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I need to apply several matrix transformations before drawing a shape, however (if on somewhere) I use rotate() the coordinates are inverted and/or reversed and cannot continue without knowing if the matrix was previously rotated.
How can solve this problem?
Example:
<canvas width="300" height="300"></canvas>
<script>
let canvas = document.querySelector("canvas");
let ctx = canvas.getContext("2d");
ctx.fillStyle = "silver";
ctx.fillRect(0, 0, canvas.width, canvas.height);
ctx.strokeStyle = "black";
ctx.lineWidth = 1;
ctx.beginPath();
ctx.moveTo(0, canvas.height/2);
ctx.lineTo(canvas.width, canvas.height/2);
ctx.stroke();
ctx.beginPath();
ctx.moveTo(canvas.width/2, 0);
ctx.lineTo(canvas.width/2, canvas.height);
ctx.stroke();
ctx.translate(150, 150);
ctx.rotate(-90 * 0.017453292519943295);
ctx.translate(-150, -150);
// move the red rectangle 100px to the left (top-left)
// but instead is moved on y axis (right-bottom)
ctx.translate(-100, 0);
// more matrix transformations
// ....
// ....
// now finally draw the shape
ctx.fillStyle = "red";
ctx.fillRect(150, 150, 100, 50);
</script>
Can be this Translation after rotation the solution?
It looks like you aren't resetting the canvas matrix each time you make a new transformation.
The Canvas API has the save() and restore() methods. Canvas states are stored on a stack. Every time the save() method is called, the current drawing state is pushed onto the stack. A drawing state consists of transformations that have been applied along with the attributes of things like the fillStyle. When you call restore(), the previous settings are restored.
// ...
ctx.save(); // save the current canvas state
ctx.translate(150, 150);
ctx.rotate(-90 * 0.017453292519943295);
ctx.translate(-150, -150);
ctx.restore(); // restore the last saved state
// now the rectangle should move the correct direction
ctx.translate(-100, 0);
Check out this link for more information on the save and restore methods.
OK finally, i solved the problem by rotating the translation point before applying it. This function does the trick:
function helperRotatePoint(point, angle) {
let s = Math.sin(angle);
let c = Math.cos(angle);
return { x: point.x * c - point.y * s, y: point.x * s + point.y * c};
}
rotating the translation point using the inverted angle I obtain the corrected translation
helperRotatePoint(translation_point, -rotation_angle);
working code:
let canvas = document.querySelector("canvas");
// proper size on HiDPI displays
canvas.style.width = canvas.width;
canvas.style.height = canvas.height;
canvas.width = Math.floor(canvas.width * window.devicePixelRatio);
canvas.height = Math.floor(canvas.height * window.devicePixelRatio);
let ctx = canvas.getContext("2d");
ctx.scale(window.devicePixelRatio, window.devicePixelRatio);
ctx.fillStyle = "whitesmoke";
ctx.fillRect(0, 0, canvas.width, canvas.height);
class UIElement {
constructor(x, y, width, height, color) {
// PoC
this.draw_pos = {x, y};
this.draw_size = {width, height};
this.color = color;
this.rotate = 0;
this.scale = {x: 1, y: 1};
this.translate = {x: 0, y: 0};
this.skew = {x: 0, y: 0};
this.childs = [];
}
addChild(uielement) {
this.childs.push(uielement);
}
helperRotatePoint(point, angle) {
let s = Math.sin(angle);
let c = Math.cos(angle);
return {
x: point.x * c - point.y * s,
y: point.x * s + point.y * c
};
}
draw(cnvs_ctx, parent_x, parent_y) {
// backup current state
cnvs_ctx.save();
let elements_drawn = 1;// "this" UIElement
// step 1: calc absolute coordinates
let absolute_x = parent_x + this.draw_pos.x;
let absolute_y = parent_y + this.draw_pos.y;
// step 2: apply all transforms
if (this.rotate != 0) {
cnvs_ctx.translate(absolute_x, absolute_y)
cnvs_ctx.rotate(this.rotate);
cnvs_ctx.translate(-absolute_x, -absolute_y);
// rotate translate point before continue
