I have a route called "./checkout" that renders embedded elements from Xola. The issue is I am using client side routing and the page needs a refresh to load the checkout page correctly (if not, Xola elements do not show up on the DOM 1). When I try to reload the page on the initial load I get an infinite reload loop. I can't use a href for specific reasons so I need to continue to use Next.js routing. Anyway I can go about this? EDIT: I have reached out to Xola support team for further assistance.
After refresh
checkout.js
import Head from "next/head";
import { useRouter } from "next/router";
import { Container, Button } from "#mui/material";
import { makeStyles } from "#mui/styles";
import { CheckoutCard } from "../components/layout/directory";
import useIsSsr from "#/config/useSsr";
function Checkout() {
const isSsr = useIsSsr();
const router = useRouter();
const classes = useStyles();
return (
<>
{isSsr ? null : window.location.reload()}
<Head>
<title>checkout</title>
</Head>
<Container className={classes.root}>
<Button
className={classes.btn}
onClick={router.back}
color="secondary"
variant={"contained"}
>
back
</Button>
<CheckoutCard />
</Container>
</>
);
}
const useStyles = makeStyles((theme) => ({
root: { marginTop: theme.spacing(10) },
btn: { marginBottom: theme.spacing(5) },
}));
export default Checkout;
CheckoutCard.js
function CheckoutCard() {
return (
<div
className="xola-embedded-checkout"
data-seller="5f3d889683cfdc77b119e592"
data-experience="5f3d8d80d6ba9c6b14748160"
data-version="2"
id="xola-checkout"
></div>
);
}
export default CheckoutCard;
Please add one more prop to CheckoutCard component calling in checkout.js.
You need to update
<CheckoutCard
url={`https://checkout.xola.com/index.html#seller/5f3d889683cfdc77b119e592/experiences/${
url && url.slice(1)
}?openExternal=true`}
/>
to
<CheckoutCard
url={`https://checkout.xola.com/index.html#seller/5f3d889683cfdc77b119e592/experiences/${
url && url.slice(1)
}?openExternal=true`}
key={new Date().getTime()}
/>
"key" prop is to identify the component and you are going to use external service ( like iframe, not sure correctly )
So in order to render the embedded elements from Xola, you should add "key" prop for CheckoutCard component calling.
I'm building a portfolio site in Gatsby, and as I work more on the illustration and design side, would like to serve up multiple design options to showcase that work, based on a user selection via click. I've found some similar questions, but none that are specific to Gatsby.
I'm using styled components to create the layout, so It seems to me that just swapping between multiple Global stylesheets (with fonts, colors, etc) via a button would be the way to go, so the layout remains intact, but I'm honestly not sure how to go about this as I'm pretty beginner in Gatsby and Javascript in general.
Thanks in advance!
Given a simply <Layout> structure like:
import React from "react"
import { createGlobalStyle } from "styled-components"
const GlobalStyle = createGlobalStyle`
body {
color: ${props => (props.theme === "purple" ? "purple" : "white")};
}
`
export default function Layout({ children }) {
return (
<React.Fragment>
<GlobalStyle theme="purple" />
{children}
</React.Fragment>
)
}
You can easily attach an onClick event to the children by adding a boolean operator to switch your <GlobalStyle>, for example:
export default function somePage(){
const [defaultStyles, setDefaultStyles]=useState(false);
const handleChange=()=>setDefaultStyles(!defaultStyles)
return <Layout defaultStyles={defaultStyles}>
<h1 onClick={handleChange}> Click me to toggle the global styles</h1>
</Layout>
}
Basically, you are creating a boolean state (initially set as false) to change between default styles. The result of that state (toggled by clicking the <h1>) will be sent upwards to your <Layout> so, there:
import React from "react"
import { createGlobalStyle } from "styled-components"
const GlobalStyle = createGlobalStyle`
body {
color: ${props => (props.theme === "purple" ? "purple" : "white")};
}
`
export default function Layout({ children, defaultStyles }) {
return (
<React.Fragment>
{defaultStyles && <GlobalStyle theme="purple" />}
{children}
</React.Fragment>
)
}
The && operator will only render <GlobalStyle> if defaultStyles is true. Adapt it to your needs or add a ternary condition if needed.
