" the levels of $lookup to other related collections.
Further usage is a bit beyond the scope of what the question here asks, but in relation to even "nested population" then the new usage pattern of $lookup allows this to be much the same, and a "lot" more powerful in it's full usage.
Working Example
The following gives an example using a static method on the model. Once that static method is implemented the call simply becomes:
Item.lookup(
{
path: 'tags',
query: { 'tags.tagName' : { '$in': [ 'funny', 'politics' ] } }
},
callback
)
Or enhancing to be a bit more modern even becomes:
let results = await Item.lookup({
path: 'tags',
query: { 'tagName' : { '$in': [ 'funny', 'politics' ] } }
})
Making it very similar to .populate() in structure, but it's actually doing the join on the server instead. For completeness, the usage here casts the returned data back to mongoose document instances at according to both the parent and child cases.
It's fairly trivial and easy to adapt or just use as is for most common cases.
N.B The use of async here is just for brevity of running the enclosed example. The actual implementation is free of this dependency.
const async = require('async'),
mongoose = require('mongoose'),
Schema = mongoose.Schema;
mongoose.Promise = global.Promise;
mongoose.set('debug', true);
mongoose.connect('mongodb://localhost/looktest');
const itemTagSchema = new Schema({
tagName: String
});
const itemSchema = new Schema({
dateCreated: { type: Date, default: Date.now },
title: String,
description: String,
tags: [{ type: Schema.Types.ObjectId, ref: 'ItemTag' }]
});
itemSchema.statics.lookup = function(opt,callback) {
let rel =
mongoose.model(this.schema.path(opt.path).caster.options.ref);
let group = { "$group": { } };
this.schema.eachPath(p =>
group.$group[p] = (p === "_id") ? "$_id" :
(p === opt.path) ? { "$push": `$${p}` } : { "$first": `$${p}` });
let pipeline = [
{ "$lookup": {
"from": rel.collection.name,
"as": opt.path,
"localField": opt.path,
"foreignField": "_id"
}},
{ "$unwind": `$${opt.path}` },
{ "$match": opt.query },
group
];
this.aggregate(pipeline,(err,result) => {
if (err) callback(err);
result = result.map(m => {
m[opt.path] = m[opt.path].map(r => rel(r));
return this(m);
});
callback(err,result);
});
}
const Item = mongoose.model('Item', itemSchema);
const ItemTag = mongoose.model('ItemTag', itemTagSchema);
function log(body) {
console.log(JSON.stringify(body, undefined, 2))
}
async.series(
[
// Clean data
(callback) => async.each(mongoose.models,(model,callback) =>
model.remove({},callback),callback),
// Create tags and items
(callback) =>
async.waterfall(
[
(callback) =>
ItemTag.create([{ "tagName": "movies" }, { "tagName": "funny" }],
callback),
(tags, callback) =>
Item.create({ "title": "Something","description": "An item",
"tags": tags },callback)
],
callback
),
// Query with our static
(callback) =>
Item.lookup(
{
path: 'tags',
query: { 'tags.tagName' : { '$in': [ 'funny', 'politics' ] } }
},
callback
)
],
(err,results) => {
if (err) throw err;
let result = results.pop();
log(result);
mongoose.disconnect();
}
)
Or a little more modern for Node 8.x and above with async/await and no additional dependencies:
const { Schema } = mongoose = require('mongoose');
const uri = 'mongodb://localhost/looktest';
mongoose.Promise = global.Promise;
mongoose.set('debug', true);
const itemTagSchema = new Schema({
tagName: String
});
const itemSchema = new Schema({
dateCreated: { type: Date, default: Date.now },
title: String,
description: String,
tags: [{ type: Schema.Types.ObjectId, ref: 'ItemTag' }]
});
itemSchema.statics.lookup = function(opt) {
let rel =
mongoose.model(this.schema.path(opt.path).caster.options.ref);
let group = { "$group": { } };
this.schema.eachPath(p =>
group.$group[p] = (p === "_id") ? "$_id" :
(p === opt.path) ? { "$push": `$${p}` } : { "$first": `$${p}` });
let pipeline = [
{ "$lookup": {
"from": rel.collection.name,
"as": opt.path,
"localField": opt.path,
"foreignField": "_id"
}},
{ "$unwind": `$${opt.path}` },
{ "$match": opt.query },
group
];
return this.aggregate(pipeline).exec().then(r => r.map(m =>
this({ ...m, [opt.path]: m[opt.path].map(r => rel(r)) })
));
}
const Item = mongoose.model('Item', itemSchema);
const ItemTag = mongoose.model('ItemTag', itemTagSchema);
const log = body => console.log(JSON.stringify(body, undefined, 2));
(async function() {
try {
const conn = await mongoose.connect(uri);
// Clean data