let tmp = this.helperRotatePoint(this.translate, -this.rotate);
// apply rotated translate
cnvs_ctx.translate(tmp.x, tmp.y);
} else {
cnvs_ctx.translate(this.translate.x, this.translate.y);
}
cnvs_ctx.scale(this.scale.x, this.scale.y);
cnvs_ctx.transform(1, this.skew.y, this.skew.x, 1, 0, 0);
// step 3: self draw (aka parent element)
cnvs_ctx.fillStyle = this.color;
cnvs_ctx.fillRect(absolute_x, absolute_y, this.draw_size.width, this.draw_size.height);
// step 4: draw childs elements
for (let i = 0; i < this.childs.length ; i++) {
elements_drawn += this.childs[i].draw(
cnvs_ctx, absolute_x, absolute_y
);
}
// done, restore state
cnvs_ctx.restore();
return elements_drawn;
}
}
// spawn some ui elements
var ui_panel = new UIElement(120, 50, 240, 140, "#9b9a9e");
var ui_textlabel = new UIElement(10, 10, 130, 18, "#FFF");
var ui_image = new UIElement(165, 25, 90, 60, "#ea9e22");
var ui_textdesc = new UIElement(17, 46, 117, 56, "#ff2100");
var ui_icon = new UIElement(5, 5, 10, 10, "#800000");
ui_panel.addChild(ui_textlabel);
ui_panel.addChild(ui_image);
ui_panel.addChild(ui_textdesc);
ui_textdesc.addChild(ui_icon);
// add some matrix transformations
ui_textdesc.skew.x = -0.13;
ui_textdesc.translate.x = 13;
ui_image.rotate = -90 * 0.017453292519943295;
ui_image.translate.y = ui_image.draw_size.width;
ui_panel.rotate = 15 * 0.017453292519943295;
ui_panel.translate.x = -84;
ui_panel.translate.y = -50;
// all ui element elements
ui_panel.draw(ctx, 0, 0);
<canvas width="480" height="360"></canvas>
I have a blue circle which is rotating around the red circle and moves on canvas continuously in one direction as long as the button is pressed.
Now I want to draw with the red circle while it is moving when the button is pressed (trace of its path).
Problems:
I have tried to make changes to clearRect() but I didn't succeed. the blue circle starts to draw on the canvas while moving which I don't need.
If its not possible to do with clearRect() function, Is it possible to do this by stacking canvas layers. Please help with example
const canvas = document.getElementById('canvas1');
const ctx = canvas.getContext('2d');
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
let positionX = 100;
let positionY = 100;
let X = 50;
let Y = 50;
let angle = 0;
let mouseButtonDown = false;
document.addEventListener('mousedown', () => mouseButtonDown = true);
document.addEventListener('mouseup', () => mouseButtonDown = false);
function circle(){
ctx.fillStyle = 'red';
ctx.beginPath();
ctx.arc(X, Y, 20, 0, Math.PI*2);
ctx.closePath();
ctx.fill();
}
function direction(){
ctx.fillStyle = 'blue';
ctx.beginPath();
ctx.arc(positionX + X, positionY + Y, 10, 0, Math.PI*2);
ctx.closePath();
positionX = 35 * Math.sin(angle);
positionY = 35 * Math.cos(angle);
ctx.fill();
}
function animate(){
if (mouseButtonDown) {
X += positionX / 10;
Y += positionY / 10;
} else {
angle += 0.1;
}
ctx.clearRect(X-positionX,Y-positionY, 20, 20);
circle();
direction();
requestAnimationFrame(animate);
}
animate();
#canvas1{
position: absolute;
top:0;
left: 0;
width: 100%;
height: 100%;
}
<!DOCTYPE html>
<html lang="en">
<head>
<link rel="stylesheet" href="style.css">
</head>
<body>
<canvas id="canvas1"></canvas>
<script src="script.js"></script>
</body>
</html>
Don`t stack canvas on the page
Each canvas you add to the page increases the amount of work the GPU and page compositor needs to do to render the page.
Use a second canvas that is not on the page and do the compositing by rendering the canvas to the onpage canvas using ctx.drawImage(secondCanvas, 0, 0).
This reduces the workload for the compositor, and in many cases avoid the need to do an addition image render (composite) for the second canvas I.E. onpage can require 3 drawImages (one for each canvas and once for the result) rather than 2 (once in your code and once as the result) if you use only one onpage canvas.