I have the following (using Material UI)....
import React from "react";
import { NavLink } from "react-router-dom";
import Tabs from "#material-ui/core/Tabs";
import Tab from "#material-ui/core/Tab";
function LinkTab(link){
return <Tab component={NavLink}
to={link.link}
label={link.label}
value={link.link}
key={link.link}
/>;
}
In the new versions this causes the following warning...
Warning: Function components cannot be given refs. Attempts to access
this ref will fail. Did you mean to use React.forwardRef()?
Check the render method of ForwardRef.
in NavLink (created by ForwardRef)
I tried changing to...
function LinkTab(link){
// See https://material-ui.com/guides/composition/#caveat-with-refs
const MyLink = React.forwardRef((props, ref) => <NavLink {...props} ref={ref} />);
return <Tab component={MyLink}
to={link.link}
label={link.label}
value={link.link}
key={link.link}
/>;
}
But I still get the warning. How do I resolve this issue?
Just give it as innerRef,
// Client.js
<Input innerRef={inputRef} />
Use it as ref.
// Input.js
const Input = ({ innerRef }) => {
return (
<div>
<input ref={innerRef} />
</div>
)
}
NavLink from react-router is a function component that is a specialized version of Link which exposes a innerRef prop for that purpose.
// required for react-router-dom < 6.0.0
// see https://github.com/ReactTraining/react-router/issues/6056#issuecomment-435524678
const MyLink = React.forwardRef((props, ref) => <NavLink innerRef={ref} {...props} />);
You could've also searched our docs for react-router which leads you to https://mui.com/getting-started/faq/#how-do-i-use-react-router which links to https://mui.com/components/buttons/#third-party-routing-library. The last link provides a working example and also explains how this will likely change in react-router v6
You can use refs instead of ref. This only works as it avoids the special prop name ref.
<InputText
label="Phone Number"
name="phoneNumber"
refs={register({ required: true })}
error={errors.phoneNumber ? true : false}
icon={MailIcon}
/>
In our case, we were was passing an SVG component (Site's Logo) directly to NextJS's Link Component which was a bit customized and we were getting such error.
Header component where SVG was used and was "causing" the issue.
import Logo from '_public/logos/logo.svg'
import Link from '_components/link/Link'
const Header = () => (
<div className={s.headerLogo}>
<Link href={'/'}>
<Logo />
</Link>
</div>
)
Error Message on Console
Function components cannot be given refs. Attempts to access this ref will fail.
Did you mean to use React.forwardRef()?
Customized Link Component
import NextLink from 'next/link'
import { forwardRef } from 'react'
const Link = ({ href, shallow, replace, children, passHref, className }, ref) => {
return href ? (
<NextLink
href={href}
passHref={passHref}
scroll={false}
shallow={shallow}
replace={replace}
prefetch={false}
className={className}
>
{children}
</NextLink>
) : (
<div className={className}>{children}</div>
)
}
export default forwardRef(Link)
Now we made sure we were using forwardRef in the our customized Link Component but we still got that error.
In order to solve it, I changed the wrapper positioning of SVG element to this and :poof:
const Header = () => (
<Link href={'/'}>
<div className={s.headerLogo}>
<Logo />
</div>
</Link>
)
If you find that you cannot add a custom ref prop or forwardRef to a component, I have a trick to still get a ref object for your functional component.
