Searching for a specific array in an array of arrays [duplicate] - javascript

This question already has answers here:
Javascript indexOf for an array of arrays not finding array
(6 answers)
Closed 1 year ago.
const a = [[1,1], [2,1], [3,1]];
console.log(a);
console.log(a.includes([1,1]));
> false
Can someone explain to me why the above outputs false? For what its worth, this occurs in any of the search functions (.find, .indexof, etc), as well as if I try [1,1] in a. I'm clearly missing something about how multidimensional array searching works in javascript.

This is basically how equal to operator works in JavaScript.
If we try to compare two arrays
[1]=== [1] // false
equality operator can compare primitive values(number,string Boolean). But in case of arrays and objects it compares for reference. So here we are comparing two different references so it is coming as false.
For same reason you are getting false. You have to write customer logic to compare arrays.

Related

Why Do I Get a Stack Overflow When Base Case Compares an Empty Array [duplicate]

This question already has answers here:
How to compare arrays in JavaScript?
(61 answers)
Why are two identical objects not equal to each other?
(9 answers)
Closed 2 years ago.
I started with:
"1:2".split(':') == ["1","2"];
// false
Then tried:
[1,2] == [1,2];
// false
and ultimately:
[] == [];
// false
I've since found that:
"1:2".split(':').toString() == [1,2].toString();
// true
So I've solved my initial issue (kind of) but why can't arrays match each other?
Javascript arrays are objects and you can't simply use the equality operator == to understand if the content of those objects is the same. The equality operator will only test if two object are actually exactly the same instance (e.g. myObjVariable==myObjVariable, works for null and undefined too).
If you need to check if two array are equals i'd recommend to just traverse both arrays and verify that all the elements have the same value (and that the two array have the same length).
Regarding custom objects equality i'd build instead a specific equals function and i'd add it to the prototype of your class.
Considering that in the end you converted both arrays to a String and tested equality of the resulting strings, you could one day consider using a similar but more generic technique you'll find described in more than a few places:
JSON.stringify(OBJ1) === JSON.stringify(OBJ2)
Well, don't.
While this could work if the order of the properties will always the same for those object instances, this leaves the door open for extremely nasty bugs that could be hard to track down. Always favor a more explicit approach and just write a clean and readable function that will test for equality checking all the required fields.
The == operator for Objects in Javascript only checks to see if the objects are the same actual object reference, not if they are two separate object that contain the same contents. There is no built in operator for checking if they contain the same contents. You would have to write a function to do that sort of comparison yourself.
Your string conversion is one way of comparing two arrays as long as the array elements only contain primitive values (not other objects). If the array elements could contain other elements, then you would have to make sure those objects were themselves converted into representative strings too.
And, converting to a string would not discern between an array element that contains "4" versus one that contains 4 since both convert to "4" in the string representation.
FYI, you can read in this answer about records and tuples, two new data types coming to future Javascript that will allow comparing an immutable version of arrays and objects by value instead of by only comparing to see if they are the same object.
Equality for objects will tell you if the two objects are the same one.
var a = [];
var b = a;
a === b; // True, a and b refer to the same object
[] === []; // False, two separate objects
You will have to loop through the arrays to see if they have the same elements.
See: How to check if two arrays are equal with JavaScript?
In javascript each [] is an instance of window.Array class. So you are basically trying to compare two different objects. Since array's can have any no. and any type of elements including Objects and Custom Objects and those nested arrays can again have numerous properties and arrays and so on.
It becomes ambiguous when it comes to comparison, you will never be sure what do you want to do with those objects and nested properties. So what you are trying to achieve by comparing can be done in so many other ways. You just have to figure out the right way for your case.
One way is to make your own Array checking function:
How to compare arrays in JavaScript?!
Another way is to convert the Array to a String with .join(), and compare the strings. Then convert them back into Arrays with .split().
If I relate this problem with that in Python:
Input:
a="1 2 3 4"
case I:
a=input.split(' ')
output: ['1', '2', '3', '4']
case II:
a=map(int,input.split(' '))
output: [1, 2, 3, 4]
So, the fault is that of type, as it could come-out aa 'true' for:
"1:2".split(':').toString() == [1,2].toString(); //true

Why comparing these javascript objects wont return True? [duplicate]