Using second canvas
Create a second canvas to store the drawn red lines.
You can create a copy of a canvas using
function copyCanvas(canvas, copyContent = false) {
const can = Object.assign(document.createElement("canvas"), {
width: canvas.width, height: canvas.height
});
can.ctx = can.getContext("2d");
copyContent && can.ctx.drawImage(canvas, 0, 0);
return can;
}
When you create render functions like circle, and direction pass as an argument the 2D context eg circle(ctx) so that it is easy to direct the rendering to any canvas.
function circle(ctx){
ctx.fillStyle = 'red';
ctx.beginPath();
ctx.arc(X, Y, redSize, 0, Math.PI*2);
ctx.fill();
}
// the background canvas
const bgCan = copyCanvas(canvas);
circle(bgCan.ctx); // will draw to the background canvas
Updating animation
When animating is is easiest to clear the whole canvas rather than mess about clearing only rendered pixels. Clearing rendered pixels gets complicated very quickly and will end up being many times slower than clearing the whole canvas.
After you clear the canvas draw the background canvas to the main canvas
ctx.clearRect(0, 0, ctx.canvas.width, ctx.canvas.height);
ctx.drawImage(bgCan, 0, 0);
When the mouse button is down draw the circle to the background canvas and while it is up draw to the main canvas.
Example
Adds a function to copy a canvas. copyCanvas
Clears the main canvas, and draws the background canvas onto the main canvas.
Render functions circle and direction have argument ctx to direct rendering to any context.
When mouse is down circle is drawn to background canvas bgCan else to the main canvas.
requestAnimationFrame(animate);
const ctx = canvas1.getContext('2d');
canvas1.width = innerWidth;
canvas1.height = innerHeight;
const bgCan = copyCanvas(canvas1);
const redSize = 10, blueSize = 5; // circle sizes on pixels
const drawSpeed = 2; // when button down draw speed in pixels per frame
var X = 50, Y = 50;
var angle = 0;
var mouseButtonDown = false;
document.addEventListener('mousedown', () => mouseButtonDown = true);
document.addEventListener('mouseup', () => mouseButtonDown = false);
function copyCanvas(canvas) {
const can = Object.assign(document.createElement("canvas"), {
width: canvas.width, height: canvas.height
});
can.ctx = can.getContext("2d");
return can;
}
function circle(ctx){
ctx.fillStyle = 'red';
ctx.beginPath();
ctx.arc(X, Y, redSize, 0, Math.PI*2);
ctx.fill();
}
function direction(ctx){
const d = blueSize + redSize + 5;
ctx.fillStyle = 'blue';
ctx.beginPath();
ctx.arc(d * Math.sin(angle) + X, d * Math.cos(angle) + Y, blueSize, 0, Math.PI*2);
ctx.fill();
}
function animate(){
ctx.clearRect(0, 0, ctx.canvas.width, ctx.canvas.height);
ctx.drawImage(bgCan, 0, 0);
if (mouseButtonDown) {
circle(bgCan.ctx);
X += Math.sin(angle) * drawSpeed;
Y += Math.cos(angle) * drawSpeed;
} else {
angle += 0.1;
circle(ctx);
}
direction(ctx);
requestAnimationFrame(animate);
}
#canvas1{
position: absolute;
top:0;
left: 0;
width: 100%;
height: 100%;
}
<canvas id="canvas1"></canvas>
BTW ctx.closePath() is like ctx.lineTo it is not the opposite to ctx.beginPath. A full arc or if you are just filling a shape you don't need to use ctx.closePath
BTW window is the default this, you don't need to include it, you dont use it to get at window.documentso why use it forwindow.innerWidth(same asinnerWidth` )
You could alter your code to keep track of the path of the red circle, with an array property, like this:
const canvas = document.getElementById('canvas1');
const ctx = canvas.getContext('2d');
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
let mouseButtonDown = false;
document.addEventListener('mousedown', () => mouseButtonDown = true);
document.addEventListener('mouseup', () => mouseButtonDown = false);
function drawCircle({x, y, radius, color}) {
ctx.fillStyle = color;
ctx.beginPath();
ctx.arc(x, y, radius, 0, Math.PI*2);
ctx.fill();
}
const red = { x: 50, y: 50, radius: 20, color: "red", path: [] };
const blue = { x: 100, y: 100, radius: 10, color: "blue", angle: 0 };
function animate(){
if (mouseButtonDown) {
red.path.push({x: red.x, y: red.y}); // store the old value
red.x += (blue.x - red.x) / 10;
red.y += (blue.y - red.y) / 10;
} else {
blue.angle += 0.1;
}
blue.x = red.x + 35 * Math.sin(blue.angle);
blue.y = red.y + 35 * Math.cos(blue.angle);
ctx.clearRect(0, 0, canvas.width, canvas.height); // clear the whole canvas
for (const {x, y} of red.path) { // draw circle at all the previous positions
drawCircle({...red, x, y});
}
drawCircle(red);
drawCircle(blue);
requestAnimationFrame(animate);
}
animate();
Using 2 canvases also works and may perform better especially when the path of the red circle has gotten long, because the background canvas doesn't need to be cleared and redrawn. Add a 2nd canvas in your html page with the same positioning, and give them ids 'background' and 'foreground'. You can then adjust the code to draw the blue circle to the foreground and red circles to the background (or vice versa).
