Trying to sort the object with the max date. One id may have multiples dates. Below is the format of the object where id:123 has two dates. So I am trying to take the max date for the user 123. I used the sort method and storing the array[0] but still there is something missing.
var arr = [
{
"scores": [
{
"score": 10,
"date": "2021-06-05T00:00:00"
}
],
"id": "3212"
},
{
"scores": [
{
"score": 10,
"date": "2021-06-05T00:00:00"
},
{
"score": 20,
"date": "2021-05-05T00:00:00"
}
],
"id": "123"
},
{
"scores": [
{
"score": 5,
"date": "2021-05-05T00:00:00"
}
],
"id": "321"
}
]
What I tried is
_.each(arr, function (users) {
users.scores = users.scores.filter(scores => new Date(Math.max.apply(null, scores.date)));
return users;
});
Expecting the output to look like the following with the max date selected.
[
{
"scores": [
{
"score": 10,
"date": "2021-06-05T00:00:00"
}
],
"id": "3212"
},
{
"scores": [
{
"score": 10,
"date": "2021-06-05T00:00:00"
}
],
"id": "123"
},
{
"scores": [
{
"score": 5,
"date": "2021-05-05T00:00:00"
}
],
"id": "321"
}
]
Your filter callback function is not performing a comparison to filter the correct element. Also, although applying the "maximum" algorithm on the dates as string would be fine in your case (because of the date format you have), it would be much safer to transform the date strings into date objects to consistantly get correct results regardless of the format.
In the solution below, you can use a combination of Array.map() and Array.sort() to copy and process your data in the correct result.
const data = [{
'scores': [{
'score': 10,
'date': '2021-06-05T00:00:00'
}],
'id': '3212'
}, {
'scores': [{
'score': 10,
'date': '2021-06-05T00:00:00'
}, {
'score': 20,
'date': '2021-05-05T00:00:00'
}],
'id': '123'
}, {
'scores': [{
'score': 5,
'date': '2021-05-05T00:00:00'
}],
'id': '321'
}];
// map the data and return the updated objects as the result
const result = data.map((user) => {
// copy the scores array to not mutate the original data
const sortedScores = user.scores.slice();
// sort the scores array by date descending
sortedScores.sort((a, b) => (new Date(b.date) - new Date(a.date)));
// return the same user with the first score from the sorted array
return {
...user,
scores: [sortedScores[0]]
};
});
console.log(result);
Related
JSON Object:
{
"students_detail": [
{
"student_id": 1,
"name": "abc",
"roll_number": 10
},
{
"student_id": 2,
"name": "pqr",
"roll_number": 12
}
],
"subject_details": [
{
"subject_id": 1,
"subject_name": "math"
},
{
"subject_id": 2,
"subject_name": "english"
}
],
"exam_details": [
{
"exam_id": 1,
"exam_name": "Prelim"
}
],
"mark_details": [
{
"id": 1,
"exam_id": 1,
"subject_id": 1,
"student_id": 1,
"mark": 51
},
{
"id": 2,
"exam_id": 1,
"subject_id": 2,
"student_id": 2,
"mark": 61
}
]
}
Ouptut:
{
"student_mark_details": [
{
"abc": {
"roll_number": 10,
"Prelim": [
{
"subject_name": "math",
"mark": 51
}
]
},
"pqr": {
"roll_number": 12,
"Prelim": [
{
"subject_name": "english",
"mark": 61
}
]
}
}
]
}
i tried using loops and accesing student_id in both object and comparing them but code gets too messy and complex,is there any way i can use map() or filter() in this or any other method.
i have no idea where to start,my brain is fried i know im asking lot but help will be appreciated (any link/source where i can learn this is fine too)
Your output object really has a weird format: student_mark_details is an array of size 1 that contains an object that has all your students in it. Anyway, this should give you what you need. It is a format that you find often because it is a system with primary key and secondary key used a lot in databases.
The key to manage that is to start with what is at the core of what you are looking for (here, you want to describe students, so you should start from there), and then navigate the informations you need by using the primary/secondary keys. In JS, you can use the find() function in the case where one secondary key can be linked only to one primary key (ex: one mark is linked to one exam), and the filter() function when a secondary key can be linked to multiple secondary keys (ex: a student is linked to many grades).
