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How to create a function in Javascript to simulate the same functionality of PBEWithHmacSHA256AndAES_256?

currently I need to create a hash that needs to be compaired in Mulesoft from a javascript file, the current way is using directly Crypto.SHA1 method but it's obsolete and now mule application is using SHA256 but I cannot figureout how to create the same flow to execute the encryption from Javascript.
This is an example shared by other user in stackoverflow to implement MD5 encryption in Javascript:
var password = CryptoJS.enc.Utf8.parse("test");
var salt = CryptoJS.enc.Hex.parse("2121F055C39F5A75");
var iterations = 31;
// PBE according to PKCS#5 v1.5 (in other words: PBKDF1)
var md5 = CryptoJS.algo.HMAC256.create();
md5.update(password);
md5.update(salt);
var result = md5.finalize();
md5.reset();
for(var i = 1; i < iterations; i++) {
md5.update(result);
result = md5.finalize();
md5.reset();
}
// splitting key and IV
var key = CryptoJS.lib.WordArray.create(result.words.slice(0, 2));
var iv = CryptoJS.lib.WordArray.create(result.words.slice(2, 4));
var encrypted = CryptoJS.DES.encrypt("test", key, {
iv: iv
});
enc.innerHTML = encrypted.ciphertext.toString(); // HEX
https://jsfiddle.net/artjomb/Lpbo7yrb/

The posted code applies PBEWithMD5andDES, which works differently than PBEWithHmacSHA256AndAES_256, and therefore unfortunately cannot be used.
PBEWithHmacSHA256AndAES_256 applies PBKDF2 for deriving a 256 bits key and AES with CBC and PKCS#7 padding for encryption. A possible implementation with CryptoJS is:
var passphrase = "My Passphrase";
var saltWA = CryptoJS.enc.Hex.parse("000102030405060708090a0b0c0d0e0f"); // static only for test!
var ivWA = CryptoJS.enc.Hex.parse("101112131415161718191a1b1c1d1e1f"); // static only for test!
var iterations = 10000;
var plaintext = "The quick brown fox jumps over the lazy dog";
var keyWA = CryptoJS.PBKDF2(
passphrase, saltWA, {keySize: 256/32, iterations: iterations, hasher: CryptoJS.algo.SHA256});
var ciphertextCP = CryptoJS.AES.encrypt(plaintext, keyWA, {iv: ivWA}); // applies CBC and PKCS#7 by default
var ciphertextHex = ciphertextCP.ciphertext.toString();
ct.innerHTML = ciphertextHex; // a08af68882ef646631c510b0742272308eca57bd251f962444a01abcecf41bfc804b5e3e9f666f125103d1954809edd5
var decrypted = CryptoJS.AES.decrypt(ciphertextCP, keyWA, {iv: ivWA});
pt.innerHTML = decrypted.toString(CryptoJS.enc.Utf8); // The quick brown fox jumps over the lazy dog
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/4.1.1/crypto-js.min.js"></script>
<div id="ct"></div>
<div id="pt"></div>
which gives the hex encoded ciphertext:
a08af68882ef646631c510b0742272308eca57bd251f962444a01abcecf41bfc804b5e3e9f666f125103d1954809edd5
Beware: For comparison with the reference value of the Java code below, a static IV and salt are used. In practice, however, salt and IV must be randomly generated for each ciphertext for security reasons. Since salt and IV are needed for decryption and are not secret, they are passed to the decrypting side along with the ciphertext, typically concatenated, e.g. salt|IV|ciphertext.
For a test of the CryptoJS implementation, a reference value is needed. The following code is an encryption with PBEWithHmacSHA256AndAES_256 in Java:
import java.nio.charset.StandardCharsets;
import java.util.HexFormat;
import javax.crypto.Cipher;
import javax.crypto.SecretKey;
import javax.crypto.SecretKeyFactory;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.PBEKeySpec;
import javax.crypto.spec.PBEParameterSpec;
...
String password = "My Passphrase" ;
byte[] salt = HexFormat.of().parseHex("000102030405060708090a0b0c0d0e0f"); // static only for test
byte[] iv = HexFormat.of().parseHex("101112131415161718191a1b1c1d1e1f"); // static only for test
int iterations = 10000 ;
String plaintext = "The quick brown fox jumps over the lazy dog";
IvParameterSpec ivSpec = new IvParameterSpec(iv);
PBEParameterSpec parameterSpec = new PBEParameterSpec(salt, iterations, ivSpec);
PBEKeySpec keySpec = new PBEKeySpec(password.toCharArray());
SecretKeyFactory kf = SecretKeyFactory.getInstance("PBEWithHmacSHA256AndAES_256");
SecretKey secretKey = kf.generateSecret(keySpec);
Cipher cipher = Cipher.getInstance("PBEWithHmacSHA256AndAES_256");
cipher.init(Cipher.ENCRYPT_MODE, secretKey, parameterSpec);
byte[] ciphertext = cipher.doFinal(plaintext.getBytes(StandardCharsets.UTF_8));
cipher.init(Cipher.DECRYPT_MODE, secretKey, parameterSpec);
byte[] decryptedtext = cipher.doFinal(ciphertext);
System.out.println(HexFormat.of().formatHex(ciphertext)); // a08af68882ef646631c510b0742272308eca57bd251f962444a01abcecf41bfc804b5e3e9f666f125103d1954809edd5
System.out.println(new String(decryptedtext, StandardCharsets.UTF_8)); // The quick brown fox jumps over the lazy dog
The ciphertext corresponds to that of the CryptoJS implementation which proves that the CryptoJS code is indeed functionally identical to PBEWithHmacSHA256AndAES_256.