This question already has answers here:
How to compare arrays in JavaScript?
(61 answers)
Why are two identical objects not equal to each other?
(9 answers)
Closed 2 years ago.
I started with:
"1:2".split(':') == ["1","2"];
// false
Then tried:
[1,2] == [1,2];
// false
and ultimately:
[] == [];
// false
I've since found that:
"1:2".split(':').toString() == [1,2].toString();
// true
So I've solved my initial issue (kind of) but why can't arrays match each other?
Javascript arrays are objects and you can't simply use the equality operator == to understand if the content of those objects is the same. The equality operator will only test if two object are actually exactly the same instance (e.g. myObjVariable==myObjVariable, works for null and undefined too).
If you need to check if two array are equals i'd recommend to just traverse both arrays and verify that all the elements have the same value (and that the two array have the same length).
Regarding custom objects equality i'd build instead a specific equals function and i'd add it to the prototype of your class.
Considering that in the end you converted both arrays to a String and tested equality of the resulting strings, you could one day consider using a similar but more generic technique you'll find described in more than a few places:
JSON.stringify(OBJ1) === JSON.stringify(OBJ2)
Well, don't.
While this could work if the order of the properties will always the same for those object instances, this leaves the door open for extremely nasty bugs that could be hard to track down. Always favor a more explicit approach and just write a clean and readable function that will test for equality checking all the required fields.
The == operator for Objects in Javascript only checks to see if the objects are the same actual object reference, not if they are two separate object that contain the same contents. There is no built in operator for checking if they contain the same contents. You would have to write a function to do that sort of comparison yourself.
Your string conversion is one way of comparing two arrays as long as the array elements only contain primitive values (not other objects). If the array elements could contain other elements, then you would have to make sure those objects were themselves converted into representative strings too.
And, converting to a string would not discern between an array element that contains "4" versus one that contains 4 since both convert to "4" in the string representation.
FYI, you can read in this answer about records and tuples, two new data types coming to future Javascript that will allow comparing an immutable version of arrays and objects by value instead of by only comparing to see if they are the same object.
Equality for objects will tell you if the two objects are the same one.
var a = [];
var b = a;
a === b; // True, a and b refer to the same object
[] === []; // False, two separate objects
You will have to loop through the arrays to see if they have the same elements.
See: How to check if two arrays are equal with JavaScript?
In javascript each [] is an instance of window.Array class. So you are basically trying to compare two different objects. Since array's can have any no. and any type of elements including Objects and Custom Objects and those nested arrays can again have numerous properties and arrays and so on.
It becomes ambiguous when it comes to comparison, you will never be sure what do you want to do with those objects and nested properties. So what you are trying to achieve by comparing can be done in so many other ways. You just have to figure out the right way for your case.
One way is to make your own Array checking function:
How to compare arrays in JavaScript?!
Another way is to convert the Array to a String with .join(), and compare the strings. Then convert them back into Arrays with .split().
If I relate this problem with that in Python:
Input:
a="1 2 3 4"
case I:
a=input.split(' ')
output: ['1', '2', '3', '4']
case II:
a=map(int,input.split(' '))
output: [1, 2, 3, 4]
So, the fault is that of type, as it could come-out aa 'true' for:
"1:2".split(':').toString() == [1,2].toString(); //true

How do I get the value of the key if the key in the Map is an array? [duplicate]

