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I'm trying to define the parameter firstname from the prompt but it shows that it's undefined and goes at the end of the template string.
'use strict';
const yearsret = (year, firstname) => {
const age = 2022 - year;
const retir = 60 - age;
return `${firstname} retires in ${retir} years`;
}
console.log(yearsret(prompt('Please enter your birth year')), (prompt('Please enter your Name')));
and the result
undefined retires in 27 years Ali
This is a typo. Your parenthesis () is in the incorrect spot. Try this:
console.log(yearsret(prompt('Please enter your birth year'), (prompt('Please enter your Name'))));
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Closed 11 months ago.
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I've got an array:
test = [{'id':'73','name':'bar', 'contact': [{'name':'barFoo','tel':'3333'}]},{'id':'45','name':'foo', 'contact':[]}]
I try to get contact.tel in first object with 'id':'73'
I'm using find method :
let contactTel = test.find(x => x.id === '73').contact.tel;
but it dosen't work. What I'm doing wrong ?
it should be like this
const test = [{'id':'73','name':'bar', 'contact': [{'name':'barFoo','tel':'3333'}]},{'id':'45','name':'foo', 'contact':[]}]
let contactTel = test.find(x => x.id === '73').contact[0].tel;
console.log(contactTel)
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Closed 2 years ago.
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I've was given this is a multiple choice JS question. I said [], I just wanted to check if this is correct and if not why?
Consider this if statement:
if (loggedIn) {
body_classes = ["user-active"];
}
Which pair of characters in this code is optional?
""
()
{}
[]
The optional characters are the braces {}
if (loggedIn) {
body_classes = ["user-active"];
}
is the same as
if (loggedIn)
body_classes = ["user-active"];
If you remove the square brackets then body_classes becomes a string rather than an array.
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Closed 7 years ago.
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I'm trying to use a function inside another function. Right now, setPanodatas() appears as not defined:
function setPoints(obj, prop) {
// Some code
if (unzippedNewPanodatas)
unzippedNewPanodatas = unzippedNewPanodatas.slice(scope.panodatas.length)
_.each(unzippedNewPanodatas, function(point) {
var Panodata = AV.Object.extend('PanoramaData')
var panodata = new Panodata()
obj[prop].push(setPanodatas(panodata.toJSON(), point))
})
}
function setPanodata(panodata, point) {
panodata.set('index', point.index)
panodata.set('x', offsetX(point.x))
panodata.set('y', offsetY(point.y))
panodata.set('roomModelId', scope.pano.id)
panodata.set('panoDataRotate', 0)
panodata.set('differentLayout', false)
panodata.set('panoCount', 6)
panodata.set('type', 'VRoom')
console.log('PANODATA', panodata)
return panodata
}
Why isn't setPanodata() visible inside setPoints()?
It is because setPanodatas is undefined.
Rather it is setPanodata, you added s.
function setPanodata(panodata, point)
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Closed 7 years ago.
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I've used this :
String.Prototype.left = function left(count){
return this.substr(0,count);
}
And apply it this way :
var string = "Hello Stack!";
console.log(string.left(5));
And the console tells me :
TypeError: example.left is not a function
console.log(example.left(5));
How can I fix it? And where is the problem?
String.prototype.left = function(index){
return this.substring(0,index);
}
var str = "Hello World";
console.log(str.left(5));
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Closed 8 years ago.
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Error is:
function (a){var b,c,d,e=this[0];{if(arguments.length)return d=m.isFunction(a),this.each(function(c){var e;1===this.nodeType&&(e=d?a.call(this,c,m(this).val()):a,null==e?e="":"number"==typeof e?e+="":m.isArray(e)&&(e=m.map(e,function(a){return null==a?"":a+""})),b=m.valHooks[this.type]||m.valHooks[this.nodeName.toLowerCase()],b&&"set"in b&&void 0!==b.set(this,e,"value")||(this.value=e))});if(e)return b=m.valHooks[e.type]||m.valHooks[e.nodeName.toLowerCase()],b&&"get"in b&&void 0!==(c=b.get(e,"value"))?c:(c=e.value,"string"==typeof c?c.replace(lc,""):null==c?"":c)}}
What I am trying to do is to catch a variable on Focus Out:
$('.field').focusout(function() {
var date = $('.field').val;
console.log(date);
//Do something else
});
The HTML for field is:
<input type="text" class="field" />
Just a Typo...
val is a function. Use val()
Yes I know this question is not worth an answer, but otherwise someone will just transplant the comment as their own answer :)