How to chain a promise wrapper around axios.request - javascript

I've this quick doubt that might be related to promise chaining but I'm not able to think about it clearly.
So basically, I've this function(myFn) that returns axios.request() which basically returns a promise, so i can now do myFn.then().catch() and it works, now what I want to do is to create a promise wrapper on top of that, which will resolve only when response.data.status =="somevalue", here response.data means the request was successful and a result came but now i want to resolve myFn only when response.data.status =="somevalue".


Since your function returns a promise, you can just use the promise's result in the .then callback. If the response.data.status isn't what you want, throw an error, otherwise return the response, thus resolving the promise:
myFn().then(response => {
if (response.data.status !== "somevalue") {
throw new Error("invalid status");
}
return response;
})
Edit: If you want to wrap this in a custom Promise, you could do something like this:
const myPromise = new Promise((resolve, reject)=>{
myFn().then(response => {
if (response.data.status !== "somevalue") {
reject("Invalid status");}
else{
resolve("somevalue");}
});
});
And then call this promise with callback functions for the fulfilled and rejected cases of the promise:
myPromise.then(handleSucess, handleFailure);
For reference see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise


You can try if this works for you. I am not sure though, if the throw here works as expected.
const axiosInstance = axios.create({
transformResponse: [function (data) {
if (data.status === "somevalue") {
return data;
}
throw new Error(`wrong status: ${data.status}`);
}],
});
Then use this axiosInstance to do your calls.
If this does not work, you could also give the axios response interceptors a try. How can you use axios interceptors.

Related

React: Promise resolves inside of async function but pending when trying to access it from outside [duplicate]

My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.

The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});

I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data

The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}

If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all

See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.

Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.

I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...

Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />

Im my case (JS) I forgot to add await

Always promises, but no results [duplicate]

My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.

The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});

I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data

The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}

If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all

See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.

Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.

I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...

Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />

Im my case (JS) I forgot to add await

Mapping a promise which returns foo, to another promise which returns bar?

I have a function which makes an XMLHttpRequest and returns a promise with the response from the request.
However I'd like to instead return a promise which contains just one string from the response.
E.g instead of the promise resolving to response = {status, data} etc, I'd like to return just response.data.some_field
How can I do this?

If you call .then on a promise, you'll produce another promise which will resolve to whatever you return in the callback function. So take the current promise that you're creating, and then add on the following:
.then((response) => {
return response.data.some_field;
});
So maybe the full function will look like this:
function getStuff() {
return new Promise((resolve, reject) => {
//somethingWithXMLHttpRequest
}).then((response) => {
return response.data.some_field;
});
}

What you're looking for is promise chaining. Link goes to mozilla's doc page on promise chaining.
function httpRequestAsync () {
// Return a promise... This is where your XMLHttpRequest takes place
}
function getStuffAsync() {
// Make your http request, chain the return promise,
// and return a promise, which resolves to the chosen field.
return httpRequestAsync() //Calling .then() on this promise is promise chaining.
.then((response) => {
return response.data.some_field;
});
}
function someBusinessLogicFunction () {
let yourString = "";
getStuffAsync()
.then((response) => {
yourString = response; // yourString does in fact equal the response param... :).catch(() => {
console.log("Something went wrong, or this answer sucks ha ha!");
});
})
}
// Or using async/await, for fun
async someBusinessLogicFunction2 () {
let yourString = "";
try {
yourString = await getStuffAsync();
} catch (e) {
console.log("Something went wrong, or this answer sucks ha ha!");
}
}
My example splits out your HTTP request into one function, with another function declared, which calls that function, and performs the promise chaining. You could omit the second function, and return the chained promise from the function that performs the HTTP request.