This question already has answers here:
How to compare arrays in JavaScript?
(55 answers)
Why are two identical objects not equal to each other?
(9 answers)
Closed 2 years ago.
I started with:
"1:2".split(':') == ["1","2"];
// false
Then tried:
[1,2] == [1,2];
// false
and ultimately:
[] == [];
// false
I've since found that:
"1:2".split(':').toString() == [1,2].toString();
// true
So I've solved my initial issue (kind of) but why can't arrays match each other?
Javascript arrays are objects and you can't simply use the equality operator == to understand if the content of those objects is the same. The equality operator will only test if two object are actually exactly the same instance (e.g. myObjVariable==myObjVariable, works for null and undefined too).
If you need to check if two array are equals i'd recommend to just traverse both arrays and verify that all the elements have the same value (and that the two array have the same length).
Regarding custom objects equality i'd build instead a specific equals function and i'd add it to the prototype of your class.
Considering that in the end you converted both arrays to a String and tested equality of the resulting strings, you could one day consider using a similar but more generic technique you'll find described in more than a few places:
JSON.stringify(OBJ1) === JSON.stringify(OBJ2)
Well, don't.
While this could work if the order of the properties will always the same for those object instances, this leaves the door open for extremely nasty bugs that could be hard to track down. Always favor a more explicit approach and just write a clean and readable function that will test for equality checking all the required fields.
The == operator for Objects in Javascript only checks to see if the objects are the same actual object reference, not if they are two separate object that contain the same contents. There is no built in operator for checking if they contain the same contents. You would have to write a function to do that sort of comparison yourself.
Your string conversion is one way of comparing two arrays as long as the array elements only contain primitive values (not other objects). If the array elements could contain other elements, then you would have to make sure those objects were themselves converted into representative strings too.
And, converting to a string would not discern between an array element that contains "4" versus one that contains 4 since both convert to "4" in the string representation.
FYI, you can read in this answer about records and tuples, two new data types coming to future Javascript that will allow comparing an immutable version of arrays and objects by value instead of by only comparing to see if they are the same object.
Equality for objects will tell you if the two objects are the same one.
var a = [];
var b = a;
a === b; // True, a and b refer to the same object
[] === []; // False, two separate objects
You will have to loop through the arrays to see if they have the same elements.
See: How to check if two arrays are equal with JavaScript?
In javascript each [] is an instance of window.Array class. So you are basically trying to compare two different objects. Since array's can have any no. and any type of elements including Objects and Custom Objects and those nested arrays can again have numerous properties and arrays and so on.
It becomes ambiguous when it comes to comparison, you will never be sure what do you want to do with those objects and nested properties. So what you are trying to achieve by comparing can be done in so many other ways. You just have to figure out the right way for your case.
One way is to make your own Array checking function:
How to compare arrays in JavaScript?!
Another way is to convert the Array to a String with .join(), and compare the strings. Then convert them back into Arrays with .split().
If I relate this problem with that in Python:
Input:
a="1 2 3 4"
case I:
a=input.split(' ')
output: ['1', '2', '3', '4']
case II:
a=map(int,input.split(' '))
output: [1, 2, 3, 4]
So, the fault is that of type, as it could come-out aa 'true' for:
"1:2".split(':').toString() == [1,2].toString(); //true

two arrays with same values are return false when comparing [duplicate]

This question already has answers here:
How to compare arrays in JavaScript?
(55 answers)
Why are two identical objects not equal to each other?
(9 answers)
Closed 2 years ago.
I started with:
"1:2".split(':') == ["1","2"];
// false
Then tried:
[1,2] == [1,2];
// false
and ultimately:
[] == [];
// false
I've since found that:
"1:2".split(':').toString() == [1,2].toString();
// true
So I've solved my initial issue (kind of) but why can't arrays match each other?
Javascript arrays are objects and you can't simply use the equality operator == to understand if the content of those objects is the same. The equality operator will only test if two object are actually exactly the same instance (e.g. myObjVariable==myObjVariable, works for null and undefined too).
If you need to check if two array are equals i'd recommend to just traverse both arrays and verify that all the elements have the same value (and that the two array have the same length).
Regarding custom objects equality i'd build instead a specific equals function and i'd add it to the prototype of your class.
Considering that in the end you converted both arrays to a String and tested equality of the resulting strings, you could one day consider using a similar but more generic technique you'll find described in more than a few places:
JSON.stringify(OBJ1) === JSON.stringify(OBJ2)
Well, don't.
While this could work if the order of the properties will always the same for those object instances, this leaves the door open for extremely nasty bugs that could be hard to track down. Always favor a more explicit approach and just write a clean and readable function that will test for equality checking all the required fields.
The == operator for Objects in Javascript only checks to see if the objects are the same actual object reference, not if they are two separate object that contain the same contents. There is no built in operator for checking if they contain the same contents. You would have to write a function to do that sort of comparison yourself.
Your string conversion is one way of comparing two arrays as long as the array elements only contain primitive values (not other objects). If the array elements could contain other elements, then you would have to make sure those objects were themselves converted into representative strings too.
And, converting to a string would not discern between an array element that contains "4" versus one that contains 4 since both convert to "4" in the string representation.
FYI, you can read in this answer about records and tuples, two new data types coming to future Javascript that will allow comparing an immutable version of arrays and objects by value instead of by only comparing to see if they are the same object.
Equality for objects will tell you if the two objects are the same one.
var a = [];
var b = a;
a === b; // True, a and b refer to the same object
[] === []; // False, two separate objects
You will have to loop through the arrays to see if they have the same elements.
See: How to check if two arrays are equal with JavaScript?
In javascript each [] is an instance of window.Array class. So you are basically trying to compare two different objects. Since array's can have any no. and any type of elements including Objects and Custom Objects and those nested arrays can again have numerous properties and arrays and so on.
It becomes ambiguous when it comes to comparison, you will never be sure what do you want to do with those objects and nested properties. So what you are trying to achieve by comparing can be done in so many other ways. You just have to figure out the right way for your case.
One way is to make your own Array checking function:
How to compare arrays in JavaScript?!
Another way is to convert the Array to a String with .join(), and compare the strings. Then convert them back into Arrays with .split().
If I relate this problem with that in Python:
Input:
a="1 2 3 4"
case I:
a=input.split(' ')
output: ['1', '2', '3', '4']
case II:
a=map(int,input.split(' '))
output: [1, 2, 3, 4]
So, the fault is that of type, as it could come-out aa 'true' for:
"1:2".split(':').toString() == [1,2].toString(); //true

