My React app has multiple functional components that repeats the same conditional logic, which I would like to extract to its own component to avoid duplicating it across all the components.
Below is an example of one of the pages that shows the repeated boilerplate code. If the global window.userPermission does not contain the value Page1, the user is redirected to the home page.
Is there some way to modularize this conditional logic including redirect, while passing it the permissions string (Page1, etc.)?
import ...
export default function SomeComponent() {
// begin boilerplate code
if (
window.userPermission != null &&
!window.userPermission.find(permission => permission.id == 'Page1')
) {
return (
<div>
<Redirect to="/" />
</div>
);
}
// end boilerplate code
return (
<div>
<Page1/>
</div>
);
}
Really easy just wrap your page in a wrapper component and if a value is true return the children or else redirect.
import {Redirect} from 'react-router-dom'
const SomeComponent = ({children, page}) => {
if (
window.userPermission != null &&
!window.userPermission.find(permission => permission.id == page)
) return children
return <Redirect to="/" />
}
export default SomeComponent
Then use this component like so:
<SomeComponent page="page1">
<Page1/>
</SomeComponent>
Related
I want to render multiple instances of the same component. Here is the component that will be repeated (not my actual component, just an example):
import React from 'react';
function Repeated () {
return (
<div></div>
)
}
export default Repeated;
And the component that will repeat the other (again, just an example):
import React from 'react';
import Repeated from './Component1';
function OtherComp () {
return (
<div>
<Repeated />
<Repeated />
<Repeated />
<Repeated />
</div>
)
}
export default OtherComp;
Is there any way I can add the "Repeated" component multiple times through something like a loop, instead of having to copy and paste the component multiple times? Thanks :)
You can create a new array of desired length and map it to the components. However, you have to add a key to every one of them or ignore a warning:
With warning:
return (
<div>
{Array(4).fill(<Repeated />)}
</div>
)
Mapping to keys:
return (
<div>
{Array(4).fill(true).map((_, i) => <Repeated key={i} />)}
</div>
)
If you have an array for example and want to render each element as Repeat you can write
import React from 'react';
import Repeated from './Component1';
function OtherComp () {
// get array via fetch or something else
return (
<div>
{ array.map(item => <Repeated key={a-unique-key} item={item} />) }
</div>
)
}
export default OtherComp;
You can loop through the array of props you want to render via the Repeated components, provided that each of the rendered components has a unique key
The solution provided by #Jakub should work fine
I'm covering app js with layout. I have the sidebar on the left and my pages on the right. But what I want is that the sidebar should not appear on the login page, how can I edit it?
_app.js
Layout.js
you can add a condition with pathname to showing the component or not
something like this:
const router = useRouter():
return (
...
{router.pathname !== '/login' && <Sidebar path={router.route} />}
...
)
If you have some pages that are protected and can be seen by logged in user than you would need Public and Protected Routes and you can show in your Public routes only
If this is not the case then solution mentioned by #kaveh karami is good
I'm thinking you should use Option 4 of the Persistent Layout Patterns article by Adam Wathan (the getLayout Pattern) to implement the layout and pass a prop to conditionally render the sidebar.
In this way, your Login / Register page controls the layout rendering
// Layout.js
export default function Layout({ showSidebar, children, ...rest }){
return (
...
{showSidebar && <Sidebar />}
...
)
}
export function getLayout(page, props) {
return <Layout {...props}>{page}</DefaultLayout>
}
// Login.js
import { getLayout as getDefaultLayout } from './Layout.js'
function Login(){
return (
...
)
}
Login.getLayout = page => getDefaultLayout(page, { showSidebar: true})
I would create a HOC(Higher-Order-Component) called WithSidebar:
import Main from '../../components/Main/Main';
import Sidebar from '../../components/Sidebar/Sidebar';
import classes from './WithSidebar.module.scss';
const WithSidebar = (Component) => {
return props => (
<div className={classes.WithSidebar}>
<Sidebar />
<Main className={classes.Container}>
<Component {...props} />
</Main>
</div>
);
};
export default WithSidebar;
And then export the pages that should include the sidebar like so:
import WithSidebar from '../hoc/WithSidebar/WithSidebar';
const MyPage = () => {
return (...)