// Create 2 canvases, set them to full size and get the contexts
const backgroundCanvas = document.getElementById('background');
const foregroundCanvas = document.getElementById('foreground');
const background = backgroundCanvas.getContext("2d");
const foreground = foregroundCanvas.getContext("2d");
backgroundCanvas.width = innerWidth;
backgroundCanvas.height = innerHeight;
foregroundCanvas.width = innerWidth;
foregroundCanvas.height = innerHeight;
let mouseButtonDown = false;
document.addEventListener('mousedown', () => mouseButtonDown = true);
document.addEventListener('mouseup', () => mouseButtonDown = false);
// Create objects to represent the current properties of the red and blue circle
const red = { x: 50, y: 50, radius: 20, color: "red" };
const blue = { x: 100, y: 100, radius: 10, color: "blue", angle: 0};
function drawCircle(ctx, {x, y, radius, color}) {
//--- Draw a circle to the specified canvas context, ctx = foreground or background
ctx.fillStyle = color;
ctx.beginPath();
ctx.arc(x, y, radius, 0, Math.PI*2);
ctx.closePath();
ctx.fill();
}
function animate(){
if (mouseButtonDown) {
red.x += (blue.x - red.x) / 10;
red.y += (blue.y - red.y) / 10;
} else {
blue.angle += 0.1;
}
blue.x = red.x + 35 * Math.sin(blue.angle);
blue.y = red.y + 35 * Math.cos(blue.angle);
drawCircle(background, red); // Draw the red circle in the background (without clearing the existing circles)
foreground.clearRect(0, 0, foregroundCanvas.width, foregroundCanvas.height); // Clear the foreground
drawCircle(foreground, blue); // Draw the blue circle on the foreground
requestAnimationFrame(animate);
}
animate();
Either way, it's convenient to abstract out the circle drawing code into a function or method, and to store the properties of the two circles in objects.
As #Blindman67's answer notes, there may be a performance cost of stacking 2 canvases, and if that is an issue you may want to try drawing the background offscreen then copying it to the on-screen canvas.
If you're not opposed to just building a particle class you can do it using them. In the snippet below I have a Circle class and a Particles class to creat what you are trying to achieve. I currently have the particles max at 500 but you can change it or delete that line all together if you ne er want them gone.
const canvas = document.getElementById("canvas");
const ctx = canvas.getContext("2d");
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
let mouseButtonDown = false;
//the array holding particles
let particles = [];
//the counter is only needed it you want to slow down how fast particles are being pushed and dispolayed
let counter = 0;
document.addEventListener("mousedown", () => (mouseButtonDown = true));
document.addEventListener("mouseup", () => (mouseButtonDown = false));
//ES6 constructor class
class Circle {
//sets the basic structor of the object
constructor(r, c) {
this.x = 100;
this.y = 100;
this.x2 = 50;
this.y2 = 50;
this.r = r; //will be assigned the argument passed in through the constructor by each instance created later
this.color = c; //same as above. This allows each instance to have different parameters.