I am not sure if this is 100% what you need because there are maybe some rules that are not shown in your example, but it solves the problem you submitted here. You might have to test it and change it depending of those rules. I don't know what your level is so I commented a lot
const data = {
"students_detail": [
{
"student_id": 1,
"name": "abc",
"roll_number": 10
},
{
"student_id": 2,
"name": "pqr",
"roll_number": 12
}
],
"subject_details": [
{
"subject_id": 1,
"subject_name": "math"
},
{
"subject_id": 2,
"subject_name": "english"
}
],
"exam_details": [
{
"exam_id": 1,
"exam_name": "Prelim"
}
],
"mark_details": [
{
"id": 1,
"exam_id": 1,
"subject_id": 1,
"student_id": 1,
"mark": 51
},
{
"id": 2,
"exam_id": 1,
"subject_id": 2,
"student_id": 2,
"mark": 61
}
]
}
function format(data) {
const output = {
"student_mark_details": [{}]
};
//I start by looping over the students_detail because in the output we want a sumary by student
data.students_detail.forEach(student => {
//Initialization of an object for a particular student
const individualStudentOutput = {}
const studentId = student.student_id;
const studentName = student.name;
//The rollNumber is easy to get
individualStudentOutput.roll_number = student.roll_number;
//We then want to find the exams that are linked to our student. We do not have that link directly, but we know that our student is linked to some marks
//Finds all the marks that correspond to the student
const studentMarkDetails = data.mark_details.filter(mark => mark.id === studentId);
studentMarkDetails.forEach(individualMark => {
//Finds the exam that corresponds to our mark
const examDetail = data.exam_details.find(exam => individualMark.exam_id === exam.exam_id);
//Finds the subject that corresponds to our mark
const subjectDetail = data.subject_details.find(subject => individualMark.subject_id === subject.subject_id);
//We then create a grade that we will add to our exam
const grade = {
subject_name: subjectDetail.subject_name,
mark: individualMark.mark
}
//We then want to add our grade to our exam, but we don't know if our output has already have an array to represent our exam
//So in the case where it does not exist, we create one
if (!individualStudentOutput[examDetail.exam_name]) {
individualStudentOutput[examDetail.exam_name] = [];
}
//We then add our grade to the exam
individualStudentOutput[examDetail.exam_name].push(grade);
});
//Now that we have finished our individual output for a student, we add it to our object
output.student_mark_details[0][studentName] = individualStudentOutput;
})
return output;
}
console.log(JSON.stringify(format(data)))
Trouble:
[
{
"project_id": 1,
"project_name": "CDP",
"role": "PL"
},
{
"project_id": 2,
"project_name": "Admincer",
"role": "PM"
},
I want to add the "project_id" property from the above three properties to another array using some method.
My idea is: 1. First of all, if I could copy the "project_id" property of this array to the second Nested JSON array, it would be fine.
What I looked up:
const obj = {
"project_id": 1,
"project_name": "CDP",
"role": "PL"
};;
const objCopy = {
"start_time": "09:00:00",
"end_time": "18:00:00",
"rest_time": "01:00:00",
"worked_time": "08:00:00",
"is_wfh": true,
"id": 1, 1,
"work_day_id": 45,
"time_cards": [
{
... obj
}
]
};;
console.log (objCopy);
I found that I could copy it this way.
I tried the above code in Chrome Console.
The array was copied, but the entire object was copied. I just want to copy the properties of project_id.
I want to create a new property called "prj_name" in this array and display only that property in Vuetify.
async fetchWorkerTimeCard() {
try {
this.worker_data = []
await this.$axios.$get('/worker_time_card', {
params: {
work_date: this.calendarVal
}
}).then(data => {
this.worker_data = data
})
var projects = await this.fetch_worker_projects()
console.log(projects)
} catch (error) {
console.log(error)
this.worker_data = []
}
},
<script src="https://cdnjs.cloudflare.com/ajax/libs/vue/2.5.5/vue.js"></script>
<v-card>
<v-data-table v-if="worker_data.time_cards" :headers="headers2" :items="worker_data.time_cards"></v-data-table>
</v-card>
You can simply change your object data like any other object in JS.
const obj = {
"project_id": 1,
"project_name": "CDP",
"role": "PL"
};
const objCopy = {
"start_time": "09:00:00",
"end_time": "18:00:00",
"rest_time": "01:00:00",
"worked_time": "08:00:00",
"is_wfh": true,
"id": 1,
"work_day_id": 45
}
console.log({...obj, ...objCopy})
This will create 1 object that merged.