}
export default WithSidebar(MyPage)
I find this approach really cleaner than conditionally rendering based on the pathname.
import books from '../books'
function BookScreen({ match }) {
const book = books.find((b) => b._id === match.params.id)
return (
<div>
{book}
</div>
)
}
export default BookScreen
I keep getting the error match is undefined. I saw a tutorial with similar code, but it seemed fine when put to the test. Any clue what might be the issue?
If match prop is undefined this could be from a few things.
react-router-dom v5
If using RRDv5 if the match prop is undefined this means that BookScreen isn't receiving the route props that are injected when a component is rendered on the Route component's component prop, or the render or children prop functions. Note that using children the route will match and render regardless, see route render methods for details.
Ensure that one of the following is implemented to access the match object:
Render BookScreen on the component prop of a Route
<Route path="...." component={BookScreen} />
Render BookScreen on the render or children prop function of a Route and pass the route props through
<Route path="...." render={props => <BookScreen {...props} />} />
or
<Route path="...." children={props => <BookScreen {...props} />} />
Decorate BookScreen with the withRouter Higher Order Component to have the route props injected
import { withRouter } from 'react-router-dom';
function BookScreen = ({ match }) {
const book = books.find((b) => b._id === match.params.id)
return (
<div>
{book}
</div>
);
};
export default withRouter(BookScreen);
Since BookScreen is a React function component, import and use the useParams hook to access the route match params
import { useParams } from 'react-router-dom';
...
function BookScreen() {
const { id } = useParams();
const book = books.find((b) => b._id === id)
return (
<div>
{book}
</div>
);
}
react-router-dom v6
If using RRDv6 then there is no match prop. Gone are the route props. Here only the useParams and other hooks exist, so use them.
import { useParams } from 'react-router-dom';
...
function BookScreen() {
const { id } = useParams();
const book = books.find((b) => b._id === id)
return (
<div>
{book}
</div>
);
}
If you've other class components and you're using RRDv6 and you don't want to convert them to function components, then you'll need to create a custom withRouter component. See my answer here with details.
I guess you rendered BookScreen component before match is initialized. This is why match is undefined when BookScreen rendered. Render it conditionally like below.
return (
... other components
{match && <BookScreen match={match}/>}
)
Also, I leave useful site which tells you some good ways to do that. :D
https://www.digitalocean.com/community/tutorials/7-ways-to-implement-conditional-rendering-in-react-applications
I hope you find an answer :D
Trying to render state from Context API, but in console it shows as undefined and doesn't render anything.
here is Context file
import React, { useReducer, createContext } from "react"
export const GlobalStateContext = createContext()
export const GlobalDispatchContext = createContext()
const initialState = {
isLoggedIn: "logged out",
}
function reducer(state, action) {
switch (action.type) {
case "TOGGLE_LOGIN":
{
return {
...state,
isLoggedIn: state.isLoggedIn === false ? true : false,
}
}
break
default:
throw new Error("bad action")
}
}
const GlobalContextProvider = ({ children }) => {
const [state, dispatch] = useReducer(reducer, initialState)
return (
<GlobalStateContext.Provider value={state}>
{children}
</GlobalStateContext.Provider>
)
}
export default GlobalContextProvider
and here is where value should be rendered
import React, { useContext } from "react"
import {
GlobalStateContext,
GlobalDispatchContext,
} from "../context/GlobalContextProvider"
const Login = () => {
const state = useContext(GlobalStateContext)
console.log(state)
return (
<>
<GlobalStateContext.Consumer>
{value => <p>{value}</p>}
</GlobalStateContext.Consumer>
</>
)
}
export default Login
I tried before the same thing with class component but it didn't solve the problem. When I console log context it looks like object with undefined values.
Any ideas?
The Context API In General
From the comments, it seems the potential problem is that you're not rendering <Login /> as a child of <GlobalContextProvider />. When you're using a context consumer, either as a hook or as a function, there needs to be a matching provider somewhere in the component tree as its parent.