Decrypt AES in JavaScript

I am encrypting a text with AES256 in swift language and outputting it as hex. I want to decrypt this code I received with JS, but I could not reach the result. I tried the CryptoJS library but still couldn't get the result I wanted. All I want is the js code that will give me the decoded version when I enter the IV, password and ciphertext.
const crypto = require("crypto");
var key = "";
const iv = "";
const token = "";
function decrypt(token, iv, key) {
const decrypter = crypto.createDecipheriv("aes-256-cbc", key, iv);
let decrypted = decrypter.update(token, "hex", "utf8");
decrypted += decrypter.final("utf8");
return decrypted
}
console.log(decrypt(token, iv, key));
With the Node.js code above, I achieve what I want, but I want to do it with normal JS code, not using node. I don't want to mess with the server. I would be very happy if you help.
EDIT:
I am using CryptoSwift library in Swift language.
func encryption(uuid: String, token: String) -> String {
do {
let aes = try AES(key: String(uuid.prefix(32)), iv: String(uuid.prefix(16)))
let ciphertext = try aes.encrypt(Array(token.utf8))
let encrypttext = ciphertext.toHexString()
return encrypttext
}
catch {
return "error"
}
}
I tried to do something with CryptoJS with the codes from the site below, but it didn't work like the codes in Node.js.
https://embed.plnkr.co/0VPU1zmmWC5wmTKPKnhg/
EDIT2:
I've been trying different things but couldn't quite figure it out. I get an error when I add PBKDF2. I don't fully understand the problem.
var password = "6268890F-9B58-484C-8CDC-34F9C6A9";
var iv = "6268890F-9B58-48";
var cipher = "79a247e48ac27ed33ca3f1919067fa64";
/*
var key = CryptoJS.PBKDF2(password, {
keySize: 32
});
*/
var dec= CryptoJS.enc.Hex.parse(cipher);
const decrypted = CryptoJS.AES.decrypt({
ciphertext: dec
},
password, {
iv: iv,
mode: CryptoJS.mode.CBC,
padding: CryptoJS.pad.Pkcs7
});
console.log(decrypted.toString(CryptoJS.enc.Utf8));
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/3.1.2/rollups/aes.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/3.1.2/rollups/pbkdf2.js"></script>

