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React Passing Same Prop Twice

I have a SideBar navigation component, that holds an open/close state.
This state is drilled down to childs (SideBarButton) to perform conditional CSS styling.
Strange thing is, that the SideBarButton, despite receiving the prop once, it is shown twice in the rendered tree, and always taking the false value.
Any one any idea why?
NavigationLinksView receives isOpenSideNav:
<div className={styles.root}>
<NavigationLinksView
isOpenSideNav={isOpenSideNav}
navigationLinksList={navigationLinksTop}
/>
<NavigationLinksView
isOpenSideNav={isOpenSideNav}
navigationLinksList={navigationLinksBottom}
/>
</div>
NavigationLinksView.js:
const NavigationLinksView = ({isOpenSideNav, navigationLinksList}) => {
return (
<ul
className={styles.root}
>
{_.map(navigationLinksList, (navigationItem, idx) => {
const {sideMenuContent, name} = navigationItem;
if (sideMenuContent) {
return (
<SideBarButtonWithSubMenu
key={`${name}_${idx}`}
isOpensideNav={isOpenSideNav}
navigationItem={navigationItem}
/>
);
}
return (
<SideBarButton
key={`${name}_${idx}`}
isOpensideNav={isOpenSideNav}
navigationItem={navigationItem}
/>
);
})}
</ul>
);
};
Yet, each SidebarButton or SideBarButtonWithSubMenu has problems reading that prop:
const SideBarButton = ({navigationItem, isOpenSideNav}) => {
const {id, className, withSeparator, disabled, to, name, analytics, icon} = navigationItem;
console.log({isOpenSideNav, comp: 'SideBarButton'});
const {icon: iconName, color, hoverColor} = icon;
const currentPathLink = to || `/${id}`;
const location = useLocation();
const activePath = _.split(location.pathname, '/')[1] === id;
const {translate} = useLocalisationService();
return (
<li key={name} className={classNames(styles.root, {[styles.disabled]: disabled})}>
{withSeparator && <div className={styles.separator}/>}
<Link
className={classNames(styles.link, {[styles.link.wideView]: isOpenSideNav, [styles.activePath]: activePath}, className)}
to={currentPathLink}
onClick={() => analyticsService.event(analytics)}
>
<Hint offset={Hint.offsets.SM} side={Hint.sides.RIGHT} show={!isOpenSideNav} content={translate(name)}>
<div className={classNames(styles.iconContainer)}>
<Icon icon={iconName} color={color} hoverColor={hoverColor || Icon.colors.PRIMARY_BRAND_REGULAR}/>
</div>
</Hint>
<div
className={classNames(className, styles.textContent, {
[styles.wideView]: isOpenSideNav,
})}
>
{translate(name)}
</div>
</Link>
</li>
);
};
Any help will be welcomed.
Thanks.
I have tried inspecting the prop drilling.
NavigationLInksView gets the right prop value every time it changes.
When drilling to a child, the Childs get it duplicated as shown in the screenshot.
The direct Childs sideBarButton and SideBarButtonWithSideMenu for some reason get it twice.
The value that they always take from the duplicated prop is "false", regardless of some scenarios being true.

Is my entire React component re-rendering unnecessarily when the state changes?

I am trying to create an accordion component using React, but the animation is not working.
The basic idea is, I believe, pretty standard, I am giving each item body a max-height of 0 which is affected by adding a show class to an element. I am able to select and show the item I want, but the animation to slide in/out is not working.
With the Chrome dev tools open, when I click on one of the items I can see that the whole "accordion" element is flashing, which leads me to believe that the whole element is being re-rendered. But I am unsure why this would be the case.
Here is the relevant Accordion component:
import React, { useState } from "react";
const Accordion = ({ items }) => {
const [selectedItem, setSelectedItem] = useState(0);
const AccordionItem = ({ item, index }) => {
const isOpen = index === selectedItem;
return (
<div className="accordion-item">
<div
onClick={() => {
setSelectedItem(index);
}}
className="accordion-header"
>
<div>{item.heading}</div>
</div>
<div className={`accordion-body ${isOpen ? "show" : ""}`}>
<div className="accordion-content">{item.body}</div>
</div>
</div>
);
};
return (
<div className="accordion">
{items.map((item, i) => {
return <AccordionItem key={i} item={item} index={i} />;
})}
</div>
);
};
export default Accordion;
And here is a codepen illustrating the problem:
https://codesandbox.io/s/heuristic-heyrovsky-xgcbe

of course, its going to re-render. When ever you call setSelectedIem, state changes and hence react re-renders on state change to exhibit that change.
Now if you place this
const [selectedItem, setSelectedItem] = useState(0);
inside Accordion Item, it would just re-render accordion item, but would mess up your functionality.

