This question already has answers here:
How to quickly and conveniently disable all console.log statements in my code?
(38 answers)
Closed 1 year ago.
Say I have a function imported from a library
import doSomething from 'someLibrary';
And doSomething has a console.log() call inside of it. So, when I call do something
doSomething();
Some message is logged to the console. How do I call the function doSomething without it logging anything to the console?
Try this:
{
let console = {log: ()=>{}};
doSomething();
}
Related
This question already has answers here:
What is the difference between a function call and function reference?
(6 answers)
addEventListener calls the function without me even asking it to
(5 answers)
Closed 1 year ago.
Goal
Console must log a message only on clicking the button.
Set-up
const button_l = document.querySelector('.btn-left');
method-1 (Using arrow function as a callback)
button_l.addEventListener('click', () => {
console.log('I am in')
});
method-2 (Using function as a callback)
button_l.addEventListener('click', changeSlide());
function changeSlide() {
console.log('Am I globally present?');
}
Problem Facing
Using method-1 gives the desired results.
Using method-2, the function is called on page load, but when I remove the parentheses (from changeSlide() to changeSlide), it functions as it should, why is it so?
I think it is something very fundamentally obvious that I do not know.
I appreciate a link/reference to any helpful theory/understanding.
This question already has answers here:
Why I can't pass console.log as a callback argument in Chrome (and Safari)?
(2 answers)
Closed 2 years ago.
Why does console.log need to wrapped before I can use it in an event handler?
https://jsfiddle.net/7e5yLh63/17/
In the example above, this code does nothing (line 44-51) when I click 'Add':
function ManufacturerWrapper() {
return <AddManufacturerForm onAddManufacturer={console.log} />
}
But when I change it to
function log(msg) {
console.log(msg);
}
function ManufacturerWrapper() {
return <AddManufacturerForm onAddManufacturer={log} />
}
It logs to the console as expected. Why can't I just pass in console.log directly? Why do I need to wrap it in my own function first?
I'm using Firefox if that matters
You're probably asking for this:
onAddManufacturer={()=>console.log('log this!')}
This question already has answers here:
How to disable JavaScript function calls from the browser console?
(6 answers)
Closed 3 years ago.
Alright so I've a function (not exactly the one written bellow, that one is just an example)
function test()
{
alert("Hello");
}
Now the problem is that people are able to go into console and just type "test()" and call the function.
Is there a way to prevent this? I dont want of people to call functions from the console.
You can narrow the context that your function is executed in, eg:
(function() {
function test() { /* Do anything */ }
test();
// Call test anywhere here
})()
test(); // Error: test is undefined
This question already has answers here:
JavaScript: Overriding alert()
(12 answers)
Closed 4 years ago.
Is it possible to change the alert() function to log the message instead of showing up a popup?
Some outside team members does like the use the alert function, but we don't want it because they aren't removing them.
So I want to add some code in our angular application that logs the message in the console instead of popping up.
So, I want some code which don't require to change all the calls to alert() but a kind of hook to that function which transforms it to console.log()
Try this
window.alert = window.console.log
window.alert('Hello from console.log')
This question already has answers here:
Why is the method executed immediately when I use setTimeout?
(8 answers)
Closed 8 years ago.
Exactly, is console.log() a function? Why do these following two code snippets have different output?
function delay(x) {
console.log('Start of timeout');
return x;
};
setTimeout(function(){console.log('End of timeout');}, delay(5000));
console.log('Start to do something else');
.
function delay(x) {
console.log('Start of timeout');
return x;
};
setTimeout(console.log('End of timeout'), delay(5000)); // ???????
console.log('Start to do something else');
Yes, console.log is a function.
The first snippet uses the expected syntac for setTimeout. The second calls console.log inline, which returns undefined. That comes the first argument to setTimeout. That explains the different timing of when End of timeout appears.