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How to build a button to click on and play / stop an audio?

i want to build a image button, that plays an audio.
My Version works but when I want to use it more than once on a site, it only play one mp3, not the other ones.
My Code:
<audio loop="false" src="audio_01.mp3"> </audio>
<p><img alt="" class="hover_pic" src="image.png" style="width: 40%;cursor:pointer" /></p>
<script>
var aud = document.getElementById("ASong").children[0];
var isPlaying = false;
aud.pause();
function playPause() {
if (isPlaying) {
aud.pause();
} else {
aud.play();
}
isPlaying = !isPlaying;
}
</script></div>
and
<div id="BSong" onclick="playPause()" type="button">
<audio loop="false" src="audio_02.mp3"> </audio>
<p><img alt="" class="hover_pic" src="image.png" style="width: 40%;cursor:pointer" /></p>
<script>
var aud = document.getElementById("BSong").children[0];
var isPlaying = false;
aud.pause();
function playPause() {
if (isPlaying) {
aud.pause();
} else {
aud.play();
}
isPlaying = !isPlaying;
}
</script></div>
So you have an idea what the problem is that the button only play one of them on the website?

You are using the same variable names multiple times like aud, isPlayig, etc..
To solve this issue, you should declare only once the whole script and form the onclick="playPause()" send the id of the song you want to play.
Be aware if there is already some music which is playing.

It's hard to tell how your two current code snippets are arranged with respect to each other, but duplicating the code over and over every time you want to add another track is going to be unmaintainable. As it stands, the variables for isPlaying and aud probably overwrite each other, depending on how they're laid out, even if they're in different scripts. Using const or let instead of var and use strict; at the top of your script can help detect these aliases.
You could add closures around each one to keep them distinct, but a better approach is to write a loop (which also acts as a scoping closure) and dynamically add the listener to each element. For example:
const trackEls = [...document.querySelectorAll(".track")];
for (const trackEl of trackEls) {
const audioEl = trackEl.querySelector("audio");
trackEl.addEventListener("click", () => {
audioEl.paused ? audioEl.play() : audioEl.pause();
});
}
<div class="tracks">
<div type="button" class="track">
<audio src="https://upload.wikimedia.org/wikipedia/commons/d/d8/Bourne_woods_2020-11-18_0732.mp3"></audio>
<img alt="play track icon" src="http://placekitten.com/50/50" class="track-icon">
</div>
<div type="button" class="track">
<audio src="https://upload.wikimedia.org/wikipedia/commons/e/ea/Rapid-Acoustic-Survey-for-Biodiversity-Appraisal-pone.0004065.s017.ogg"></audio>
<img alt="play track icon" src="http://placekitten.com/50/50" class="track-icon">
</div>
</div>
Note that the above code lets multiple audio files play at once. If you want to stop all other audio elements when a new one is clicked and reset their time, you can do that with a loop or an extra variable that keeps track of the currently-playing track. For example:
const trackEls = [...document.querySelectorAll(".track")];
let currentTrack;
for (const trackEl of trackEls) {
const audioEl = trackEl.querySelector("audio");
trackEl.addEventListener("click", () => {
if (audioEl !== currentTrack) {
if (currentTrack) {
currentTrack.pause();
currentTrack.currentTime = 0;
}
currentTrack = audioEl;
}
audioEl.paused ? audioEl.play() : audioEl.pause();
});
}
<div class="tracks">
<div type="button" class="track">
<audio src="https://upload.wikimedia.org/wikipedia/commons/d/d8/Bourne_woods_2020-11-18_0732.mp3"></audio>
<img alt="play track icon" src="http://placekitten.com/50/50" class="track-icon">
</div>
<div type="button" class="track">
<audio src="https://upload.wikimedia.org/wikipedia/commons/e/ea/Rapid-Acoustic-Survey-for-Biodiversity-Appraisal-pone.0004065.s017.ogg"></audio>
<img alt="play track icon" src="http://placekitten.com/50/50" class="track-icon">
</div>
</div>
A few remarks on your code:
There's no need for isPlaying variables since audio elements already track their playing/paused state with audioElement.paused. If you track it in external state, you add further complication and room for bugs if your variable and the the audio element's state go out of sync.
Avoid putting a <script> in a <div>. <script> is usually a child of <body> or <head> (probably <body> in this case), after all of the HTML tags are closed.
onclick on an HTML element is generally poor practice. HTML should be structural, not behavioral. Similarly, style="width: 40%;cursor:pointer" should be moved to an external stylesheet and applied to a class.
.children[0]; is a brittle way to select the audio element in a track. If you wind up rearranging elements in the div, this code is liable to break. document.querySelector("#BSong audio") is more precise and robust to refactors, although using classes instead of ids enables easier dynamism so you don't have to type each track out by hand.
CSS classes are usually kebab-case, so hover_pic would be hover-pic.

