I have a question about how to loop an object in typescript and to get the value that I want.
my object looks like this:
mockdata = {
"subobj1": {
"order": 1
"value": "abc"
},
"subobj2": {
"order": 2
"value": "aaa"
},
...
}
I want to loop this object and only get the subobject, if order == 1
what I expect is to get object
"subobj1": {
"order": 1
"value": "abc"
}
any solutions?
Just loop through the object using for in syntax and find the respective value!
const mockdata = {
"subobj1": {
"order": 1,
"value": "abc"
},
"subobj2": {
"order": 2,
"value": "aaa"
},
}
let output;
for (const property in mockdata) {
if (mockdata[property].order === 1) {
output = {
[property]: mockdata[property]
}
break;
}
}
console.log('result', output);
Here's a pretty slim way to do it. I usually use Object.keys or .entries to all my obj for loops
const arrOfOrderEqualToOne = Object.entries(mockdata).filter(([key, value]) => value.order === 1));
Try this
let mockdata = {
"subobj1": {
"order": 1,
"value": "abc"
},
"subobj2": {
"order": 2,
"value": "aaa"
},
}
let temp;
Object.keys(mockdata).forEach(key=>{
if(mockdata[key].order==1){
temp=mockdata[key]
}
})
console.log(temp)
Related
I have input data like this:
[{
"name": "outField2",
"value": "something"
}, {
"name": "outField3[index].outField4",
"value": "something"
}, {
"name": "outField3[index].outField5",
"value": "something"
}, {
"name": "outField3[index].outField6.outField7",
"value": "something"
}]
I am trying to achieve an output like this based on substring '[index]' (i.e. if that substring is not present then that element should be an object instead of an array):
{
"outField2": "something",
"outField3[index]": [{
"outField4": "something",
"outField5": "something",
"outField6": {
"outField7": "something"
}
}]
}
My current code (below) is able to produce the outField3 as an object if there is no substring '[index]' but I'm unable to find a good solution to generate it as an array in the presence of the substring. Can someone help out? I've tried a few options but none gives me the desired result.
function doThis(item, index) {
let path = map[index].name.split(".");
if (path.length > 1) {
createNestedObject(mapOutput, path, map[index].value);
} else {
mapOutput[map[index].name] = map[index].value;
};
};
function createNestedObject(element, path, value) {
var lastElement = arguments.length === 3 ? path.pop() : false;
for (var i = 0; i < path.length; i++) {
if (path[i].includes('[index]')) {
/*some logic here to push the child elements
that do not contain [index] as an array into
the ones that contain [index]*/
} else {
element = element[path[i]] = element[path[i]] || {};
};
}
if (lastElement) element = element[lastElement] = value;
return element;
};
const map = [{
"name": "outField2",
"value": "something"
}, {
"name": "outField3[index].outField4",
"value": "something"
}, {
"name": "outField3[index].outField5",
"value": "something"
}, {
"name": "outField3[index].outField6.outField7",
"value": "something"
}];
let mapOutput = {};
map.forEach(doThis);
let mapOutputJSON = JSON.stringify(mapOutput, null, 2);
console.log(mapOutputJSON);
.as-console-wrapper { min-height: 100%!important; top: 0; }
you can do something like this
const data = [{
"name": "outField2",
"value": "something"
},
{
"name": "outField3[index].outField4",
"value": "something"
},
{
"name": "outField3[index].outField5",
"value": "something"
},
{
"name": "outField3[index].outField6.outField7",
"value": "something"
}
]
const buildObject = (paths, value, obj) => {
if (paths.length === 0) {
return value
}
const [path, ...rest] = paths
if(path.includes('[index]')) {
return {
...obj,
[path]: [buildObject(rest, value, (obj[path] || [])[0] || {})]
}
}
return {
...obj,
[path]: buildObject(rest, value, obj[path] || {})
}
}
const result = data.reduce((res, {
name,
value
}) => buildObject(name.split('.'), value, res), {})
console.log(result)
A possible generic approach which in my opinion also assigns the correct type of the OP's "outField3[index]" property (object type instead of an Array instance) is based on reduce where ...
the outer loop iterates the array of { name, value } items
by executing a single function accumulateObjectTypeFromPathAndValue where ...
this function does split each name-value into an array of object-path keys which then gets iterated by the inner reduce method where the passed object programmatically accumulates nested key-value pairs.
function accumulateObjectTypeFromPathAndValue(root, path, value) {
path
.split('.')
.reduce((obj, key, idx, arr) => {
if (!obj.hasOwnProperty(key)) {
Object.assign(obj, {
[ key ]: (idx === arr.length - 1)
? value
: {},
});
}
return obj[key];
}, root);
return root;
}
console.log(
[{
"name": "outField2",
"value": "something"
}, {
"name": "outField3[index].outField4",
"value": "something"
}, {
"name": "outField3[index].outField5",
"value": "something"
}, {
"name": "outField3[index].outField6.outField7",
"value": "something"
}].reduce((result, { name: path, value }) => {
return accumulateObjectTypeFromPathAndValue(result, path, value);
}, {})
);
.as-console-wrapper { min-height: 100%!important; top: 0; }
The above implementation of the 2nd reducer function then could be changed according to the OP's custom array-type requirements ...
function accumulateCustomObjectTypeFromPathAndValue(root, path, value) {
path
.split('.')