How to Change a css property based on a state of another component

I'm building a web page with gatsby which is based in react, and I need my nav component changes his sticky position to relative or auto, every time that I open the modal of the gallery component..but I don't know how to approach and solve the problem. The nav component belongs to the layout component which is Gallery's parent component...Here are the components involved:
nav component:
import React, { Component } from 'react'
import { Location } from '#reach/router'
import { Link } from 'gatsby'
import { Menu, X } from 'react-feather'
import Logo from './Logo'
import './Nav.css'
export class Navigation extends Component {
state = {
active: false,
activeSubNav: false,
currentPath: false
}
componentDidMount = () =>
this.setState({ currentPath: this.props.location.pathname })
handleMenuToggle = () => this.setState({ active: !this.state.active })
// Only close nav if it is open
handleLinkClick = () => this.state.active && this.handleMenuToggle()
toggleSubNav = subNav =>
this.setState({
activeSubNav: this.state.activeSubNav === subNav ? false : subNav
})
render() {
const { active } = this.state,
{ subNav } = this.props,
NavLink = ({ to, className, children, ...props }) => (
<Link
to={to}
className={`NavLink ${
to === this.state.currentPath ? 'active' : ''
} ${className}`}
onClick={this.handleLinkClick}
{...props}
>
{children}
</Link>
)
return (
<nav className={`Nav ${active ? 'Nav-active' : ''}`}>
<div className="Nav--Container container">
<Link to="/" onClick={this.handleLinkClick}>
<div style={{ width: `40px`, margin:`0 20px`}}>
<Logo />
</div>
</Link>
<div className="Nav--Links">
<NavLink to="/">Home</NavLink>
<NavLink to="/contact/">Contacto</NavLink>
<div className={`Nav--Group ${this.state.activeSubNav === 'about' ? 'active' : '' }`} >
<span className={`NavLink Nav--GroupParent ${
this.props.location.pathname.includes('about') ||
this.props.location.pathname.includes('team') ||
this.props.location.pathname.includes('news')
? 'active'
: ''
}`}
onClick={() => this.toggleSubNav('about')}
>
Nosotros
</span>
<div className="Nav--GroupLinks">
{subNav.map( (link, index)=> (
<NavLink
to={link.link}
key={'posts-subnav-link-' + index}
className="Nav--GroupLink">{link.name}</NavLink>
))}
</div>
</div>
</div>
<button
className="Button-blank Nav--MenuButton"
onClick={this.handleMenuToggle}
>
{active ? <X /> : <Menu />}
</button>
</div>
</nav>
)
}
}
export default ({ subNav }) => (
<Location>{route => <Navigation subNav={subNav} {...route} />}</Location>
)
the default position property is set to sticky in the nav.css file I want remove that and change it
dynamically depending of the modal gallery state, open or close.
this is my gallery component:
import React, { useState, useCallback } from "react";
import Gallery from "react-photo-gallery";
import Carousel, { Modal, ModalGateway } from "react-images";
const PhotoGallery = ({photos}) => {
const [currentImage, setCurrentImage] = useState(0);
const [viewerIsOpen, setViewerIsOpen] = useState(false);
const openLightbox = useCallback((event, { photo, index }) => {
setCurrentImage(index);
setViewerIsOpen(true);
}, []);
const closeLightbox = () => {
setCurrentImage(0);
setViewerIsOpen(false);
};
return(
<div>
<Gallery photos={photos} onClick={openLightbox} />
<ModalGateway>
{viewerIsOpen ? (
<Modal onClose={closeLightbox}>
<Carousel
currentIndex={currentImage}
views={photos.map(x => ({
...x,
srcset: x.srcSet,
caption: x.title
}))}
/>
</Modal>
) : null}
</ModalGateway>
</div>
)
}
export default PhotoGallery
the problem is that when the modal is open the nav still sticky and does not allow me access to the modal controls, like close and expand...and I need to change that.