Or if you just want to project_id value then just change it like:
objCopy.project_id = obj.project_id
If I'm understanding your first question correctly, you might be interested in the map function, which allows you to create a new array from an existing array. So, for example, if the first snippet you posted is an array of objects we call projects, you could use:
var projectIds = projects.map(p => p.project_id), where projectIds would now be an array of just project ids.
It seems like you might be asking more than this though, so I second Bravo's request for more clarification/reorganization in your question.
I'm not pretty sure if you want either of the following results:
{
"start_time": "09:00:00",
"end_time": "18:00:00",
"rest_time": "01:00:00",
"worked_time": "08:00:00",
"is_wfh": true,
"id": [
1,
1
],
"work_day_id": 45,
"time_cards": [
{
"project_id": 1
},
{
"project_id": 2
}
]
}
or this
{
"start_time": "09:00:00",
"end_time": "18:00:00",
"rest_time": "01:00:00",
"worked_time": "08:00:00",
"is_wfh": true,
"id": [
1,
1
],
"work_day_id": 45,
"time_cards": [
"project_id": [1, 2]
}
In case you need the first scenario, the following code may help you:
// This function return an array with: [{project_id: Number}]
function onlyIds(obj) {
const ids = [];
// Iterate the obj Array
obj.forEach(element => {
// Push a new JSON: "{project_id: 1}" or whatever
ids.push({ project_id: element.project_id });
});
// return an array that only contains the project_id
return ids;
}
const obj = [
{
project_id: 1,
project_name: 'CDP',
role: 'PL',
},
{
project_id: 2,
project_name: 'Admincer',
role: 'PM',
},
];
const objCopy = {
start_time: '09:00:00',
end_time: '18:00:00',
rest_time: '01:00:00',
worked_time: '08:00:00',
is_wfh: true,
id: [1, 1],
work_day_id: 45,
time_cards: onlyIds(obj),
};
console.log(onlyIds(obj));
console.log(objCopy);
I'm pretty sure there should be any more elegant/optimal way (as using any kind of higher-order function I may be missing right now) but as far as I understood, this should do the job.
I have two different JSON object. One object is empList and other one is holidayList.
I want to add hours from each JSON object.Andthe sum of hours should be pushed to sumHoursList JSON object.I am doing this using Angular6.
I am not getting exactly how to iterate this to get the required result.
Basically I want to add hours from both the datalist of empList , to that want to add hours from holiday list, and the sum value should
append in sumhourlist
Below is my code.
this.empList = [
{
'id': 1,
'name': 'Name1',
datalist: [
{
"date": 1,
"hours": 6
},
{
"date": 2,
"hours": 0
},
{
"date": 3,
"hours": 12
}
]
},
{
'id': 2,
'name': 'Name2',
datalist:[
{
"date": 1,
"hours": 0
},
{
"date": 2,
"hours": 8
},
{
"date": 3,
"hours": 0
}
]
},
];
this.holidayList=[
{
"date": 1,
"hours": 0
},
{
"date": 2,
"hours": 8
},
{
"date": 3,
"hours": 12
}
]
sumHoursList = [
{
"date": 1,
"hours": 6
},
{
"date": 2,
"hours": 16
},
{
"date": 3,
"hours": 24
}
]
Can anyone please help me how to do this.
If I understand you correctly, you need to sum the hour values of all entries with the same date and it's irrelevant in which source they are located.