How to hide an element in if statement?

I am making an html change to a CMS that will affect all pages when the changes are live. I would like this html alert to only affect 1 specific page. I am attempting to do an if statement for the page title.
The logic is that if the page title is Test Article Two then show the html that I have put in place, if not then display=none. With this logic in place, I am viewing the html on all pages not just the one I want it to show.
<div class="container">
<div class="title-wrapper">
<span id="article-banner-country">#countryFullText</span> /
<span id="article-banner-category">#subCatText</span>
<div id="article-banner-title">#pageTitle</div>
<!--page alert -->
<div class="feedback-container content-desktop" id="alert-dialog">
<div class="feedback-left">
<p>Have any feedback? Reach out to us!</p>
</div>
<div class="feedback-right">
<button class="feedback-button">Give Feedback</button>
<button class="feedback-button">Dismiss</button>
</div>
</div>
</div>
</div>
<script>
function showAlert() {
if(#pageTitle === "Test Article Two") {
document.getElementById('alert-dialog').style.display = 'block';
}else {
document.getElementById('alert-dialog').style.display = 'none';
}
}
</script>

I'd recommend changing a class on the body element so that you can use CSS for the styling.
HTML: nothing really changed here
<body>
<div class="container">
<div class="title-wrapper">
<span id="article-banner-country">#countryFullText</span> /
<span id="article-banner-category">#subCatText</span>
<div id="article-banner-title">#pageTitle</div>
<div class="feedback-container content-desktop" id="alert-dialog">
<div class="feedback-left">
<p>Have any feedback? Reach out to us!</p>
</div>
<div class="feedback-right">
<button class="feedback-button">Give Feedback</button>
<button class="feedback-button">Dismiss</button>
</div>
</div>
</div>
</div>
</div>
</body>
javascript: just check the document.title and add the class the the body element
<script>
if(document.title === "Test Article Two") {
document.body.classList.add("show-alert");
}
</script>
Use CSS for the styling. Always hide #alert-dialog and only show it when we add the class to the body.
<style>
#alert-dialog {
display: none;
}
.show-alert #alert-dialog {
display: block;
}
</style>

If you are making static pages or using server side rendering, you could add logic to add a class to show or hide the alert element without adding more javascript to the page. It will have the relevant class(es) when the html is generated and delivered. This way you won't have to create a function, call it and manipulate the DOM after everything is rendered.
I may have missed this in the code above, are you calling the showAlert function anywhere? If not, your alert won't be shown (or will be shown depending on the default styles).
One thing I'd caution against is the imperative nature of the code here. If you wanted to reuse this alert functionality on another page, you'd have to add another more logic to detect another page title every time you wanted to use the alert. Since you are using a CMS, you might consider adding a flag to show the alert, and on this specific page, turn that flag on.
If you wanted to use the function strategy, I'd set your default alert styles:
#alert-dialog {
display: none;
}
.show {
display: block;
}
and try something like this:
<script>
function showAlert() {
if(document.title === "Test Article Two") {
document.getElementById('alert-dialog').classList.add('show');
}
}
document.addEventListener("DOMContentLoaded", showAlert);
</script>
Another alternative is to take a look at the path of the page this is supposed to be on (window.location.pathname) and using regex to see if it matches what you want. I'd recommend that over looking at the title since it's more likely the title of the page will change rather than the url.

In JavaScript, you can access the page title with document.title. You should change the script like this:
function showAlert() {
if(document.title === "Test Article Two") {
document.getElementById('alert-dialog').style.display = 'block';
} else {
document.getElementById('alert-dialog').style.display = 'none';
}
}

Slider - How would you make a simple slider?

EDIT: I WANT MY SLIDER TO BE EASY TO YOU AND ONCE A LINK IS CLICKED THE IMAGE THAT CORRELATES WITH LINK SHOWS.
I'm looking to make a really simple "slider" that if you click a link, the img shows that correlates with it. I've been trying to find something for a bit now and things are either too flash or don't suit my needs. This came close: http://jsfiddle.net/bretmorris/ULNa2/7/
I would something a little simpler that can be applied easily to multiple images for different divs.
This is what my code looks like with just a plain img tag to it:
<div id="adobe_content" class="hdiv"><button class="x">X</button>
<img src="images/adobefront.png"><br>
<img src="images/adobeinside.png"><br>
<img src="images/adobeback.png"><br>
<h5>Adobe Brochure</h5>
<p>
I wanted to make something functional and out the box that Adobe might consider giving out. It's clean like their work and sparks interest in opening the brochure with the cut out in the center. The front flap is able to slide into a slot on the right side for a neat logo. They're now more interested in their cloud, but the information is inside is still relevant!
</p>
<b>Programs used: Adobe Illustrator, InDesign and Photoshop.</b>
</div>
The code doesn't work for me because, well I partially don't understand it, and I'm not sure how to make it suit my needs (especially if I got up to multiple images) like correlating with an image.

