Matched leaf route at location "/" does not have an element - javascript

Matched leaf route at location "/" does not have an element. This means it will render an with a null value by default resulting in an "empty" page
//App.js File
import { BrowserRouter as Router, Routes, Route } from 'react-router-dom';
import Home from './pages/Home';
// import ReactDOM from "react-dom";
const App = () => {
return (
<Router >
<Routes>
<Route path="/" component={ Home }></Route>
</Routes>
</Router>
)
}
export default App;
**My any react router related code not working i don't know why it happend when i start insert some route in program so it show this error **

In V6, you can't use the component prop anymore. It was replaced in favor of element:
<Route path="/" element={<Home />}></Route>
More info in the migration doc.

I had the same problem. Replace component with element and it worked.
Replace this:
<Route path="/" component={HomePage} exact />
with this:
<Route path="/" element={<HomePage/>} exact />

I had the same error however my fix was slightly different
I had spelled element wrong.
<Route exact path='/MyGames' elemtent={<MyGames/>}/>
and this was the error it gave me in the browser console
Matched leaf route at location "/MyGames" does not have an element. This means it will render an <Outlet /> with a null value by default resulting in an "empty" page.

Very simple:
use element instead of component
wrap the your component like this: {<Home/>} instead of {Home}
<Route path="/" component={ <Home/> } />

in version 6:
component replaced with element and needs to close "</Route>"
<Route exact path="/" element={<AddTutorial />}></Route>
https://reactrouter.com/docs/en/v6/getting-started/overview

This is a common problem if you are using react-router-dom V6
To solve this it's simple
In your code
Replace component with element
Replace {home} with {}
This becomes...
<Route path="/" element={}>
This will definitely solve the problem.

If you're using react-router-dom 6 or above, you may have a routes array that includes parent and child routes. You may then try to open a route such as
/portal
and get this error because that component corresponds to a child route
/:customerid/portal
but you haven't read your routes (and their child routes) closely enough to see that.

Related

How should I return HTML in a React.js class component without getting an error? [duplicate]

Matched leaf route at location "/" does not have an element. This means it will render an with a null value by default resulting in an "empty" page
//App.js File
import { BrowserRouter as Router, Routes, Route } from 'react-router-dom';
import Home from './pages/Home';
// import ReactDOM from "react-dom";
const App = () => {
return (
<Router >
<Routes>
<Route path="/" component={ Home }></Route>
</Routes>
</Router>
)
}
export default App;
**My any react router related code not working i don't know why it happend when i start insert some route in program so it show this error **
In V6, you can't use the component prop anymore. It was replaced in favor of element:
<Route path="/" element={<Home />}></Route>
More info in the migration doc.
I had the same problem. Replace component with element and it worked.
Replace this:
<Route path="/" component={HomePage} exact />
with this:
<Route path="/" element={<HomePage/>} exact />
I had the same error however my fix was slightly different
I had spelled element wrong.
<Route exact path='/MyGames' elemtent={<MyGames/>}/>
and this was the error it gave me in the browser console
Matched leaf route at location "/MyGames" does not have an element. This means it will render an <Outlet /> with a null value by default resulting in an "empty" page.
Very simple:
use element instead of component
wrap the your component like this: {<Home/>} instead of {Home}
<Route path="/" component={ <Home/> } />
in version 6:
component replaced with element and needs to close "</Route>"
<Route exact path="/" element={<AddTutorial />}></Route>
https://reactrouter.com/docs/en/v6/getting-started/overview
This is a common problem if you are using react-router-dom V6
To solve this it's simple
In your code
Replace component with element
Replace {home} with {}
This becomes...
<Route path="/" element={}>
This will definitely solve the problem.
If you're using react-router-dom 6 or above, you may have a routes array that includes parent and child routes. You may then try to open a route such as
/portal
and get this error because that component corresponds to a child route
/:customerid/portal
but you haven't read your routes (and their child routes) closely enough to see that.

