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I need a good and best RegExp for validate Iranian phone number like this:
0903*******
0918*******
in this RegExp should check the user should just start phone number with 0 not other things like area code (+98)
try it:
("^[0][9][0-9][0-9]{8,8}$")
Using case in js:
const IsValidPhone = (val) => {
let regex = new RegExp("^[0][9][0-9][0-9]{8,8}$").test(val);
return regex;
};
You can use this regex:
/^(09)[0-9]{9,9}$/gu
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How do i match the url below ?
I want my regex to return true if my url pattern is
/products/e2e-test-products-2022-08-17T18-30-49-882Z:7ebee29f-dde2-4446-b2b1-327c15fbbabb/items
and return false when the url is
/products/e2e-test-products-2022-08-17T18-30-49-882Z:7ebee29f-dde2-4446-b2b1-327c15fbbabb/cart/items
const myRegex = /^\/products\/[^/]*\/items$/;
myRegex.test('/products/e2e-test-products-2022-08-17T18-30-49-882Z:7ebee29f-dde2-4446-b2b1-327c15fbbabb/items')
true
myRegex.test('/products/e2e-test-products-2022-08-17T18-30-49-882Z:7ebee29f-dde2-4446-b2b1-327c15fbbabb/cart/items')
false
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How can i find a string between two strings with regex for example i want find example.com in string https://example.com/path OR http://example.com/path
var str = "https://example.com/path";
str.match(/(?!http:\/\/|https:\/\/)(.*)(?!\/)/g);
Why not use URL
const url = new URL("https://example.com/path");
console.log(url.hostname)
you want to know if the string contains it ?
console.log(!!('https://example.com/path'.match(/example\.com/)))
Also, check this :
https://www.w3schools.com/jsref/jsref_includes.asp
might be useful for you
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I don't no how regex works. but I have a url like:
http://localhost/BetaLeren/public/dashboard/general/video.php?video=13&time=19
but I want it that way:
http://localhost/BetaLeren/public/dashboard/general/video.php?video=13
How I can i do that with refex?
or is there a better way?
If you'll always have video= followed by time=, you could use the following regex:
const link = 'http://localhost/BetaLeren/public/dashboard/general/video.php?video=13&time=19';
const updatedLink = link.match(/^.+video=\d+/)[0];
console.log(updatedLink);
^ represents the beginning of the string.
.+ represents any character 1 or more times.
\d+ represents any digit 1 or more times.
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Does anyone know how can I get the last digits 192.168.1.180
Example : 192.168.1.180 from this ip address i want to extract 180.
Thanks in advance
Well, if that ip address is a string you could always use the split function.
let str = "192.168.1.180";
let x = str.split(".")[3];
// where str is the ip and x is the last part you want to extract
console.log(x)
Use:
let ip = '192.168.1.180';
let last = ip.split('.')[3];
console.log(last); // '180'
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i want to set validation rule for company names which should start with character and it can contain numbers and special characters..
For example:
360 Angel - should not be allowed
Angel 360 - Allowed
Javascript regular expressions should help
Documentation:
http://www.javascriptkit.com/javatutors/redev3.shtml
Simple example:
var str = "360 Angel";
/^[a-zA-Z].*/.test(str); // return false