CryptoJS uses WordArrays, so that key, IV and ciphertext have to be converted accordingly. For this purpose the appropriate encoders have to be applied. Furthermore decrypt() expects the ciphertext as CipherParams object.
This results in the following possible CryptoJS implementation:
var ciphertext = "79a247e48ac27ed33ca3f1919067fa64";
var key = "6268890F-9B58-484C-8CDC-34F9C6A9";
var iv = "6268890F-9B58-48";
var ciphertextWA = CryptoJS.enc.Hex.parse(ciphertext);
var keyWA = CryptoJS.enc.Utf8.parse(key);
var ivWA = CryptoJS.enc.Utf8.parse(iv);
var ciphertextCP = { ciphertext: ciphertextWA };
var decrypted = CryptoJS.AES.decrypt(
ciphertextCP,
keyWA,
{ iv: ivWA }
);
console.log(decrypted.toString(CryptoJS.enc.Utf8)); // Apple
<script src="https://cdnjs.cloudflare.com/ajax/libs/crypto-js/4.0.0/crypto-js.min.js"></script>
which is functionally identical to the posted NodeJS code that also successfully decrypts the test data.
Regarding the question asked in the comment about the encodings:
In general, the decryption side must have knowledge of the encodings used for encryption. However, in this case the encodings can be derived from the posted NodeJS code:
For decryption, the input encoding of the ciphertext is specified as 'hex', see decipher.update().
key and iv are defined as strings which are UTF-8 encoded, see crypto.createDecipheriv().
Also, the data used is consistent with these conclusions.
Note that for security reasons a static IV may not be used. Instead, a random IV must be generated for each encryption.
Also, no password may be applied as key, even if it has the right length. If a password is to be used, a key derivation is necessary, e.g. with PBKDF2.
For test purposes, the data is of course enough.

CryptoJS to Pycrypto AES [duplicate]

I have a password which is encrypt from JavaScript via
var password = 'sample'
var passphrase ='sample_passphrase'
CryptoJS.AES.encrypt(password, passphrase)
Then I tried to decrypt the password comes from JavaScript in Python:
from Crypto.Cipher import AES
import base64
PADDING = '\0'
pad_it = lambda s: s+(16 - len(s)%16)*PADDING
key = 'sample_passphrase'
iv='11.0.0.101' #------> here is my question, how can I get this iv to restore password, what should I put here?
key=pad_it(key) #------> should I add padding to keys and iv?
iv=pad_it(iv) ##
source = 'sample'
generator = AES.new(key, AES.MODE_CFB,iv)
crypt = generator.encrypt(pad_it(source))
cryptedStr = base64.b64encode(crypt)
print cryptedStr
generator = AES.new(key, AES.MODE_CBC,iv)
recovery = generator.decrypt(crypt)
print recovery.rstrip(PADDING)
I checked JS from browser console, it shows IV in CryptoJS.AES.encrypt(password, passphrase) is a object with some attributes( like sigBytes:16, words: [-44073646, -1300128421, 1939444916, 881316061]). It seems generated randomly.
From one web page, it tells me that JS has two way to encrypt password
(reference link ):
a. crypto.createCipher(algorithm, password)
b. crypto.createCipheriv(algorithm, key, iv)
What I saw in JavaScript should be option a. However, only option b is equivalent to AES.new() in python.
The questions are:
How can I restore this password in Python without changing JavaScript code?
If I need IV in Python, how can I get it from the password that is used in JavaScript?