There are a few approaches to this.
Old school classname toggling
Pass a prop down to the child component that reflects the state. On the child, use that prop to conditionally render one or more classes that represent the desired presentation.
Assign styles via style prop
This is similar to #1, but eliminates a layer of abstraction. Instead of assembling a class list you just assemble the CSS styles you'd like to apply as an object.
const Component = ({ someState }) =>
<div style={someState ? { border: "5px solid red" } : { color: "#999" }}>
Some Text
</div>
Use a CSS-in-JS library
The downside of the above approach is that you wind up duplicating styles for each instance of your element on the page. CSS-in-JS libraries solve this by extracting your styles into an automatically generated class and applying the class to your component instead. I prefer Emotion, but there are others.
Using Emotion you're able to accept a className prop from the parent that override the defaults set by the child. This inversion-of-control is really powerful and solves many of the shortcomings with early CSS-in-JS approaches.
const ParentComponent = () => {
const [someState] = useState(false)
return <ChildComponent css={{ color: someState ? "blue" : "red" }} />
}
const ChildComponent = ({ className }) =>
<div
css={{
color: "#000",
border: "4px solid currentColor"
}}
className={className}
>
Some Text
</div>
In the above example, className is assigned by Emotion using the generated class name assigned based on the css prop passed to ChildComponent inside of ParentComponent. The result of this would be a div with a blue border and blue text when someState is false (default). When someState is switched to true, the border and text will be red. This is because the styles passed in via className will override the styles assigned directly via css in Emotion.

Update component when prop value changes

I have an object with the property home.ready = false. When the object is done getting data, cleaning it etc it changes to home.ready= true.
I need my component to register the change and update. My component:
class HomeNav extends React.Component {
render() {
let data = this.props.data;
let uniqueTabs = _.uniq(_.map(data, x => x.tab)).sort();
let tabs = uniqueTabs.map((tab, index) => {
let itemsByTab = _.filter(data, (x => x.tab == tab));
return <Tabs key={tab} tab={tab} index={index} data={itemsByTab} />;
});
console.log(this.props)
return (
<section>
<div className="wb-tabs">
<div className="tabpanels">
{ this.props.ready ? {tabs} : <p>Loading...</p> }
</div>
</div>
</section>
)
}
};
ReactDOM.render(
<HomeNav data={home.data.nav} ready={home.ready}/>,
document.getElementById('home-nav')
);
This is the home object. It's a simple object that gets data and once the data is ready the property ready changes from false to true. I can't get React to recognize that change. And at times React will say home is undefined.

Since you didn't post any code around the request, or data formatting, I will assume you got all that figured out. So, for your component to work the way it is currently written, you need to drop the curly braces around tabs ({ this.props.ready ? tabs : <p>Loading...</p> }), then, this.props.data should always contain a valid Array, otherwise it will break when you try to sort, filter, etc.
Or, you can do an early dropout, based on the ready property:
class HomeNav extends React.Component {
render() {
if(!this.props.ready){
return <section>
<div className="wb-tabs">
<div className="tabpanels">
<p>Loading...</p>
</div>
</div>
</section>
}
let data = this.props.data;
let uniqueTabs = _.uniq(_.map(data, x => x.tab)).sort();
let tabs = uniqueTabs.map((tab, index) => {
let itemsByTab = _.filter(data, (x => x.tab == tab));
return <Tabs key={tab} tab={tab} index={index} data={itemsByTab} />;
});
console.log(this.props)
return (
<section>
<div className="wb-tabs">
<div className="tabpanels">
{tabs}
</div>
</div>
</section>
)
}
};

Show or hide element in React

I am messing around with React.js for the first time and cannot find a way to show or hide something on a page via click event. I am not loading any other library to the page, so I am looking for some native way using the React library. This is what I have so far. I would like to show the results div when the click event fires.
var Search= React.createClass({
handleClick: function (event) {
console.log(this.prop);
},
render: function () {
return (
<div className="date-range">
<input type="submit" value="Search" onClick={this.handleClick} />
</div>
);
}
});
var Results = React.createClass({
render: function () {
return (
<div id="results" className="search-results">
Some Results
</div>
);
}
});
React.renderComponent(<Search /> , document.body);

React circa 2020
In the onClick callback, call the state hook's setter function to update the state and re-render:
const Search = () => {
const [showResults, setShowResults] = React.useState(false)
const onClick = () => setShowResults(true)
return (
<div>
<input type="submit" value="Search" onClick={onClick} />
{ showResults ? <Results /> : null }
</div>
)
}
const Results = () => (
<div id="results" className="search-results">
Some Results
</div>
)
ReactDOM.render(<Search />, document.querySelector("#container"))
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.13.1/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.13.1/umd/react-dom.production.min.js"></script>
<div id="container">
<!-- This element's contents will be replaced with your component. -->
</div>
JSFiddle
React circa 2014
The key is to update the state of the component in the click handler using setState. When the state changes get applied, the render method gets called again with the new state:
var Search = React.createClass({
getInitialState: function() {
return { showResults: false };
},
onClick: function() {
this.setState({ showResults: true });
},
render: function() {
return (
<div>
<input type="submit" value="Search" onClick={this.onClick} />
{ this.state.showResults ? <Results /> : null }
</div>
);
}
});
var Results = React.createClass({
render: function() {
return (
<div id="results" className="search-results">
Some Results
</div>
);
}
});
ReactDOM.render( <Search /> , document.getElementById('container'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.6.2/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/15.6.2/react-dom.min.js"></script>
<div id="container">
<!-- This element's contents will be replaced with your component. -->
</div>
JSFiddle