For example, these would not work:
<div>
<h1>Please log in!</h1>
<Login />
</div>
<React.Fragment>
<GlobalContextProvider />
<Login />
</React.Fragment>
because in both of those, the Login component is either a sibling of the context provider, or the provider is missing entirely.
This, however, would work:
<React.Fragment>
<GlobalContextProvider>
<Login />
</GlobalContextProvider>
</React.Fragment>
because the Login component is a child of the GlobalContextProvider.
Related To Gatsby
This concept is true regardless of what library or framework you're using to make your app. In Gatsby specifically there's a little bit of work you have to do to get this to work at a page level, but it's possible.
Let's say you have a Layout.jsx file defined, and the following page:
const Index = () => (
<Layout>
<h1>{something that uses context}</h1>
</Layout>
)
You have 2 options:
The easier option is to extract that h1 into its own component file. Then you can put the GlobalContextProvider in the Layout and put the context consumer in the new component. This would work because the h1 is being rendered as a child of the layout.
Is to do some shuffling.
You might be inclined to put the Provider in the layout and try to consume it in the page. You might think this would work because the h1 is still being rendered as a child of the Layout, right? That is correct, but the context is not being consumed by the h1. The context is being rendered by the h1 and consumed by Index, which is the parent of <Layout>. Using it at a page level is possible, but what you would have to do is make another component (IndexContent or something similar), consume your context in there, and render that as a child of layout. So as an example (with imports left out for brevity):
const Layout = ({children}) => (
<GlobalContextProvider>
{children}
</GlobalContextProvider>
);
const IndexContent = () => {
const {text} = useContext(GlobalStateContext);
return <h1>{text}</h1>;
}
const Index = () => (
<Layout>
<IndexContent />
</Layout>
);
Test Case
https://codesandbox.io/s/rr00y9w2wm
Steps to reproduce
Click on Topics
Click on Rendering with React
OR
Go to https://rr00y9w2wm.codesandbox.io/topics/rendering
Expected Behavior
match.params.topicId should be identical from both the parent Topics component should be the same as match.params.topicId when accessed within the Topic component
Actual Behavior
match.params.topicId when accessed within the Topic component is undefined
match.params.topicId when accessed within the Topics component is rendering
I understand from this closed issue that this is not necessarily a bug.
This requirement is super common among users who want to create a run in the mill web application where a component Topics at a parent level needs to access the match.params.paramId where paramId is a URL param that matches a nested (child) component Topic:
const Topic = ({ match }) => (
<div>
<h2>Topic ID param from Topic Components</h2>
<h3>{match.params.topicId}</h3>
</div>
);
const Topics = ({ match }) => (
<div>
<h2>Topics</h2>
<h3>{match.params.topicId || "undefined"}</h3>
<Route path={`${match.url}/:topicId`} component={Topic} />
...
</div>
);
In a generic sense, Topics could be a Drawer or Navigation Menu component and Topic could be any child component, like it is in the application I'm developing. The child component has it's own :topicId param which has it's own (let's say) <Route path="sections/:sectionId" component={Section} /> Route/Component.
Even more painful, the Navigation Menu needn't have a one-to-one relationship with the component tree. Sometimes the items at the root level of the menu (say Topics, Sections etc.) might correspond to a nested structure (Sections is only rendered under a Topic, /topics/:topicId/sections/:sectionId though it has its own normalized list that is available to the user under the title Sections in the Navigation Bar).
Therefore, when Sections is clicked, it should be highlighted, and not both Sections and Topics.
With the sectionId or sections path unavailable to the Navigation Bar component which is at the Root level of the application, it becomes necessary to write hacks like this for such a commonplace use case.
I am not an expert at all at React Router, so if anyone can venture a proper elegant solution to this use case, I would consider this to be a fruitful endeavor. And by elegant, I mean
Uses match and not history.location.pathname
Does not involve hacky approaches like manually parsing the window.location.xxx
Doesn't use this.props.location.pathname
Does not use third party libraries like path-to-regexp
Does not use query params
Other hacks/partial solutions/related questions:
React Router v4 - How to get current route?
React Router v4 global no match to nested route childs
TIA!
