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How to convert this Array to Object

I can't seem to find the answer, how to change array in array to object in array ..??
problem this in javaScript. How to convert? How to convert?
I have this array.
[
"or",
[
"or",
{
"status": 1
},
{
"verified": 1
}
],
[
"and",
{
"social_account": 1
},
{
"enable_social": 1
}
]
]
I want this object:
{
"or": [
{
"or": [
{
"status": 1
},
{
"verified": 1
}
]
},
{
"and": [
{
"social_account": 1
},
{
"enable_social": 1
}
]
}
]
}

You can use a recursive function. The base case is when the argument is not an array. In the other case, extract the first array value as key for the object, and map the rest of the array via the recursive function:
const convert = data => Array.isArray(data) && ["or","and"].includes(data[0])
? { [data[0]]: data.slice(1).map(convert) }
: data;
// demo:
let data = ["or",
["or", {"status": 1}, {"verified": 1}],
["and",{"social_account": 1}, {"enable_social": 1}]
];
console.log(convert(data));

How to create a sub-associative object from a list of array keys in JavaScript?

I have an object from user input. The keys to that object are separated by commas, and I just want to separate those keys and make the keys of the object.
The key_array below is dynamic from user input, generates a different array each time, below I give you an example.
I have shown the object in my code which you can see below. you can also see the output by running that code.
var main_array = {};
var key_array = {
'user,name' : 'user name',
'user,email' : 'Email address',
'order,id' : 123456,
'order,qty' : 2,
'order,total' : 300,
'order,product,0,name' : "product1",
'order,product,0,qty' : 1,
'order,product,0,price' : 100,
'order,product,1,name' : "product2",
'order,product,1,qty' : 1,
'order,product,1,price' : 200,
};
for (keys in key_array){
var value = key_array[keys];
// What do I do here to get the output I want?
main_array['[' + keys.split(",").join('][')+ ']'] = value;
}
console.log(main_array);
Running the code above will give you the following output which is incorrect. And the output I don't want.
{
[order][id]: 123456,
[order][product][0][name]: "product1",
[order][product][0][price]: 100,
[order][product][0][qty]: 1,
[order][product][1][name]: "product2",
[order][product][1][price]: 200,
[order][product][1][qty]: 1,
[order][qty]: 2,
[order][total]: 300,
[user][email]: "Email address",
[user][name]: "user name"
}
I want an output like JSON below, so please tell me how to do it.
{
"user":{
"email" : "Email address",
"name" : "user name"
},
"order":{
"id" : 123456,
"qty" : 2,
"total" : 300,
"product":[
{
"name" : "product1",
"price" : 100,
"qty" : 1
},{
"name" : "product2",
"price" : 200,
"qty" : 1
}
]
}
}
Note: Please do not use eval, as using eval in this way is terribly unreliable, bad work and unsafe. Because I get all my data from user input, the likelihood of abuse can increase.

Use Object.entries to go over key and values of object.
Split the key by , separator and then build the object.
While building object, make sure to merge the keys and values using mergeTo method.
Then convert the objects which has the numerical keys then convert to object using convertObjsToArray method.
var key_array = {
"user,name": "user name",
"user,email": "Email address",
"order,id": 123456,
"order,qty": 2,
"order,total": 300,
"order,product,0,name": "product1",
"order,product,0,qty": 1,
"order,product,0,price": 100,
"order,product,1,name": "product2",
"order,product,1,qty": 1,
"order,product,1,price": 200
};
const mergeTo = (target, obj) => {
Object.entries(obj).forEach(([key, value]) => {
if (typeof value === "object" && !Array.isArray(value)) {
if (!target[key]) {
target[key] = {};
}
mergeTo(target[key], obj[key]);
} else {
target[key] = value;
}
});
};
const convertObjsToArray = obj => {
Object.entries(obj).forEach(([key, value]) => {
if (typeof value === "object") {
if (Object.keys(value).every(num => Number.isInteger(Number(num)))) {
obj[key] = Object.values(value);
} else {
convertObjsToArray(obj[key]);
}
}
});
};
const res = {};
Object.entries(key_array).map(([key, value]) => {
const keys = key.split(",");
let curr = { [keys.pop()]: value };
while (keys.length > 0) {
curr = { [keys.pop()]: curr };
}
mergeTo(res, curr);
});
convertObjsToArray(res);
console.log(res);

You can create the objects and keys required from the string dynamically, take each key and split it to an array using split(','). Using each item in the array create the structure required. Assuming if a key is a number, then it's parent must be an array.
Object.keys(key_array).forEach(key => {
const path = key.split(',');
let current = main_array;
for (let i = 0; i < path.length - 1; i++) {
if (!current[path[i]]) {
current[path[i]] = path[i + 1] && !isNaN(path[i + 1]) ? [] : {};
}
current = current[path[i]];
}
current[path.pop()] = key_array[key];
});
console.log(main_array); // Desired result