<style type="text/css">
.hidden { display:none; }
</style>
const Example = props =>
<div className={props.shouldHide? 'hidden' : undefined}>Hello</div>

Here is an alternative syntax for the ternary operator:
{ this.state.showMyComponent ? <MyComponent /> : null }
is equivalent to:
{ this.state.showMyComponent && <MyComponent /> }
Learn why
Also alternative syntax with display: 'none';
<MyComponent style={this.state.showMyComponent ? {} : { display: 'none' }} />
However, if you overuse display: 'none', this leads to DOM pollution and ultimately slows down your application.

Here is my approach.
import React, { useState } from 'react';
function ToggleBox({ title, children }) {
const [isOpened, setIsOpened] = useState(false);
function toggle() {
setIsOpened(wasOpened => !wasOpened);
}
return (
<div className="box">
<div className="boxTitle" onClick={toggle}>
{title}
</div>
{isOpened && (
<div className="boxContent">
{children}
</div>
)}
</div>
);
}
In code above, to achieve this, I'm using code like:
{opened && <SomeElement />}
That will render SomeElement only if opened is true. It works because of the way how JavaScript resolve logical conditions:
true && true && 2; // will output 2
true && false && 2; // will output false
true && 'some string'; // will output 'some string'
opened && <SomeElement />; // will output SomeElement if `opened` is true, will output false otherwise (and false will be ignored by react during rendering)
// be careful with 'falsy' values eg
const someValue = [];
someValue.length && <SomeElement /> // will output 0, which will be rednered by react
// it'll be better to:
someValue.length > 0 && <SomeElement /> // will render nothing as we cast the value to boolean
Reasons for using this approach instead of CSS 'display: none';
While it might be 'cheaper' to hide an element with CSS - in such case 'hidden' element is still 'alive' in react world (which might make it actually way more expensive)
it means that if props of the parent element (eg. <TabView>) will change - even if you see only one tab, all 5 tabs will get re-rendered
the hidden element might still have some lifecycle methods running - eg. it might fetch some data from the server after every update even tho it's not visible
the hidden element might crash the app if it'll receive incorrect data. It might happen as you can 'forget' about invisible nodes when updating the state
you might by mistake set wrong 'display' style when making element visible - eg. some div is 'display: flex' by default, but you'll set 'display: block' by mistake with display: invisible ? 'block' : 'none' which might break the layout
using someBoolean && <SomeNode /> is very simple to understand and reason about, especially if your logic related to displaying something or not gets complex
in many cases, you want to 'reset' element state when it re-appears. eg. you might have a slider that you want to set to initial position every time it's shown. (if that's desired behavior to keep previous element state, even if it's hidden, which IMO is rare - I'd indeed consider using CSS if remembering this state in a different way would be complicated)

with the newest version react 0.11 you can also just return null to have no content rendered.
Rendering to null

This is a nice way to make use of the virtual DOM:
class Toggle extends React.Component {
state = {
show: true,
}
toggle = () => this.setState((currentState) => ({show: !currentState.show}));
render() {
return (
<div>
<button onClick={this.toggle}>
toggle: {this.state.show ? 'show' : 'hide'}
</button>
{this.state.show && <div>Hi there</div>}
</div>
);
}
}
Example here
Using React hooks:
const Toggle = () => {
const [show, toggleShow] = React.useState(true);
return (
<div>
<button
onClick={() => toggleShow(!show)}
>
toggle: {show ? 'show' : 'hide'}
</button>
{show && <div>Hi there</div>}
</div>
)
}
Example here

I created a small component that handles this for you: react-toggle-display
It sets the style attribute to display: none !important based on the hide or show props.
Example usage:
var ToggleDisplay = require('react-toggle-display');
var Search = React.createClass({
getInitialState: function() {
return { showResults: false };
},
onClick: function() {
this.setState({ showResults: true });
},
render: function() {
return (
<div>
<input type="submit" value="Search" onClick={this.onClick} />
<ToggleDisplay show={this.state.showResults}>
<Results />
</ToggleDisplay>
</div>
);
}
});
var Results = React.createClass({
render: function() {
return (
<div id="results" className="search-results">
Some Results
</div>
);
}
});
React.renderComponent(<Search />, document.body);

