how to Sum the max from two keys similarly, object javascript [closed] - javascript

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I need the sum total of the object, where, but the maximum of each similar pair
javascript
var score = {
"work_1": 5,
"work_1|pm": 10,
"work_2": 8,
"work_2|pm": 7
"work_3": 10
};
the work_3 doesn't have a pair similar
I wish this result
total = 28

Group the maximums by key-prefix in a new object, and then sum the values of that object. In both phases you can use reduce:
var score = {
"work_1": 5,
"work_1|pm": 10,
"work_2": 8,
"work_2|pm": 7,
"work_3": 10
};
var result = Object.values(
Object.entries(score).reduce((acc, [k, v]) => {
k = k.split("|")[0];
acc[k] = Math.max(v, acc[k] ?? v);
return acc;
}, {})
).reduce((a, b) => a + b, 0);
console.log(result);

You can get the property values of the object with Object.values, sort the resulting array, then sum the first 2 items:
var score = {
"work_1": 5,
"work_1|pm": 10,
"work_2": 8,
"work_2|pm": 7,
"work_3": 10
};
const max2 = Object.values(score).sort().splice(0, 2)
const result = max2[0] + max2[1];
console.log(result)

Related

javascript Extract multiple series array from string [closed]

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I have string like
var t = 'red: 5, purple: 7, fuchsia: 10, green: 8';
I want to make array like
a = ['red', 'purple', 'fuchsia', 'green'];
b = [ 5, 7, 10, 8]
Please help me
Sample solution:
const t = 'red: 5, purple: 7, fuchsia: 10, green: 8';
const tarr = t.split(', ');
const a = [];
const b = [];
for (const item of tarr) {
const [k, v] = item.split(': ');
a.push(k);
b.push(~~v); // '~~' is a shortcut to convert string value to number
}
console.log(a, b);

How can I formulate the function solution? [closed]

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x = [1, 2, 3, 4]
t = []
c = []
for(i = 0; i<x.length; i++){
function solution(){
t = Math.pow(x, 2)
c = t[i]++
return c
}
}
The function needs to:
Count the squares of the array numbers
Then to get sum of squared (I am not sure if I wrote it correct, LOL) numbers. Thanks!
const result = [1, 2, 3, 4].map(n => n ** 2).reduce((acc, val) => acc + val, 0);
console.log(result);
You can also use ** operator which is faster than Math.pow(). https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators
var result = [1, 2, 3, 4].map(n => Math.pow(n, 2)).reduce((acc, val) => acc + val, 0);
console.log(result);

Array of Objects check for equality and place accordingly [closed]

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I have a very interesting Problem and would like to hear some approaches that you would take.
Scenario:
A Tournament of 32 Players, each represented in an Array of Objects ex:
[
{ player: 'Badgy', points: 5, place: tba, reward: 0 },
{ player: 'Ceff', points: 5, place: tba, reward: 0},
{ player: 'Niclas', points: 10, place: tba, reward: 0}
]
Now there are prices defined for each of the top places like:
1 Place = 100 Coins
2 Place = 50 Coins
3 Place = 10 Coins
Now in this example 'Ceff' and 'Badgy' have the same point amount, which means they both have to be place 2 and get the reward of (place2 + place3) / 2, each of them would get 30 coins in this example.
Now I tried around but I have a hard time finding a good solution to this case, specially if a 3+ way tie happens.
You could take a sum and an index for the first found group of same points and take the average for the last same group.
var prices = [100, 50, 20, 15, 10, 5, 2, 1],
points = [ 20, 10, 10, 5, 5, 5, 4, 3],
sum = 0,
index,
profit = points.reduce((r, v, i, { [i - 1]: last }) => {
if (last !== v) {
sum = 0;
index = i;
}
sum += prices[i];
var avg = sum / (i - index + 1);
while (i >= index) r[i--] = avg;
return r;
}, []);
console.log(profit);

Given an array of unique numbers, list the combination of numbers which sum equals to given integer [closed]

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Input
Array =[4,2,8,11,14,6,1]
Expectedtotal=20
Output
[2,4,6,8], [11,8,1],[6,11,1,2],[2,14,4],[14,6]
code:
const arr = [4, 2, 8, 11, 14, 6, 1];
const target = 20;
res = _.filter(arr, v => _.filter(arr, v1 => _.filter(arr, v2 => _.filter(arr, v3 => v + v1 + v2 + v3 === target))); console.log(res);
I am the beginner of javascript and lodash. I tried this code by own..please help me to write good code.
You could use a temporary array and the index and iterate the next index by either taking the actual value or not.
function subsetSum(array, sum) {
function iter(index, temp, s) {
if (s === sum) return result.push(temp.slice()); // exit sum found
if (index >= array.length) return; // exit index over
iter(index + 1, temp.concat(array[index]), s + array[index]); // take value
iter(index + 1, temp, s); // omit value
}
var result = [];
iter(0, [], 0);
return result;
}
console.log(subsetSum([4, 2, 8, 11, 14, 6, 1], 20).map(a => a.join(' ')));

How to multiply each element in an array with a different number (javascript) [closed]

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var array = [0, 1, 2, 3];
var numbers = [3, 6 ,2, 7];
I want to multiply each number in array with numbers without repetition of numbers from numbers
Fixed number for all index
var array = [0, 1, 2, 3];
array.map(
function(n){
return (n* number to be multiplied);
}
);
Different number for each index
var array = [0, 1, 2, 3], numberToBeMultiplied = [1,3,5,7];
array.map(
function(n, i){
return n * numberToBeMultiplied[i];
});
You can also push the returning elements in an array.
Your question is not clear enough, what I get you may want to do something like this.
var array = [1,2,3,4]
var array2 = [];
for(var i = 0; i < array.length; i++) {
var randomMultiplier = Math.floor((Math.random() * 10) + 1); //Return a random number between 1 and 10
array2.push(array[i] * randomMultiplier);
$('#multiplied-list').append('<li>'+array[i] * randomMultiplier+'</li>')
}
console.log(array2);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul id="multiplied-list"></ul>

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