Set order of uploaded images (JS, PHP) - javascript

My goal is to get a way to upload multiple images and also set in which order they should be displayed later on (it's for an ecommerce website). I have an idea which seems to work. But I would like to know if there is a better way of doing this. Here is my code. Let's assume the number of images is limited to 3.
One input for multiple images.
Preview images and make them sortable.
Store the order in hidden inputs.
Store the images in the filesystem.
Add the path and order index of every image to the database.
HTML
<!-- One input for all images -->
<input type="file" name="images[]" onchange="previewImages(this)" multiple>
<!-- This <div> will be made sortable with SortableJS -->
<div id="preview-parent">
<div class="preview">
<!--
Hidden input to save the order of images.
The idea is to have images_order[name_of_image] = index.
name_of_image and index will be set with JavaScript
-->
<input class="order-input" type="hidden" name="images_order[]" value="0">
<!-- <img> is for preview -->
<img class="preview-image" src="" alt="Image1">
</div>
<div class="preview">
<input class="order-input" type="hidden" name="images_order[]" value="1">
<img class="preview-image" src="" alt="Image2">
</div>
<div class="preview">
<input class="order-input" type="hidden" name="images_order[]" value="2">
<img class="preview-image" src="" alt="Image3">
</div>
</div>
JavaScript
function previewImages(input) {
// First I take the images
var file = input.files
// Then I go through each of them. This code is based on the explanation
// from https://developer.mozilla.org/en-US/docs/Web/API/FileReader/readAsDataURL
for (var i = 0; i < file.length; i++) {
let preview = document.querySelectorAll('.preview-image')[i]
let reader = new FileReader()
reader.onloadend = function () {
preview.src = reader.result
}
if (file[i]) {
reader.readAsDataURL(file[i])
// In addition to previewing images I take their names
// and put them into my hidden inputs
let order_inputs = document.querySelectorAll('.order-input')
order_inputs[i].name = 'images_order[' + file[i].name +']'
} else {
preview.src = ""
}
}
}
// I make the images sortable by means of SortableJS
var el = document.getElementById('preview-parent')
new Sortable(el, {
animation: 150,
// This function updates the values of my hidden inputs
// every time a change is made
onEnd: function (event) {
let order_inputs = document.querySelectorAll('.order-input')
for (var i = 0; i < order_inputs.length; i++) {
order_inputs[i].value = [i]
}
}
})
function previewImages(input) {
var file = input.files
for (var i = 0; i < file.length; i++) {
let preview = document.querySelectorAll('.preview-image')[i]
let reader = new FileReader()
reader.onloadend = function () {
preview.src = reader.result
}
if (file[i]) {
reader.readAsDataURL(file[i])
let order_inputs = document.querySelectorAll('.order-input')
order_inputs[i].name = 'images_order[' + file[i].name +']'
} else {
preview.src = ""
}
}
}
var el = document.getElementById('preview-parent')
new Sortable(el, {
animation: 150,
onEnd: function (event) {
let order_inputs = document.querySelectorAll('.order-input')
for (var i = 0; i < order_inputs.length; i++) {
order_inputs[i].value = [i]
}
}
})
#preview-parent {
display: flex;
gap: 1rem;
margin: 1rem;
}
.preview {
height: 100px;
width: 100px;
padding: 1rem;
border: 1px solid grey;
}
.preview img {
max-height: 100%;
max-width: 100%;
}
<script src="https://cdn.jsdelivr.net/npm/sortablejs#latest/Sortable.min.js"></script>
<input type="file" name="images[]" onchange="previewImages(this)" multiple>
<div id="preview-parent">
<div class="preview">
<input class="order-input" type="hidden" name="images_order[]" value="0">
<img class="preview-image" src="" alt="Image1">
</div>
<div class="preview">
<input class="order-input" type="hidden" name="images_order[]" value="1">
<img class="preview-image" src="" alt="Image2">
</div>
<div class="preview">
<input class="order-input" type="hidden" name="images_order[]" value="2">
<img class="preview-image" src="" alt="Image3">
</div>
</div>
I haven't figured out yet how to limit the number of submitted images. But I saw a number of discussions about that, so I hope it will not be a problem.
PHP. The next step is done by means of PHP (CodeIgniter 4). I take the images, store them in my filesystem. Also I add the path to every image and its order index (taken from the hidden input) to the database. Later when a user will open certain product, the data will be taken from the database and ordered by order index. So basically my controller has this:
// I inserted the product before and can get its id
$product_id = $this->products->insertID();
// This line is just for reference, I actually create $input earlier
$input = $this->request->getPost();
// Here I take all the images as suggested in CodeIgniter docs
if($imagefile = $this->request->getFiles())
{
foreach($imagefile['images'] as $img)
{
if ($img->isValid() && ! $img->hasMoved())
{
// Store each image
$name = $img->getName();
$img->move('assets/images/'.$product_id, $name);
// Add info about the image to the database
$data = [
'product_id' => $product_id,
'path' => base_url('assets/images/'.$product_id.'/'.$name),
'order_index' => $input['images_order'][$name],
];
$this->imagesModel->insert($data);
}
}
}
It would be perfect if I could upload multiple images at once and then not only reorder them but also be able to replace one of the images. If someone could share any ideas, I will appreciate it very much!