You will have to implement OpenSSL's EVP_BytesToKey, because that is what CryptoJS uses to derive the key and IV from the provided password, but pyCrypto only supports the key+IV type encryption. CryptoJS also generates a random salt which also must be send to the server. If the ciphertext object is converted to a string, then it uses automatically an OpenSSL-compatible format which includes the random salt.
var data = "Some semi-long text for testing";
var password = "some password";
var ctObj = CryptoJS.AES.encrypt(data, password);
var ctStr = ctObj.toString();
out.innerHTML = ctStr;
<script src="https://cdn.rawgit.com/CryptoStore/crypto-js/3.1.2/build/rollups/aes.js"></script>
<div id="out"></div>
Possible output:
U2FsdGVkX1+ATH716DgsfPGjzmvhr+7+pzYfUzR+25u0D7Z5Lw04IJ+LmvPXJMpz
CryptoJS defaults to 256 bit key size for AES, PKCS#7 padding and CBC mode. AES has a 128 bit block size which is also the IV size. This means that we have to request 32+16 = 48 byte from EVP_BytesToKey. I've found a semi-functional implementation here and extended it further.
Here is the full Python (tested with 2.7 and 3.4) code, which is compatible with CryptoJS:
from Cryptodome import Random
from Cryptodome.Cipher import AES
import base64
from hashlib import md5
BLOCK_SIZE = 16
def pad(data):
length = BLOCK_SIZE - (len(data) % BLOCK_SIZE)
return data + (chr(length)*length).encode()
def unpad(data):
return data[:-(data[-1] if type(data[-1]) == int else ord(data[-1]))]
def bytes_to_key(data, salt, output=48):
# extended from https://gist.github.com/gsakkis/4546068
assert len(salt) == 8, len(salt)
data += salt
key = md5(data).digest()
final_key = key
while len(final_key) < output:
key = md5(key + data).digest()
final_key += key
return final_key[:output]
def encrypt(message, passphrase):
salt = Random.new().read(8)
key_iv = bytes_to_key(passphrase, salt, 32+16)
key = key_iv[:32]
iv = key_iv[32:]
aes = AES.new(key, AES.MODE_CBC, iv)
return base64.b64encode(b"Salted__" + salt + aes.encrypt(pad(message)))
def decrypt(encrypted, passphrase):
encrypted = base64.b64decode(encrypted)
assert encrypted[0:8] == b"Salted__"
salt = encrypted[8:16]
key_iv = bytes_to_key(passphrase, salt, 32+16)
key = key_iv[:32]
iv = key_iv[32:]
aes = AES.new(key, AES.MODE_CBC, iv)
return unpad(aes.decrypt(encrypted[16:]))
password = "some password".encode()
ct_b64 = "U2FsdGVkX1+ATH716DgsfPGjzmvhr+7+pzYfUzR+25u0D7Z5Lw04IJ+LmvPXJMpz"
pt = decrypt(ct_b64, password)
print("pt", pt)
print("pt", decrypt(encrypt(pt, password), password))
Similar code can be found in my answers for Java and PHP.
JavaScript AES encryption in the browser without HTTPS is simple obfuscation and does not provide any real security, because the key must be transmitted alongside the ciphertext.
[UPDATE]:
You should use pycryptodome instead of pycrypto because pycrypto(latest pypi version is 2.6.1) no longer maintained and it has vulnerabilities CVE-2013-7459 and CVE-2018-6594 (CVE warning reported by github). I choose pycryptodomex package here(Cryptodome replace Crypto in code) instead of pycryptodome package to avoid conflict name with Crypto from pycrypto package.

Encrypt in python - decrypt in Javascript

I have need to simply encrypt some text in python and being able to decrypt in JavaScrypt.
So far I have in python:
from Crypto import Random
from Crypto.Cipher import AES
import base64
BLOCK_SIZE = 16
key = "1234567890123456" # want to be 16 chars
textToEncrypt = "This is text to encrypt"
def encrypt(message, passphrase):
# passphrase MUST be 16, 24 or 32 bytes long, how can I do that ?
IV = Random.new().read(BLOCK_SIZE)
aes = AES.new(passphrase, AES.MODE_CFB, IV)
return base64.b64encode(aes.encrypt(message))
def decrypt(encrypted, passphrase):
IV = Random.new().read(BLOCK_SIZE)
aes = AES.new(passphrase, AES.MODE_CFB, IV)
return aes.decrypt(base64.b64decode(encrypted))
print encrypt( textToEncrypt, key )
this is producing text: ZF9as5JII5TlqcB5tAd4sxPuBXd5TrgE
in JavaScript:
<script src="http://crypto-js.googlecode.com/svn/tags/3.1.2/build/rollups/aes.js"></script>
<script>
var decrypted = CryptoJS.AES.decrypt( "ZF9as5JII5TlqcB5tAd4sxPuBXd5TrgE", "1234567890123456");
console.log ( decrypted.toString( CryptoJS.enc.Utf8 ) );
</script>
however it does not produce original string (empty string instead).
What I am doing wrong ?
Is it focusing on AES is a best idea - I will be happy if I have some kind of encryption that will blur data.