React-router doesn't give you the match params of any of the matched children Route , rather it gives you the params based on the current match. So if you have your Routes setup like
<Route path='/topic' component={Topics} />
and in Topics component you have a Route like
<Route path=`${match.url}/:topicId` component={Topic} />
Now if your url is /topic/topic1 which matched the inner Route but for the Topics component, the matched Route is still, /topic and hence has no params in it, which makes sense.
If you want to fetch params of the children Route matched in the topics component, you would need to make use of matchPath utility provided by React-router and test against the child route whose params you want to obtain
import { matchPath } from 'react-router'
render(){
const {users, flags, location } = this.props;
const match = matchPath(location.pathname, {
path: '/topic/:topicId',
exact: true,
strict: false
})
if(match) {
console.log(match.params.topicId);
}
return (
<div>
<Route exact path="/topic/:topicId" component={Topic} />
</div>
)
}
EDIT:
One method to get all the params at any level is to make use of context and update the params as and when they match in the context Provider.
You would need to create a wrapper around Route for it to work correctly, A typical example would look like
RouteWrapper.jsx
import React from "react";
import _ from "lodash";
import { matchPath } from "react-router-dom";
import { ParamContext } from "./ParamsContext";
import { withRouter, Route } from "react-router-dom";
class CustomRoute extends React.Component {
getMatchParams = props => {
const { location, path, exact, strict } = props || this.props;
const match = matchPath(location.pathname, {
path,
exact,
strict
});
if (match) {
console.log(match.params);
return match.params;
}
return {};
};
componentDidMount() {
const { updateParams } = this.props;
updateParams(this.getMatchParams());
}
componentDidUpdate(prevProps) {
const { updateParams, match } = this.props;
const currentParams = this.getMatchParams();
const prevParams = this.getMatchParams(prevProps);
if (!_.isEqual(currentParams, prevParams)) {
updateParams(match.params);
}
}
componentWillUnmount() {
const { updateParams } = this.props;
const matchParams = this.getMatchParams();
Object.keys(matchParams).forEach(k => (matchParams[k] = undefined));
updateParams(matchParams);
}
render() {
return <Route {...this.props} />;
}
}
const RouteWithRouter = withRouter(CustomRoute);
export default props => (
<ParamContext.Consumer>
{({ updateParams }) => {
return <RouteWithRouter updateParams={updateParams} {...props} />;
}}
</ParamContext.Consumer>
);
ParamsProvider.jsx
import React from "react";
import { ParamContext } from "./ParamsContext";
export default class ParamsProvider extends React.Component {
state = {
allParams: {}
};
updateParams = params => {
console.log({ params: JSON.stringify(params) });
this.setState(prevProps => ({
allParams: {
...prevProps.allParams,
...params
}
}));
};
render() {
return (
<ParamContext.Provider
value={{
allParams: this.state.allParams,
updateParams: this.updateParams
}}
>
{this.props.children}
</ParamContext.Provider>
);
}
}
Index.js
ReactDOM.render(
<BrowserRouter>
<ParamsProvider>
<App />
</ParamsProvider>
</BrowserRouter>,
document.getElementById("root")
);
Working DEMO
Try utilizing query parameters ? to allow the parent and child to access the current selected topic. Unfortunately, you will need to use the module qs because react-router-dom doesn't automatically parse queries (react-router v3 does).
Working example: https://codesandbox.io/s/my1ljx40r9
URL is structured like a concatenated string:
topic?topic=props-v-state
Then you would add to the query with &:
/topics/topic?topic=optimization&category=pure-components&subcategory=shouldComponentUpdate
✔ Uses match for Route URL handling
✔ Doesn't use this.props.location.pathname (uses this.props.location.search)
✔ Uses qs to parse location.search
✔ Does not involve hacky approaches
Topics.js
import React from "react";
import { Link, Route } from "react-router-dom";
import qs from "qs";
import Topic from "./Topic";
export default ({ match, location }) => {
const { topic } = qs.parse(location.search, {
ignoreQueryPrefix: true
});
return (
<div>
<h2>Topics</h2>
<ul>
<li>
<Link to={`${match.url}/topic?topic=rendering`}>
Rendering with React
</Link>
</li>
<li>
<Link to={`${match.url}/topic?topic=components`}>Components</Link>
</li>
<li>
<Link to={`${match.url}/topic?topic=props-v-state`}>
Props v. State
</Link>
</li>
</ul>
<h2>
Topic ID param from Topic<strong>s</strong> Components
</h2>
<h3>{topic && topic}</h3>
<Route
path={`${match.url}/:topicId`}
render={props => <Topic {...props} topic={topic} />}
/>
<Route
exact
path={match.url}
render={() => <h3>Please select a topic.</h3>}
/>
</div>
);
};
Another approach would be to create a HOC that stores params to state and children update the parent's state when its params have changed.
