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Array transformation in JavaScript [duplicate]

I have a heavy array like this:
[
{Id: 1, Name: 'Red', optionName: 'Color'},
{Id: 2, Name: 'Yellow', optionName: 'Color'},
{Id: 3, Name: 'Blue', optionName: 'Color'},
{Id: 4, Name: 'Green', optionName: 'Color'},
{Id: 7, Name: 'Black', optionName: 'Color'},
{Id: 8, Name: 'S', optionName: 'Size'},
{Id: 11, Name: 'M', optionName: 'Size'},
{Id: 12, Name: 'L', optionName: 'Size'},
{Id: 13, Name: 'XL', optionName: 'Size'},
{Id: 14, Name: 'XXL', optionName: 'Size'}
]
What I need to do is to group them by optionName and have two row in the main array like this:
[
{
Name: 'Color',
Data:[{Id: 1, Name: 'Red'},
{Id: 2, Name: 'Yellow'},
{Id: 3, Name: 'Blue'},
{Id: 4, Name: 'Green'},
{Id: 7, Name: 'Black'}]
}, {
Name: 'Size',
Data:[{Id: 8, Name: 'S'},
{Id: 11, Name: 'M'},
{Id: 12, Name: 'L'},
{Id: 13, Name: 'XL'},
{Id: 14, Name: 'XXL'}]
}
]
How to do it in javascript?

This is a snippet I wrote for these kind of situations. You can add this functionality to all of your arrays:
Object.defineProperty(Array.prototype, 'group', {
enumerable: false,
value: function (key) {
var map = {};
this.forEach(function (e) {
var k = key(e);
map[k] = map[k] || [];
map[k].push(e);
});
return Object.keys(map).map(function (k) {
return {key: k, data: map[k]};
});
}
});
You can use it like this. You can just pass a function which defines how you want to group your data.
var newArray = arr.group(function (item) {
return item.optionName;
});
Working Fiddle
If you need, you can replace {key: k, data: map[k]} with {Name: k, Data: map[k]}.
This is also more compact ES6 version of the code above:
Object.defineProperty(Array.prototype, 'group', {
enumerable: false,
value: function (key) {
let map = {};
this.map(e => ({k: key(e), d: e})).forEach(e => {
map[e.k] = map[e.k] || [];
map[e.k].push(e.d);
});
return Object.keys(map).map(k => ({key: k, data: map[k]}));
}
});
Use it like this:
let newArray = arr.group(item => item.optionName))

An ES6 solution using Map object:
function groupBy(arr, key) {
return arr.reduce(
(sum, item) => {
const groupByVal = item[key];
groupedItems = sum.get(groupByVal) || [];
groupedItems.push(item);
return sum.set(groupByVal, groupedItems);
},
new Map()
);
}
var Data = [
{ Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
document.getElementById("showArray").innerHTML =JSON.stringify([...groupBy(Data, 'optionName')], null, 4);
<pre id="showArray"></pre>

You can use reduce to get the resultset you need:
var result = list.reduce(function(memo, item) {
if (item.optionName === 'Color') {
memo[0].Data.push(
Id: item.Id,
Name: item.Name
});
}
if (item.optionName === 'Size') {
memo[1].Data.push({
Id: item.Id,
Name: item.Name
});
}
return memo;
}, [{ Name: 'Color', Data: [] }, { Name: 'Size', Data: [] }]);
variable list is your first list.
Hope this helps.

This is a snippet I wrote for kind of my situation in my application functionality of all arrays. This snippet code is use in node js application. All the above is is given solution but I was finding some problem in server side in node js.
This snippet is user full me....
var Data= [
{ Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
function groupBy(arr, key) {
var newArr = [],
types = {},
newItem, i, j, cur;
for (i = 0, j = arr.length; i < j; i++) {
cur = arr[i];
if (!(cur[key] in types)) {
types[cur[key]] = { type: cur[key], data: [] };
newArr.push(types[cur[key]]);
}
types[cur[key]].data.push(cur);
}
return newArr;
}
I use it like this. I just pass a function which defines how you want to group our data.
filterData= groupBy(Data,'optionName');
Result of this snippet of code output.....
[
{"type":"Color","data":[{"Id":1,"Name":"Red","optionName":"Color"},
{"Id":2,"Name":"Yellow","optionName":"Color"},
{"Id":3,"Name":"Blue","optionName":"Color"},
{"Id":4,"Name":"Green","optionName":"Color"},
{"Id":7,"Name":"Black","optionName":"Color"}]},
{"type":"Size","data":[{"Id":8,"Name":"S","optionName":"Size"},
{"Id":11,"Name":"M","optionName":"Size"},
{"Id":12,"Name":"L","optionName":"Size"},
{"Id":13,"Name":"XL","optionName":"Size"},
{"Id":14,"Name":"XXL","optionName":"Size"}]}
]
Show on fiddle