There are many problems with your Python code and CryptoJS code:
You use a random IV to encrypt some plaintext in Python. If you want to retrieve that plaintext, you need to use the same IV during decryption. The plaintext cannot be recovered without the IV. Usually the IV is simply prepended to the ciphertext, because it doesn't have to be secret. So you need to read the IV during decryption and not generate a new one.
You use CBC mode in CryptoJS (default) instead of CFB mode. The mode has to be the same. The other tricky part is that CFB mode is parametrized with a segment size. PyCrypto uses by default 8-bit segments (CFB8), but CryptoJS is only implemented for fixed segments of 128-bit (CFB128). Since the PyCrypto version is variable, you need to change that.
The CryptoJS decrypt() function expects as ciphertext either an OpenSSL formatted string or a CipherParams object. Since you don't have an OpenSSL formatted string, you have to convert the ciphertext into an object.
The key for CryptoJS is expected to be a WordArray and not a string.
Use the same padding. PyCrypto doesn't pad the plaintext if CFB8 is used, but padding is needed when CFB128 is used. CryptoJS uses PKCS#7 padding by default, so you only need to implement that padding in python.
Python code (for version 2):
def pad(data):
length = 16 - (len(data) % 16)
return data + chr(length)*length
def unpad(data):
return data[:-ord(data[-1])]
def encrypt(message, passphrase):
IV = Random.new().read(BLOCK_SIZE)
aes = AES.new(passphrase, AES.MODE_CFB, IV, segment_size=128)
return base64.b64encode(IV + aes.encrypt(pad(message)))
def decrypt(encrypted, passphrase):
encrypted = base64.b64decode(encrypted)
IV = encrypted[:BLOCK_SIZE]
aes = AES.new(passphrase, AES.MODE_CFB, IV, segment_size=128)
return unpad(aes.decrypt(encrypted[BLOCK_SIZE:]))
JavaScript code:
<script src="https://cdn.rawgit.com/CryptoStore/crypto-js/3.1.2/build/rollups/aes.js"></script>
<script src="https://cdn.rawgit.com/CryptoStore/crypto-js/3.1.2/build/components/mode-cfb-min.js"></script>
<script>
var base64ciphertextFromPython = "...";
var ciphertext = CryptoJS.enc.Base64.parse(base64ciphertextFromPython);
// split iv and ciphertext
var iv = ciphertext.clone();
iv.sigBytes = 16;
iv.clamp();
ciphertext.words.splice(0, 4); // delete 4 words = 16 bytes
ciphertext.sigBytes -= 16;
var key = CryptoJS.enc.Utf8.parse("1234567890123456");
// decryption
var decrypted = CryptoJS.AES.decrypt({ciphertext: ciphertext}, key, {
iv: iv,
mode: CryptoJS.mode.CFB
});
console.log ( decrypted.toString(CryptoJS.enc.Utf8));
</script>
Other considerations:
It seems that you want to use a passphrase as a key. Passphrases are usually human readable, but keys are not. You can derive a key from a passphrase with functions such as PBKDF2, bcrypt or scrypt.
The code above is not fully secure, because it lacks authentication. Unauthenticated ciphertexts may lead to viable attacks and unnoticed data manipulation. Usually the an encrypt-then-MAC scheme is employed with a good MAC function such as HMAC-SHA256.