After long time I have returned to this project and made further research. So I would like to share my solution.
So I have decided that a convenient option will be to have only one input for multiple images. The user clicks it and chooses the needed images. If he needs to add more images after this, he clicks the same input again and the new images are added to the list. All images immediately appear as previews with the "delete" button. So if the user needs to replace one image, he can delete it, upload a new image and move it to the needed place.
The PHP code from my post does not require any changes. The work is done in Javascript. There are lots of lines of code, but a big part of them is simply for dynamic generating of previews. Please see the snippet.
// DataTransfer allows updating files in input
var dataTransfer = new DataTransfer()
const form = document.querySelector('#form')
const input = document.querySelector('#input')
input.addEventListener('change', () => {
let files = input.files
for (let i = 0; i < files.length; i++) {
// A new upload must not replace images but be added
dataTransfer.items.add(files[i])
// Generate previews using FileReader
let reader, preview, previewImage
reader = new FileReader()
preview = document.createElement('div')
previewImage = document.createElement('img')
deleteButton = document.createElement('button')
orderInput = document.createElement('input')
preview.classList.add('preview')
document.querySelector('#preview-parent').appendChild(preview)
deleteButton.setAttribute('data-index', i)
deleteButton.setAttribute('onclick', 'deleteImage(this)')
deleteButton.innerText = 'Delete'
orderInput.type = 'hidden'
orderInput.name = 'images_order[' + files[i].name + ']'
preview.appendChild(previewImage)
preview.appendChild(deleteButton)
preview.appendChild(orderInput)
reader.readAsDataURL(files[i])
reader.onloadend = () => {
previewImage.src = reader.result
}
}
// Update order values for all images
updateOrder()
// Finally update input files that will be sumbitted
input.files = dataTransfer.files
})
const updateOrder = () => {
let orderInputs = document.querySelectorAll('input[name^="images_order"]')
let deleteButtons = document.querySelectorAll('button[data-index]')
for (let i = 0; i < orderInputs.length; i++) {
orderInputs[i].value = [i]
deleteButtons[i].dataset.index = [i]
// Just to show that order is always correct I add index here
deleteButtons[i].innerText = 'Delete (index ' + i + ')'
}
}
const deleteImage = (item) => {
// Remove image from DataTransfer and update input
dataTransfer.items.remove(item.dataset.index)
input.files = dataTransfer.files
// Delete element from DOM and update order
item.parentNode.remove()
updateOrder()
}
// I make the images sortable by means of SortableJS
const el = document.getElementById('preview-parent')
new Sortable(el, {
animation: 150,
// Update order values every time a change is made
onEnd: (event) => {
updateOrder()
}
})
#preview-parent {
display: flex;
}
.preview {
display: flex;
flex-direction: column;
margin: 1rem;
}
img {
width: 100px;
height: 100px;
object-fit: cover;
}
<script src="https://cdn.jsdelivr.net/npm/sortablejs#latest/Sortable.min.js"></script>
<form method="post" enctype="multipart/form-data" id="form">
<input type="file" name="images[]" id="input" multiple>
<button type="submit">Save</button>
</form>
<!-- This <div> will be made sortable with SortableJS -->
<div id="preview-parent">
<!-- After upload Javascript will generate previews with this pattern
<div class="preview">
<img src="...">
<button data-index=0>Delete</button>
<input type="hidden" name="images_order['name']" value=0>
</div>
-->
</div>