You have something like this (got it from your code block before you edited the question)
const promise = axios
.post(url("fistbump"), data)
.then(result => {
window.console.log("Got fistbump response: ", result.data);
localStorage.setItem(ACCOUNT_TOKEN_FIELD, result.data.key);
});
return promise;
If the Axios promise respects the ES6 promise spec, you can simply return what you want from the .then clause to get the value wrapped in a promise, which gives you
const promise = axios
.post(url("fistbump"), data)
.then(result => {
window.console.log("Got fistbump response: ", result.data);
localStorage.setItem(ACCOUNT_TOKEN_FIELD, result.data.key);
return result.data;
});
return promise;

JavaScript Promise Not Awaiting Asynchronous Call

I'm working with JavaScript promises, but somewhat new to them and having some issues. In the code below "todoService.addTodo(description);" is an asynchronous call to a server. However, the code does not wait for "todoService.addTodo(description);" to finish, and instead continues executing the code, which means "test" is always equal to null. I'm using promises because I thought this would help deal with the asynch calls, do I'm I simply not understanding the concept, or just doing something wrong syntactically?
let promise = new Promise(function (resolve, reject){
let test = todoService.addTodo(description);
console.log(test)
if (test) {
console.log("GOOD");
resolve("OK");
} else {
console.log("BAD");
reject("Unable to connect to server");
}
});
promise.then(function(result) {
console.log(result);
}, function(err) {
alert(err);
});
Here is the implementation of addTodo():
addTodo: function (description) {
serv.todoUrl ='http://localhost:8080/add?description=' + description;
serv.todoResource = $resource(serv.todoUrl);
serv.todoResource.save().$promise.then(function (data) {
console.log(data);
let toReturn = {result: data.result, details: data.details};
console.log(toReturn);
return toReturn;
}, function (error) {
return null;
});

If test is a promise, then if (test) is not the right way to deal with it. What's more, you should not create a new Promise when addTodo already provides the promise.
All you would need is this:
todoService.addTodo(description).then(function(result) {
console.log(result);
}, function(err) {
alert(err);
});
Now that you also added the implementation of addToDo in your question, it turns out that it lacks a return of the promise you create there, so it just returned undefined, which obviously is not a promise. Add return here:
addTodo: function (description) {
serv.todoUrl ='http://localhost:8080/add?description=' + description;
serv.todoResource = $resource(serv.todoUrl);
return serv.todoResource.save().$promise.then(function (data) {
// ^^^^^
console.log(data);
let toReturn = {result: data.result, details: data.details};
console.log(toReturn);
return toReturn;
}, function (error) {
return null;
});
Note that the other return statements are in the relative callback functions which execute asynchronously, so they don't provide the return value for addToDo, but they provide the resolving value for the promise.
NB: Since you treat the rejection case in addToDo and don't cascade the error, but just return null, addToDo will not represent a rejected promise in that case, but a fulfilled one. If you prefer to have the caller of addToDo to get a rejected promise in that case, then just remove the rejection handler function from within addToDo.

Why is my asynchronous function returning Promise { <pending> } instead of a value?

My code:
let AuthUser = data => {
return google.login(data.username, data.password).then(token => { return token } )
}
And when i try to run something like this:
let userToken = AuthUser(data)
console.log(userToken)
I'm getting:
Promise { <pending> }
But why?
My main goal is to get token from google.login(data.username, data.password) which returns a promise, into a variable. And only then preform some actions.

The promise will always log pending as long as its results are not resolved yet. You must call .then on the promise to capture the results regardless of the promise state (resolved or still pending):
let AuthUser = function(data) {
return google.login(data.username, data.password).then(token => { return token } )
}
let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }
userToken.then(function(result) {
console.log(result) // "Some User token"
})
Why is that?
Promises are forward direction only; You can only resolve them once. The resolved value of a Promise is passed to its .then or .catch methods.
Details
According to the Promises/A+ spec:
The promise resolution procedure is an abstract operation taking as
input a promise and a value, which we denote as [[Resolve]](promise,
x). If x is a thenable, it attempts to make promise adopt the state of
x, under the assumption that x behaves at least somewhat like a
promise. Otherwise, it fulfills promise with the value x.
This treatment of thenables allows promise implementations to
interoperate, as long as they expose a Promises/A+-compliant then
method. It also allows Promises/A+ implementations to “assimilate”
nonconformant implementations with reasonable then methods.
This spec is a little hard to parse, so let's break it down. The rule is:
If the function in the .then handler returns a value, then the Promise resolves with that value. If the handler returns another Promise, then the original Promise resolves with the resolved value of the chained Promise. The next .then handler will always contain the resolved value of the chained promise returned in the preceding .then.
The way it actually works is described below in more detail:
1. The return of the .then function will be the resolved value of the promise.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return "normalReturn";
})
.then(function(result) {
console.log(result); // "normalReturn"
});
2. If the .then function returns a Promise, then the resolved value of that chained promise is passed to the following .then.
function initPromise() {
return new Promise(function(res, rej) {
res("initResolve");
})
}
initPromise()
.then(function(result) {
console.log(result); // "initResolve"
return new Promise(function(resolve, reject) {
setTimeout(function() {
resolve("secondPromise");
}, 1000)
})
})
.then(function(result) {
console.log(result); // "secondPromise"
});