var originalList = [ { Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
var output = [{ Name: "Color", Data: [] },{ Name: "Size", Data: [] }] ;
originalList.map(function(entry){
if ( entry.optionName === "Color") output[0].Data.push({ Id: entry.Id, Name: entry.Name });
if ( entry.optionName === "Size") output[1].Data.push({ Id: entry.Id, Name: entry.Name });
});

'use strict'
let l = [ { Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
let color = [];
let size = [];
l.forEach(element => {
if (element['optionName'] === 'Color') {
color.push({'Id': element.Id, 'Name': element.Name});
} else {
size.push({'Id': element.Id, 'Name': element.Name});
}
});
console.log(color);
console.log(size);
You can try this method.

All of the answers lead to the same result, so it all comes down to a personal preference (or company guidelines) on how to tackle this.
// ES5 (traditional javascript) version
function groupByOptionName(list, optionName) {
return list
// filter out any item whose optionName does not match the desired name
.filter(function(item) {
return item.optionName === optionName;
})
// map the item into the desired shape
// (appears to be everything except optionName itself
.map(function(item) {
return {
Id: item.Id,
Name: item.Name
};
})
}
// ES2015/ES6 version
function groupByOptionName(list, optionName) {
return list
// filter out any item whose optionName does not match the desired name
.filter(item => item.optionName === optionName)
// map the item into the desired shape
// (appears to be everything except optionName itself
.map(item => {
Id: item.Id,
Name: item.Name
});
}
This function would let you program the desired result as follows:
var output = [
{Name: 'Color', Data: groupByOptionName(list, 'Color')},
{Name: 'Size', Data: groupByOptionName(list, 'Size')},
];
// the ES2015/ES6 version of this code would replace var with let
While the code itself differs, it is much like the other answers, with only a variation on the steps needed.
One could also opt to leave out any hardcoded option names (Color and Size) by extracting those aswel, this would allow for a more dynamic input, but could also introduce more processing that actually needed.
// ES5 (traditional javascript) version
function getOptionNames(list) {
return list
// map the array into a list of optionNames
.map(function(item) {
return item.optionName;
})
// remove duplicates
.filter(function(item, index, all) {
return all.indexOf(item) === index;
});
}
// ES2015/ES6 version (does exactly the same as the one above)
function getOptionNames(list) {
return list
// map the array into a list of optionNames
.map(item => item.optionName)
// remove duplicates
.filter((item, index, all) => all.indexOf(item) === index);
}
Which allows the result to be fully based on the input data:
// ES5 (traditional javascript) version
var output = getOptionNames(list)
// map the names into the desired structure
.map(function(buffer, name) {
return {
Name: name,
Data: groupByOptionName(list, name)
};
});
// ES2015/ES6 version (does exactly the same as the one above)
var output = getOptionNames(list)
// map the names into the desired structure
.map((buffer, name) => {
Name: name,
Data: groupByOptionName(list, name)
});
By writing all of the data-mangling steps in short consice steps you'd do yourself (especially your future self) a favor if this code ever needs to be adjusted.
If the data set really is heavy (in terms of a lot of data), you must also make sure to keep the number of copies you keep in memory limited. For example, if you never need the original dataset, make sure it can be garbage collected (by not having a variable containing it outside the scope where you receive the data)