There are several great answers already, but I don't think they've been explained very well and several of the methods given contain some gotchas that might trip people up. So I'm going to go over the three main ways (plus one off-topic option) to do this and explain the pros and cons. I'm mostly writing this because Option 1 was recommended a lot and there's a lot of potential issues with that option if not used correctly.
Option 1: Conditional Rendering in the parent.
I don't like this method unless you're only going to render the component one time and leave it there. The issue is it will cause react to create the component from scratch every time you toggle the visibility.
Here's the example. LogoutButton or LoginButton are being conditionally rendered in the parent LoginControl. If you run this you'll notice the constructor is getting called on each button click. https://codepen.io/Kelnor/pen/LzPdpN?editors=1111
class LoginControl extends React.Component {
constructor(props) {
super(props);
this.handleLoginClick = this.handleLoginClick.bind(this);
this.handleLogoutClick = this.handleLogoutClick.bind(this);
this.state = {isLoggedIn: false};
}
handleLoginClick() {
this.setState({isLoggedIn: true});
}
handleLogoutClick() {
this.setState({isLoggedIn: false});
}
render() {
const isLoggedIn = this.state.isLoggedIn;
let button = null;
if (isLoggedIn) {
button = <LogoutButton onClick={this.handleLogoutClick} />;
} else {
button = <LoginButton onClick={this.handleLoginClick} />;
}
return (
<div>
<Greeting isLoggedIn={isLoggedIn} />
{button}
</div>
);
}
}
class LogoutButton extends React.Component{
constructor(props, context){
super(props, context)
console.log('created logout button');
}
render(){
return (
<button onClick={this.props.onClick}>
Logout
</button>
);
}
}
class LoginButton extends React.Component{
constructor(props, context){
super(props, context)
console.log('created login button');
}
render(){
return (
<button onClick={this.props.onClick}>
Login
</button>
);
}
}
function UserGreeting(props) {
return <h1>Welcome back!</h1>;
}
function GuestGreeting(props) {
return <h1>Please sign up.</h1>;
}
function Greeting(props) {
const isLoggedIn = props.isLoggedIn;
if (isLoggedIn) {
return <UserGreeting />;
}
return <GuestGreeting />;
}
ReactDOM.render(
<LoginControl />,
document.getElementById('root')
);
Now React is pretty quick at creating components from scratch. However, it still has to call your code when creating it. So if your constructor, componentDidMount, render, etc code is expensive, then it'll significantly slow down showing the component. It also means you cannot use this with stateful components where you want the state to be preserved when hidden (and restored when displayed.) The one advantage is that the hidden component isn't created at all until it's selected. So hidden components won't delay your initial page load. There may also be cases where you WANT a stateful component to reset when toggled. In which case this is your best option.
Option 2: Conditional Rendering in the child
This creates both components once. Then short circuits the rest of the render code if the component is hidden. You can also short circuit other logic in other methods using the visible prop. Notice the console.log in the codepen page. https://codepen.io/Kelnor/pen/YrKaWZ?editors=0011
class LoginControl extends React.Component {
constructor(props) {
super(props);
this.handleLoginClick = this.handleLoginClick.bind(this);
this.handleLogoutClick = this.handleLogoutClick.bind(this);
this.state = {isLoggedIn: false};
}
handleLoginClick() {
this.setState({isLoggedIn: true});
}
handleLogoutClick() {
this.setState({isLoggedIn: false});
}
render() {
const isLoggedIn = this.state.isLoggedIn;
return (
<div>
<Greeting isLoggedIn={isLoggedIn} />
<LoginButton isLoggedIn={isLoggedIn} onClick={this.handleLoginClick}/>
<LogoutButton isLoggedIn={isLoggedIn} onClick={this.handleLogoutClick}/>
</div>
);
}
}
class LogoutButton extends React.Component{
constructor(props, context){
super(props, context)
console.log('created logout button');
}
render(){
if(!this.props.isLoggedIn){
return null;
}
return (
<button onClick={this.props.onClick}>
Logout
</button>
);
}
}
class LoginButton extends React.Component{
constructor(props, context){
super(props, context)
console.log('created login button');
}
render(){
if(this.props.isLoggedIn){
return null;
}
return (
<button onClick={this.props.onClick}>
Login
</button>
);
}
}
function UserGreeting(props) {
return <h1>Welcome back!</h1>;
}
function GuestGreeting(props) {
return <h1>Please sign up.</h1>;
}
function Greeting(props) {
const isLoggedIn = props.isLoggedIn;
if (isLoggedIn) {
return <UserGreeting />;
}
return <GuestGreeting />;
}
ReactDOM.render(
<LoginControl />,
document.getElementById('root')
);
Now, if the initialization logic is quick and the children are stateless, then you won't see a difference in performance or functionality. However, why make React create a brand new component every toggle anyway? If the initialization is expensive however, Option 1 will run it every time you toggle a component which will slow the page down when switching. Option 2 will run all of the component's inits on first page load. Slowing down that first load. Should note again. If you're just showing the component one time based on a condition and not toggling it, or you want it to reset when toggledm, then Option 1 is fine and probably the best option.
If slow page load is a problem however, it means you've got expensive code in a lifecycle method and that's generally not a good idea. You can, and probably should, solve the slow page load by moving the expensive code out of the lifecycle methods. Move it to an async function that's kicked off by ComponentDidMount and have the callback put it in a state variable with setState(). If the state variable is null and the component is visible then have the render function return a placeholder. Otherwise render the data. That way the page will load quickly and populate the tabs as they load. You can also move the logic into the parent and push the results to the children as props. That way you can prioritize which tabs get loaded first. Or cache the results and only run the logic the first time a component is shown.
Option 3: Class Hiding
Class hiding is probably the easiest to implement. As mentioned you just create a CSS class with display: none and assign the class based on prop. The downside is the entire code of every hidden component is called and all hidden components are attached to the DOM. (Option 1 doesn't create the hidden components at all. And Option 2 short circuits unnecessary code when the component is hidden and removes the component from the DOM completely.) It appears this is faster at toggling visibility according some tests done by commenters on other answers but I can't speak to that.
Option 4: One component but change Props. Or maybe no component at all and cache HTML.
This one won't work for every application and it's off topic because it's not about hiding components, but it might be a better solution for some use cases than hiding. Let's say you have tabs. It might be possible to write one React Component and just use the props to change what's displayed in the tab. You could also save the JSX to state variables and use a prop to decide which JSX to return in the render function. If the JSX has to be generated then do it and cache it in the parent and send the correct one as a prop. Or generate in the child and cache it in the child's state and use props to select the active one.