this.angle = 0;
}
//this function creates the red circle
drawRed() {
ctx.fillStyle = this.color;
ctx.beginPath();
ctx.arc(this.x, this.y, this.r, 0, Math.PI * 2);
ctx.fill();
ctx.closePath();
}
//this function creates the blue circle
drawBlue() {
ctx.fillStyle = this.color;
ctx.beginPath();
ctx.arc(this.x + this.x2, this.y + this.y2, this.r, 0, Math.PI * 2);
ctx.fill();
ctx.closePath();
}
//this function is where we'll place parameter that change our object
update() {
//makes the blue circle rotate
this.x2 = 35 * Math.sin(this.angle);
this.y2 = 35 * Math.cos(this.angle);
//mouse action is same as your code
if (mouseButtonDown) {
this.x += this.x2 / 20;
this.y += this.y2 / 20;
} else {
this.angle += 0.1;
}
}
}
//When using this type of constructor class you have to create an instance of it by calling new Object. You can create as money as you want.
let blueCircle = new Circle(10, "blue"); //passing in the radius and color in to the constructor
let redCircle = new Circle(20, "red");
//another class for the particles
class Particles {
constructor() {
this.x = redCircle.x;
this.y = redCircle.y;
this.r = redCircle.r;
this.color = redCircle.color;
}
draw() {
ctx.fillStyle = this.color;
ctx.beginPath();
ctx.arc(this.x, this.y, this.r, 0, Math.PI * 2);
ctx.fill();
ctx.closePath();
}
}
//just wrapping all of the particle stuff into one function
function handleParticles() {
//while the mouse is held it will push particles
if (mouseButtonDown) {
particles.push(new Particles());
}
//this loops through the array and calls the draw() function for each particle
for (let i = 0; i < particles.length; i++) {
particles[i].draw();
}
//this keeps the array from getting too big.
if (particles.length > 500) {
particles.shift();
}
}
//wrap all functions into this one animate one and call requeatAnimationFrame
function animate() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
handleParticles();
//These must be called for each instance created of the object
blueCircle.drawBlue();
blueCircle.update();
redCircle.drawRed();
redCircle.update();
requestAnimationFrame(animate);
}
animate();
#canvas1{
position: absolute;
top:0;
left: 0;
width: 100%;
height: 100%;
}
<canvas id="canvas"></canvas>
I'd also like to add you can change the rate that the particles are drawn by adding a counter variable and then limiting the draw like counter % 10 == 0
EXAMPLE
add global variable let counter = 0;
then in the handleParticles function add this
function handleParticles() {
counter++
if (mouseButtonDown && counter % 10 == 0) {
particles.push(new Particles());
}
for (let i = 0; i < particles.length; i++) {
particles[i].draw();
}
if (particles.length > 500) {
particles.shift();
}
}
I'm trying to implement zoom in an HTML5 Canvas. I came across other threads that explain how to do it, but they take advantage of the canvas' context, storing previous transformations. I want to avoid that.
So far I managed to do the following (https://jsfiddle.net/wfqzr538/)
<!DOCTYPE html>
<html>
<body style="margin: 0">
<canvas id="canvas" width="400" height="400" style="border: 1px solid #d3d3d3"></canvas>
<script>
const canvas = document.getElementById("canvas");
const context = canvas.getContext("2d");
let cursorX = 0,
cursorY = 0;
let zoom = 1;
canvas.onmousemove = mouseMove;
window.onkeydown = keyDown;
draw();
function mouseMove(evt) {
cursorX = evt.clientX;
cursorY = evt.clientY;
}
function keyDown(evt) {
if (evt.key == "p") {
zoom += 0.1;
}
if (evt.key == "m") {
zoom -= 0.1;
}
draw();
}
function draw() {
context.clearRect(0, 0, canvas.width, canvas.height);
const translationX = -cursorX * (zoom - 1);
const translationY = -cursorY * (zoom - 1);
context.translate(translationX, translationY);
context.scale(zoom, zoom);
context.fillRect(100, 100, 30, 30);
context.scale(1 / zoom, 1 / zoom);
context.translate(-translationX, -translationY);
}
</script>
</body>
</html>
The code above works If I zoom at the same location, but breaks as soon as I change it. For example, if I zoom in twice at the top left corner of the square, it works. However, if I zoom once at the top left corner, followed by zooming at the right bottom corner, it breaks.