Multiple path names for a same component in Reach Router

I am using the same component for three different routes:
<Router>
<Home path="/" />
<Home path="/home" />
</Router>
Is there anyway to combine it, to be like:
<Router>
<Home path=["/home", "/"] />
</Router>
For Reach Router: (https://reach.tech/router/example/)
With the exact sample shown, the only way I can see how to do this(on a single line) is with a wildcard.
To find a way to reproduce this without side effects, we would need to see the entire nav menu.
<Router>
<Home path="/*" />
<Chicken path="chicken">
</Router>
...
const Home = props => {
let urlPath = props["*"]
// URL: "/home"
// urlPath === "home"
// URL/: "/"
// urlPath ===""
}
You could continue with other paths below Home and the router would allow them to process.
Check out the the example using a wildcard and reach router on codesandbox, I wrote!
Note: This is a catch-all, but without parsing a parameter is the only single line solution I saw.
Some DrawBacks include Home rendering instead of '404', etc.
//This could be resolved with an if statement in your render
//It will not produce the intended URL either for /home, and I have not looked into that since it is not part of the question.. but if it matched props[*] I'm sure you could redirect or something.
You can read more about the Route Component for Reach Router.
https://reach.tech/router/api/RouteComponent
I wasn't happy with the wildcard solution from the documentation and #cullen-bond because I had to map many other paths and came up with this solution:
<Router>
{["/home", "/", "/other", "/a-lot-more"].map(page => <Home path={page} />)}
</Router>
Example: https://codesandbox.io/s/reach-router-starter-v1-forked-6f44c?file=/src/index.js
Depending on the situation you're dealing with, <Redirect /> could also make the work.
<Router>
<Redirect from="/" path="/home" noThrow />
<Home path="/home" />
</Router>
You can use a single component for mutiple paths, by using a array of routes.
code example :
import sampleComponent from './sampleComponent'; // single component for mutiple routes
<Router>
<Switch>
{["/pathname_1", "/pathname_2", "/pathname_3", "/pathname_4", "/pathname_5", "/pathname_6"].map(pathname => (<Route exact path={pathname} component={sampleComponent} />) )}
<Switch>
<Router>

<BrowserRouter> ignores the history prop

I was using the following code from an online course for React routing:
import { Router, Route, browserHistory } from 'react-router';
ReactDOM.render(
<Router history={browserHistory}>
<Route path="/" component={App></Route>
<Route path="/One" component={One}></Route>
<Route path="/Two" component={Two}></Route>
</Router>, document.getElementById('root'));
It gave me a following error 'react-router' does not contain an export named 'browserHistory'.
I did some research and found that I was using React Router v4, and the above code was for v3, so i found that I should be using <BrowserRouter> instead of <Router> so I changed my code to:
import { BrowserRouter, Route, Switch } from 'react-router-dom';
ReactDOM.render(
<BrowserRouter history={History}>
<div>
<Route path="/" component={App}></Route>
<Route path="/One" component={One}></Route>
<Route path="/Two" component={Two}></Route>
<Route path="*" component={NoMatch}></Route>
</div></BrowserRouter>, document.getElementById('root'));
History I have in a separate file:
import { createBrowserHistory } from 'history'
export default createBrowserHistory();
Now the page loads without an error but if I use Developer tools, I can see a warning:
Warning: <BrowserRouter> ignores the history prop. To use a custom history, use `import { Router }` instead of `import { BrowserRouter as Router }`."
Another issue is that <Route path="*" component="NoMatch}></Route> only supposed to load NoMatch component when no path specified in the router but it loads on every page, regardless.
Can anyone help figure out how can I fix the issues?
I am assuming you are using react-router v4
Firstly, Instead of <BrowserRouter> make use of <Router>
import { Router } from 'react-router-dom';
You can get access to the history object's properties by using <withRouter> as mentioned Here
Export the component using <withRouter> , something like :
import React, { Component } from 'react';
import { withRouter } from 'react-router-dom';
class SomeComponent extends Component {
render() {}
}
export default withRouter(SomeComponent);
Secondly , you can make use of <Switch> as it renders the first child <Route> or <Redirect> that matches the location
And you can wrap a <Switch> in a <div> like this:
<Router>
<div>
<Switch>
<Route path="/" component={App}></Route>
<Route path="/One" component={One}></Route>
<Route path="/Two" component={Two}></Route>
<Route component={NoMatch}></Route>
</Switch>
</div>
</Router>
NOTE : Last Route doesn't have path="*"
You can read more about <Switch> on a ReactTraining Github
If you want to read more about React Router V4 or <withRouter> , You can read on this Medium Article
You can only use history with <Router> hence the error message.
See the API on the sidebar in react-router docs.
Browser Router
<BrowserRouter>
basename: string
getUserConfirmation: func
forceRefresh: bool
keyLength: number
children: node
Router
<Router>
history: object
children: node
https://reacttraining.com/react-router/web/api/Router/history-object
As for the no match, you need a switch and to put the last component without a path. Right now you are grabbing every route with path="*"
Again, see docs https://reacttraining.com/react-router/web/example/no-match
<Switch>
<Route path="/" exact component={Home}/>
<Redirect from="/old-match" to="/will-match"/>
<Route path="/will-match" component={WillMatch}/>
<Route component={NoMatch}/>
</Switch>