(1 Year later but I hope this works for someone)
First of all, thanks Artjom B. your post helps me a lot. And Like OP, I have the same same problem Python server endonding and Javascript client decoding. This was my solution:
Python 3.x (Server)
I used an excplicit PKCS7 encode for padding, why? because I want to be sure Im using the same padding enconding and decoding, this is the link where I found it http://programmerin.blogspot.com.co/2011/08/python-padding-with-pkcs7.html .
Then, like Artjom B. said, be sure about your segment size, IV size and AES mode (CBC for me),
This is the code:
def encrypt_val(clear_text):
master_key = '1234567890123456'
encoder = PKCS7Encoder()
raw = encoder.encode(clear_text)
iv = Random.new().read( 16 )
cipher = AES.new( master_key, AES.MODE_CBC, iv, segment_size=128 )
return base64.b64encode( iv + cipher.encrypt( raw ) )
Note than your are enconding on base64 the concatenation of IV and encryption data.
Javascript (client)
function decryptMsg (data) {
master_key = '1234567890123456';
// Decode the base64 data so we can separate iv and crypt text.
var rawData = atob(data);
// Split by 16 because my IV size
var iv = rawData.substring(0, 16);
var crypttext = rawData.substring(16);
//Parsers
crypttext = CryptoJS.enc.Latin1.parse(crypttext);
iv = CryptoJS.enc.Latin1.parse(iv);
key = CryptoJS.enc.Utf8.parse(master_key);
// Decrypt
var plaintextArray = CryptoJS.AES.decrypt(
{ ciphertext: crypttext},
key,
{iv: iv, mode: CryptoJS.mode.CBC, padding: CryptoJS.pad.Pkcs7}
);
// Can be Utf8 too
output_plaintext = CryptoJS.enc.Latin1.stringify(plaintextArray);
console.log("plain text : " + output_plaintext);
}
One of my main problem was keep in mind all kind of encoding and decoding data, for example, I didn't know that the master_key on client side was to be parse with Utf8.

//First pip install pycryptodome -- (pycrypto is obsolete and gives issues)
// pip install pkcs7
from Crypto import Random
from Crypto.Cipher import AES
import base64
from pkcs7 import PKCS7Encoder
from app_settings.views import retrieve_settings # my custom settings
app_secrets = retrieve_settings(file_name='secrets');
def encrypt_data(text_data):
#limit to 16 bytes because my encryption key was too long
#yours could just be 'abcdefghwhatever'
encryption_key = app_secrets['ENCRYPTION_KEY'][:16];
#convert to bytes. same as bytes(encryption_key, 'utf-8')
encryption_key = str.encode(encryption_key);
#pad
encoder = PKCS7Encoder();
raw = encoder.encode(text_data) # Padding
iv = Random.new().read(AES.block_size ) #AES.block_size defaults to 16
# no need to set segment_size=BLAH
cipher = AES.new( encryption_key, AES.MODE_CBC, iv )
encrypted_text = base64.b64encode( iv + cipher.encrypt( str.encode(raw) ) )
return encrypted_text;

CryptoJS and Pycrypto working together

I'm encrypting a string in a web application using CryptoJS (v 2.3), and I need to decrypt it on the server in Python, so I'm using PyCrypto. I feel like I'm missing something because I can't can it working.
Here's the JS:
Crypto.AES.encrypt('1234567890123456', '1234567890123456',
{mode: new Crypto.mode.CBC(Crypto.pad.ZeroPadding)})
// output: "wRbCMWcWbDTmgXKCjQ3Pd//aRasZ4mQr57DgTfIvRYE="
The python:
from Crypto.Cipher import AES
import base64
decryptor = AES.new('1234567890123456', AES.MODE_CBC)
decryptor.decrypt(base64.b64decode("wRbCMWcWbDTmgXKCjQ3Pd//aRasZ4mQr57DgTfIvRYE="))
# output: '\xd0\xc2\x1ew\xbb\xf1\xf2\x9a\xb9\xb6\xdc\x15l\xe7\xf3\xfa\xed\xe4\xf5j\x826\xde(m\xdf\xdc_\x9e\xd3\xb1'