I've been trying to fix this for a while now. I think it has something with not taking into account previous translations made in the canvas, but I'm not sure.
I'd really appreciate some help.
Not keeping previous state
If you don't want to keep the previous transform state then the is no way to do what you are trying to do.
There are many way to keep the previous state
Previous world state
You can transform all object's world state, in effect embedding the previous transform in the object's coordinates.
Eg with zoom and translate
object.x = object.x * zoom + translate.x;
object.y = object.y * zoom + translate.y;
object.w *= zoom;
object.h *= zoom;
then draw using default transform
ctx.setTransform(1,0,0,1,0,0);
ctx.fillRect(object.x, object.y, object.w, object.h);
Previous transformation state
To zoom at a point (absolute pixel coordinate) you need to know where the previous origin was so you can workout how far the zoom point is from that origin and move it correctly when zooming.
Your code does not keep track of the origin, in effect it assumes it is always at 0,0.
Example
The example tracks the previous transform state using an array that represents the transform. It is equivalent to what your code defines as translation and zoom.
// from your code
context.translate(translationX, translationY);
context.scale(zoom, zoom);
// is
transform = [zoom, 0, 0, zoom, translationX, translationY];
The example also changes the rate of zooming. In your code you add and subtract from the zoom, this will result in negative zooms, and when zooming in it will take forever to get to large scales. The scale is apply as a scalar eg zoom *= SCLAE_FACTOR
The function zoomAt zooms in or out at a given point on the canvas
const ctx = canvas.getContext("2d");
const transform = [1,0,0,1,0,0];
const SCALE_FACTOR = 1.1;
const pointer = {x: 0, y: 0};
var zoom = 1;
canvas.addEventListener("mousemove", mouseMove);
addEventListener("keydown", keyDown);
draw();
function mouseMove(evt) {
pointer.x = evt.clientX;
pointer.y = evt.clientY;
drawPointer();
}
function keyDown(evt) {
if (evt.key === "p") { zoomAt(SCALE_FACTOR, pointer) }
if (evt.key === "m") { zoomAt(1 / SCALE_FACTOR, pointer) }
}
function zoomAt(amount, point) {
zoom *= amount;
transform[0] = zoom; // scale x
transform[3] = zoom; // scale y
transform[4] = point.x - (point.x - transform[4]) * amount;
transform[5] = point.y - (point.y - transform[5]) * amount;
draw();
}
function draw() {
ctx.setTransform(1, 0, 0, 1, 0, 0);
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.setTransform(...transform);
ctx.fillRect(100, 100, 30, 30);
}
function drawPointer() {
draw();
ctx.lineWidth = 1;
ctx.strokeStyle = "black";
const invScale = 1 / transform[0]; // Assumes uniform scale
const x = (pointer.x - transform[4]) * invScale;
const y = (pointer.y - transform[5]) * invScale;
const size = 10 * invScale;
ctx.beginPath();
ctx.lineTo(x - size, y);
ctx.lineTo(x + size, y);
ctx.moveTo(x, y - size);
ctx.lineTo(x, y + size);
ctx.setTransform(1, 0, 0, 1, 0, 0); // to ensure line width is 1 px
ctx.stroke();
ctx.font = "16px arial";
ctx.fillText("Pointer X: " + x.toFixed(2) + " Y: " + y.toFixed(2), 10, 20);
}
* {margin: 0px}
canvas { border: 1px solid #aaa }
<canvas id="canvas" width="400" height="400"></canvas>
Update
I have added the function drawPointer which uses the transform to calculate the pointers world position, render a cross hair at the position and display the coordinates.
I want draw something like this in javascript:
Example:
The bigger circle: r = 5
What do I want to do? to position circles by forming a circle
My questions are (I would like to know):
How much points can I draw on a circle if I know the ray,
the distance between each circle and the radius of each circle?
How can I find the position of each circle (to draw automatically)?
Like the question 1 but the circles do not have the same radius.
Thank you!