React Router V3 - Nested Route Component unmounts on path param change

I just noticed that in react router (v3.x) a component unmounts and remounts if a path param changes. Is this the expected behaviour?
Route:
<Route path="/landing/register/:step" component={Register}/>
Now, lets say I am on route "/landing/register/personal-data" and I am navigating via <Link/> or router.push({...}) to the next registration step "/landing/register/address", the Register-component gets first unmounted and then mounted again, loosing all its state.
Is this the correct way or am I doing something wrong?
EDIT:
It seems that the problem is that I am using nested routes, where I use a component for the parent route.
This example works (not re-mounting Register-Comp on path param change):
<Route path="/landing">
<Route path="register/:step" component={Register}></Route>
</Route>
But when I use a component for the parent route, it doesnt (not re-mounting AppView-Comp, but Register-Comp on path param change):
<Route path="/landing" component={AppView}>
<Route path="register/:step" component={Register}></Route>
</Route>
I solve this problem by nesting routes in child components, like this:
// Router class
<Route path="/landing/register" component={Register}/>
//Register component
<BrowserRouter>
<div>
<Route path="/landing/register/personal-data" component={PersonalData}/>
<Route path="/landing/register/payment-data" component={PaymentData}/>
...other routes
</div>
</BrowserRouter>
But in this case i store user data in redux store instead of component state, however you can store it on your component state it is not problem.