Usage:
groupValues([
{ color: 'blue', value: 100 },
{ color: 'blue', value: 75 },
{ color: 'yellow', value: 50 },
{ color: 'yellow', value: 25 }
], 'color')
Result:
[
[{ color: 'blue', value: 100 }, { color: 'blue', value: 75 }],
[{ color: 'yellow', value: 50 }, { color: 'yellow', value: 25 }]
]
Function:
const groupValues = function(arr, key) {
const mapped = {}
arr.forEach(el => {
const actualKey = el[key]
if(!mapped.hasOwnProperty(actualKey)) mapped[actualKey] = []
mapped[actualKey].push(el)
})
return Object.keys(mapped).map(el => mapped[el])
}

javascript: rearrange array of objects with arrays, injecting objects into groups along with their parameters [duplicate]

I have a heavy array like this:
[
{Id: 1, Name: 'Red', optionName: 'Color'},
{Id: 2, Name: 'Yellow', optionName: 'Color'},
{Id: 3, Name: 'Blue', optionName: 'Color'},
{Id: 4, Name: 'Green', optionName: 'Color'},
{Id: 7, Name: 'Black', optionName: 'Color'},
{Id: 8, Name: 'S', optionName: 'Size'},
{Id: 11, Name: 'M', optionName: 'Size'},
{Id: 12, Name: 'L', optionName: 'Size'},
{Id: 13, Name: 'XL', optionName: 'Size'},
{Id: 14, Name: 'XXL', optionName: 'Size'}
]
What I need to do is to group them by optionName and have two row in the main array like this:
[
{
Name: 'Color',
Data:[{Id: 1, Name: 'Red'},
{Id: 2, Name: 'Yellow'},
{Id: 3, Name: 'Blue'},
{Id: 4, Name: 'Green'},
{Id: 7, Name: 'Black'}]
}, {
Name: 'Size',
Data:[{Id: 8, Name: 'S'},
{Id: 11, Name: 'M'},
{Id: 12, Name: 'L'},
{Id: 13, Name: 'XL'},
{Id: 14, Name: 'XXL'}]
}
]
How to do it in javascript?

This is a snippet I wrote for these kind of situations. You can add this functionality to all of your arrays:
Object.defineProperty(Array.prototype, 'group', {
enumerable: false,
value: function (key) {
var map = {};
this.forEach(function (e) {
var k = key(e);
map[k] = map[k] || [];
map[k].push(e);
});
return Object.keys(map).map(function (k) {
return {key: k, data: map[k]};
});
}
});
You can use it like this. You can just pass a function which defines how you want to group your data.
var newArray = arr.group(function (item) {
return item.optionName;
});
Working Fiddle
If you need, you can replace {key: k, data: map[k]} with {Name: k, Data: map[k]}.
This is also more compact ES6 version of the code above:
Object.defineProperty(Array.prototype, 'group', {
enumerable: false,
value: function (key) {
let map = {};
this.map(e => ({k: key(e), d: e})).forEach(e => {
map[e.k] = map[e.k] || [];
map[e.k].push(e.d);
});
return Object.keys(map).map(k => ({key: k, data: map[k]}));
}
});
Use it like this:
let newArray = arr.group(item => item.optionName))

An ES6 solution using Map object:
function groupBy(arr, key) {
return arr.reduce(
(sum, item) => {
const groupByVal = item[key];
groupedItems = sum.get(groupByVal) || [];
groupedItems.push(item);
return sum.set(groupByVal, groupedItems);
},
new Map()
);
}
var Data = [
{ Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
document.getElementById("showArray").innerHTML =JSON.stringify([...groupBy(Data, 'optionName')], null, 4);
<pre id="showArray"></pre>

You can use reduce to get the resultset you need:
var result = list.reduce(function(memo, item) {
if (item.optionName === 'Color') {
memo[0].Data.push(
Id: item.Id,
Name: item.Name
});
}
if (item.optionName === 'Size') {
memo[1].Data.push({
Id: item.Id,
Name: item.Name
});
}
return memo;
}, [{ Name: 'Color', Data: [] }, { Name: 'Size', Data: [] }]);
variable list is your first list.
Hope this helps.