Related

JQuery remove selected file from list

I have multiple file input and I am returning names of selected items, I want to add remove option to my list so for instance when user selects 2 files then can remove any of them before uploading files.
Code
<!-- HTML -->
<input type="file" name="file" placeholder="Choose File" id="file" multiple>
<!-- showing selected files names -->
<div class="row">
<div class="col-md-12 filenames"></div>
</div>
<!-- SCRIPT -->
$(document).ready(function (e) {
document.getElementById('file').onchange = function () {
var row = 0;
if (this.files.length > 0) {
// THE TOTAL FILE COUNT.
$('.filenames').append('Total Selected Files: <b>' + this.files.length + '</b></br >');
// RUN A LOOP TO CHECK EACH SELECTED FILE.
for (var i = 0; i <= this.files.length - 1; i++) {
var fname = this.files.item(i).name; // THE NAME OF THE FILE.
var fsize = this.files.item(i).size; // THE SIZE OF THE FILE.
// SHOW THE EXTRACTED DETAILS OF THE FILE.
$('.filenames').append(++row + "- " + fname + ' (<b>' + fsize + '</b> bytes) <hr/>');
}
}
};
});
Current result
Any suggestions?
Seems like there is no method provided by the File API to remove the file from the FileList, but you could create an regular array from the FileList object and then just use the splice method and delete the file by the index.
let files = []
$("#file").on('change', function() {
files = [...files, ...this.files]
renderFiles(files)
})
$("#submit").on('click', function() {
console.log(files)
})
function renderFiles(files) {
let row = 0;
$('.filenames').html('')
if (files.length) {
$('.filenames').append(`Total Selected Files: <b>${files.length}</b></br >`);
files.forEach(({ name, size }, index) => {
const fileEl = $('<div class="file-item">')
const text = $('<span>', {
html: `${++row}- ${name} (<b>${size}</b> bytes)`
})
const btn = $('<button>', {
text: 'X'
})
btn.on('click', function() {
files.splice(index, 1)
renderFiles(files)
})
fileEl.append(text)
fileEl.append(btn)
$('.filenames').append(fileEl);
$('.filenames').append('<hr />')
})
}
}
.file-item {
display: flex;
align-items: center;
justify-content: space-between;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<!-- HTML -->
<input type="file" name="file" placeholder="Choose File" id="file" multiple>
<!-- showing selected files names -->
<div class="row">
<div class="col-md-12 filenames"></div>
</div>
<div class="row">
<button id="submit">Submit</button>
</div>

How to get multiple files from user separately?