Displace points around a circle edge equidistantly
Using HTML Canvas and a bit of trigonometry
Create a reusable circles() function and pass the desired arguments for Number of circles, Size, Radius, Color:
const ctx = document.getElementById("canvas").getContext("2d");
const cvsSize = 400;
ctx.canvas.width = cvsSize;
ctx.canvas.height = cvsSize;
function circles(tot, rad, dist, color) {
const arc = Math.PI * 2 / tot; // Arc in Radians
let ang = 0; // Start at angle 0 (East)
for (let i = 0; i < tot; i++) {
const x = dist * Math.cos(ang) + (cvsSize / 2);
const y = dist * Math.sin(ang) + (cvsSize / 2);
ctx.beginPath();
ctx.arc(x, y, rad, 0, Math.PI * 2, false);
ctx.fillStyle = color;
ctx.fill();
ctx.closePath();
ang += arc;
}
}
// Circles, Radius, Distance, Color
circles(3, 5, 10, "#f0b");
circles(10, 8, 50, "#0bf");
circles(17, 10, 90, "#bf0");
circles(21, 15, 140, "#b0f");
<canvas id="canvas"></canvas>
the rotate() function seems to rotate the whole drawing area. Is there a way to rotate paths individually? I want the center for the rotation to be the object, not the drawing area.
Using save() and restore() still makes rotate take into account the whole drawing area.
var canvas = document.getElementById('canvas');
var context = canvas.getContext('2d');
context.save();
context.fillStyle = 'red';
context.rotate(0.35);
context.fillRect(40,40, 100, 100);
context.restore();
context.save();
context.fillStyle = 'blue';
context.rotate(0.35);
context.fillRect(200, 40, 100, 100);
context.restore();
<canvas id="canvas" width="500" height="500"></canvas>
Use local space
Instead of drawing object at the position you want them draw everything around its own origin in its local space. The origin is at (0,0) and is the location that the object rotates around.
So if you have a rectangle that you draw with
function drawRect(){
context.fillRect(200, 40, 100, 100);
}
change it so that it is drawn at its origin
function drawRect(){
context.fillRect(-50,-50 , 100, 100);
}
Now you can easily draw it wherevery you want
Start with the setTransform function as that clears any existing tranforms and is a convenient way to set the location of the center of the object will be
ctx.setTransform(1,0,0,1,posX,posY); // clear transform and set center location
if you want to rotate it then add the rotation
ctx.rotate(ang);
and scale with
ctx.scale(scale,scale);
if you have two different scales you should scale before the rotate.
Now just call the draw function
drawRect();
and it is drawn with its center at posX,posY rotated and scaled.
You can combine it all into a function that has the x,y position, the width and the height, scale and rotation. You can include the scale in the setTransform
function drawRect(x,y,w,h,scale,rotation){
ctx.setTransform(scale,0,0,scale,x,y);
ctx.rotate(rotation);
ctx.strokeRect(-w/2,-h/2,w,h);
}
It also applies to an image as a sprite, and I will include a alpha
function drawImage(img,x,y,w,h,scale,rotation,alpha){
ctx.globalAlpha = alpha;
ctx.setTransform(scale,0,0,scale,x,y);
ctx.rotate(rotation);
ctx.drawImage(img,-img.width/2,-img.height/2,img.width,img.height);
}
On a 6 year old laptop that can draw 2000 sprites on firefox every 1/60th of a second, each rotated, scaled, positioned, and with a alpha fade.
No need to mess about with translating back and forward. Just keep all the objects you draw around there own origins and move that origin via the transform.
Update
Lost the demo so here it is to show how to do it in practice.
Just draws a lot of rotated, scaled translated, alphaed rectangles.