This is a snippet I wrote for kind of my situation in my application functionality of all arrays. This snippet code is use in node js application. All the above is is given solution but I was finding some problem in server side in node js.
This snippet is user full me....
var Data= [
{ Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
function groupBy(arr, key) {
var newArr = [],
types = {},
newItem, i, j, cur;
for (i = 0, j = arr.length; i < j; i++) {
cur = arr[i];
if (!(cur[key] in types)) {
types[cur[key]] = { type: cur[key], data: [] };
newArr.push(types[cur[key]]);
}
types[cur[key]].data.push(cur);
}
return newArr;
}
I use it like this. I just pass a function which defines how you want to group our data.
filterData= groupBy(Data,'optionName');
Result of this snippet of code output.....
[
{"type":"Color","data":[{"Id":1,"Name":"Red","optionName":"Color"},
{"Id":2,"Name":"Yellow","optionName":"Color"},
{"Id":3,"Name":"Blue","optionName":"Color"},
{"Id":4,"Name":"Green","optionName":"Color"},
{"Id":7,"Name":"Black","optionName":"Color"}]},
{"type":"Size","data":[{"Id":8,"Name":"S","optionName":"Size"},
{"Id":11,"Name":"M","optionName":"Size"},
{"Id":12,"Name":"L","optionName":"Size"},
{"Id":13,"Name":"XL","optionName":"Size"},
{"Id":14,"Name":"XXL","optionName":"Size"}]}
]
Show on fiddle

var originalList = [ { Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
var output = [{ Name: "Color", Data: [] },{ Name: "Size", Data: [] }] ;
originalList.map(function(entry){
if ( entry.optionName === "Color") output[0].Data.push({ Id: entry.Id, Name: entry.Name });
if ( entry.optionName === "Size") output[1].Data.push({ Id: entry.Id, Name: entry.Name });
});

'use strict'
let l = [ { Id: 1, Name: 'Red', optionName: 'Color' },
{ Id: 2, Name: 'Yellow', optionName: 'Color' },
{ Id: 3, Name: 'Blue', optionName: 'Color' },
{ Id: 4, Name: 'Green', optionName: 'Color' },
{ Id: 7, Name: 'Black', optionName: 'Color' },
{ Id: 8, Name: 'S', optionName: 'Size' },
{ Id: 11, Name: 'M', optionName: 'Size' },
{ Id: 12, Name: 'L', optionName: 'Size' },
{ Id: 13, Name: 'XL', optionName: 'Size' },
{ Id: 14, Name: 'XXL', optionName: 'Size' } ];
let color = [];
let size = [];
l.forEach(element => {
if (element['optionName'] === 'Color') {
color.push({'Id': element.Id, 'Name': element.Name});
} else {
size.push({'Id': element.Id, 'Name': element.Name});
}
});
console.log(color);
console.log(size);
You can try this method.

All of the answers lead to the same result, so it all comes down to a personal preference (or company guidelines) on how to tackle this.
// ES5 (traditional javascript) version
function groupByOptionName(list, optionName) {
return list
// filter out any item whose optionName does not match the desired name
.filter(function(item) {
return item.optionName === optionName;
})
// map the item into the desired shape
// (appears to be everything except optionName itself
.map(function(item) {
return {
Id: item.Id,
Name: item.Name
};
})
}
// ES2015/ES6 version
function groupByOptionName(list, optionName) {
return list
// filter out any item whose optionName does not match the desired name
.filter(item => item.optionName === optionName)
// map the item into the desired shape
// (appears to be everything except optionName itself
.map(item => {
Id: item.Id,
Name: item.Name
});
}
This function would let you program the desired result as follows:
var output = [
{Name: 'Color', Data: groupByOptionName(list, 'Color')},
{Name: 'Size', Data: groupByOptionName(list, 'Size')},
];
// the ES2015/ES6 version of this code would replace var with let
While the code itself differs, it is much like the other answers, with only a variation on the steps needed.
One could also opt to leave out any hardcoded option names (Color and Size) by extracting those aswel, this would allow for a more dynamic input, but could also introduce more processing that actually needed.
// ES5 (traditional javascript) version
function getOptionNames(list) {
return list
// map the array into a list of optionNames
.map(function(item) {
return item.optionName;
})
// remove duplicates
.filter(function(item, index, all) {
return all.indexOf(item) === index;
});
}
// ES2015/ES6 version (does exactly the same as the one above)
function getOptionNames(list) {
return list
// map the array into a list of optionNames
.map(item => item.optionName)
// remove duplicates
.filter((item, index, all) => all.indexOf(item) === index);
}
Which allows the result to be fully based on the input data:
// ES5 (traditional javascript) version
var output = getOptionNames(list)
// map the names into the desired structure
.map(function(buffer, name) {
return {
Name: name,
Data: groupByOptionName(list, name)
};
});
// ES2015/ES6 version (does exactly the same as the one above)
var output = getOptionNames(list)
// map the names into the desired structure
.map((buffer, name) => {
Name: name,
Data: groupByOptionName(list, name)
});
By writing all of the data-mangling steps in short consice steps you'd do yourself (especially your future self) a favor if this code ever needs to be adjusted.
If the data set really is heavy (in terms of a lot of data), you must also make sure to keep the number of copies you keep in memory limited. For example, if you never need the original dataset, make sure it can be garbage collected (by not having a variable containing it outside the scope where you receive the data)