.reduce((obj, key, idx, arr) => {
if (!obj.hasOwnProperty(key)) {
Object.assign(obj, {
[ key ]: (idx === arr.length - 1)
? value
: {},
});
if (key.endsWith('[index]')) {
obj[ key ] = [obj[ key ]];
}
}
return Array.isArray(obj[ key ])
//? obj[ key ].at(-1) // last item.
? obj[ key ][obj[ key ].length - 1] // last item.
: obj[ key ];
}, root);
return root;
}
console.log(
[{
"name": "outField2",
"value": "something"
}, {
"name": "outField3[index].outField4",
"value": "something"
}, {
"name": "outField3[index].outField5",
"value": "something"
}, {
"name": "outField3[index].outField6.outField7",
"value": "something"
}].reduce((result, { name: path, value }) => {
return accumulateCustomObjectTypeFromPathAndValue(result, path, value);
}, {})
);
.as-console-wrapper { min-height: 100%!important; top: 0; }
I have a data array
var data=[{
"key": "KUZEY",
"items": [
{
"key": "MARMARA",
"items": [
{
"key": "T100",
"items": [
{
"Ref": 1,
"ApprovedReserveQuantity": 1
}
]
}
]
},
{
"key": "MARMARA 2",
"items": [
{
"key": "T100",
"items": [
{
"Ref": 2,
"ApprovedReserveQuantity": 1
}
]
}
]
}
] }]
İ want to get items when i call function. how can do that recursiveMethod?
groupedItems=recursiveMethod(data)
groupedItems==>[{"Ref": 1,"ApprovedReserveQuantity": 1},{"Ref": 2,"ApprovedReserveQuantity": 1}]
groupedItems:any[]=[];
recursiveMethod(element){
if(element.items==null)
this.groupedItems.push(element)
if (element.items != null){
let i;
for(i=0; i < element.items.length; i++){
this.recursiveMethod(element.items[i]);
}
}
}
it's worked
Couldn't find any 'key' checking in your answer.
Even though I don't trust my function completely, and am confused for as why it worked, It can be reusable if you tweak/adjust it.
const extractInnermostByKey = (data, targetKey, res = []) => {
data.forEach((obj) => {
for (let key of Object.keys(obj)) {
if (key === targetKey) {
// console.log(res); observe res
res.shift();
res.push(...obj[key]);
return extractInnermostByKey(res, targetKey, res);
}
}
});
return res;
};
const groupedItems = extractInnermostByKey(data, 'items');
console.log(groupedItems);
This question already has answers here:
How to remove all duplicates from an array of objects?
(77 answers)
Closed 3 years ago.
How to remove complete record of same object in array please help me this, I am using below funtion but its only remove one value I want remove complete object of same object
var data = [{
"QuestionOid": 1,
"name": "hello",
"label": "world"
}, {
"QuestionOid": 2,
"name": "abc",
"label": "xyz"
}, {
"QuestionOid": 1,
"name": "hello",
"label": "world"
}];
function removeDumplicateValue(myArray) {
var newArray = [];
$.each(myArray, function (key, value) {
var exists = false;
$.each(newArray, function (k, val2) {
if (value.QuestionOid == val2.QuestionOid) { exists = true };
});
if (exists == false && value.QuestionOid != undefined) { newArray.push(value); }
});
return newArray;
}
I want result like this
[{
"QuestionOid": 2,
"name": "abc",
"label": "xyz"
}]
You can use reduce.
var data = [{"QuestionOid": 1,"name": "hello","label": "world"}, {"QuestionOid": 2,"name": "abc","label": "xyz"}, {"QuestionOid": 1,"name": "hello","label": "world"}];
let op = data.reduce((op,inp)=>{
if(op[inp.QuestionOid]){
op[inp.QuestionOid].count++
} else {
op[inp.QuestionOid] = {...inp,count:1}
}
return op
},{})
let final = Object.values(op).reduce((op,{count,...rest})=>{
if(count === 1){
op.push(rest)
}
return op
},[])
console.log(final)
Do with Array#filter.Filter the array matching QuestionOid value equal to 1
var data = [{ "QuestionOid": 1, "name": "hello", "label": "world" }, { "QuestionOid": 2, "name": "abc", "label": "xyz" }, { "QuestionOid": 1, "name": "hello", "label": "world" }]
var res = data.filter((a, b, c) => c.map(i => i.QuestionOid).filter(i => i == a.QuestionOid).length == 1)
console.log(res)
I have a set of checkboxes - which the user ticks on. The checkboxes pass some data an id and a name that i need later on for sorting. Because two objects are not equal even though they contain the same values I cant use Array.includes.