Basically you could do it like this (not the most efficient way but to give you an idea):
// map sources into a unified data structure
const extractedArraysFromEmpList = emplist.map((entry)=>entry.datalist)
const sources:Array<Array<{
date:number,
hours:number
}>> = [...extractedArraysFromEmpList,holidaylist];
// now reduce the various sources into one summed array
const result = sources.reduce((reducer:Array<{date:number,hours:number}>, singleSourceArray)=>{
singleSourceArray.forEach((item:{date:number,hours:number}) => {
const existingEntry = result.find((summedItem)=>summedItem.date===item.date);
// if a entry with matching date already exists, sum hours
if(existingEntry) existingEntry.hours += item.hours;
// if no entry exists, add it.
else result.push({date:item.date,hours:item.hours})
}
}, [])
// result is sumHoursList
Note that code is untested. But it should give you an idea of how to solve this case.
This is how I understand the question. You want for each date add the hours together. With this loop you emp array can contain a dynamic number of datalists.
let sum = holidayList
empList.forEach((emp) => emp.datalist.forEach((obj, i) => sum[i].hours += obj.hours))
console.log(sum)
// output: [{ date: 1, hours: 6 }, { date: 2, hours: 16 }, { date: 3, hours: 24 }]
Please also note that these are not JSON objects. They are JavaScript objects.
I need a way to match the closest number of an elasticsearch document.
I'm wanting to use elastic search to filter quantifiable attributes and have been able to achieve hard limits using range queries accept that results that are outside of that result set are skipped. I would prefer to have the closest results to multiple filters match.
const query = {
query: {
bool: {
should: [
{
range: {
gte: 5,
lte: 15
}
},
{
range: {
gte: 1979,
lte: 1989
}
}
]
}
}
}
const results = await client.search({
index: 'test',
body: query
})
Say I had some documents that had year and sales. In the snippet is a little example of how it would be done in javascript. It runs through the entire list and calculates a score, then based on that score it sorts them, at no point are results filtered out, they are just organized by relevance.
const data = [
{ "item": "one", "year": 1980, "sales": 20 },
{ "item": "two", "year": 1982, "sales": 12 },
{ "item": "three", "year": 1986, "sales": 6 },
{ "item": "four", "year": 1989, "sales": 4 },
{ "item": "five", "year": 1991, "sales": 6 }
]
const add = (a, b) => a + b
const findClosestMatch = (filters, data) => {
const scored = data.map(item => ({
...item,
// add the score to a copy of the data
_score: calculateDifferenceScore(filters, item)
}))
// mutate the scored array by sorting it
scored.sort((a, b) => a._score.total - b._score.total)
return scored
}
const calculateDifferenceScore = (filters, item) => {
const result = Object.keys(filters).reduce((acc, x) => ({
...acc,
// calculate the absolute difference between the filter and data point
[x]: Math.abs(filters[x] - item[x])
}), {})
// sum the total diffences
result.total = Object.values(result).reduce(add)
return result
}
console.log(
findClosestMatch({ sales: 10, year: 1984 }, data)
)
<script src="https://codepen.io/synthet1c/pen/KyQQmL.js"></script>
I'm trying to achieve the same thing in elasticsearch but having no luck when using a function_score query. eg
const query = {
query: {
function_score: {
functions: [
{
linear: {
"year": {
origin: 1984,
},
"sales": {
origin: 10,
}
}
}
]
}
}
}
const results = await client.search({
index: 'test',
body: query
})
There is no text to search, I'm using it for filtering by numbers only, am I doing something wrong or is this not what elastic search is made for and are there any better alternatives?
Using the above every document still has a default score, and I have not been able to get any filter to apply any modifiers to the score.
Thanks for any help, I new to elasticsearch links to articles or areas of the documentation are appreciated!
You had the right idea, you're just missing a few fields in your query to make it work.
It should look like this:
{
"query": {
function_score: {
functions: [
{
linear: {
"year": {
origin: 1984,
scale: 1,
decay: 0.999
},
"sales": {
origin: 10,
scale: 1,
decay: 0.999
}
}
},
]
}
}
}
The scale field is mandatory as it tells elastic how to decay the score, without it the query just fails.
The decay field is not mandatory, however without it elastic does not really know how to calculate the new score to documents so it will end up giving a default score only to documents in the range of origin + scale which is not useful for us.
source docs.
I also recommend you limit the result size to 1 if you want the top scoring document, otherwise you'll have add a sort phase (either in elastic or in code).