You set a boolean value in the state (e.g. 'show)', and then do:
var style = {};
if (!this.state.show) {
style.display = 'none'
}
return <div style={style}>...</div>

A simple method to show/hide elements in React using Hooks
const [showText, setShowText] = useState(false);
Now, let's add some logic to our render method:
{showText && <div>This text will show!</div>}
And
onClick={() => setShowText(!showText)}
Good job.

I was able to use css property "hidden". Don't know about possible drawbacks.
export default function App() {
const [hidden, setHidden] = useState(false);
return (
<div>
<button onClick={() => setHidden(!hidden)}>HIDE</button>
<div hidden={hidden}>hidden component</div>
</div>
);
}

Best practice is below according to the documentation:
{this.state.showFooter && <Footer />}
Render the element only when the state is valid.

Simple hide/show example with React Hooks: (srry about no fiddle)
const Example = () => {
const [show, setShow] = useState(false);
return (
<div>
<p>Show state: {show}</p>
{show ? (
<p>You can see me!</p>
) : null}
<button onClick={() => setShow(!show)}>
</div>
);
};
export default Example;

class FormPage extends React.Component{
constructor(props){
super(props);
this.state = {
hidediv: false
}
}
handleClick = (){
this.setState({
hidediv: true
});
}
render(){
return(
<div>
<div className="date-range" hidden = {this.state.hidediv}>
<input type="submit" value="Search" onClick={this.handleClick} />
</div>
<div id="results" className="search-results" hidden = {!this.state.hidediv}>
Some Results
</div>
</div>
);
}
}