Suppose you want to add ref to a custom functional component like:
const ref = useRef();
//throws error as Button is a functional component without ref prop
return <Button ref={ref}>Hi</Button>;
You can wrap it in a generic html element and set ref on that.
const ref = useRef();
// This ref works. To get button html element inside div, you can do
const buttonRef = ref.current && ref.current.children[0];
return (
<div ref={ref}>
<Button>Hi</Button>
</div>
);
Of course manage state accordingly and where you want to use the buttonRef object.
to fix this warning you should wrap your custom component with the forwardRef function as mentioned in this blog very nicely
const AppTextField =(props) {return(/*your component*/)}
change the above code to
const AppTextField = forwardRef((props,ref) {return(/*your component*/)}
const renderItem = ({ item, index }) => {
return (
<>
<Item
key={item.Id}
item={item}
index={index}
/>
</>
);
};
Use Fragment to solve React.forwardRef()? warning
If you're using functional components, then React.forwardRef is a really nice feature to know how to use for scenarios like this. If whoever ends up reading this is the more hands on type, I threw together a codesandbox for you to play around with. Sometimes it doesn't load the Styled-Components initially, so you may need to refresh the inline browser when the sandbox loads.
https://codesandbox.io/s/react-forwardref-example-15ql9t?file=/src/App.tsx
// MyAwesomeInput.tsx
import React from "react";
import { TextInput, TextInputProps } from "react-native";
import styled from "styled-components/native";
const Wrapper = styled.View`
width: 100%;
padding-bottom: 10px;
`;
const InputStyled = styled.TextInput`
width: 100%;
height: 50px;
border: 1px solid grey;
text-indent: 5px;
`;
// Created an interface to extend the TextInputProps, allowing access to all of its properties
// from the object that is created from Styled-Components.
//
// I also define the type that the forwarded ref will be.
interface AwesomeInputProps extends TextInputProps {
someProp?: boolean;
ref?: React.Ref<TextInput>;
}
// Created the functional component with the prop type created above.
//
// Notice the end of the line, where you wrap everything in the React.forwardRef().
// This makes it take one more parameter, called ref. I showed what it looks like
// if you are a fan of destructuring.
const MyAwesomeInput: React.FC<AwesomeInputProps> = React.forwardRef( // <-- This wraps the entire component, starting here.
({ someProp, ...props }, ref) => {
return (
<Wrapper>
<InputStyled {...props} ref={ref} />
</Wrapper>
);
}); // <-- And ending down here.
export default MyAwesomeInput;
Then on the calling screen, you'll create your ref variable and pass it into the ref field on the component.
// App.tsx
import React from "react";
import { StyleSheet, Text, TextInput, View } from "react-native";
import MyAwesomeInput from "./Components/MyAwesomeInput";
const App: React.FC = () => {
// Set some state fields for the inputs.
const [field1, setField1] = React.useState("");
const [field2, setField2] = React.useState("");
// Created the ref variable that we'll use down below.
const field2Ref = React.useRef<TextInput>(null);
return (
<View style={styles.app}>
<Text>React.forwardRef Example</Text>
<View>
<MyAwesomeInput
value={field1}
onChangeText={setField1}
placeholder="field 1"
// When you're done typing in this field, and you hit enter or click next on a phone,
// this makes it focus the Ref field.
onSubmitEditing={() => {
field2Ref.current.focus();
}}
/>
<MyAwesomeInput
// Pass the ref variable that's created above to the MyAwesomeInput field of choice.
// Everything should work if you have it setup right.
ref={field2Ref}
value={field2}
onChangeText={setField2}
placeholder="field 2"
/>
</View>
</View>
);
};
const styles = StyleSheet.create({
app: {
flex: 1,
justifyContent: "center",
alignItems: "center"
}
});
export default App;
It's that simple! No matter where you place the MyAwesomeInput component, you'll be able to use a ref.