Combine two arrays into one by matching elements using Javascript

I have two arrays. One fetched from an API the other fetched from firebase. They both have a similar key inside of them, that being the tld. As seen below.
API Array
[
{
"tld" : "com",
"tld_type": 1,
},
"tld" : "org",
"tld_type" : 1,
}
]
Firebase Array
[
{
"TLD" : "com",
"register_price" : 14.99
},
{
"TLD" : "org",
"register_price" : 15.99
}
]
I want to combine these two arrays into one and return it like below
[
{
"tld" : "com",
"tld_type" : 1,
"register_price" : 14.99
},
{
"tld" : "org",
"tld_type" : 1,
"register_price" : 15.99
}
]
I've done some google searching and found concact but that doesn't seem to be using the key to find the match. How would I do this?

You can use map and create a new object whose keys and values will be from the other two arrays and return that object. map will create a new array of objects
let api = [{
"tld": "com",
"tld_type": 1,
},
{
"tld": "org",
"tld_type": 1,
}
]
let fb = [{
"TLD": "com",
"register_price": 14.99
},
{
"TLD": "org",
"register_price": 15.99
}
]
let k = api.map(function(item, index) {
let obj = {};
obj.tld = item.tld;
obj['tld_type'] = item['tld_type'];
obj['register_price'] = fb[index]['register_price']
return obj;
});
console.log(k)

There is no unique method for solving that kind of issue. You'll have to loop through all elements and add register_price property if that property exists in firebase array. In shortest possible:
let combined = apiArray.map(ele=>{
let machedElement = fbArray.find(e => e.TLD === ele.tld)
if(machedElement != undefined) ele.register_price = machedElement.register_price
return ele
})
In case if you want to merge all properties not only register_price:
let combined = apiArray.map(ele=>{
let machedElement = fbArray.find(e => e.TLD === ele.tld)
if(machedElement != undefined) {
let mergedObject = Object.assign(ele, machedElement)
return mergedObject
}else{
return ele
}
})

I don't know how to implementate the function reduce

I do not know how to implement the reduce function.
I have output from my map a document as ...
for example two documents
key "_id":"AD"
"values"
{
"numtweets" : 1,
"hastags" : {
"OPINIÓ" : 1,
"debat" : 1,
"inexistent" : 1,
"tampoc" : 1,
"promet" : 1,
"gaire" : 1,
"diàleg" : 1
}
}
and other
{
"numtweets" : 1,
"hastags" : {
"other" : 1,
"debat" : 1,
"inexistent" : 1,
"another" : 1,
}
}
I need a function that reduces all sum so that
"numtweets" : 2,
"dicwords" : {
"OPINIÓ" : 1,
"debat" : 2,
"inexistent" : 2,
"tampoc" : 1,
"promet" : 1,
"gaire" : 1,
"diàleg" : 1,
"other" : 1,
"another" : 1
},
"lisuser" : {
"user2" : 1
}
if my json values was only nuwtweets the reduce is
function(key, values) {
return Array.sum(values);
};
if mi json values only was hastags (without numtweets and lisuser) the reduce function was
var r = function(key, values) {
result = {}
values.forEach(function(val) {
for (hashtag in val) {
if (hashtag in result) {
result[hashtag] = result[hashtag] + val[hashtag]
} else {
result[hashtag] = val[hashtag]
}
}
});
return(result)
};
But I don't know how mix the 2 reduce function.
My level of mongodb and JavaScript is very low.
Thanks

Try this:
let data = values.reduce((finalObj, ele) => {
finalObj.numtweets += ele.numtweets
for (key in ele.hastags) {
if(ele.hastags.hasOwnProperty(key)) {
if(finalObj.hastags[key])
finalObj.hastags[key] += ele.hastags[key]
else
finalObj.hastags[key] = ele.hastags[key]
}
}
return finalObj
})
console.log(data)
Where values is array for objects which you want reduce to one object

Removing duplicate objects with Underscore for Javascript

I have this kind of array:
var foo = [ { "a" : "1" }, { "b" : "2" }, { "a" : "1" } ];
I'd like to filter it to have:
var bar = [ { "a" : "1" }, { "b" : "2" }];
I tried using _.uniq, but I guess because { "a" : "1" } is not equal to itself, it doesn't work. Is there any way to provide underscore uniq with an overriden equals function?