Currently, I'm developing a drag and drop feature. The problem is that I can't figure out how to get multiple files from user separately. Let's say that we have a drop zone container and when user drops there images, it assigns them to <input type="file">. Let's say, a user drops here an image and then decides to drop another image and we have to somehow add this second image to the input. I tried finding solution in the Internet(of course :)) but found nothing that solves this problem.
Here is my HTML:
<form action="" method="POST" enctype="multipart/form-data">
<div class="drop_zone">
<span class="drop_zone__prompt">Drop your files here</span>
<input required name="images" type="file" multiple class="drop_zone__input">
</div>
<input type="submit" value="Отправить">
</form>
JavaScript:
document.querySelectorAll('.drop_zone__input').forEach(InputElement => {
const dropZoneElement = InputElement.closest('.drop_zone');
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
if (e.dataTransfer.files.length){
InputElement.files = e.dataTransfer.files;
}
});
I tried this:
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
if (e.dataTransfer.files.length){
myfiles = e.dataTransfer.add(InputElement.files);
InputElement.files = myfiles;
}
});
But it returns error saying that 'e.dataTransfer.add is not a function'
Why I tried this:
I found add() method here
And this article says:
The DataTransferItemList object is a list of DataTransferItem objects representing items being dragged. During a drag operation, each DragEvent has a dataTransfer property and that property is a DataTransferItemList.
Actually, there is a way to do that. It's far from straightforward, but it does work.
The only way to create a FileList object is to create a custom DataTransfer object. You can add files to it using dataTransfer.items.add(), and obtain the corresponding FileList through dataTransfer.files.
So, create a new DataTransfer object every time you want to add files, add the existing and the new files to it, and assign its FileList to the files property of the input element.
Note: You can't use the drop event's DataTransfer object for this, because it's read-only.
document.querySelectorAll('.drop_zone__input').forEach(InputElement => {
const dropZoneElement = InputElement.closest('.drop_zone');
dropZoneElement.addEventListener('dragover', e => {
e.preventDefault()
});
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
//Create a new DataTransfer object
const dataTransfer = new DataTransfer
//Add new files from the event's DataTransfer
for(let i = 0; i < e.dataTransfer.files.length; i++)
dataTransfer.items.add(e.dataTransfer.files[i])
//Add existing files from the input element
for(let i = 0; i < InputElement.files.length; i++)
dataTransfer.items.add(InputElement.files[i])
//Assign the files to the input element
InputElement.files = dataTransfer.files
});
})
.drop_zone{
height: 200px;
width: 200px;
border: solid black 1px;
}
<form action="" method="POST" enctype="multipart/form-data">
<div class="drop_zone">
<span class="drop_zone__prompt">Drop your files here</span>
<input required name="images" type="file" multiple class="drop_zone__input">
</div>
<input type="submit" value="Отправить">
</form>
You can also reuse the same DataTransfer object, so you don't have to re-add the existing files.
However, in this case, you also have to handle input events on the input element.
document.querySelectorAll('.drop_zone__input').forEach(InputElement => {
const dropZoneElement = InputElement.closest('.drop_zone');
const dataTransfer = new DataTransfer
dropZoneElement.addEventListener('dragover', e => {
e.preventDefault()
});
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
//Add new files from the event's DataTransfer
for(let i = 0; i < e.dataTransfer.files.length; i++)
dataTransfer.items.add(e.dataTransfer.files[i])
//Assign the files to the input element
InputElement.files = dataTransfer.files
});
InputElement.addEventListener('input', e => {
dataTransfer.items.clear()
for(let i = 0; i < InputElement.files.length; i++)
dataTransfer.items.add(InputElement.files[i])
})
})
.drop_zone{
height: 200px;
width: 200px;
border: solid black 1px;
}
<form action="" method="POST" enctype="multipart/form-data">
<div class="drop_zone">
<span class="drop_zone__prompt">Drop your files here</span>
<input required name="images" type="file" multiple class="drop_zone__input">
</div>
<input type="submit" value="Отправить">
</form>
Or, if you want to add the files when interacting with the file input instead of replacing them, you can do this:
document.querySelectorAll('.drop_zone__input').forEach(InputElement => {
const dropZoneElement = InputElement.closest('.drop_zone');
const dataTransfer = new DataTransfer
dropZoneElement.addEventListener('dragover', e => {
e.preventDefault()
});
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
//Add new files from the event's DataTransfer
for(let i = 0; i < e.dataTransfer.files.length; i++)