Why doesn't equality check work with arrays [duplicate]

This question already has answers here:
How to compare arrays in JavaScript?
(55 answers)
Why are two identical objects not equal to each other?
(9 answers)
Closed 2 years ago.
I started with:
"1:2".split(':') == ["1","2"];
// false
Then tried:
[1,2] == [1,2];
// false
and ultimately:
[] == [];
// false
I've since found that:
"1:2".split(':').toString() == [1,2].toString();
// true
So I've solved my initial issue (kind of) but why can't arrays match each other?
Javascript arrays are objects and you can't simply use the equality operator == to understand if the content of those objects is the same. The equality operator will only test if two object are actually exactly the same instance (e.g. myObjVariable==myObjVariable, works for null and undefined too).
If you need to check if two array are equals i'd recommend to just traverse both arrays and verify that all the elements have the same value (and that the two array have the same length).
Regarding custom objects equality i'd build instead a specific equals function and i'd add it to the prototype of your class.
Considering that in the end you converted both arrays to a String and tested equality of the resulting strings, you could one day consider using a similar but more generic technique you'll find described in more than a few places:
JSON.stringify(OBJ1) === JSON.stringify(OBJ2)
Well, don't.
While this could work if the order of the properties will always the same for those object instances, this leaves the door open for extremely nasty bugs that could be hard to track down. Always favor a more explicit approach and just write a clean and readable function that will test for equality checking all the required fields.
The == operator for Objects in Javascript only checks to see if the objects are the same actual object reference, not if they are two separate object that contain the same contents. There is no built in operator for checking if they contain the same contents. You would have to write a function to do that sort of comparison yourself.
Your string conversion is one way of comparing two arrays as long as the array elements only contain primitive values (not other objects). If the array elements could contain other elements, then you would have to make sure those objects were themselves converted into representative strings too.
And, converting to a string would not discern between an array element that contains "4" versus one that contains 4 since both convert to "4" in the string representation.
FYI, you can read in this answer about records and tuples, two new data types coming to future Javascript that will allow comparing an immutable version of arrays and objects by value instead of by only comparing to see if they are the same object.
Equality for objects will tell you if the two objects are the same one.
var a = [];
var b = a;
a === b; // True, a and b refer to the same object
[] === []; // False, two separate objects
You will have to loop through the arrays to see if they have the same elements.
See: How to check if two arrays are equal with JavaScript?
In javascript each [] is an instance of window.Array class. So you are basically trying to compare two different objects. Since array's can have any no. and any type of elements including Objects and Custom Objects and those nested arrays can again have numerous properties and arrays and so on.
It becomes ambiguous when it comes to comparison, you will never be sure what do you want to do with those objects and nested properties. So what you are trying to achieve by comparing can be done in so many other ways. You just have to figure out the right way for your case.
One way is to make your own Array checking function:
How to compare arrays in JavaScript?!
Another way is to convert the Array to a String with .join(), and compare the strings. Then convert them back into Arrays with .split().
If I relate this problem with that in Python:
Input:
a="1 2 3 4"
case I:
a=input.split(' ')
output: ['1', '2', '3', '4']
case II:
a=map(int,input.split(' '))
output: [1, 2, 3, 4]
So, the fault is that of type, as it could come-out aa 'true' for:
"1:2".split(':').toString() == [1,2].toString(); //true

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