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Javascipt replacing exact numbers in an array

am trying to replace numbers in an array but am facing an issue which am not really able to correctly manage regarding how to correctly target the just one data I really have to change.
I'll make an example to have more accuracy on describing it.
Imagine my data array look like that:
["data", "phone numbers", "address"]
I can change numbers via following script but my first problem is that it makes no differences between the number it find in columns, for example "phone numbers" from "address" (at the moment am not using it, but should I include a ZIP code in the address it would be really be a problem)
Beside, my second and current problem with my script, is that obviosuly in the same "phone numnbers" a number may appear more times while I'd like to affect only the first block of the data - let's say to add/remove the country code (or even replace it with it's country vexillum) which I normally have like that "+1 0000000000" or "+54 0000000000"
So if a number is for example located in EU it really make this script useless: Spain is using "+34" while France "+33" and it wouldn't succeded in any case becouse it recognize only "+3" for both.
I've found some one else already facing this problems which seems to solved it wrapping the values inside a buondaries - for example like that "\b"constant"\b" - but either am wronging syntax either it does not really apply to my case. Others suggest to use forEach or Array.prototype.every which I failed to understand how to apply at this case.
Should you have other ideas about that am open to try it!
function phoneUPDATES(val)
{
var i= 0;
var array3 = val.value.split("\n");
for ( i = 0; i < array3.length; ++i) {
array3[i] = "+" + array3[i];
}
var arrayLINES = array3.join("\n");
const zero = "0";
const replaceZERO = "0";
const one = "1";
const replaceONE = "1";
const result0 = arrayLINES.replaceAll(zero, replaceZERO);
const result1 = result0.replaceAll(one, replaceONE);
const result2 = result1.replaceAll(two, replaceTWO);
const result3 = result2.replaceAll(thre, replaceTHREE);
const result4 = result3.replaceAll(four, replaceFOUR);
const result5 = result4.replaceAll(five, replaceFIVE);
const result6 = result5.replaceAll(six, replaceSIX);
const result7 = result6.replaceAll(seven, replaceSEVEN);
const result8 = result7.replaceAll(eight, replaceEIGHT);
const result9 = result8.replaceAll(nine, replaceNINE);
const result10 = result9.replaceAll(ten, replaceTEN);
const result11 = result10.replaceAll(eleven, replaceELEVEN);

Why not use a regex replace, you could do something like /(\+\d+ )/g which will find a + followed by one or more digits followed by a space, and then you can strip out the match:
const phoneNumbers = [, "+54 9876543210"]
console.log(phoneNumbers.map((num) => num.replaceAll(/(\+\d+ )/g, '')))
If you need to only target the second element in an array, i'd imagine your data looks like
const data = [["data", "+1 1234567890, +1 5555555555", "address"], ["data", "+11 111111111, +23 23232323", "address"]];
console.log(data.map((el) => {
el[1] = el[1].replaceAll(/(\+\d+ )/g, '');
return el;
}))

ok, this almost is cheating but I really didn't thought it before and, by the way does, not even actually solve the problems but jsut seems to work around it.
If I call the replacemente in decreasing order that problem just does not show up becouse condition of replacement involving higher numbers are matched before the smaller one.
but should some one suggest a complete "true code comply" solution is wellcome

Leading and trailing zeros in numbers

I am working on a project where I require to format incoming numbers in the following way:
###.###
However I noticed some results I didn't expect.
The following works in the sense that I don't get an error:
console.log(07);
// or in my case:
console.log(007);
Of course, it will not retain the '00' in the value itself, since that value is effectively 7.
The same goes for the following:
console.log(7.0);
// or in my case:
console.log(7.000);
JavaScript understands what I am doing, but in the end the actual value will be 7, which can be proven with the following:
const leadingValue = 007;
const trailingValue = 7.00;
console.log(leadingValue, trailingValue); // both are exactly 7
But what I find curious is the following: the moment I combine these two I get a syntax error:
// but not this:
console.log(007.000);
1) Can someone explain why this isn't working?
I'm trying to find a solution to store numbers/floats with the exact precision without using string.
2) Is there any way in JS/NodeJS or even TypeScript to do this without using strings?
What I currently want to do is to receive the input, scan for the format and store that as a separate property and then parse the incoming value since parseInt('007.000') does work. And when the user wants to get this value return it back to the user... in a string.. unfortunately.