dataTransfer.items.add(e.dataTransfer.files[i])
//Assign the files to the input element
InputElement.files = dataTransfer.files
});
InputElement.addEventListener('input', e => {
e.preventDefault()
for(let i = 0; i < InputElement.files.length; i++)
dataTransfer.items.add(InputElement.files[i])
InputElement.files = dataTransfer.files
})
})
.drop_zone{
height: 200px;
width: 200px;
border: solid black 1px;
}
<form action="" method="POST" enctype="multipart/form-data">
<div class="drop_zone">
<span class="drop_zone__prompt">Drop your files here</span>
<input required name="images" type="file" multiple class="drop_zone__input">
</div>
<input type="submit" value="Отправить">
</form>
You can remove files from the DataTransfer object using dataTransfer.items.remove():
document.querySelectorAll('.drop_zone__input').forEach(InputElement => {
const dropZoneElement = InputElement.closest('.drop_zone');
const removeFirstElement = dropZoneElement.querySelector('.drop_zone__remove_first')
const dataTransfer = new DataTransfer
dropZoneElement.addEventListener('dragover', e => {
e.preventDefault()
});
dropZoneElement.addEventListener('drop', e => {
e.preventDefault();
//Add new files from the event's DataTransfer
for(let i = 0; i < e.dataTransfer.files.length; i++)
dataTransfer.items.add(e.dataTransfer.files[i])
//Assign the files to the input element
InputElement.files = dataTransfer.files
});
InputElement.addEventListener('input', e => {
e.preventDefault()
for(let i = 0; i < InputElement.files.length; i++)
dataTransfer.items.add(InputElement.files[i])
InputElement.files = dataTransfer.files
})
removeFirstElement.addEventListener('click', () => {
dataTransfer.items.remove(0)
InputElement.files = dataTransfer.files
})
})
.drop_zone{
height: 200px;
width: 200px;
border: solid black 1px;
}
<form action="" method="POST" enctype="multipart/form-data">
<div class="drop_zone">
<span class="drop_zone__prompt">Drop your files here</span>
<input required name="images" type="file" multiple class="drop_zone__input">
<input type="button" class="drop_zone__remove_first" value="Remove first file">
</div>
<input type="submit" value="Отправить">
</form>
You can't add to the files to the input's list of files, although apparently you can replace that list as described by FZs, which largely comes to the same thing.
Another way to deal with this is to make the original input hidden via CSS and add a new input where it used to be, so it can receive new files. You can make the UI clean by listing all of the files you're going to upload separately from the input.
How you deal with on submission depends on how you're handling submission.
If you're doing a standard HTTP form submission, ensure that your server side script handles all of the files regardless of which input they came from (it will receive more than one).
If you're submitting via ajax, you can use a FormData object and append each file to it, then submit that.
Here's a quick and dirty example maintaining the files in a FormData object:
let nextFileNum = 1;
const formData = new FormData();
const fileList = document.getElementById("file-list");
document.getElementById("inputs").addEventListener("input", function() {
let input = event.target.closest("input[type=file]");
if (!input) {
return;
}
for (const file of input.files) {
const fileId = `file${nextFileNum++}`;
formData.append(fileId, file, file.name);
debugShowCurrentFiles("added");
let div = document.createElement("div");
// This is a Q&D sketch, needs a11y
div.innerHTML = "<span tabindex class=delete>[X]</span><span class=filename></span>";
div.querySelector(".filename").textContent = file.name;
div.querySelector(".delete").addEventListener("click", function() {
formData.delete(fileId);
debugShowCurrentFiles("deleted");
div.remove();
div = null;
});
fileList.appendChild(div);
}
this.removeChild(input);
this.insertAdjacentHTML("beforeend", input.outerHTML);
input = null;
});
function debugShowCurrentFiles(action) {
const contents = [...formData.entries()];
console.log(`--- ${action}, updated formData contents (${contents.length}):`);
for (const [key, value] of contents) {
console.log(`${key}: ${value.name}`);
}
}
#file-list .delete {
margin-right: 2em;
cursor: pointer;
}
<div id="inputs">
<input type="file" multiple>
</div>
<div id="file-list"></div>
You can do this with FileList, heres an article about it.
Also added code snippet which outputs file name and type after you submit the form just for visualization.
let form = document.getElementById('file_drop_form');
function getFiles(event) {
event.preventDefault();
let files = document.getElementById('file').files;
for(let i = 0; i < files.length; i++) {
document.write(`Title: ${files[i].name}; Type: ${files[i].type} <br>`);
}
}
form.addEventListener('submit', getFiles);
<form id="file_drop_form" method="post" enctype="multipart/form-data">
<div>
<label for="file">Drop your files here</label>
<input type="file" id="file" name="file" required multiple>
</div>
<input type="submit" value="Submit">
</form>