.uniq/.unique accepts a callback
var list = [{a:1,b:5},{a:1,c:5},{a:2},{a:3},{a:4},{a:3},{a:2}];
var uniqueList = _.uniq(list, function(item, key, a) {
return item.a;
});
// uniqueList = [Object {a=1, b=5}, Object {a=2}, Object {a=3}, Object {a=4}]
Notes:
Callback return value used for comparison
First comparison object with unique return value used as unique
underscorejs.org demonstrates no callback usage
lodash.com shows usage
Another example :
using the callback to extract car makes, colors from a list

If you're looking to remove duplicates based on an id you could do something like this:
var res = [
{id: 1, content: 'heeey'},
{id: 2, content: 'woah'},
{id: 1, content:'foo'},
{id: 1, content: 'heeey'},
];
var uniques = _.map(_.groupBy(res,function(doc){
return doc.id;
}),function(grouped){
return grouped[0];
});
//uniques
//[{id: 1, content: 'heeey'},{id: 2, content: 'woah'}]

Implementation of Shiplu's answer.
var foo = [ { "a" : "1" }, { "b" : "2" }, { "a" : "1" } ];
var x = _.uniq( _.collect( foo, function( x ){
return JSON.stringify( x );
}));
console.log( x ); // returns [ { "a" : "1" }, { "b" : "2" } ]

When I have an attribute id, this is my preffered way in underscore:
var x = [{i:2}, {i:2, x:42}, {i:4}, {i:3}];
_.chain(x).indexBy("i").values().value();
// > [{i:2, x:42}, {i:4}, {i:3}]

Using underscore unique lib following is working for me, I m making list unique on the based of _id then returning String value of _id:
var uniqueEntities = _.uniq(entities, function (item, key, a) {
return item._id.toString();
});

Here is a simple solution, which uses a deep object comparison to check for duplicates (without resorting to converting to JSON, which is inefficient and hacky)
var newArr = _.filter(oldArr, function (element, index) {
// tests if the element has a duplicate in the rest of the array
for(index += 1; index < oldArr.length; index += 1) {
if (_.isEqual(element, oldArr[index])) {
return false;
}
}
return true;
});
It filters out all elements if they have a duplicate later in the array - such that the last duplicate element is kept.
The testing for a duplicate uses _.isEqual which performs an optimised deep comparison between the two objects see the underscore isEqual documentation for more info.
edit: updated to use _.filter which is a cleaner approach

The lodash 4.6.1 docs have this as an example for object key equality:
_.uniqWith(objects, _.isEqual);
https://lodash.com/docs#uniqWith

Try iterator function
For example you can return first element
x = [['a',1],['b',2],['a',1]]
_.uniq(x,false,function(i){
return i[0] //'a','b'
})
=> [['a',1],['b',2]]

here's my solution (coffeescript) :
_.mixin
deepUniq: (coll) ->
result = []
remove_first_el_duplicates = (coll2) ->
rest = _.rest(coll2)
first = _.first(coll2)
result.push first
equalsFirst = (el) -> _.isEqual(el,first)
newColl = _.reject rest, equalsFirst
unless _.isEmpty newColl
remove_first_el_duplicates newColl
remove_first_el_duplicates(coll)
result
example:
_.deepUniq([ {a:1,b:12}, [ 2, 1, 2, 1 ], [ 1, 2, 1, 2 ],[ 2, 1, 2, 1 ], {a:1,b:12} ])
//=> [ { a: 1, b: 12 }, [ 2, 1, 2, 1 ], [ 1, 2, 1, 2 ] ]

with underscore i had to use String() in the iteratee function
function isUniq(item) {
return String(item.user);
}
var myUniqArray = _.uniq(myArray, isUniq);

I wanted to solve this simple solution in a straightforward way of writing, with a little bit of a pain of computational expenses... but isn't it a trivial solution with a minimum variable definition, is it?
function uniq(ArrayObjects){
var out = []
ArrayObjects.map(obj => {
if(_.every(out, outobj => !_.isEqual(obj, outobj))) out.push(obj)
})
return out
}

var foo = [ { "a" : "1" }, { "b" : "2" }, { "a" : "1" } ];
var bar = _.map(_.groupBy(foo, function (f) {
return JSON.stringify(f);
}), function (gr) {
return gr[0];
}
);
Lets break this down. First lets group the array items by their stringified value
var grouped = _.groupBy(foo, function (f) {
return JSON.stringify(f);
});
grouped looks like:
{
'{ "a" : "1" }' = [ { "a" : "1" } { "a" : "1" } ],
'{ "b" : "2" }' = [ { "b" : "2" } ]
}
Then lets grab the first element from each group
var bar = _.map(grouped, function(gr)
return gr[0];
});
bar looks like:
[ { "a" : "1" }, { "b" : "2" } ]
Put it all together:
var foo = [ { "a" : "1" }, { "b" : "2" }, { "a" : "1" } ];
var bar = _.map(_.groupBy(foo, function (f) {
return JSON.stringify(f);
}), function (gr) {
return gr[0];
}
);

You can do it in a shorthand as:
_.uniq(foo, 'a')