EDIT: (AVOID NULLS)
You can add a filter above the functions like so:
{
"query": {
"function_score": {
"query": {
"bool": {
"must": [
{
"bool": {
"filter": [
{
"bool": {
"must": [
{
"exists": {
"field": "year"
}
},
{
"exists": {
"field": "sales"
}
},
]
}
}
]
}
},
{
"match_all": {}
}
]
}
},
"functions": [
{
"linear": {
"year": {
"origin": 1999,
"scale": 1,
"decay": 0.999
},
"sales": {
"origin": 50,
"scale": 1,
"decay": 0.999
}
}
}
]
}
}
}
Notice i have a little hack going on using match_all query, this is due to filter query setting the score to 0 so by using the match all query i reset it back to 1 for all matched documents.
This can also be achieved in a more "proper" way by altering the functions, a path i choose not to take.
I want to use Lodash chain function to filter through an arrays nested array items and then return the full parent object.
Here is some dummy data from my use case to illustrate my issue:
const capital = [
{
"financeCategory": "Loans",
"financeCategoryId": "22HM6fFFwx9eK2P42Onc",
"financeElements": [
{
"financeCategoryId": "22HM6fFFwx9eK2P42Onc",
"financeElementId": "JQiqqvGEugVQuI0fN1xQ",
"financeElementTitle": "Convertible loan",
"data": [
{
"month": 1,
"value": 100,
"year": "2020"
},
{
"month": 1,
"value": 100,
"year": "2019"
},
],
}
]
},
{
"financeCategory": "Investments",
"financeCategoryId": "JtnUsk5M4oklIFk6cAlL",
"financeElements": []
},
{
"financeCategory": "Ownerships Contribution",
"financeCategoryId": "PaDhGBm5uF0PhKJ1l6WX",
"financeElements": []
}
];
I want to filter on the "data" array within the financeElements and then return full expense object with the filter applied on "data".
Let's say I want to manipulate the expense object and only get the data on the financeElements that have the year 2020. I've tried like so:
const expenseFiltered: any = _.chain(expenses)
.flatMap('financeElements')
.flatMap('data')
.filter({year: '2020' as any}).value();
But that just gives me the filtered "data" objects.
Output:
[{
"month": 1,
"value": 100,
"year": "2020"
}]
Now I know there are ways that I could use that to produce the full object with the filtered data, but I really want to do this in just one simple _.chain command
Desired output
[
{
"financeCategory": "Loans",
"financeCategoryId": "22HM6fFFwx9eK2P42Onc",
"financeElements": [
{
"financeCategoryId": "22HM6fFFwx9eK2P42Onc",
"financeElementId": "JQiqqvGEugVQuI0fN1xQ",
"financeElementTitle": "Convertible loan",
"data": [
{
"month": 1,
"value": 100,
"year": "2020"
}
],
}
]
},
{
"financeCategory": "Investments",
"financeCategoryId": "JtnUsk5M4oklIFk6cAlL",
"financeElements": []
},
{
"financeCategory": "Ownerships Contribution",
"financeCategoryId": "PaDhGBm5uF0PhKJ1l6WX",
"financeElements": []
}
]
Is this possible using lodash chain?
A chain is used to transform a structure in several steps. In your case, you don't want to change the structure. You can use nested Array.map() (or lodash's _.map()) calls to iterate and rebuild the structure, and internally _.filter() the data:
const capital = [{"financeCategory":"Loans","financeCategoryId":"22HM6fFFwx9eK2P42Onc","financeElements":[{"financeCategoryId":"22HM6fFFwx9eK2P42Onc","financeElementId":"JQiqqvGEugVQuI0fN1xQ","financeElementTitle":"Convertible loan","data":[{"month":1,"value":100,"year":"2020"},{"month":1,"value":100,"year":"2019"}]}]},{"financeCategory":"Investments","financeCategoryId":"JtnUsk5M4oklIFk6cAlL","financeElements":[]},{"financeCategory":"Ownerships Contribution","financeCategoryId":"PaDhGBm5uF0PhKJ1l6WX","financeElements":[]}];
const expenseFiltered = capital.map(ex => ({
...ex,
financeElements: ex.financeElements.map(fe => ({
...fe,
data: _.filter(fe.data, { year: '2020' })
}))
}));
console.log(expenseFiltered);
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.js"></script>