1) 007.000 is a syntax error because 007 is an octal integer literal, to which you're then appending a floating point part. (Try console.log(010). This prints 8.)
2) Here's how you can achieve your formatting using Intl.NumberFormat...
var myformat = new Intl.NumberFormat('en-US', {
minimumIntegerDigits: 3,
minimumFractionDigits: 3
});
console.log(myformat.format(7)); // prints 007.000

Hi
You can use an aproach that uses string funtions .split .padStart and .padEnd
Search on MDN
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padStart
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/padEnd
Here you have an example:
const x = 12.1;
function formatNumber( unformatedNumber) {
const desiredDecimalPad = 3;
const desiredNonDecimalPad = 3;
const unformatedNumberString = unformatedNumber.toString();
const unformatedNumberArr = unformatedNumberString.split('.');
const decimalStartPadded = unformatedNumberArr[0].padStart(desiredDecimalPad, '0');
const nonDecimalEndPadded = unformatedNumberArr[1].padEnd(desiredNonDecimalPad, '0');
const formatedNumberString = decimalStartPadded + '.' + nonDecimalEndPadded;
return formatedNumberString;
}
console.log(formatNumber(x))

d3.format thousand separator on variables?

Hello I'm yet again stuck on d3...
I'd like to know how to use a thousand seperator on a variable all the examples I've managed to find seem to be on static data.
This is what I've tried so far:
d3.csv("OrderValueToday.csv", function(obj) {
var text = 'Today = £';
var totalSales = text + d3.format(",") + obj[0].Today;
svgLabel = d3.select("#label").append("h2")
.text (totalSales);
});
However it just outputs a load a stuff on the webpage this is it:
Today = £function (n){var e=d;if(m&&n%1)return"";var u=0>n||0===n&&0>1/n?(n=-n,"-"):a; if(0>p){var c=Zo.formatPrefix(n,h);n=c.scale(n),e=c.symbol+d}else n*=p;n=g(n,h);var x=n.lastIndexOf("."),M=0>x?n:n.substring(0,x),_=0>x?"":t+n.substring(x+1);!s&&f&&(M=i(M));var b=v.length+M.length+_.length+(y?0:u.length),w=l>b?new Array(b=l-b+1).join(r):"";return y&&(M=i(w+M)),u+=v,n=M+_,("<"===o?u+n+w:">"===o?w+u+n:"^"===o?w.substring(0,b>>=1)+u+n+w.substring(b):u+(y?n:w+n))+e}20000
So all I want is to be able to make the totalSales value have thousand separators so like 20,000 everything else I've tried doesnt do anything. I've read this https://github.com/mbostock/d3/wiki/Formatting but didnt see what I could do for my scenario.
Any help would be greatly appreciated. Cheers

Specifying a d3.format returns a formatting function, which you must then call as a function, passing in the number to be formatted as an argument:
var myNumber = 22400;
d3.format(',')(myNumber); // returns '22,400'
Sometimes you will see a format function stored as a variable like this:
var commaFormat = d3.format(',');
commaFormat(1234567); // returns '1,234,567'
In your case, you could do the following:
var totalSales = text + d3.format(',')(obj[0].Today);

Finding the difference between two fields using JavaScript in iText

I would like to find difference between two fields using JavaScript in iText.
I am able to find the sum of them using below code:
PdfStamper stamperResult = new PdfStamper(readersectionResult, new FileOutputStream(RESULT_NEW));
stamperResult .addJavaScript("var nameField = this.getField(\"total\");"+ "nameField.setAction(\"Calculate\",'AFSimple_Calculate(\"SUM\",\"total1\", \"total2\")')");
Is there any way to find the difference using 'AFSimple_Calculate' similar to what I did in the above code snippet?
Thanks for editing! I tried your suggestion but it does not seem to work for some reason.
stamperResult.addJavaScript(" var total1 = this.getField(\"value1\"); var total2 = this.getField (\"value2\"); var subtr = this.getField(\"total\"); subtr.value = total1.value - total2.value;");
I separated newlines by spaces and added right escape characters.
I was also thinking of using a different logic for subtraction using AF methods : like this
stamperResult.addJavaScript("var nameField = this.getField(\"total\");"+ "nameField.setAction(\"Calculate\",'AFSimple_Calculate(\"SUM\",\"total1\", \"-total2\")')");
In the above code I was trying to add -(negative value) to total 2 so that it will be subtracted from total1 though the AF method is still 'SUM'.
But that does not work.
The below simple code seem to work :
stamperResult.addJavaScript("var nameField = this.getField('total');" +
"nameField.setAction('Calculate'," +
"'subtract()');" +
"" +"function subtract(){this.getField('total').value
= (this.getField('total_1').value -this.getField('total_2').value); }");