I just paste here skychavda solution, as it provide a ref to a child : so you can call child method or child ref from parent directly, without any warn.
source: https://github.com/reactjs/reactjs.org/issues/2120
/* Child.jsx */
import React from 'react'
class Child extends React.Component {
componentDidMount() {
const { childRef } = this.props;
childRef(this);
}
componentWillUnmount() {
const { childRef } = this.props;
childRef(undefined);
}
alertMessage() {
window.alert('called from parent component');
}
render() {
return <h1>Hello World!</h1>
}
}
export default Child;
/* Parent.jsx */
import React from 'react';
import Child from './Child';
class Parent extends React.Component {
onClick = () => {
this.child.alertMessage(); // do stuff
}
render() {
return (
<div>
<Child childRef={ref => (this.child = ref)} />
<button onClick={this.onClick}>Child.alertMessage()</button>
</div>
);
}
}
I'm able to change a styled components styles based on state but only at page load, if I toggle the state after page load, the state changes successfully but the styles remain the same. The styled component whose styles I'm trying to change is "S.Search" which is inside of a "Search" component whose parent is "Navbar". I'm passing "Search" an "isVisible" state as a prop that is toggled by the onClick event handler in the parent component "Navbar".
The parent component:
import React, { useContext, useState } from "react"
import Search from "../components/Search"
import * as S from "../styled/Navbar"
const Navbar = () => {
const [isVisible, setVisibility] = useState(false)
return (
<S.Navbar>
/* S.SearchButton toggles the isVisible state onclick */
<S.SearchButton onClick={() => setVisibility(!isVisible)}>
<S.SearchButtonText>Search</S.SearchButtonText>
</S.SearchButton>
/* Passing isVisible state into the Search component as props */
<Search isVisible={isVisible} setVisibility={setVisibility} />
</S.Navbar>
)
}
export default Navbar
The search component:
import React, { useState } from "react"
import Icon from "../components/Icon"
import * as S from "../styled/Search"
const Search = props => {
return (
<S.Search>
<S.InputWrapper>
<S.SearchButtonIcon>
<Icon icon={"search"} />
</S.SearchButtonIcon>
<S.Input
type="text"
placeholder="Search for a character"
autocomplete="off"
/>
<S.ChampList></S.ChampList>
</S.InputWrapper>
</S.Search>
)
}
export default Search
I'm sure my state is being toggled correctly, but I have no idea why the style isn't being updated when toggling the state after page load. This is the styled component that has access to the isVisible state via props passed to the search component:
import styled from "styled-components"
export const Search = styled.div`
height: ${p => (!p.isVisible ? `0` : `2.5rem`)};
visibility: ${p => (!p.isVisible ? `hidden` : `visible`)};
opacity: ${p => (!p.isVisible ? `0` : `100`)};
display: flex;
justify-content: center;
transition: ${p => p.theme.easings.easeOut};
`
How can I change the style after page load when I toggle the state? Thank you for your time!
Your style isnt being applied because you are not passing isVisible prop to Search style-component.
You just need to do this in your Search Component:
const Search = props => {
return (
// Here´s the trick
<S.Search isVisible={props.isVisible}>
.....
.....
.....
I'm using a quill js component (a text editor) for Reactjs and I'm testing it to see all it's features.
I managed to build a editor with a toolbar, but now I have a doubt, how can I get everything the user typed and save it in my state? As I'll show you in the code if I console.log(the quillRef.current) I get a div and way inside it I have a p element which contains everything the user has typed. My idea is to place a button in the end, and when the user stops typing and clicks the button I store what they typed.
here's a link to the sandbox where I'm testing it:
codesandbox link
With quill.getText() function :
import React, { useState } from "react";
import { useQuill } from "react-quilljs";
export default () => {
const { quill, quillRef } = useQuill();
const [savedText, setSavedText] = useState("");
const handleSave = () => {
const text = quill.getText();
setSavedText(text);
};
return (
<div style={{ width: 500, height: 300 }}>
<button onClick={handleSave}>SAVE</button>
<div>Saved State : {savedText}</div>
<div ref={quillRef} />
</div>
);
};
Check on codesandbox : https://codesandbox.io/s/react-quilljsbasic-tt6pm?file=/src/App.js