Here is a version with CryptoJS 3.1.2. Always beware of the following things (use the same in both languages):
Mode of operation (CBC in this case)
Padding (Zero Padding in this case; better use PKCS#7 padding)
Key (the same derivation function or clear key)
Encoding (same encoding for key, plaintext, ciphertext, ...)
IV (generated during encryption, passed for decryption)
If a string is passed as the key argument to the CryptoJS encrypt() function, the string is used to derive the actual key to be used for encryption. If you wish to use a key (valid sizes are 16, 24 and 32 byte), then you need to pass it as a WordArray.
The result of the CryptoJS encryption is an OpenSSL formatted ciphertext string. To get the actual ciphertext from it, you need to access the ciphertext property on it.
The IV must be random for each encryption so that it is semantically secure. That way attackers cannot say whether the same plaintext that was encrypted multiple times is actually the same plaintext when only looking at the ciphertext.
Below is an example that I have made.
JavaScript:
var key = CryptoJS.enc.Utf8.parse('1234567890123456'); // TODO change to something with more entropy
function encrypt(msgString, key) {
// msgString is expected to be Utf8 encoded
var iv = CryptoJS.lib.WordArray.random(16);
var encrypted = CryptoJS.AES.encrypt(msgString, key, {
iv: iv
});
return iv.concat(encrypted.ciphertext).toString(CryptoJS.enc.Base64);
}
function decrypt(ciphertextStr, key) {
var ciphertext = CryptoJS.enc.Base64.parse(ciphertextStr);
// split IV and ciphertext
var iv = ciphertext.clone();
iv.sigBytes = 16;
iv.clamp();
ciphertext.words.splice(0, 4); // delete 4 words = 16 bytes
ciphertext.sigBytes -= 16;
// decryption
var decrypted = CryptoJS.AES.decrypt({ciphertext: ciphertext}, key, {
iv: iv
});
return decrypted.toString(CryptoJS.enc.Utf8);
}
Python 2 code with pycrypto:
BLOCK_SIZE = 16
key = b"1234567890123456" # TODO change to something with more entropy
def pad(data):
length = BLOCK_SIZE - (len(data) % BLOCK_SIZE)
return data + chr(length)*length
def unpad(data):
return data[:-ord(data[-1])]
def encrypt(message, key):
IV = Random.new().read(BLOCK_SIZE)
aes = AES.new(key, AES.MODE_CBC, IV)
return base64.b64encode(IV + aes.encrypt(pad(message)))
def decrypt(encrypted, key):
encrypted = base64.b64decode(encrypted)
IV = encrypted[:BLOCK_SIZE]
aes = AES.new(key, AES.MODE_CBC, IV)
return unpad(aes.decrypt(encrypted[BLOCK_SIZE:]))
Warning: Keep in mind that both python2 and pycrypto are obsolete, so the code has to be adjusted to fit python3 and pycryptodome.
Other considerations:
It seems that you want to use a passphrase as a key. Passphrases are usually human readable, but keys are not. You can derive a key from a passphrase with functions such as PBKDF2, bcrypt or scrypt.
The code above is not fully secure, because it lacks authentication. Unauthenticated ciphertexts may lead to viable attacks and unnoticed data manipulation. Usually the an encrypt-then-MAC scheme is employed with a good MAC function such as HMAC-SHA256.