how submit dynamic forms

I have the following problem that I cannot solve
is a form of this type
in HTML
<button (click)="addform()">agregar formulario</button>
<div class="conten-form">
<div class="MyForm">
<label>Nombre</label>
<input type="text" class="name">
<label>descripcion</label>
<input type="text" class="description">
<label>Foto</label>
<div class="img-cont">
<div class="img">
<img src="{{img}}">
</div>
<div class="addimg">
<input type="file" (change)="createimg($event)">
</div>
</div>
</div>
<div class="AddForm"></div>
<input type="buttom" value="enviar" (click)="enviarform()">
</div>
in TS
img : any; //to show
imgfile : any; //to send it through the form
constructor(...){...}
addform(){
let addform = document.querySelectorAll('.AddForm');
let myform = document.querySelectorAll('.MyForm');
let cloneform = myform.cloneNode(true);
addform.appendChild(cloneform);
}
createimg(event){
this.imgfile = event.target.files[0];
const reader = new FileReader();
reader.readAsDataURL(this.imgfile);
reader.onload = () => {
this.img = reader.result;
};
}
enviarform(event){
let nombre = document.querySelectorAll(".name");
let description = document.querySelectorAll(".description");
let formdata = new FormData;
//add all inputs class name
for (let i = 0; i < nombre .length; i++) {
let stringname = (nombre.[i] as HTMLTextAreaElement).value;
formdata.append('name',stringname);
}
//add all inputs class description
for (let i = 0; i < description.length; i++) {
let stringdescription = (description.[i] as HTMLTextAreaElement).value;
formdata.append('description',stringdescription );
}
//send the form
}
As you will see, I can add more forms with the add button, cloning the first one, the part of the text inputs I have solved to add as many as I want, but in the part of the inputs for the image I have no idea how to do it, the operation is that after attaching an image to the input, I get a preview image of what I am going to attach in the div.class = img, this makes it only work in the first form, and it no longer works in the forms that I add dynamically, as it could fix this issue? taking into account that I have to send it through the formdata in a single shipment, I thank you in advance.
you should not use
let addform = document.querySelectorAll('.AddForm');
let myform = document.querySelectorAll('.MyForm');
let cloneform = myform.cloneNode(true);
at all. to add forms. instead you should create a separate component for each form.
check my question earlier on stackoverflow to get what I mean.
more specifically check the answer stackblitz.

How can I display an image and text from an array on a webpage?

Basically, I have a simple webpage with two text fields, and a button to choose an image from the computer. What I need to happen, is for the user to pick a photo, fill in the "artist" and "text" field, press the "Add image" button. This should then add all three items to an array, and display both the image in a div, and the text in an "li" list item.
At the moment, the image works, and will display on the screen when the button is pressed, the text seems to get pushed into the array, but no matter what I do, I can't get the text to display on the web page. I also couldn't get the image to display if I turned the array into objects, which is why I've split the pushing of the text to a separate function.
Either way, whatever I try, either breaks the image display, or breaks the text display. I can't get both to display on the page. I am trying to make it so whenever a new image and text is added, it will all display one after another sort of like this:
[album cover]
[text]
[album cover]
[text]
And this would carry on down the screen as you keep adding more. Can someone please tell me where I'm going wrong with this. Thanks.
var info = {
myImages: [],
addImage: function(imageBlob) {
this.myImages.push(imageBlob);
},
addInfo: function(artist, title) {
this.myImages.push({
artist: artist,
title: title
});
},
redrawImages: function() {
var divForImages = document.getElementById('myImages');
divForImages.innerHTML = '';
this.myImages.forEach((imageBlob) => {
var img = document.createElement('img');
img.style.width = "200px";
img.style.height = "200px";
img.src = URL.createObjectURL(imageBlob);
divForImages.appendChild(img);
});
},
redrawInfo: function() {
var ul = document.querySelector('ul');
this.myImages.forEach(function (item) {
let li = document.createElement('li');
ul.appendChild(li);
li.innerHTML += item;
});
}
}
var handlers = {
addImageAndRedraw: function() {
var fileInput = document.getElementById('fileInput');
var artistField = document.getElementById('artistField');
var titleField = document.getElementById('titleField');
if (fileInput.files.length === 1) {
info.addImage(fileInput.files[0]);
info.addInfo(artistField.value, titleField.value);
info.redrawImages();
info.redrawInfo();
}
}
}
var button = document.getElementById('button');
button.addEventListener('click', handlers.addImageAndRedraw);
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<h1>My images</h1>
<input id="fileInput" type="file" accept="image/*" multiple="false" value="Select image">
<input id="button" type="button" value="Add image and redraw">
<div>
<input id="artistField" type="text" placeholder="artist">
<input id="titleField" type="text" placeholder="title">
</div>
<hr>
<div id="myImages">
</div>
<ul></ul>
<script src="album.js"></script>
</body>
</html>
You're adding the info to the same array as the images, so it will end up like [image, info, image, info] etc.. You're better off adding an object that contains both the image and the info, and then treating it as a single object when you add the contents to the page, rather than adding the images and text in separate functions. Also, you're not clearing the info list, so it would grow exponentially.
Here's a modified example, just after tweaking the bits I mentioned above...
var info = {
myInfo: [],
add: function(imageBlob, artist, title) {
this.myInfo.push({
image: imageBlob,
artist: artist,
title: title
});
},
redraw: function() {
var divForImages = document.getElementById('myImages');
divForImages.innerHTML = '';
var ul = document.querySelector('ul');
ul.innerHTML = "";
this.myInfo.forEach((info) => {
var img = document.createElement('img');
img.style.width = "200px";
img.style.height = "200px";
img.src = URL.createObjectURL(info.image);
divForImages.appendChild(img);
let li = document.createElement('li');
ul.appendChild(li);
li.innerHTML = info.artist + " - " + info.title;
});
},
}
var handlers = {
addImageAndRedraw: function() {
var fileInput = document.getElementById('fileInput');
var artistField = document.getElementById('artistField');
var titleField = document.getElementById('titleField');
if (fileInput.files.length === 1) {
info.add(fileInput.files[0], artistField.value, titleField.value);
info.redraw();
}
}
}
var button = document.getElementById('button');
button.addEventListener('click', handlers.addImageAndRedraw);
<h1>My images</h1>
<input id="fileInput" type="file" accept="image/*" multiple="false" value="Select image">
<input id="button" type="button" value="Add image and redraw">
<div>
<input id="artistField" type="text" placeholder="artist">
<input id="titleField" type="text" placeholder="title">
</div>
<hr>
<div id="myImages"></div>
<ul></ul>