I updated your question because it contained many spelling errors. I didn't edit the code snippet because I don't know what the original code snippet is like. In any case: I think something went wrong during the copy/paste process, as I don't think your code snippet compiles in its current state.
In any case: as far as I know the AF-methods (the AF stands for Adobe Forms) may not be present in every viewer, and as far as I know Adobe didn't implement a way to subtract values from each other in the AFSimple_Calculate method.
For these two reasons, you may prefer regular JavaScript instead of using a pre-canned function that may or may not be pre-canned.
This regular JavaScript may look like this:
var total1 = this.getField("total1");
var total2 = this.getField("total2");
var subtr = this.getField("difference");
subtr.value = total1.value - total2.value;
I'm not sure if that answers your question. Maybe you just want:
var total1 = this.getField("total1");
var total2 = this.getField("total2");
var namefield = total1.value - total2.value;
You can put these lines inside a String using the right escape characters and replacing the newlines by spaces or newline characters.
Of course, you need to trigger this code somewhere. Below you'll find an example that puts the negative value of the content of a value1 field into a value2 field.
public static void main(String[] args) throws IOException, DocumentException {
Document document = new Document();
PdfWriter writer = PdfWriter.getInstance(document, new FileOutputStream("js.pdf"));
document.open();
writer.addJavaScript("function makeNegative() { this.getField('value2').value = -(this.getField('value1').value); } ");
Rectangle rect1 = new Rectangle(40, 740, 200, 756);
TextField value = new TextField(writer, rect1, "value1");
value.setBorderColor(GrayColor.GRAYBLACK);
value.setBorderWidth(0.5f);
PdfFormField field = value.getTextField();
field.setAdditionalActions(PdfName.BL, PdfAction.javaScript("makeNegative();", writer));
writer.addAnnotation(field);
Rectangle rect2 = new Rectangle(40, 710, 200, 726);
TextField neg = new TextField(writer, rect2, "value2");
neg.setBorderColor(GrayColor.GRAYBLACK);
neg.setBorderWidth(0.5f);
writer.addAnnotation(neg.getTextField());
document.close();
}
Note that I used a Blur action. This means the method will be triggered as soon as you select another field after filling out the value1 field.

ExtJS 4.1.1: Evaluating a field in a grid

I'm struggling with a ExtJS 4.1.1 grid that has editable cells (CellEditing plugin).
A person should be able to type a mathematic formula into the cell and it should generate the result into the field's value. For example: If a user types (320*10)/4 the return should be 800. Or similar if the user types (320m*10cm)/4 the function should strip the non-mathematical characters from the formula and then calculate it.
I was looking to replace (or match) with a RegExp, but I cannot seem to get it to work. It keeps returning NaN and when I do console.log(e.value); it returns only the originalValue and not the value that I need.
I don't have much code to attach:
onGridValidateEdit : function(editor,e,opts) {
var str = e.value.toString();
console.log(str);
var strCalc = str.match(/0-9+-*\/()/g);
console.log(strCalc);
var numCalc = Number(eval(strCalc));
console.log(numCalc);
return numCalc;
},
Which returns: str=321 strCalc=null numCalc=0 when I type 321*2.
Any help appreciated,
GR.
Update:
Based on input by Paul Schroeder, I created this:
onGridValidateEdit : function(editor,e,opts) {
var str = e.record.get(e.field).toString();
var strCalc = str.replace(/[^0-9+*-/()]/g, "");
var numCalc = Number(eval(strCalc));
console.log(typeof numCalc);
console.log(numCalc);
return numCalc;
},
Which calculates the number, but I am unable to print it back to the grid itself. It shows up as "NaN" even though in console it shows typeof=number and value=800.
Final code:
Here's the final code that worked:
onGridValidateEdit : function(editor,e,opts) {
var fldName = e.field;
var str = e.record.get(fldName).toString();
var strCalc = str.replace(/[^0-9+*-/()]/g, "");
var numCalc = Number(eval(strCalc));
e.record.set(fldName,numCalc);
},

Lets break this code down.
onGridValidateEdit : function(editor,e,opts) {
var str = e.value.toString();
What listener is this code being used in? This is very important for us to know, here's how I set up my listeners in the plugin:
listeners: {
edit: function(editor, e){
var record = e.record;
var str = record.get("your data_index of the value");
}
}
Setting it up this way works for me, So lets move on to:
var strCalc = str.match(/0-9+-*\/()/g);
console.log(strCalc);
at which point strCalc=null, this is also correct. str.match returns null because your regex does not match anything in the string. What I think you want to do instead is this:
var strCalc = str.replace(/[^0-9+*-]/g, "");
console.log(strCalc);
This changes it to replace all characters in the string that aren't your equation operators and numbers. After that I think it should work for whole numbers. I think that you may actually want decimal numbers too, but I can't think of the regex for that off the top of my head (the . needs to be escaped somehow), but it should be simple enough to find in a google search.