Perhaps understanding what is going on would maybe get you on the right track, so here is an explanation:
$('a.prev').click(function() {
prevSlide($(this).parents('.slideshow').find('.slides'));
});
//clicking image goes to next slide
$('a.next, .slideshow img').click(function() {
nextSlide($(this).parents('.slideshow').find('.slides'));
});
This part is relatively straightforward, when you click on the previous or next links, call the prevSlide or nextSlide function, passing the collection of slides as an argument.
//initialize show
iniShow();
function iniShow() {
//show first image
$('.slideshow').each(function() {
$(this).find('img:first').fadeIn(500);
})
}
Initialize the slideshow by finding each slideshow on the page and fading in the first image. $(this) refers to the <div class="slideshow"> parent, find all child image tags and take the first, fade that element in (and do it in 500 milliseconds).
function prevSlide($slides) {
$slides.find('img:last').prependTo($slides);
showSlide($slides);
}
function nextSlide($slides) {
$slides.find('img:first').appendTo($slides);
showSlide($slides);
}
The prevSlide and nextSlide functions both rearrange the order of images, this line in particular:
$slides.find('img:first').appendTo($slides);
Is moving the first image to the end of the images, so:
<img src="http://placekitten.com/300/500" width="300" height="500" />
<img src="http://placekitten.com/200/400" width="200" height="400" />
<img src="http://placekitten.com/400/400" width="500" height="400" />
becomes:
<img src="http://placekitten.com/200/400" width="200" height="400" />
<img src="http://placekitten.com/400/400" width="500" height="400" />
<img src="http://placekitten.com/300/500" width="300" height="500" />
$slides.find('img:last').prependTo($slides); does the inverse and moves the last image to the beginning.
function showSlide($slides) {
//hide (reset) all slides
$slides.find('img').hide();
//fade in next slide
$slides.find('img:first').fadeIn(500);
}
Finally, showSlide accepts the collection of images, hides all of them and then fades in the first image (since the collection is reordered each time, the first is a different image).
Now, if you want a link for each image that will display a corresponding image, you could do something as simple as:
<a class="image" data-src="http://placekitten.com/300/500">Kitten 1</a>
<a class="image" data-src="http://placekitten.com/200/400">Kitten 2</a>
<a class="image" data-src="http://placekitten.com/400/500">Kitten 3</a>
<div id="image-container">
<img src="http://placekitten.com/300/500" />
</div>
and something like the following:
$('.image').on('click', function() {
var imageSrc = $(this).data('src');
$('#image-container img').prop('src', imageSrc);
});
Which will update the child image tag of <div id="image-container"> with the data-src attribute value in the clicked link.
http://jsfiddle.net/9sxt6n0t/
Hope this helps.

just a quick function to slide
function slideIt(images , prev , next){
$('.slideshow img:nth-child(1)').show();
var imagesLength = $(images).length;
var i = 1;
$(prev).click(function() {
$(images).hide();
if(i !== 1){
$(images + ':nth-child('+ (i - 1) +')').show();
i--;
}else{
$(images +':nth-child('+imagesLength +')').show();
i = imagesLength;
}
});
//clicking image goes to next slide
$(''+next+','+images+'').on('click',function() {
$(images).hide();
if(i !== imagesLength){
$(images + ':nth-child('+ (i + 1) +')').show();
i++;
}else{
$(images + ':nth-child(1)').show();
i = 1;
}
});
}
and use like that slideIt(Images , prevArrow , nextArrow)
slideIt('.slideshow img','a.prev' , 'a.next');
DEMO HERE