Usage:
groupValues([
{ color: 'blue', value: 100 },
{ color: 'blue', value: 75 },
{ color: 'yellow', value: 50 },
{ color: 'yellow', value: 25 }
], 'color')
Result:
[
[{ color: 'blue', value: 100 }, { color: 'blue', value: 75 }],
[{ color: 'yellow', value: 50 }, { color: 'yellow', value: 25 }]
]
Function:
const groupValues = function(arr, key) {
const mapped = {}
arr.forEach(el => {
const actualKey = el[key]
if(!mapped.hasOwnProperty(actualKey)) mapped[actualKey] = []
mapped[actualKey].push(el)
})
return Object.keys(mapped).map(el => mapped[el])
}

How to find matching colors in an array of objects?

I have this list of colors:
colors = ['red', 'yellow', 'white'];
This is my array objects:
products = [
{id: 1, ​name: "Apple", color: ['Brown','black'] },
{id: 2, name: "Orange", color: ['red']},
​{id: 3, name: "Grape", color: ['red','white']},
​ {id: 4, name: "Banana", color: ['yellow']},
{id: 5, name: "Mandarin", color: ['blue']}
];
I want to return an array of the matching colors like so: [Orange,Grape,Banana];

Try this, it traverses through product lists and checks if the color list contains one of the colors
const list = products.filter((obj)=>{
return obj.color.some(c=>colors.includes(c))
});

Try using a filter and a map...
const colors = ['red', 'yellow', 'white'];
const products = [
{id: 1, name: "Apple", color: ['Brown','black'] },
{id: 2, name: "Orange", color: ['red']},
{id: 3, name: "Grape", color: ['red','white']},
{id: 4, name: "Banana", color: ['yellow']},
{id: 5, name: "Mandarin", color: ['blue']}
];
const arr = products.filter(product => {
return product.color.some(color => colors.some(c => c === color))
}).map(product => product.name);
console.log(arr);
This should be what you're looking for as it produces the correct list of items as requested in the question.

This runs 2 filters to find matching colors
products.filter(e => e.color.filter( c=> colors.includes(c)).length>0)
colors = ['red', 'yellow', 'white']
products = [
{id: 1, name: "Apple", color: ['Brown','black'] },
{id: 2, name: "Orange", color: ['red']},
{id: 3, name: "Grape", color: ['red','white']},
{id: 4, name: "Banana", color: ['yellow']},
{id: 5, name: "Mandarin", color: ['blue']}
]
let filtered = products.filter(e => e.color.filter( c=> colors.includes(c)).length>0)
console.log(filtered)

let requiredArray = products.filter(({ color }) => colors.some(item => color.includes(item)));
console.log(requiredArray);

How to get an object's value from another object's key?

Having:
const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
And:
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
How can I reference the colors in shirts by the id in colors? I need to end up with shirt.color = blue.
I'm thinking about something like this, but can't get it right:
if (shirt.color === color.id) {
shirt.color = color.name;
}
Thanks in advance!