Drag and drop zone in JS - File input

I have problem with uploading files in my existing form.
What I am looking for is script that will make possible to add multiple files (max 5) and you can add at once from one to five files. If you add one by one, I need it to add new, not replace the previous one.
I got form looking like this:
Name
LastName
Email
Phone number
Interests
Files
and filenames are created like this: name+lastname+phonenumber+filename
And I add entry to database with path of everyfile - this is done and I need only good drag and drop zone.
I need it to show added filename and make it possible to delete added file from queue.
But I don't want files to upload when I add them. I want it to upload when I submit my whole form so filename can be created and path to DB can be added.
Could anyone please provide me good script to that, or based on my scripts from two topics I mentioned before make it avaiable to do what I want?
I was able to add 5 files one by one and I described it here:
HTML Add multiple file to the input
Also I was able to add more at once what I described here:
https://stackoverflow.com/questions/30499388/dropzone-js-into-another-form
I think that this example help you.
This app allow drag and drop files to gray zone (1 or 5)
If you click on the file name, it removes file from the list.
function init() {
//get dragdrop element
var dd = document.getElementById("dragdrop");
//get files element
$files = document.getElementById("files");
dd.ondragover = stop;
dd.ondragleave = stop;
if ('FileReader' in window) {
document.ondrop = dragAccept;
}
//get form
var $form = document.querySelector("form");
//catch on submit
$form.onsubmit = function (e) {
stop(e);
var fd = new FormData();
//apend files to FormData
for (var i in files){
var file = files[i].file;
var filename = file.name;
var name = "file";
fd.append(name, file, filename);
};
//append inputs to FormData
var $inputs = $form.querySelectorAll("input");
for (var i = 0; i < $inputs.length; i++) {
var $input = $inputs[i];
fd.append($input.getAttribute("name"), $input.value);
}
//Send data
var xhr = new XMLHttpRequest();
xhr.open('POST', '/echo/html/', true);
xhr.send(fd)
}
}
function stop(e) {
e.stopPropagation();
e.preventDefault();
}
function dragAccept(e) {
stop(e);
if (e.dataTransfer.files.length > 0)
for (var i = 0; i < e.dataTransfer.files.length; i++) {
addFile(e.dataTransfer.files[i]);
}
}
//file list store
var files = {};
// html element of file list
var $files = null;
//add file to file list
function addFile(file) {
//add files with diferent name, max files count 5
if (!(file.name in files) && Object.keys(files).length < 5) {
var div = createFile(file.name);
$files.appendChild(div);
files[file.name] = {
file: file,
element: div
}
}
}
//create html element with file name
function createFile(name) {
var div = document.createElement("div");
div.innerText = name;
var input = document.createElement("input")
//remove on click
div.addEventListener("click", function () {
$files.removeChild(this);
delete files[name];
})
return div;
}
window.addEventListener("load", init);
<form method="post" enctype="multipart/form-data" action="">
<label>Name<input name="name" /></label>
<label>Last name<input name="lastName" /></label>
<label>Email<input name="email" /></label>
<div id="dragdrop" style="width: 300px; height: 300px; background-color:lightgray">Drag drop zone</div>
<div id="files"></div>
<button type="submit">Send</button>
</form>

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