I start with this statement from the React team:
In React, you can create distinct components that encapsulate behaviour
you need. Then, you can render only some of them, depending on the
state of your application.
Conditional rendering in React works the same way conditions work in
JavaScript. Use JavaScript operators like if or the conditional
operator to create elements representing the current state, and let
React update the UI to match them.
You basically need to show the component when the button gets clicked, you can do it two ways, using pure React or using CSS, using pure React way, you can do something like below code in your case, so in the first run, results are not showing as hideResults is true, but by clicking on the button, state gonna change and hideResults is false and the component get rendered again with the new value conditions, this is very common use of changing component view in React...
var Search = React.createClass({
getInitialState: function() {
return { hideResults: true };
},
handleClick: function() {
this.setState({ hideResults: false });
},
render: function() {
return (
<div>
<input type="submit" value="Search" onClick={this.handleClick} />
{ !this.state.hideResults && <Results /> }
</div> );
}
});
var Results = React.createClass({
render: function() {
return (
<div id="results" className="search-results">
Some Results
</div>);
}
});
ReactDOM.render(<Search />, document.body);
If you want to do further study in conditional rendering in React, have a look here.

class Toggle extends React.Component {
state = {
show: true,
}
render() {
const {show} = this.state;
return (
<div>
<button onClick={()=> this.setState({show: !show })}>
toggle: {show ? 'show' : 'hide'}
</button>
{show && <div>Hi there</div>}
</div>
);
}
}

If you would like to see how to TOGGLE the display of a component checkout this fiddle.
http://jsfiddle.net/mnoster/kb3gN/16387/
var Search = React.createClass({
getInitialState: function() {
return {
shouldHide:false
};
},
onClick: function() {
console.log("onclick");
if(!this.state.shouldHide){
this.setState({
shouldHide: true
})
}else{
this.setState({
shouldHide: false
})
}
},
render: function() {
return (
<div>
<button onClick={this.onClick}>click me</button>
<p className={this.state.shouldHide ? 'hidden' : ''} >yoyoyoyoyo</p>
</div>
);
}
});
ReactDOM.render( <Search /> , document.getElementById('container'));

Use ref and manipulate CSS
One way could be to use React's ref and manipulate CSS class using the browser's API. Its benefit is to avoid rerendering in React if the sole purpose is to hide/show some DOM element on the click of a button.
// Parent.jsx
import React, { Component } from 'react'
export default class Parent extends Component {
constructor () {
this.childContainer = React.createRef()
}
toggleChild = () => {
this.childContainer.current.classList.toggle('hidden')
}
render () {
return (
...
<button onClick={this.toggleChild}>Toggle Child</button>
<div ref={this.childContainer}>
<SomeChildComponent/>
</div>
...
);
}
}
// styles.css
.hidden {
display: none;
}
PS Correct me if I am wrong. :)

In some cases higher order component might be useful:
Create higher order component:
export var HidableComponent = (ComposedComponent) => class extends React.Component {
render() {
if ((this.props.shouldHide!=null && this.props.shouldHide()) || this.props.hidden)
return null;
return <ComposedComponent {...this.props} />;
}
};
Extend your own component:
export const MyComp= HidableComponent(MyCompBasic);
Then you can use it like this:
<MyComp hidden={true} ... />
<MyComp shouldHide={this.props.useSomeFunctionHere} ... />
This reduces a bit boilerplate and enforces sticking to naming conventions, however please be aware of that MyComp will still be instantiated - the way to omit is was mentioned earlier:
{ !hidden && <MyComp ... /> }

If you use bootstrap 4, you can hide element that way
className={this.state.hideElement ? "invisible" : "visible"}

Use rc-if-else module
npm install --save rc-if-else
import React from 'react';
import { If } from 'rc-if-else';
class App extends React.Component {
render() {
return (
<If condition={this.props.showResult}>
Some Results
</If>
);
}
}

Use this lean and short syntax:
{ this.state.show && <MyCustomComponent /> }

Here comes the simple, effective and best solution with a Classless React Component for show/hide the elements. Use of React-Hooks which is available in the latest create-react-app project that uses React 16
import React, {useState} from 'react';
function RenderPara(){
const [showDetail,setShowDetail] = useState(false);
const handleToggle = () => setShowDetail(!showDetail);
return (
<React.Fragment>
<h3>
Hiding some stuffs
</h3>
<button onClick={handleToggle}>Toggle View</button>
{showDetail && <p>
There are lot of other stuffs too
</p>}
</React.Fragment>)
}
export default RenderPara;
Happy Coding :)

//use ternary condition
{ this.state.yourState ? <MyComponent /> : null }
{ this.state.yourState && <MyComponent /> }
{ this.state.yourState == 'string' ? <MyComponent /> : ''}
{ this.state.yourState == 'string' && <MyComponent /> }
//Normal condition
if(this.state.yourState){
return <MyComponent />
}else{
return null;
}
<button onClick={()=>this.setState({yourState: !this.props.yourState}>Toggle View</button>

Just figure out a new and magic way with using(useReducer) for functional components
const [state, handleChangeState] = useReducer((state) => !state, false);
change state

