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Put input text and submit button same line

I am writing a search box and search submission button, I try several way to make the button and text box in same line, but doesn't work. Here is my code.
return (
<Form onSubmit={submitHandler} inline>
<Form.Control
type='text'
name='q'
onChange={(e) => setKeyword(e.target.value)}
placeholder='Serach product'
className='mr-sm-2 ml-sm-5'
></Form.Control>
<Button type='submit' variant='btn btn-success' className='p-2'>
search
</Button>
</Form>
)
What I expect is
But what I have is
Reactjs version is ^17.0.1 in my package.jason file, but when I use npm info react in cmd it shows me react#18.1.0
Thanks the answer from Mr.Gandhi https://stackoverflow.com/a/72385731/19202374

Change the input and/or the button to be display: inline in the css
Or you can just put display flex on the parent container of the input and button.

Wrap your form elements in a div and give a className (ex: flex-container).
return (
<Form onSubmit={submitHandler} inline>
<div className="flex-container">
<Form.Control
type='text'
name='q'
onChange={(e) => setKeyword(e.target.value)}
placeholder='Serach product'
className='mr-sm-2 ml-sm-5'
></Form.Control>
<Button type='submit' variant='btn btn-success' className='p-2'>
search
</Button>
</div>
</Form>
)
After that add below css
.flex-container {
display: flex;
}

React From Group input field is not working

I attached dropdown items to my form group input field (image below). When I add onChange() key in order to get its value, I cannot write anything to input field. But when I remove onChange() key, it is working, I am able to write anything, but I need to get the value of input field. Is there any other way than onChange() key or any solution? Thank you in advance :)
Here is the my code:
<Form.Control
ref={ref}
onClick={e => {
e.preventDefault();
onClick(e);
}}
size="sm"
type="text"
className="search-or-jump shadow-none"
placeholder="Search or jump to..."
onChange={event => setSearchName(event.target.value)}
/>
{children}
</Form.Group>

You have to add value attributes, like
<Form.Control
ref={ref}
onClick={e => {
e.preventDefault();
onClick(e);
}}
size="sm"
type="text"
className="search-or-jump shadow-none"
placeholder="Search or jump to..."
value={searchName}
onChange={event => setSearchName(event.target.value)}
/>
{children}
</Form.Group>
Your code didn't have value attribule but you called 'value' on 'onChange' that why your code didn't work.

React final form - submit a wizard form on click of a radio button

I would like to submit a step of wizard form on click of radio button instead of classic submit button.
Radio component :
const Radio = ({ input, children }) => (
<label className="form-radio city">
<input {...input} />
<span className="radio-text">{children}</span>
</label>
)
My class :
<ProfileForm.Page>
{CITIES.map(({ name }) => (
<Field component={Radio} type="radio" name="city" key={name} value={name}>
{name}
</Field>
))}
<button type="submit"></button>
</ProfileForm.Page>
This worked when I use the submit button but I want to remove it and submit city directly on click on the radio button.

I tried to had an onChange event with "this.form.submit()" but I cannot acced to "form".
I have a parent component ProfileForm.jsx with :
<Form validate={this.validate} onSubmit={this.handleSubmit} initialValues={values}>
{({ handleSubmit, invalid, pristine, values }) => (
<form onSubmit={handleSubmit}>
{activePage}
</form>
)}
</Form>
and my radio buttons are on the "active page" City.jsx with the code of my first post

Formik onSubmit not registered within modal

I trying to do formik within Modal itself, however, onSubmit button doesn't registered with. The alert function alert("test"); should appear. Do I need to input the onChange event inside the phone div?
.
.
<Modal
show={this.state.testing}
onHide={this.onHide}
size="lg"
aria-labelledby="contained-modal-title-vcenter"
centered
>
<Modal.Header closeButton>
<Modal.Title id="contained-modal-title-vcenter">
Hello World
</Modal.Title>
</Modal.Header>
<Formik
onSubmit={({phone},{ setStatus, setSubmitting }) => {
alert("test");
)
render={({ errors, status, touched, isSubmitting }) => (
<Form>
<div className="form-group">
<label htmlFor="phone">phone</label>
<Field
name="phone"
type="text"
className={
"form-control" +
(errors.phone&& touched.phone? " is-invalid" : "")
}
/>
.
.
.
<button
type="submit"
className="btn btn-primary"
disabled={isSubmitting}
>Update</button>
Alert("test")