<Switch> component matching null value in react-router-4

I'm trying to migrate to use React Router 4 and having some trouble understanding the logic of the <Switch> component as it's used in the docs to handle a 404 (or unmatched) route.
For my entry JavaScript file, I have the following routes set up.
index.js
<Switch>
<Route path="/login" component={Login} />
<Route path="/forgot-password" component={ForgotPassword} />
<Route path="/email-verification" component={EmailVerification} />
<Route component={App} />
</Switch>
The Login component will check to see if the user is authenticated, and if so, redirect the user to the /dashboard route (via history.replace).
The App component is only accessible when the user is authenticated and it has a similar check to redirect the user to /login if she is not.
In my App component I have more specified routes that I can be sure are only accessible if the user is logged in.
App.js
<Switch>
<Route path="/dashboard" component={Dashboard} />
<Route path="/accounts" component={Account} />
<Authorize permissions={['view-admin']}>
<Route path="/admin" component={Admin} />
</Authorize>
<Route path="/users" component={Users} />
<Route component={NotFound} />
</Switch>
Herein lies my problem. The Authorize component checks against the permissions passed to see if the user has those permissions, if so, it renders the children directly, if not, it returns null from render().
The expected behavior here is that the <Route path="/admin" /> does not render at all when there are insufficient permissions and the <Route component={NotFound} /> component renders.
According to the docs:
A renders the first child that matches. A
with no path always matches.
However, if I go to any route declared after the <Authorize> component, the router is matching to null. This means that, based on the example above, going to /users returns null. Is the expected behavior of react-router to return the first match in a <Switch/> component, even if it's a null value?
How can I provide a "catch-all" route (404) for such a situation without creating a <PrivateRoute> component for each of the many, authenticated routes in App.js? Should a null value really produce a match?
Unfortunately, react-router's Switch component won't work with routes nested inside other components like in your example. If you check the docs for Switch, it says:
All children of a <Switch> should be <Route> or <Redirect> elements.
... so your Authorize component is not actually legal there as a direct child of Switch.
If you have a read through the source code of the Switch component, you'll see that it rather evilly reads the props of each of its children and manually applies react-router's matchPath method on each child's path (or from) prop to determine which one should be rendered.
So, what's happening in your case is Switch iterates through its children until it gets to your Authorize component. It then looks at that component's props, finding neither a path or from prop, and calls matchPath on an undefined path. As you note yourself, "a <Route> with no path always matches", so matchPath returns true, and Switch renders your Authorize component (ignoring any subsequent Routes or Redirects, since it believes it found a match). The nested '/admin' route inside your Authorize component doesn't match the current path however, so you get a null result back from the render.
I'm facing a similar situation at work. My plan to work around it is to replace react-router's Switch in my routing code with a custom component which iterates through its children, manually rendering each one in turn, and returning the result of the first one that returns something other than null. I'll update this answer when I've given it a shot.
Edit: Well, that didn't work. I couldn't work out a supported way to manually invoke "render" on the children. Sorry I couldn't give you a workaround to Switch's limitations.
In case anyone reads this in >= 2019, one way to deal with this behaviour is to simply wrap the Route-component like so:
import React from 'react'
import { Route } from 'react-router-dom'
type Props = {
permissions: string[]
componentWhenNotAuthorized?: React.ElementType
}
const AuthorizedRoute: React.FunctionComponent<Props> = ({
permissions,
componentWhenNotAuthorized: ComponentWhenNotAuthorized,
...rest
}) => {
const isAuthorized = someFancyAuthorizationLogic(permissions)
return isAuthorized
? <Route {...rest} />
: ComponentWhenNotAuthorized
? <ComponentWhenNotAuthorized {...rest} />
: null
}
export default AuthorizedRoute
Then, simply use it as such:
import React from 'react'
import { Route, Switch } from 'react-router-dom'
import AuthorizedRoute from 'some/path/AuthorizedRoute'
import Account from 'some/path/Account'
import Admin from 'some/path/Admin'
import Dashboard from 'some/path/Dashboard'
import NotFound from 'some/path/NotFound'
import Users from 'some/path/Users'
const AppRouter: React.FunctionComponent = () => (
<Switch>
<Route
component={Account}
path='/accounts'
/>
<AuthorizedRoute
component={Admin}
componentWhenNotAuthorized={NotFound}
path='/admin'
permissions={['view-admin']}
/>
<Route
component={Dashboard}
path='/dashboard'
/>
<Route
component={Users}
path='/users'
/>
<Route
component={NotFound}
/>
</Switch>
)
export default AppRouter
Similar idea to what Robert said, here's how I did it
class NullComponent extends React.Component {
shouldComponentBeRenderedByRoute() {
return false;
}
render() {
return null;
}
}
class CustomSwitch extends React.Component {
render() {
return (
// React.Children.map returns components even for null, which
const children = React.Children.toArray(this.props.children).map(child => {
const { render, shouldComponentBeRenderedByRoute } = child.type.prototype;
if (shouldComponentBeRenderedByRoute && !shouldComponentBeRenderedByRoute.call(child)) {
return null;
}
if (shouldComponentBeRenderedByRoute) {
return render.call(child);
}
return child;
});
return <Switch>{children}</Switch>;
);
}
}
then use it just do
<CustomSwitch>
<Route path... />
<NullComponent />
<Route path... />
</CustomSwitch>
here, a component without shouldComponentBeRenderedByRoute function is assumed to be a valid Route component from react-router, but you can add more condition (maybe use path props) to check if it's a valid Route

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