I know this question was asked 2 years ago, but I run into the same issue and the answer for the problem is since ES2017, that you can simply await the functions return value (as of now, only works in async functions), like:
let AuthUser = function(data) {
return google.login(data.username, data.password)
}
let userToken = await AuthUser(data)
console.log(userToken) // your data

The then method returns a pending promise which can be resolved asynchronously by the return value of a result handler registered in the call to then, or rejected by throwing an error inside the handler called.
So calling AuthUser will not suddenly log the user in synchronously, but returns a promise whose then registered handlers will be called after the login succeeds ( or fails). I would suggest triggering all login processing by a then clause of the login promise. E.G. using named functions to highlight the sequence of flow:
let AuthUser = data => { // just the login promise
return google.login(data.username, data.password);
};
AuthUser(data).then( processLogin).catch(loginFail);
function processLogin( token) {
// do logged in stuff:
// enable, initiate, or do things after login
}
function loginFail( err) {
console.log("login failed: " + err);
}

If that situation happens for a multiple values like an array.
[
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> },
Promise { <pending> }
]
You can use Promise.all() this will resolve all promises.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise/all

See the MDN section on Promises. In particular, look at the return type of then().
To log in, the user-agent has to submit a request to the server and wait to receive a response. Since making your application totally stop execution during a request round-trip usually makes for a bad user experience, practically every JS function that logs you in (or performs any other form of server interaction) will use a Promise, or something very much like it, to deliver results asynchronously.
Now, also notice that return statements are always evaluated in the context of the function they appear in. So when you wrote:
let AuthUser = data => {
return google
.login(data.username, data.password)
.then( token => {
return token;
});
};
the statement return token; meant that the anonymous function being passed into then() should return the token, not that the AuthUser function should. What AuthUser returns is the result of calling google.login(username, password).then(callback);, which happens to be a Promise.
Ultimately your callback token => { return token; } does nothing; instead, your input to then() needs to be a function that actually handles the token in some way.

Your Promise is pending, complete it by
userToken.then(function(result){
console.log(result)
})
after your remaining code.
All this code does is that .then() completes your promise & captures the end result in result variable & print result in console.
Keep in mind, you cannot store the result in global variable.
Hope that explanation might help you.

I had the same issue earlier, but my situation was a bit different in the front-end. I'll share my scenario anyway, maybe someone might find it useful.
I had an api call to /api/user/register in the frontend with email, password and username as request body. On submitting the form(register form), a handler function is called which initiates the fetch call to /api/user/register. I used the event.preventDefault() in the beginning line of this handler function, all other lines,like forming the request body as well the fetch call was written after the event.preventDefault(). This returned a pending promise.
But when I put the request body formation code above the event.preventDefault(), it returned the real promise. Like this:
event.preventDefault();
const data = {
'email': email,
'password': password
}
fetch(...)
...
instead of :
const data = {
'email': email,
'password': password
}
event.preventDefault();
fetch(...)
...

Try this
var number1 = document.getElementById("number1");
var number2 = document.getElementById("number2");
startAsync.addEventListener("click", function() {
if (number1.value > 0 && number2.value > 0) {
asyncTest(parseInt(number1.value), parseInt(number2.value)).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
} else {
asyncTest(1, 2).then(function(result) {
document.getElementById("promiseResolved").textContent = "promiseResolved: " + result
});
}
});
async function asyncTest(a, b) {
return await (a + b);
};
<button id="startAsync">start Async function</button><br />
<input type="number" id="number1" /><br />
<input type="number" id="number2" /><br />
<span id="promiseResolved"></span><br />

Im my case (JS) I forgot to add await

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