How to use jquery to swap the position of multiple images on click

I'm a novice at jquery/javascript, so apologies in advance if this is a dumb question.
I have 3 images and I want to be able to change their position when a user clicks either the second or the third one. For example, if the user clicks image #2, I want image #2 to become image #1 (left-most), then image #3 becomes image #2 (middle) and finally image #1 becomes image #3 (right-most). If the user clicks image #3, I want image #3 to become image #1 (left-most), then image #1 becomes image #2 (middle) and finally image #2 becomes image #3 (right-most).
If the user clicks the first image, I don't want anything to happen.
Here is my code:
<!DOCTYPE html>
<html>
<head>
<title>ImageSwap</title>
<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function () {
var img = new Array("http://i.imgur.com/QWso5yB.png", "http://i.imgur.com/O4X3egC.png", "http://i.imgur.com/w3p2qLp.png");
$('#first').bind('click', firstChannel);
$('#second').bind('click', secondChannel);
});
function firstChannel() {
var tempImg = img[0];
img[1] = img[2];
img[2] = tempImg;
$('#home').attr('src',img[0]);
$('#first').attr('src',img[1]);
$('#second').attr('src',img[2]);
};
function secondChannel() {
var tempImg = img[0];
img[0] = img[2];
img[2] = img[1];
img[1] = tempImg;
$('#home').attr('src',img[0]);
$('#first').attr('src',img[1]);
$('#second').attr('src',img[2]);
};
</script>
</head>
<body>
<img id="home" src="http://i.imgur.com/QWso5yB.png">
<img id="first" src="http://i.imgur.com/O4X3egC.png">
<img id="second" src="http://i.imgur.com/w3p2qLp.png">
</body>
</html>
When clicking the 2nd and 3rd images, nothing happens. What the heck am I doing wrong here? Is there an easier way to do this? I've been pulling my hair out searching everywhere but can't seem to find an answer. Many thanks in advance for any feedback you can give me...

Why not make it simple? jsBin demo
A parent element:
<div id="channels">
<img src="http://i.imgur.com/QWso5yB.png">
<img src="http://i.imgur.com/O4X3egC.png">
<img src="http://i.imgur.com/w3p2qLp.png">
</div>
and some prepend():
$(function () {
var $chn = $("#channels");
$chn.on("click","img", function(){
$chn.prepend( this );
});
});
I mean, if the first image represents the current channel, than all you need to do (as above) is to prepend the clicked element. To style the first element simply use CSS img:first-child
EDIT: KEEP ORDER
jsBin demo with Order
If appending creates at some point a mess of channels order,
I'd suggest you to:
Create a MAIN or currently watching big image and place all channels inside a parent:
<img id="current">
<div id="channels">
<img src="//placehold.it/90x40/a7b&text=1">
<img src="//placehold.it/90x40/ba7&text=2">
<img src="//placehold.it/90x40/7ba&text=3">
<img src="//placehold.it/90x40/bb7&text=4">
<img src="//placehold.it/90x40/77a&text=5">
<img src="//placehold.it/90x40/ab7&text=6">
</div>
Than on a channel-click, set the clicked image src to the BIG image, and hide the clicked one:
$(function () {
var $img = $("#channels").find("img");
var $current = $("#current"); // The big image
$img.on("click", function(){
$current[0].src = this.src;
$img.show();
$(this).hide();
}).eq(0).click();
});
Example with a better UI

How make a popup work

I am trying to develop a popup feature when you click on an Image the image opens up as a popup. Here is the example
http://soumghosh.com/otherProjects/natalierosscms/175-2/
Click on the first image and close it. Then click on the second image. The images are repeating. Any ideas what I am doing wrong? For some reason I am not able to post code here.
JavaScript:
$('.alignnone').click(function(){
$('.overlay').appendTo('body');
$('.overlay').show();
var popImage = $('.projectContainer').show();
var thumbHolder = $(this).parent();
thumbHolder.css('position', 'relative');
$(this).clone().appendTo('.projectContainer');
var cssAtrOne = {
padding:'10px',
width:'110%'
};
popImage.appendTo(thumbHolder).css(cssAtrOne);
});
$('.closeButton').click(function(){
$('.overlay').hide();
$('.projectContainer').hide();
});
HTML:
<!-- clickable image -->
<img src="http://soumghosh.com/otherProjects/natalierosscms/wp-content/uploads/2013/03/T1Main.jpg" alt="T1Main" width="559" height="745" class="alignnone size-full wp-image-181">
<!-- popup -->
<div class="projectContainer" style="padding: 10px; width: 110%; display: block;">
<img class="closeButton" src="/otherProjects/natalierosscms/wp-content/themes/twentyeleven/images/closeButton.png">
</div>

You have this:
$(this).clone().appendTo('.projectContainer');
You're appending the image to the projectContainer without clearing the projectContainer first (So images just continue to build up each time). So what you'll need to do is clear out the previous images, then insert the new one.
But inside projectContainer is your close button, which makes things a wee bit tricker. There are many ways to work around this issue, but a straight-forward solution would be to introduce another <div>, imageContainer inside projectContainer:
HTML:
<div class="projectContainer" style="display: none; padding: 10px; width: 110%;">
<img class="closeButton" src="/otherProjects/natalierosscms/wp-content/themes/twentyeleven/images/closeButton.png">
<div class="imageContainer"></div>
</div>
Then modify your JS:
Change JS:
//REPLACE the contents of imageContainer, not append to it.
//$(this).clone().appendTo('.projectContainer');
$('.projectContainer > .imageContainer').html($(this).clone());
Something to that effect should work.