You can use forEach
const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
shirts.forEach(e=>{
colors.forEach(c=>{
if(e.color == c.id ){
e.color = c.name;
}
})
})
console.log(shirts);

You can use Array.map() for that to loop over the colors and then use Array.filter() to get all the shirts that matches color.id === shirt.color. With that you can then assign that color name to all the shirt object as expected.
const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
colors.map((color) => {
let matchShirt = shirts.filter((shirt) => color.id === shirt.color);
matchShirt.forEach((shirt) => shirt.color = color.name);
});
console.log(shirts);

You could take a Map and create new objects with the color name.
const
colors = [{ id: 1, name: "blue" }, { id: 2, name: "red" }, { id: 3, name: "green" }],
shirts = [{ id: 1, color: 2 }, { id: 2, color: 3 }, { id: 3, color: 2 }, { id: 4, color: 1 }, { id: 5, color: 3 }],
colorMap = new Map(colors.map(({ id, name }) => [id, name])),
result = shirts.map(o => ({ ...o, name: colorMap.get(o.color) }));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
shirts.forEach(s => {
s.color = (colors.find(c => c.id === s.color) || {}).name;
});
console.log(shirts);

If you use an object for the color codes, it makes your life so much easier. It avoids having to loop over it and convert it into a format that resembles this for a quick look up.
const colors = {
1: "blue",
2: "red",
3: "green"
}
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
shirts.forEach( shirt => shirt.colorName = colors[shirt.color] )
console.log(shirts)
If it really has to be in that format, than do the conversion
const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
const colorCodes = colors.reduce((o, c) => { o[c.id] = c.name; return o }, {})
shirts.forEach( shirt => shirt.colorName = colorCodes[shirt.color] )
console.log(shirts)

Given
const colors = [
{id: 1, name: "blue"},
{id: 2, name: "red"},
{id: 3, name: "green"}
];
The shape of colors above is an array of objects with names and ids. This makes the code needlessly awkward.
We can dramatically simplify things by making colors an object.
const colors = {
1: "blue",
2: "red",
3: "green"
};
const shirts = [
{id: 1, color: 2},
{id: 2, color: 3},
{id: 3, color: 2},
{id: 4, color: 1},
{id: 5, color: 3}
];
function assignShirtColor(shirt) {
shirt.color = colors[shirt.color];
}
Then all we need to do is write
shirts.forEach(assignShirtColor);

Filter array of objects based on values in second array

I have an array of objects that I'd like to filter to create a new array based on whether or not the value of any key matches any value in another array.
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red, id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}]
const array2 = ['red', 'blue', 'green', 'pink']
I've tried using a for...of loop inside of a return function but that is giving me errors.
const array3 = array1.filter(color => {
for (mainColor of array2){
return color.name === mainColor
}
});
This works but is clearly not the best way.
const array3 = array1.filter(color => {
return (color.main === 'red') || (color.main === 'blue')
});
How can I get a third array from array1 that contains only the objects where the array1.name matches a value in array2?
Is it possible with ES6 or Lodash?
Thanks in advance!

Almost there, instead of for-loop use includes and return
const array3 = array1.filter(color => {
return array2.includes ( color.name );
});
Or
const array3 = array1.filter( color => array2.includes ( color.name ) );

Let me give an alternative, that has slightly more code, but is more efficient as well, as it only needs to scan array2 once:
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}],
array2 = ['red', 'blue', 'green', 'pink'];
const colorSet = new Set(array2),
array3 = array1.filter(color => colorSet.has(color.name));
console.log(array3);

Try the following with Array's includes():
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}]
const array2 = ['red', 'blue', 'green', 'pink'];
const array3 = array1.filter(color => array2.includes(color.name));
console.log(array3);

The filter method already iterates on each item. You just have to return true if the element is present in the second array (by using indexOf or includes)
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}]
const array2 = ['red', 'blue', 'green', 'pink'];
let filteredArray = array1.filter(e => array2.indexOf(e.name) > -1);
console.log(filteredArray);

I know indexOf might seem a little outfashioned and ES5-ish, but it still does the job:
const array1 = [{name: 'pink', id: 13}, {name: 'orange', id: 17}, {name: 'red', id: 64}, {name: 'purple', id: 47}, {name: 'yellow', id: 23}, {name: 'gray', id: 2}, {name: 'black', id: 200}, {name: 'violet', id: 4}],
array2 = ['red', 'blue', 'green', 'pink'];
let array3 = array1.filter(x => array2.indexOf(x.name) != -1)
console.log(array3)