jQuery How To Use Backticks In Append [closed] - javascript

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I wanted to interpolate variables in strings in JS so I used ``(backticks) as shown here -
How To Interpolate Variables In String in JS
Then, I Wanted To put IF-Statements in jQuery Append So I got this -
IF Statements In jQuery Append
But When I use Both Together , Backticks Don't Output Text As Usual-
$("main").append(`Hello ${my_var}`+(second_var>1?"hi ":"bye")+`Bye ${my_var})`
This Results Only In "hi" , The Backticks Before And After The Ternary Operator Don't Output Anything.
HELP ??

You can do something like the below.
const my_var = "Name";
const seconde_var = 2;
console.log(`Hello ${my_var} ${seconde_var >1 ? "hi": "bye"} bye ${my_var}`);

Related

How to remove underscores from a string array in typescript-angular project? [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 months ago.
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i want to replace all the "_" occurrences from an array like this (TASK_1,TASK_2,TASK_3).
I receive this from the back-end and i cannot use the replace all because the project doesn't support es2021. I need to display the array like this (TASK 1,TASK 2, TASK 3).
I tried this method:
formatWithoutUnderScore(valueToFormat:any) {
return valueToFormat.map((value:any) => value.replace(/_/g, ' '));
}
and the used it:
this.formatWithoutUnderScore(this.totalTasks);
But it does nothing :(
Can someone help?
this.totalTasks = this.formatWithoutUnderScore(this.totalTasks);

Javascript if statement: Which pair of characters in this code is optional? [closed]

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Closed 2 years ago.
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I've was given this is a multiple choice JS question. I said [], I just wanted to check if this is correct and if not why?
Consider this if statement:
if (loggedIn) {
body_classes = ["user-active"];
}
Which pair of characters in this code is optional?
""
()
{}
[]
The optional characters are the braces {}
if (loggedIn) {
body_classes = ["user-active"];
}
is the same as
if (loggedIn)
body_classes = ["user-active"];
If you remove the square brackets then body_classes becomes a string rather than an array.

Why are consts different to simple objects javascript [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
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when i work in javascript canvas, when i created a basic object for aqngles like thius
const Angle =
{
Beginning:0*Math.PI,
OneQuarter:0.5*Math.PI,
TwoQuarter:1.0*Math.PI,
End:2*Math.Pi
}
and when i console log the outputs i get this:
0
NaN
but at the same time when i create unique consts for each like so:
const
startAngle = 0*Math.PI,
endAngle = 2*Math.PI;
and i console log it i get the response i want:
0
6.283185307179586
why does this happen? and how can i create a simple object with calculation and get a correct response? Thanks
Repl page:
https://repl.it/#Ballatoilet/EMDR
You have typo, it should be End:2*Math.PI and you have End:2*Math.Pi (small "i" letter).

Simple javascript for selecting random element out of array outputting "undefined" on 2 elements (jsfiddle included) [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 years ago.
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Below is my code, for some reason it outputs undefined for ['6'] & ['7'], all the other ones work. I don't understand what is going wrong.
var array = [
['1'],
['2'],
['3'],
['4'],
['5'],
['6']
['7'],
['8'],
['9'],
['10']
];
if(document.getElementById("random-element")) {
var rand = array[Math.floor(Math.random() * array.length)];
document.getElementById('random-element').innerHTML = rand;
}
https://jsfiddle.net/ggky7a03/
You missed a comma in your array, which will explain why those 2 values are not returning (they don't exist)
Side note, array is a reserved word in JS, so you can't (shouldn't) use it for your variable name, so change it to
var myAwesomeArray = [
// or similar
Here's your fixed code

JavaScript match() function does not give output [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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In JavaScript code I use regular expression match() function to find pattern and show the result, but it does not give a proper answer, means finding [i] character in giving sentences
<button onclick = "searchPattern()">pattern</button><br>
<p id = "demo"></p>
<script>
function searchPattern(){
var str = "Visti W3Schools!";
var paat = /[i]/g;
var result = str.match(patt);
document.getElementById("demo").innerHTML = result;
}
</script>
Read your JavaScript console
Uncaught ReferenceError: patt is not defined
You changed your variable name from paat to patt half way through your code.

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