I had to port a Javascript implementation of AES encryption/decryption which was using crypto-js library, to Python3.
Basically, my approach was to run the debugger on the existing JS code and look at variables getting filled in each step. I was able to figure out the equivalent methods to do the same in python as well.
Here is how I ported it using pycryptodome library which has some useful features.
AES.js
var CryptoJS = require("crypto-js");
var Base64 = require("js-base64");
function decrypt(str, secret) {
try {
var _strkey = Base64.decode(secret);
var reb64 = CryptoJS.enc.Hex.parse(str);
var text = reb64.toString(CryptoJS.enc.Base64);
var Key = CryptoJS.enc.Base64.parse(_strkey.split(",")[1]); //secret key
var IV = CryptoJS.enc.Base64.parse(_strkey.split(",")[0]); //16 digit
var decryptedText = CryptoJS.AES.decrypt(text, Key, { keySize: 128 / 8, iv: IV, mode: CryptoJS.mode.CBC, padding: CryptoJS.pad.Pkcs7 });
return decryptedText.toString(CryptoJS.enc.Utf8); //binascii.unhexlify(decryptedText)
} catch (e) {
console.log("Error", e)
}
}
function encrypt(str, secret) {
str = Math.random().toString(36).substring(2, 10) + str;
var _strkey = Base64.decode(secret);
_strkey.split(",");
var text = CryptoJS.enc.Utf8.parse(str);
var Key = CryptoJS.enc.Base64.parse(_strkey.split(",")[1]); //secret key
var IV = CryptoJS.enc.Base64.parse(_strkey.split(",")[0]); //16 digit
var encryptedText = CryptoJS.AES.encrypt(text, Key, { keySize: 128 / 8, iv: IV, mode: CryptoJS.mode.CBC, padding: CryptoJS.pad.Pkcs7 });
var b64 = encryptedText.toString();
var e64 = CryptoJS.enc.Base64.parse(b64);
var eHex = e64.toLocaleString(CryptoJS.enc.Hex);
return eHex.toUpperCase();
}
const secret = "V1VWTVRFOVhJRk5WUWsxQlVrbE9SUT09LFRrOUNUMFJaSUZkSlRFd2dTMDVQVnc9PQ=="
const data = "THIS IS MY SECRET MESSAGE!"
encData = EncryptText2(data, secret)
decData = DecryptText2(encData, secret)
console.log("encryptedData", encData)
console.log("decryptedData", decData)
AESify.py
import string
import random
import base64
import binascii
from Crypto.Cipher import AES
from Crypto.Util.Padding import pad, unpad
class AESify:
def __init__(self, key=None, iv=None,secret = None, block_len=16, salt_len= 8):
self.key = key
self.iv = iv
self.salt_len = salt_len
self.block_len = block_len
self.mode = AES.MODE_CBC
if(secret):
self.useSecret(secret)
if(self.key is None and self.iv is None):
raise Exception("No key , IV pair or secret provided")
#staticmethod
def makeSecret(key, iv):
if(len(key) % 8 != 0):
raise Exception("Key length must be a mutliple of 8")
if(len(iv) % 8 != 0):
raise Exception("Initial vector must be a multiple of 8")
key64 = base64.b64encode(key.encode()).decode()
iv64 = base64.b64encode(iv.encode()).decode()
secret = iv64 + "," + key64
secret64 = base64.b64encode(secret.encode()).decode()
return secret64
def useSecret(self, secret):
iv64, key64 = base64.b64decode(secret).decode().split(",") # decode and convert to string
self.iv = base64.b64decode(iv64)
self.key = base64.b64decode(key64)
return self
def encrypt(self, text):
text = self.add_salt(text, self.salt_len)
cipher = AES.new(self.key, self.mode, self.iv)
text = cipher.encrypt(pad(text.encode('utf-8'), self.block_len))
return binascii.hexlify(text).decode()
def decrypt(self, data):
text = binascii.unhexlify(data) # UNHEX and convert the encrypted data to text
cipher = AES.new(self.key, self.mode, self.iv)
return unpad(cipher.decrypt(text), self.block_len).decode('utf-8')[self.salt_len:]
def add_salt(self, text, salt_len):
# pre-pad with random salt
salt = ''.join(random.choice(string.ascii_letters + string.digits) for _ in range(salt_len))
text = salt + text
return text
main.py
from AESify import AESify
key , iv = "NOBODY WILL KNOW", "YELLOW SUBMARINE"
# contains IV and key
secret = AESify.makeSecret(key, iv)
aes = AESify(secret= secret, block_len=16, salt_len=4)
msg = "THIS IS MY SECRET MESSAGE"
encrypted = aes.encrypt(msg)
decrypted = aes.decrypt(encrypted)
print(f"{secret=}")
print(f"{encrypted=}")
print(f"{decrypted=}")

Note : salt , iv , padding should be same in js and python
generate salt and iv value and convert it into a byte string uisng CryptoJS.enc.Utf8.parse()
js file
var encrypted = CryptoJS.AES.encrypt(JSON.stringify(json_data), CryptoJS.enc.Utf8.parse(data['salt']) , { iv: CryptoJS.enc.Utf8.parse(data['iv']) , mode: CryptoJS.mode.CBC , padding: CryptoJS.pad.Pkcs7});
en_data = encrypted.ciphertext.toString(CryptoJS.enc.Base64)
send this encrypted data to the python file
python file
from Crypto.Util.Padding import pad, unpad
ct = request.POST['encrypted_data']
data = base64.b64decode(ct)
cipher1 = AES.new(salt, AES.MODE_CBC, iv)
pt = unpad(cipher2.decrypt(data), 16)
data = json.loads(pt.decode('utf-8'))
pad and upad in pycrypto by default uses pkcs#7
salt and iv value should in byte string