URL is structured like a folder tree: /topics/rendering/optimization/pure-components/shouldComponentUpdate
Working example: https://codesandbox.io/s/9joknpm9jy
✔ Uses match for Route URL handling
✔ Doesn't use this.props.location.pathname
✔ Uses lodash for object to object comparison
✔ Does not involve hacky approaches
Topics.js
import map from "lodash/map";
import React, { Fragment, Component } from "react";
import NestedRoutes from "./NestedRoutes";
import Links from "./Links";
import createPath from "./createPath";
export default class Topics extends Component {
state = {
params: "",
paths: []
};
componentDidMount = () => {
const urlPaths = [
this.props.match.url,
":topicId",
":subcategory",
":item",
":lifecycles"
];
this.setState({ paths: createPath(urlPaths) });
};
handleUrlChange = params => this.setState({ params });
showParams = params =>
!params
? null
: map(params, name => <Fragment key={name}>{name} </Fragment>);
render = () => (
<div>
<h2>Topics</h2>
<Links match={this.props.match} />
<h2>
Topic ID param from Topic<strong>s</strong> Components
</h2>
<h3>{this.state.params && this.showParams(this.state.params)}</h3>
<NestedRoutes
handleUrlChange={this.handleUrlChange}
match={this.props.match}
paths={this.state.paths}
showParams={this.showParams}
/>
</div>
);
}
NestedRoutes.js
import map from "lodash/map";
import React, { Fragment } from "react";
import { Route } from "react-router-dom";
import Topic from "./Topic";
export default ({ handleUrlChange, match, paths, showParams }) => (
<Fragment>
{map(paths, path => (
<Route
exact
key={path}
path={path}
render={props => (
<Topic
{...props}
handleUrlChange={handleUrlChange}
showParams={showParams}
/>
)}
/>
))}
<Route
exact
path={match.url}
render={() => <h3>Please select a topic.</h3>}
/>
</Fragment>
);
If you have a known set of child routes then you can use something like this:
Import {BrowserRouter as Router, Route, Switch } from 'react-router-dom'
<Router>
<Route path={`${baseUrl}/home/:expectedTag?/:expectedEvent?`} component={Parent} />
</Router>
const Parent = (props) => {
return (
<div >
<Switch>
<Route path={`${baseUrl}/home/summary`} component={ChildOne} />
<Route
path={`${baseUrl}/home/:activeTag/:activeEvent?/:activeIndex?`}
component={ChildTwo}
/>
</Switch>
<div>
)
}
In the above example Parent will get expectedTag, expectedEvent as the match params and there is no conflict with the child components and Child component will get activeTag, activeEvent, activeIndex as the parameters. Same name for params can also be used, I have tried that as well.
Try to do something like this:
<Switch>
<Route path="/auth/login/:token" render={props => <Login {...this.props} {...props}/>}/>
<Route path="/auth/login" component={Login}/>
First, the route with the parameter and after the link without parameter.
Inside my Login component I put this line of code console.log(props.match.params.token); to test and worked for me.
If you happen to use React.FC, there is a hook useRouteMatch.
For instance, parent component routes:
<div className="office-wrapper">
<div className="some-parent-stuff">
...
</div>
<div className="child-routes-wrapper">
<Switch>
<Route exact path={`/office`} component={List} />
<Route exact path={`/office/:id`} component={Alter} />
</Switch>
</div>
</div>
And in your child component:
...
import { useRouteMatch } from "react-router-dom"
...
export const Alter = (props) => {
const match = useRouteMatch()
const officeId = +match.params.id
//... rest function code
}