await Promise.all(Object.entries(conn.models).map(([k,m]) => m.remove()));
// Create tags and items
const tags = await ItemTag.create(
["movies", "funny"].map(tagName =>({ tagName }))
);
const item = await Item.create({
"title": "Something",
"description": "An item",
tags
});
// Query with our static
const result = (await Item.lookup({
path: 'tags',
query: { 'tags.tagName' : { '$in': [ 'funny', 'politics' ] } }
})).pop();
log(result);
mongoose.disconnect();
} catch (e) {
console.error(e);
} finally {
process.exit()
}
})()
And from MongoDB 3.6 and upward, even without the $unwind and $group building:
const { Schema, Types: { ObjectId } } = mongoose = require('mongoose');
const uri = 'mongodb://localhost/looktest';
mongoose.Promise = global.Promise;
mongoose.set('debug', true);
const itemTagSchema = new Schema({
tagName: String
});
const itemSchema = new Schema({
title: String,
description: String,
tags: [{ type: Schema.Types.ObjectId, ref: 'ItemTag' }]
},{ timestamps: true });
itemSchema.statics.lookup = function({ path, query }) {
let rel =
mongoose.model(this.schema.path(path).caster.options.ref);
// MongoDB 3.6 and up $lookup with sub-pipeline
let pipeline = [
{ "$lookup": {
"from": rel.collection.name,
"as": path,
"let": { [path]: `$${path}` },
"pipeline": [
{ "$match": {
...query,
"$expr": { "$in": [ "$_id", `$$${path}` ] }
}}
]
}}
];
return this.aggregate(pipeline).exec().then(r => r.map(m =>
this({ ...m, [path]: m[path].map(r => rel(r)) })
));
};
const Item = mongoose.model('Item', itemSchema);
const ItemTag = mongoose.model('ItemTag', itemTagSchema);
const log = body => console.log(JSON.stringify(body, undefined, 2));
(async function() {
try {
const conn = await mongoose.connect(uri);
// Clean data
await Promise.all(Object.entries(conn.models).map(([k,m]) => m.remove()));
// Create tags and items
const tags = await ItemTag.insertMany(
["movies", "funny"].map(tagName => ({ tagName }))
);
const item = await Item.create({
"title": "Something",
"description": "An item",
tags
});
// Query with our static
let result = (await Item.lookup({
path: 'tags',
query: { 'tagName': { '$in': [ 'funny', 'politics' ] } }
})).pop();
log(result);
await mongoose.disconnect();
} catch(e) {
console.error(e)
} finally {
process.exit()
}
})()
what you are asking for isn't directly supported but can be achieved by adding another filter step after the query returns.
first, .populate( 'tags', null, { tagName: { $in: ['funny', 'politics'] } } ) is definitely what you need to do to filter the tags documents. then, after the query returns you'll need to manually filter out documents that don't have any tags docs that matched the populate criteria. something like:
query....
.exec(function(err, docs){
docs = docs.filter(function(doc){
return doc.tags.length;
})
// do stuff with docs
});
Try replacing
.populate('tags').where('tags.tagName').in(['funny', 'politics'])
by
.populate( 'tags', null, { tagName: { $in: ['funny', 'politics'] } } )
Update: Please take a look at the comments - this answer does not correctly match to the question, but maybe it answers other questions of users which came across (I think that because of the upvotes) so I will not delete this "answer":
First: I know this question is really outdated, but I searched for exactly this problem and this SO post was the Google entry #1. So I implemented the docs.filter version (accepted answer) but as I read in the mongoose v4.6.0 docs we can now simply use:
Item.find({}).populate({
path: 'tags',
match: { tagName: { $in: ['funny', 'politics'] }}
}).exec((err, items) => {
console.log(items.tags)
// contains only tags where tagName is 'funny' or 'politics'
})
Hope this helps future search machine users.
After having the same problem myself recently, I've come up with the following solution:
First, find all ItemTags where tagName is either 'funny' or 'politics' and return an array of ItemTag _ids.
Then, find Items which contain all ItemTag _ids in the tags array
ItemTag
.find({ tagName : { $in : ['funny','politics'] } })
.lean()
.distinct('_id')
.exec((err, itemTagIds) => {
if (err) { console.error(err); }
Item.find({ tag: { $all: itemTagIds} }, (err, items) => {
console.log(items); // Items filtered by tagName
});
});
#aaronheckmann 's answer worked for me but I had to replace return doc.tags.length; to return doc.tags != null; because that field contain null if it doesn't match with the conditions written inside populate.