When you are using the Field component, formik handles input with the onChange event automatically for you. So you don't need to change that.
Please consider these two notes:
Form component should be imported from formik like this:
import { Form } from 'formik';
and your button should be inside it. something like this:
<Form>
.
.
.
<button
type="submit"
className="btn btn-primary"
disabled={isSubmitting}
>Update</button>
</Form>
if you still couldn't get the job done with these notes please share more of your code so i can help you.
please let me know if you still have any problem

Submit Form using Button in Parent Component in React

So I have to implement a form in modal, as you can see, the button in the modal are not the buttons in the form. I created the form as a child component of the modal. How can I submit the form using the button in the parent component. I am using React Semantic-UI react as my UI framework.
I think if I can hide the button in the form and trigger it using JavaScript. I think this might be achieved via getElementById, but is there a react way of doing it?
My current Modal looks like this:
<Modal open={this.props.open} onClose={this.props.onClose} size="small" dimmer={"blurring"}>
<Modal.Header> Edit Activity {this.props.name} </Modal.Header>
<Modal.Content>
<ActivityInfoForm/>
</Modal.Content>
<Modal.Actions>
<Button negative onClick={this.props.onClose}>
Cancel
</Button>
<Button positive
content='Submit'
onClick={this.makeActivityInfoUpdateHandler(this.props.activityId)} />
</Modal.Actions>
</Modal>
My form code looks like this:
<Form>
<Form.Group widths='equal'>
<Form.Input label='Activity Name' placeholder='eg. CIS 422' />
<Form.Input label='Activity End Date' placeholder='Pick a Date' />
</Form.Group>
<Form.Group widths='equal'>
<Form.Input label='Total Capacity' placeholder='eg. 30' />
<Form.Input label='Team Capacity' placeholder='eg. 3' />
</Form.Group>
</Form>

The simplest solution would be to use HTML form Attribute
Add "id" attribute to your form: id='my-form'
<Form id='my-form'>
<Form.Group widths='equal'>
<Form.Input label='Activity Name' placeholder='eg. CIS 422' />
<Form.Input label='Activity End Date' placeholder='Pick a Date' />
</Form.Group>
<Form.Group widths='equal'>
<Form.Input label='Total Capacity' placeholder='eg. 30' />
<Form.Input label='Team Capacity' placeholder='eg. 3' />
</Form.Group>
</Form>
Add the appropriate "form" attribute to the needed button outside of the form: form='my-form'
<Button positive form='my-form' content='Submit' value='Submit' />

What does your makeActivityInfoUpdateHandler function look like?
I assume you did it by the following way, and just continue adding more code to make it work for you:
1/ Add ref to your Form, then you can access the Form in the parent (Modal):
<Modal>
<Modal.Content>
<ActivityInfoForm ref="activityForm" />
</Modal.Content>
</Modal>
2/ Then in the makeActivityInfoUpdateHandler function:
makeActivityInfoUpdateHandler = (activityId) => {
// ...
this.refs.activityForm.getWrappedInstance().submit();
// ...
}
The above code is the way you should do, please post here some more details in case this doesn't work yet!
===========
EDITED VERSION BELOW: (after discussion with the author, and we together found a good way around!):
The idea now is put the ref on a button (this button has type="submit", and it belongs to the form), then when the button outside is clicked, we just need to call the "click()" function of the ref button [which is a smart thinking from the author himself]
(Actually, component from semantic-ui is a modified and improved version, no longer the standard form, so my previous way above may not work when it tries to submit the form, however, the below way will work)
The code will now look like:
1/ Add ref to the button on the form:
<Form onSubmit={ this.handleSubmit} >
<button style={{}} type='submit' ref={ (button) => { this.activityFormButton = button } } >Submit</button>
</Form>
2/ Then in the makeActivityInfoUpdateHandler function, trigger click() of the above button:
makeActivityInfoUpdateHandler = (activityId) => {
// ...
this.activityFormButton.click();
// ...
}

The selected answer was useful. But the method in it doesn't seem to work any longer. Here's how I went about it.
You can give a ref to the child component when it is being created.
<ChildComponent ref={this.childComponent}/>
And use it in the button's onClick method. (This is the code for the button)
<Button variant= "light" onClick={this.onClick}>
Submit
</Button>
(This is the onClick method)
onClick = (event) => {
this.childComponent.current.handleSubmit(event);
}
I'm calling a method in the child component called handleSubmit. It can look like this.
handleSubmit = (event)=> {
event.preventDefault();
//Your code here. For example,
alert("Form submitted");
}