Here is an example of the data
[
{
"id": 9,
"name": "age_group_ids"
},
{
"id": 9,
"name": "age_group_ids"
},
{
"id": 9,
"name": "earnings_group_ids"
},
{
"id": 3,
"name": "earnings_group_ids"
},
]
This is the current function (which would work if the items were not objects
const submitFilterDetails = (value) => {
return async (dispatch,getState) => {
const currentArray = (getState().filter.filtersArray);
if(!currentArray.includes(value)) {
dispatch(addToFiltersArray(value))
} else {
dispatch(removeFromFiltersArray(value));
}
}
}
How can you sort this so I only have unique values
You can use find :
YourArray.find(obj => obj.id == value.id && obj.name == value.name);
const src = [
{
"id": 9,
"name": "age_group_ids"
},
{
"id": 9,
"name": "age_group_ids"
},
{
"id": 1,
"name": "earnings_group_ids"
},
]
const out = src.reduce((acc, curr) => acc.some(i => i.id === curr.id) ? acc : acc.concat([curr]) , [])
// the `out` variable has 2 unique items
I have an array from an API call.
var response = {
"data": {
"data": [{
"1": "Arun",
"index": "name"
}, {
"1": 70.78,
"index": "score"
}]
}
}
I connect to a lot of other API's and they return me a similar response but the keys change. Sometimes it might be
var response = {
"data": {
"data": [{
"values": "Harry",
"index": "name"
}, {
"values": 45,
"index": "score"
}]
}
}
var response = {
"data": {
"data": [{
"4": "Richard",
"index": "name"
}, {
"4": 98,
"index": "score"
}]
}
}
I would like to get an array like this.
[
{
name: 'Arun',
score: 70.78
}
]
This is what I did.
var response = {
"data": {
"data": [{
"1": "Arun",
"index": "name"
}, {
"1": 70.78,
"index": "score"
}]
}
}
const result = [];
const mappedData = _.map(response.data.data, (item) => {
return {
[item.index]: item[1]
};
});
const resultObject = _.reduce(mappedData, (result, currentObject) => {
for (const key in currentObject) {
if (currentObject.hasOwnProperty(key)) {
result[key] = currentObject[key];
}
}
return result;
}, {});
result.push(resultObject)
console.log(result)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>
So instead of hardcoding "1" or "values" in the map function, is there a more universal way to get the key and achieve the same result?
Thanks.
Use reduce rather than map, so you're updating the same object, not creating an array.
And since the property containing the value can vary, I use a loop to look for the first property that isn't named index, and use its value.
var response = {
"data": {
"data": [{
"1": "Arun",
"index": "name"
}, {
"1": 70.78,
"index": "score"
}]
}
}
const mappedData = response.data.data.reduce((acc, item) => {
var value;
// find the property that isn't named "item"
for (var i in item) {
if (i != "index") {
value = item[i];
break;
}
}
acc[item.index] = value;
return acc;
}, {});
console.log(mappedData)
There's no need for lodash for this, the built-in reduce function is fine (but _.reduce will work similarly).
Since you only care about the values of that object and it only has two keys you can do this quite easily in lodash with reduce & fromPairs:
var response = { "data": { "data": [{ "1": "Arun", "index": "name" }, { "1": 70.78, "index": "score" }] } }
const rv = (o) => _.reverse(_.values(o))
const r = _.reduce(response.data.data, (a,c) => _.fromPairs([rv(a), rv(c)]))
console.log(r)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.10/lodash.min.js"></script>
The same thing converted to ES6 would be:
var response = { "data": { "data": [{ "1": "Arun", "index": "name" }, { "1": 70.78, "index": "score" }] } }
const rv = (o) => Object.values(o).reverse() // reverse values
const fp = (arr) => arr.reduce((r, [k,v]) => (r[k] = v, r), {}) // from pairs
const result = response.data.data.reduce((a,c) => fp([rv(a), rv(c)]))
console.log(result)
The main idea here is to first get the object values in an array form, reverse them so the key & value are in the correct order and then reduce that array via from pairs to create the final object.
The main advantage of this approach is that we never deal with the object keys and only focus on the values which is what you really care about. This way the keys can be any value and it would still not matter.
You could try deleting the key-pair index and using the first value of the resulting object:
const mappedData = _.map(response.data.data, (item) => {
var tempObj = Object.assign({}, item)
var index = tempObj.index;
delete tempObj.index;
var otherData = Object.values(tempObj)[0];
return {
[index]: otherData
};
});
Just modified the #barmar approach. I have used Object.keys to get keys from object. This will remove the any hard-coded dependency.
var response = {
"data": {
"data": [{
"1": "Arun",
"index": "name"
}, {
"1": 70.78,
"index": "score"
}]
}
}
const mappedData = response.data.data.reduce((acc, item,i) => {
var key = Object.keys(item);
acc[item[key[1]]] = item[key[0]]
return acc ;
}, {});
console.log(mappedData)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>