So the final code:
query....
.exec(function(err, docs){
docs = docs.filter(function(doc){
return doc.tags != null;
})
// do stuff with docs
});
I've got a MongoDB document which has records that looks like this:
[
{ _id: id, category_name: 'category1', parent_category: null },
{ _id: id, category_name: 'category2', parent_category: null },
{ _id: id, category_name: 'subcategory1', parent_category: id_parent_1 },
{ _id: id, category_name: 'subcategory2', parent_category: id_parent_1 },
{ _id: id, category_name: 'subcategory3', parent_category: id_parent_2 },
{ _id: id, category_name: 'subcategory4', parent_category: id_parent_2 }
]
As you can see, I'm storing categories with a parent_category of null, and subcategories have the parent category's ID. What I'm looking for is to group these into some kind of format like this:
[
{ category_name: 'category1', categories: [
{ category_name: 'subcategory1', _id: id },
{ category_name: 'subcategory2', _id: id }
]
},
{ category_name: 'category2', categories: [
{ category_name: 'subcategory3', _id: id },
{ category_name: 'subcategory4', _id: id }
]
}
]
So basically group the parent categories with an array with their child categories. I'm using Mongoose. I tried using the aggregation framework MongoDB provides but I can't get the desired result. :(
I have access to modify the schema in any way that could be needed!
Thanks in advance!
It seems like you're treating Mongo like an relational database (separating all these fields and bringing them together with a query). What you should do is rebuild your Schema. For example:
var CategorySchema = new Schema({
category_name: String,
subCategories:[subCategorySchema]
}
var subCategorySchema = new Schema({
category_name: String
})
This way when you need to query the collection it's a simple
db.find({category_name: "name of the category"}, function(){})
to get everything you need.
Just in case: you can add the sub categories to the array with simple updates. Read this for more info.
Please try this if Your schema is not changed:
var MongoClient = require('mongodb').MongoClient
//connect away
MongoClient.connect('mongodb://127.0.0.1:27017/test', function(err, db) {
if (err) throw err;
console.log("Connected to Database");
//simple json record
var document = [];
//insert record
//db.data.find({"parent_category":null }).forEach(function(data) {print("user: " + db.data.findOne({"parent_category":data._id })) })
db.collection('data').find({"parent_category":null }, function(err, parentrecords) {
if (err) throw err;
var cat ={};
parentrecords.forEach(function(data){
cat["category_name"] = data["category_name"];
db.collection('data').find({"parent_category":data._id },function(err, childrecords) {
var doc = [];
childrecords.forEach(function(childdata){
doc.push(childdata);
},function(){
cat["categories"] = doc;
document.push(cat);
console.log(document);
});
});
});
});
});
If you want to find out expected results without changing schema then you basically follow some complex mongo aggregation query. For finding output I follow following steps :
First in $project check parent_category equals null if true then add _id else add parent_category.
Now document structure looks like with new key name as parent_id presents and group by parent_id and push remaining data like category_name and parent_category.
After that use $setDifference and $setIntersection to differentiate parent data and child data.
And in finally unwind only single array objects so this single array object and used project for showing only those fields which to display.
Check working aggregation query as below :
db.collectionName.aggregate({
"$project": {
"parent_id": {
"$cond": {
"if": {
"$eq": ["$parent_category", null]
},
"then": "$_id",
"else": "$parent_category"
}
},
"category_name": 1,
"parent_category": 1
}
}, {
"$group": {
"_id": "$parent_id",
"categories": {
"$push": {
"category_name": "$category_name",
"parent_category": "$parent_category"
}
},
"parentData": {
"$push": {
"$cond": {
"if": {
"$eq": ["$parent_category", null]
},
"then": {
"category_name": "$category_name",
"parent_category": "$parent_category"
},
"else": null
}
}
}
}
}, {
"$project": {
"findParent": {
"$setIntersection": ["$categories", "$parentData"]
},
"categories": {
"$setDifference": ["$categories", "$parentData"]
}
}
}, {
"$unwind": "$findParent"
}, {
"$project": {
"category_name": "$findParent.category_name",
"categories": 1
}
}).pretty()
In order to group records by a field try using $group in Aggreegation.This worked for me.
Example
db.categories.aggregate(
[
{ $group : { _id : {category_name:"$category_name"}, categories: { $push: {category_name:"$category_name",_id:"$_id"} } } }
]
)
Reference:
MongoDB Aggregation
Hope this works.