By using setTransform you save a lot of time by avoiding save and restore
// create canvas and add resize
var canvas,ctx;
function createCanvas(){
canvas = document.createElement("canvas");
canvas.style.position = "absolute";
canvas.style.left = "0px";
canvas.style.top = "0px";
canvas.style.zIndex = 1000;
document.body.appendChild(canvas);
}
function resizeCanvas(){
if(canvas === undefined){
createCanvas();
}
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
ctx = canvas.getContext("2d");
}
resizeCanvas();
window.addEventListener("resize",resizeCanvas);
// simple function to draw a rectangle
var drawRect = function(x,y,w,h,scale,rot,alpha,col){
ctx.setTransform(scale,0,0,scale,x,y);
ctx.rotate(rot);
ctx.globalAlpha = alpha;
ctx.strokeStyle = col;
ctx.strokeRect(-w/2,-h/2, w, h);
}
// create some rectangles in unit scale so that they can be scaled to fit
// what ever screen size this is in
var rects = [];
for(var i = 0; i < 200; i ++){
rects[i] = {
x : Math.random(),
y : Math.random(),
w : Math.random() * 0.1,
h : Math.random() * 0.1,
scale : 1,
rotate : 0,
dr : (Math.random() - 0.5)*0.1, // rotation rate
ds : Math.random()*0.01, // scale vary rate
da : Math.random()*0.01, // alpha vary rate
col : "hsl("+Math.floor(Math.random()*360)+",100%,50%)",
};
}
// draw everything once a frame
function update(time){
var w,h;
w = canvas.width; // get canvas size incase there has been a resize
h = canvas.height;
ctx.setTransform(1,0,0,1,0,0); // reset transform
ctx.clearRect(0,0,w,h); // clear the canvas
// update and draw each rect
for(var i = 0; i < rects.length; i ++){
var rec = rects[i];
rec.rotate += rec.dr;
drawRect(rec.x * w, rec.y * h, rec.w * w,rec.h * h,rec.scale + Math.sin(time * rec.ds) * 0.4,rec.rotate,Math.sin(time * rec.da) *0.5 + 0.5,rec.col);
}
requestAnimationFrame(update); // do it all again
}
requestAnimationFrame(update);
All transformations in canvas are for the whole drawing area. If you want to rotate around a point you're going to have to translate that point to the origin, do your rotation and translate it back. Something like this is what you want.
Use a rotate function to rotate all of the shape's points around its center.
<!DOCTYPE html>
<html>
<head>
<style>
body
{
margin: 0px;
padding: 0px;
overflow: hidden;
}
canvas
{
position: absolute;
}
</style>
</head>
<body>
<canvas id="canvas"></canvas>
<script>
var canvas;
var context;
canvas = document.getElementById("canvas");
context = canvas.getContext("2d");
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
var degreesToRadians = function(degrees)
{
return degrees*Math.PI/180;
}
var rotate = function(x, y, cx, cy, degrees)
{
var radians = degreesToRadians(degrees);
var cos = Math.cos(radians);
var sin = Math.sin(radians);
var nx = (cos * (x - cx)) + (sin * (y - cy)) + cx;
var ny = (cos * (y - cy)) - (sin * (x - cx)) + cy;
return new Vector2(nx, ny);
}
var Vector2 = function(x, y)
{
return {x:x,y:y};
}
var Shape = function(points, color)
{
this.color = color;
this.points = points;
};
Shape.prototype.rotate = function(degrees)
{
var center = this.getCenter();
for (var i = 0; i < this.points.length; i++)
{
this.points[i] = rotate(this.points[i].x,this.points[i].y,center.x,center.y,degrees);
}
context.beginPath();
context.arc(center.x,center.y,35,0,Math.PI*2);
context.closePath();
context.stroke();
}
Shape.prototype.draw = function()
{
context.fillStyle = this.color;
context.strokeStyle = "#000000";
context.beginPath();
context.moveTo(this.points[0].x, this.points[0].y);
for (var i = 0; i < this.points.length; i++)
{
context.lineTo(this.points[i].x, this.points[i].y);
//context.fillText(i+1, this.points[i].x, this.points[i].y);
}
context.closePath();
context.fill();
context.stroke();
}
Shape.prototype.getCenter = function()
{
var center = {x:0,y:0};
for (var i = 0; i < this.points.length; i++)
{
center.x += this.points[i].x;
center.y += this.points[i].y;
}
center.x /= this.points.length;
center.y /= this.points.length;
return center;
}
Shape.prototype.translate = function(x, y)
{
for (var i = 0; i < this.points.length; i++)
{
this.points[i].x += x;
this.points[i].y += y;
}
}
var Rect = function(x,y,w,h,c)
{
this.color = c;
this.points = [Vector2(x,y),Vector2(x+w,y),Vector2(x+w,y+h),Vector2(x,y+h)];
}
Rect.prototype = Shape.prototype;
var r = new Rect(50, 50, 200, 100, "#ff0000");
r.draw();
r.translate(300,0);
r.rotate(30);
r.draw();
</script>
</body>
</html>