This can also be achieved like this (very easy way)
class app extends Component {
state = {
show: false
};
toggle= () => {
var res = this.state.show;
this.setState({ show: !res });
};
render() {
return(
<button onClick={ this.toggle }> Toggle </button>
{
this.state.show ? (<div> HELLO </div>) : null
}
);
}

this example shows how you can switch between components by using a toggle which switches after every 1sec
import React ,{Fragment,Component} from "react";
import ReactDOM from "react-dom";
import "./styles.css";
const Component1 = () =>(
<div>
<img
src="https://i.pinimg.com/originals/58/df/1d/58df1d8bf372ade04781b8d4b2549ee6.jpg" />
</div>
)
const Component2 = () => {
return (
<div>
<img
src="http://www.chinabuddhismencyclopedia.com/en/images/thumb/2/2e/12ccse.jpg/250px-
12ccse.jpg" />
</div>
)
}
class App extends Component {
constructor(props) {
super(props);
this.state = {
toggleFlag:false
}
}
timer=()=> {
this.setState({toggleFlag:!this.state.toggleFlag})
}
componentDidMount() {
setInterval(this.timer, 1000);
}
render(){
let { toggleFlag} = this.state
return (
<Fragment>
{toggleFlag ? <Component1 /> : <Component2 />}
</Fragment>
)
}
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);

The application of states and effects has and must be encapsulated in the same component, for this reason, there is nothing better than creating a custom component as a hook to solve in this case whether to make particular blocks or elements visible or invisible.
// hooks/useOnScreen.js
import { useState, useEffect } from "react"
const useOnScreen = (ref, rootMargin = "0px") => {
const [isVisible, setIsVisible] = useState(false)
useEffect(() => {
const observer = new IntersectionObserver(
([entry]) => {
setIsVisible(entry.isIntersecting)
},
{
rootMargin
}
);
const currentElement = ref?.current
if (currentElement) {
observer.observe(currentElement)
}
return () => {
observer.unobserve(currentElement)
}
}, [])
return isVisible
}
export default useOnScreen
Then the custom hook is embedded inside the component
import React, { useRef } from "react";
import useOnScreen from "hooks/useOnScreen";
const MyPage = () => {
const ref = useRef(null)
const isVisible = useOnScreen(ref)
const onClick = () => {
console.log("isVisible", isVisible)
}
return (
<div ref={ref}>
<p isVisible={isVisible}>
Something is visible
</p>
<a
href="#"
onClick={(e) => {
e.preventDefault();
onClick(onClick)
}}
>
Review
</a>
</div>
)
}
export default MyPage
The ref variable, controlled by the useRef hook, allows us to capture the location in the DOM of the block that we want to control, then the isVisible variable, controlled by the useOnScreen hook, allows us to make the inside the block I signal by the useRef hook.
I believe that this implementation of the useState, useEfect, and useRef hooks allows you to avoid component rendering by separating them using custom hooks.
Hoping that this knowledge will be of use to you.

It is very simple to hide and show the elements in react.
There are multiple ways but I will show you two.
Way 1:
const [isVisible, setVisible] = useState(false)
let onHideShowClick = () =>{
setVisible(!isVisible)
}
return (<div>
<Button onClick={onHideShowClick} >Hide/Show</Button>
{(isVisible) ? <p>Hello World</p> : ""}
</div>)
Way 2:
const [isVisible, setVisible] = useState(false)
let onHideShowClick = () =>{
setVisible(!isVisible)
}
return (<div>
<Button onClick={onHideShowClick} >Hide/Show</Button>
<p style={{display: (isVisible) ? 'block' : 'none'}}>Hello World</p>
</div>)
It is just working like if and else.
In Way one, it will remove and re-render elements in Dom.
In the Second way you are just displaying elements as false or true.
Thank you.

You've to do the small change in the code for continuously hiding and showing
const onClick = () => {setShowResults(!showResults}
Problem will be solved
const Search = () => {
const [showResults, setShowResults] = React.useState(false)
const onClick = () => setShowResults(true)
const onClick = () => {setShowResults(!showResults}
return (
<div>
<input type="submit" value="Search" onClick={onClick} />
{ showResults ? <Results /> : null }
</div>
)
}
const Results = () => (
<div id="results" className="search-results">
Some Results
</div>
)
ReactDOM.render(<Search />, document.querySelector("#container"))
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.13.1/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.13.1/umd/react-dom.production.min.js"></script>
<div id="container">
<!-- This element's contents will be replaced with your component. -->
</div>
```